Build A Dimensional Fieldname In A Query

Feb 20, 2008

As example, I have a table with an Item number, introduction year and a number of historical and future Sales periods set per year, these sales columns are listed Y1990, Y1991, Y1992....... Y2015.

Based on each items introduction year, I want to list the first 5 years of sales.

I wanted to create a dimensional fieldname eg: FirstYear: "Y"&[introduction year] to get the value of that respective year. (I currently just get a text saying "Y1995", and not the content )

Any help is appreciated!:)


(Note: I can't transpose the data in the tables for other reason)

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Queries :: SUM Of Fieldname Holler When Fieldname Area Has The Same Value

Jun 26, 2015

I have got a query which gives me the following output;

Nr ----------- area ------- area 2 ---------- holler
14-1096-------1------------1-----------------5.9
14-1097-------2------------2-----------------7.8
14-1100-------1------------1-----------------13.4
14-1101-------2------------2-----------------7.8

What i would like to do is to calculate the sum of holler when they are in the same area.So the sum of nr 14-1096 + 14-1100 and 14-1097 + 14-1101. Ive tried to do the following;I tried to do the following just to check it would even work;

Code:
test: (SELECT Sum([holler]) FROM querytoetsn2hr_gemiddelde_filter WHERE ((querytoetsn2hr_gemiddelde_filter.area)=("1")))

Which worked perfectly, it gave me 19.3..

Code:
test: (SELECT Sum([holler]) FROM querytoetsn2hr_gemiddelde_filter WHERE ((querytoetsn2hr_gemiddelde_filter.area)=(querytoetsn2hr_gemiddelde_filter.area2)))

That gave me the sum of all 4 the Nrs. Which makes sense, because you basically say that as long as area and area are the same calculate the sum of holler.if there is a way to say "sum of holler when area has the same value".

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Inspection of the subreport fieldlist shows field 'Comment' still present.

How, other than remaking the rpt100 and both srpt100a and srpt100b, do I remove the field 'Comment'?

Gunner...:confused:

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Hi,
Self learning trying to modify a query fieldname and criteria thru code.

Have a small form with a button making a copy of a query/s (eventually making about 50 copies).
Once these have been made, would like to open the query up, which I can do, then modify both
the fieldname and the field criteria to suit my needs from parameters set in the form.

How do I do this if it can be done ?

Thanks in advance

Ian T

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Im finding a solution. Help me please. Thanks :eek:

- Roger
--
Have a nice day.

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I have some database with columns 'Number', 'Mfr Name' and 'Mfr Part Number'.
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Mfr Part Number - part number of a manufacturer where from we purchase the item
Each item may have one or more Mfr Name & Mfr Part Numbers.
----------------------------------------------------------------------
I need to build a following query:
Input gets part of Mfr Part Number and output is all Mfr Name & Mfr Part Number of match item.

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Oct 26, 2006

Hi everybody,

Let's say that I've got the following tables:
- tblCustomers(IDCust,NameCust)
- tblEmployees(IDEmpl,NameEmpl)
- tblProjects(IDProj,IDCust,IDEmpl,Duration)

My query:
SELECT tblCustomers.NameCust, tblProjects.IDProj, tblProjects.Duration, tblEmployees.NameEmpl, Sum(tblProjects.Duration) AS SumOfDuration
FROM (tblProjects INNER JOIN tblEmployees ON tblProjects.IDEmpl = tblEmployees.IDEmpl) INNER JOIN tblCustomers ON tblProjects.IDCust = tblCustomers.IDCust
GROUP BY tblCustomers.NameCust, tblProjects.IDProj, tblProjects.Duration, tblEmployees.NameEmpl
ORDER BY tblCustomers.NameCust;

What I'd like get when running my query is:

NameCust ------ IDProj - Duration ----- NameEmpl ------- ?????????
CUST1 ---------- 1 ------ 3 ------------ EMPL3 ---------- 7
CUST1 ---------- 2 ----- 10 ------------ EMPL4 --------- 10
CUST1 ---------- 9 ------ 2 ------------ EMPL3 ---------- 7
CUST1 --------- 11 ------ 2 ------------ EMPL3 ---------- 7
CUST1 --------- 13 ------ 8 ------------ EMPL1 ---------- 9
CUST1 --------- 18 ------ 1 ------------ EMPL1 ---------- 9
CUST2 ---------- 3 ----- 20 ------------ EMPL1 --------- 20
CUST2 ---------- 4 ----- 12 ------------ EMPL3 --------- 17
CUST2 ---------- 5 ------ 3 ------------ EMPL2 ---------- 4
CUST2 --------- 10 ------ 5 ------------ EMPL3 --------- 17
CUST2 --------- 17 ------ 1 ------------ EMPL2 ---------- 4
CUST3 ---------- 6 ----- 25 ------------ EMPL4 --------- 27
CUST3 --------- 14 ------ 2 ------------ EMPL1 --------- 14
CUST3 --------- 15 ------ 2 ------------ EMPL4 --------- 27
CUST3 --------- 16 ----- 12 ------------ EMPL1 --------- 14
CUST3 --------- 19 ------ 2 ------------ EMPL2 ---------- 2

where ???????? (manually done) = the sum of the Employee duration for ONE Customer !!!

But what I get instead:

NameCust ------ IDProj - Duration ----- NameEmpl ------- SumOfDuration
CUST1 ---------- 1 ------ 3 ------------ EMPL3 ---------- 3
CUST1 ---------- 2 ----- 10 ------------ EMPL4 --------- 10
CUST1 ---------- 9 ------ 2 ------------ EMPL3 ---------- 2
CUST1 --------- 11 ------ 2 ------------ EMPL3 ---------- 2
CUST1 --------- 13 ------ 8 ------------ EMPL1 ---------- 8
CUST1 --------- 18 ------ 1 ------------ EMPL1 ---------- 1
CUST2 ---------- 3 ----- 20 ------------ EMPL1 --------- 20
CUST2 ---------- 4 ----- 12 ------------ EMPL3 --------- 12
CUST2 ---------- 5 ------ 3 ------------ EMPL2 ---------- 3
CUST2 --------- 10 ------ 5 ------------ EMPL3 ---------- 5
CUST2 --------- 17 ------ 1 ------------ EMPL2 ---------- 1
CUST3 ---------- 6 ----- 25 ------------ EMPL4 --------- 25
CUST3 --------- 14 ------ 2 ------------ EMPL1 ---------- 2
CUST3 --------- 15 ------ 2 ------------ EMPL4 ---------- 2
CUST3 --------- 16 ----- 12 ------------ EMPL1 --------- 12
CUST3 --------- 19 ------ 2 ------------ EMPL2 ---------- 2

Any suggestion to build this Query ??
Thanks in advance

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(Dear Admin, don't be mad I posted this post elsewhere but had no luck with answers)

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id id1
1 1
2 1
3 1
4 1
5 3
6 3
7 4
8 4
9 4
...


I need to count the id1 - how many different id1 values are there.

This doesn't work:
SELECT COUNT(id1) FROM table GROUP BY id1
this also doesn't work:
SELECT COUNT(id1) FROM table

As I recall, it was something about DISTINCT function or something like that...?

Please help, I'm sure it's totally simple, but I'm stuck.

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A.

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