Cant Get Pop-up To Sync With Sub-form?

Hi Gang,

I am using Access 2000.

I have a Main form that displays a sub-form. On the sub-form is a image box that displays a jpeg associated with the current record. The jpegs are stored outside of the db as links and the links are stored in a table in a field called Image1Lrg_Path. Due to the GUI design the image box is a set size = 4cms X 5cms.

On the sub-form I have a cmd button that when clicked should open a seperate pop-up form that *should* display a large version of what ever jpeg is being displayed on the sub-form. The user would then have to close this pop-up to return to the db in order to continue scrolling through the records as normal.

Main Form = frmPlant_Main
Sub-Form = frmPlant_Sub1
Sub-Form Control = Garden_Sub
Image Box = Image1

pop-up form = frmLargeImage1
pop-up Image Box = Image1Lrg

Here's my problem:

If I set the pop-up form up a normal form and have a linked control on it (to display the image) and a text box (in which to type in the image path and name) and a cmd button that, when clicked, sets the image box to the value of the text box. Then this all works great, what ever jpeg file name I type in the text box, providing it exists of course, is displayed when I click the command button. Iset it up this way first as a test to see if I could get the image displayed OK.

Just for reference, here is the code I use for the command button;

-------------------------Code Start---------------------------

Private Sub Command1_Click()
On Error GoTo Err_Command1_Click

Me!Image1Lrg.Picture = Me!Image1Lrg_Path.Value

Exit_Command1_Click:
Exit Sub

Err_Command1_Click:
MsgBox Err.Description
Resume Exit_Command1_Click

End Sub
----------------------Code End--------------------------------


Now, if I try to link the pop-up to the image being displayed in the sub-form Access throws up "Can't find the form" errors.Just while I set this up, I am using the cmb button to set the path but in the final db I will want the pop-up form to select what ever jpeg is being displayed on the sub-form as its path.

Can any one suggest how I can get this to work?

Again, for reference, here is the code that I am trying to use when linking the image in the pop-up with that shown on the sub-form;

-------------------------Code Start---------------------------

Private Sub Command1_Click()
On Error GoTo Err_Command1_Click

Me!Image1Lrg.Picture = Forms![frmPlant_Main]![Garden_Sub].Form![Image1_Path].Value

Exit_Command1_Click:
Exit Sub

Err_Command1_Click:
MsgBox Err.Description
Resume Exit_Command1_Click

End Sub
----------------------Code End--------------------------------

My grateful thanks in advance,

Kenny