'Left' Function No Longer Working??
Jan 8, 2008
I developed a database in 2005 and used the 'Left' function in many of the queries to obtain the the correct text for output to reports. The database worked extremely well for a year and a half.
I have not accessed it for the past year. Recently I opened the database for use with a new project and I keep receiving the error message:
! Undefined function 'Left' in expression.
I haven't changed any of the expressions and do not understand why this funtion no longer works.
Any ideas?
Thanks
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Sep 29, 2005
Not exactly sure if we has anything to do with sql server so sorry if it isnt strictly relevant.
I have a database on sql server and am using an access data project as the front end. Have finsihed this and is working fine till I try and use it on another computer on the network. It still connects to the database fine (well on most machines on the network not sure why not on the others) but the problem is access functions in my reports and forms seem to have stopped working and show up as ?#name
Examples of the kind of functions I am talking about are
=Format$([DateFrom],"Long Date")
=[SumOfMinutes]60 & Format([SumOfMinutes] Mod 60,":00")
any suggestions?
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Nov 7, 2006
I recently upgraded to Access XP (2002) and now my application will not respond to F11 to get into the development window. This application has two mdb files. One is the database (with security), and the other one has the forms, queries, reports and links to the tables in the first mdb.
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Dec 6, 2005
This is really weird:
I have one text field [Lot Number], and another calculated field Left$([Lot Number],3) As Grade in a query. I'm getting the following error:
Function is not available in expressions in query expression Left$([Lot Number],3)
This query was working fine up until a few days ago when all my users started having the same issue.
If I use the expression Len([Lot Number]) As Length as a field, I get the correct length of the field value for every record.
Any thoughts here? Anyone else encounter a similar problem?
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Jul 20, 2005
I have a column in access containing codes in format K2316 and wish to remove Prefix (K) from this code.
How can i do this as a calculated field?
thanks
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May 17, 2006
Hello,
I have used the left function to provide me with the left x characters of a field, which works fine.
Description: Left([c$products],[diff])
However, I want to query this field to only give me certain descrpitions, but it will not work.
Can anyone let me know if this is possible, or if I'm totally out of luck,
Thanks,
J.
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Sep 13, 2007
I have an imported table with zipcodes, some are 5 digit some are 9. When i go to build my query i dont get an accurate number, i tried a left function to get the 1st 5 digits but keep getting a invalid syntax. I am in the query builder. anyone help me with syntax, heres what i currently have
Mail Zipcode «Expr» Left («stringexpr», «n»)
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May 2, 2005
Hi all - I have a database that has only 1 field of patient names (e.g., "Johnson,Peter S"). I also have a form that allows clinicians to lookup their patients and I want them to be able to type in the last name of their patient and get the info they need. Anyone know how to pull just the part of the name BEFORE the comma (i.e., the last name only)? The Left function won't do it because the last names are different lengths.
Also, is there a way to have the form pull all the names after each letter they enter? So when the user typed "J" it would pull Johnson, Jones, Jackowa, etc, but when they typed the "o" it would decrease the list to only Johnson and Jones.
Any thoughts would be great. Thanks.
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Mar 11, 2006
Hi there,
I have a query with Expr3: Left([POK],2) as one of my fields.
Whenever I try to run the query it pops out a message window saying
Syntax error (comma) in query expression.
Please tell me what I am doing wrong.
Thanks in advance.
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Feb 4, 2008
Hi, hope someone can help me. I want to run a query which acts on data in a table which has been imported from excel, where it was somewhat mangled. Basically, the field shows telephone numbers, but the leading zeros on the phone numbers have mostly been discarded. I want to replace the zeros if they're missing. (Here in the UK phone numbers always start with zero). What I'm trying to use is:
IIf(Left[fieldname],1)="0",[fieldname], "0" &[fieldname]))
But I get errors, I think maybe because of the first comma(?). Can anyone tell me how to achieve this? Any suggestions appreciated.
