3022 Error With Linked Tables

Mar 27, 2008

I dont use linked tables very often, and when I always seem to run into the same problem.

I have two tables. The pri table has an index key defined as an autoindex, with no duplicates. The sub-table is linked to the pri
table key in a many-to-one relationship. The linked field in the subtable is defined as a long integer non-keyed field.

All is okay, until I attemp to add a SECOND record. At that point I get a 3022 error, stating I cant do something because I am attempting to create a duplicate key.

I would love to fix it, nut I am not sure exactly what the problem is that needs to be fixed. The pri key would not SEEM to be getting duplicated, and the subtable linked field is not keyed. Hmmm, I guess I need a steer here please.

eatc7402

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Aug 3, 2006

Okay, I'm kind of stumped here.I have a subform that has a button that sends a user to a "sibling" subform on another tab page, pass some information to ensure they are adding more details to the same records rather than creating two separate record.First time I programmed it, I got an error 3022 (keys cannot have duplicate values). I checked the query of the sibling subform and saw that the ID is from the one side table. I changed it so many table's foreign key is used. Second try, I got an error 3341 (there isn't a matching key in one side table).After some thinking, it also occured to me that I had set the query this way to allow addition of new record which wouldn't be possible if I had the query pulling the many side key, not the one side key.How do I get the subform to accept the ID that is being passed and create a new record using that ID?:confused:

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http://www.imagedump.com/index.cgi?pick=get&tp=288631

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'do something


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