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Jan 9, 2012
I have a column with a date in it, and the left four characters are the year. I want to add another column that is just the year. I've tried doing an update query and updating the year column to left(date,4) but it doesn't work. How should I go about updating my year column?
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Aug 19, 2006
Hi!In my query i'd like to format a selected field.At the moment i write it like this:MyOwnFieldName:[Table].Field I want to achieve:MyOwnFieldName: Left([Table].Field, 4) & "-" & Right([Table].Field, 4).Is this possible?Thanks for helpful feedback ;)
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Nov 27, 2006
I have seen variations of this question and have tried to modify for my purpose, but have been unsuccessful. I need to extract the first four digits of the Social Security Number. We no longer view the whole number, but a variation of the first four of social and first four of first name. I have tried many variations of the Left Function to extract the data from the field:
Expr1: SSN(Left([SSN],4))
Expr1: Left([SSN],4)
Etc.
I get various errors, mostly involving the comma. I am at a loss since I usually search for the code and find that it works. In this case, it doesn't work. I am also trying to extract the first four of the first name and will later combine the two although I broke it down since I couldn't get the basic "left" function to work.
Please help if possible. :)
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Jul 23, 2015
I have to query a record with 2 of the same static characters. "-".I can get the left function with the first " but I can't get the rest up to the second "-"
Example: B-4352B-PXP02W01-10
TagNo: Left([EventInstanceID],InStr([EventInstanceID],"-")) Brings me the first char plus "-" The next section is needed also but the remainder is not.
Needed: B-4352B
Is there a Mid Function that I could add to go to the second chaacter instead of stopping at the first one?
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May 10, 2013
I am creating a query which uses 2 unbound text boxes to populate a Between function for 2 date fields. If I fill in the dates, it returns the corresponding data. If I leave them blank, however, it returns no records. Is there an easy way to tweak the query to return all records if left blank?
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Nov 2, 2014
I managed to produce a working Query with AllenBrowne's ConcatRelated function.What i'm unable to do is a new query with left join on the result of the query using the ConcatRelated function.I get error 3075: syntax error (missing operator) in query expression (free translation - MS ACCESS not English version)
If I do the normal join then it works fine, but I only get rows for which there are related concatenated values. But I do also need those rows where there are no concatenated values' fields.
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Aug 3, 2015
In my table I have a numerical field for case numbers. Our case numbers are in the format of YYMM000000 (YY = 2 digit year, MM = 2 digit month, remaining 0's are consecutive case numbers). In order to properly list the case numbers in descending order, I have
caseyr: Left([CaseNo],2) (which pulls the first 2 digits being the year)
officeno: Right([CaseNo],3) (which pulls the last 3 for our part of the case number)
This was working fantastic until I had to enter cases from 2009, ex: 0911000587
I have set the format for the CaseNo field to 000000000 everywhere it is. It displays the 09 cases perfectly, retaining the zero, however, my left function ignores it. In the case number of 0911000587, it pulls 91 as the first 2 digits. So, in the form that I list my cases in order, the 2009 cases are showing up first (because they're pulling as 91 instead of 09).
Is there anything I can do to force it to NOT ignore the leading zero?
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May 18, 2013
I am trying to calculate how many days are left till end of contract...
whats wrong with this formula
=DateDiff("d",[Completion_Date], Date())
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Jun 14, 2006
I have a large query that basically collects all informations for a given record from various tables. The query is then used as a controlsource for a report. It works fine. However, one of the tables referenced is a one-on-one relationship to the master table and there some records that do not have any corresponding records in that child table. I've entered in Nz() function for all fields from the child function to prevent the records without child records removed from the query's recordset, but it doesn't work. That is, query returns all records that has a child record, but not those without.I've already checked the Join properties to ensure that all parent records are displayed and only child records where there is a parent records.What should I do?
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Jun 29, 2006
Hi, I'm trying to compare 2 name fields to see if the last name of one field is found in the last name of the other field. In table A, the name is stored as LastName, FirstName. I've used the Left and InStr function to extract the last name successfully.
In Table S the name is stored as separate fields, Lastname and Firstname.
In a query I am trying to determine if the last name from table A appears in the last name field in table S
(s.lname Not Like '*Left([a.name],InStr([a.name],",")-1)*')
the problem I think I'm encountering is that I want access to see this statement as:
(s.lname NOT LIKE '*JOHNSON*') instead of searching for the Left function string
is there any way to put the value of the function in there without actually searching the function literally?
I tried [ ] and that didn't work.. any ideas? thanks!
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Oct 6, 2005
I am using the “count function” on an MS Access 2003 Form field. The count function seems to be working fine except it is not placing the result into the table field.
Does anybody know what I am doing wrong?
Can someone show me the proper format for using the count function used on a form field, where the result is to be placed in a table field?
Please Help!!!
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Aug 14, 2014
I have a specific question on the datediff function.
My example is =DateDiff("d",[Policy Issue Date],Date()) where [Policy Issue Date] is the inception date of an Insurance Policy.
I need to determine how many days the policy has been inforce. The formula works great in a query and I can see the number of days in that field when the query is run.
However, my dilemma is I want the same function to run off of a text box using its control source property and have the number of days calculate and be visible for each record on the form. This part is not working and the field is returning the #Error? message.
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Jul 1, 2013
I have an IIF function specified on a continuous sub-form as below - basically it checks to see if the value of two text boxes is equal, and if they are it displays 'And', if not it displays the value of the column EntitlementName. I'm trying to work around grouping not working in continuous forms.
When I view the form directly it works no problems but when I view the form as a sub-form instead of showing the correct output it shows #Name? Both the text boxes I refer to have the correct values in them.
=IIF([txtPrevValue]=[txtValue], Format("And"),Format([EntitlementName])
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Jul 23, 2015
I recently created a database to be used to store incoming invoices. We have 4 suppliers which supply the same material and wanted each supplier to have its own database.
I began by making a database which included all the key tables, forms, queries and functions I would need to then save 4 copies, one for each supplier. This just meant I would not have to repeat the process for each individual supplier.
The problem is all my data is external and upon importing it into the database it has made the search function (combo box) not return results.
I believe this is because:
1) The form was created before the records existed
2) The records were imported from an external source and not created using the form.
However, the way I have designed the form is so I can see all relevant information linked with a specific invoice. This aids in gathering information quickly about an invoice but also so I can input credit note and invoice query information linked to a specific invoice on the same page.
Is there anyway to remedy this?
Or use a similar search function that returns records in my form "Main View"
The last thing I want to do is have to create the form again, although I don't think this will work either as reason 2) states.
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Aug 21, 2014
I have a code module in my interface with 3 functions that run via separate forms with user inputs. Each function is similar in design, exporting data from a generated query to excel for input into external software.
The database is split into an interface FE (Access 2007) with linked tables BE (Access 2000). I have successfully tested each of the 3 functions in my code module with a set of tables containing fake test data. However, I have discovered that if I link to a different copy of the .mdb tables, 2 of the export functions no longer work and the third one still works fine.
What is causing the problem but the part that is not working correctly is the loop.
Here is my code module:
Option Compare Database
Option Explicit
Public Function CreateQCStaticChartsforReports() As Boolean
'Define variables for Static Chart creation
Dim qdf As DAO.QueryDef
Dim strSQLStatic As String
[Code] .....
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Jan 14, 2006
I created a DB program for my last job that resided on a stand alone PC. It has the Access generated user level security (so there's a "secured.mdb" file) and can only be opened via the desktop icon. In the past, when I copeid the db to a flash drive, took it home to work on it, it always said I didn't have permissions to run it unless I placed it in the right spot on my computer where I've got it set up with a secured file and the desktop to open it.
Yesterday, I noticed that I can now open it anywhere, including my laptop, and it just opens. My concern is, I don't trust the business where the program is being used to not take it and call it their own (I trust the management team, however).
ANy ideas why it no longer looks for the user level security now?
I'm running XP Pro on both machines, Access 2002 on the desktop and 2003 on the laptop.
Thanks.
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