Check If A Form Is Open.

Sep 7, 2006

Hello everyone,

I have a question:

I have a form in wich I can add and edit employees.
I can open this "employee" form in 2 ways:
1. From another form
2. From the mainmenu

When I close the "employee" form I want to check if the otherform (1.) is open. If it is open I want to requery the other form. If it is closed I don't want to requery the other form.
How can I check if the other form is open?

I hope that you guys can help me and thanks in advance,
Johnny

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How I Can Check If Form Is Open

Mar 10, 2005

How i can check if form is open ??? sorry for noob question

I want check with VB if form is open or close ???
How i can do it???

example in VC++
if(!dialog.IsOpen())
{
...
}
else
{
...
}

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I'm trying to lock a checkbox when the forms open and depending if one has role as admin, it should unlock it.When I add the below code in the on open form I get error:

Code:
Me.lock_case_admin.Locked = True
Me.lock_case_admin.BackColor = 12632256

This is the part that should onlock if it is admin:

Code:
Me.lock_case_admin.Locked = False
Me.lock_case_admin.BackColor = 16777215

Maybe it is me, or the checkbox is giving the error that causes the dialogbox to open to to choose the ID nr.

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This is the idea I have but I don't know how to code the part where the form checks after update if the part_no exists in the other table, nor how to capture the part_no to the other form and then append both the part_no and the lines per part to the other table.

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I have a main form with 2 check boxes. The title of the first box is Manufacturing and the title of the second check box is Purchased. I have 2 different forms based on the titles of the check boxes. After the user checks one of the boxes, I want the user to click a command button which opens the correct form based on the box checked.

Using the On Click for the command button, I created this code, with no success:

Dim stDocName As String

If Me.Check14 = 1 Then
stDocName = "frmManufacture"
DoCmd.OpenForm stDocName
Else
If Me.Check16 = 2 Then
stDocName = "frmPurchase"
DoCmd.OpenForm stDocName
Else
stDocName = "frmError"
DoCmd.OpenForm stDocName
End If

End Sub

Thanks for helping with this problem.

Jeff

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Jul 4, 2007

hey guys

having a corruption issue with my database, it happens when a user updates a record and a second user has that record open elsewhere. then when the second user closes they save their changes over the top, corrupting the whole record.

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thanks

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Some of the things that bring me screeching halt really surprise me. I swear, this sounds like it should be so easy....

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All help, as always, is much appreciated!

John

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My application relies on whether Outlook is open and more importantly, with the correct Exchange profile selected. To ensure this I have the following code which, on the work PCs (Windows XP and Office 2003) works correctly.

Code:

If Outlook_is_Running = True Then
Set myOlApp = CreateObject("Outlook.Application", "localhost")
Set myNameSpace = myOlApp.GetNamespace("MAPI")
Set colFolders = myNameSpace.Folders
On Error Resume Next

[code]....

The work PCs are being upgraded soon to Windows 7 and Office 2007 so I have taken the application home and started to develop it on my home PC (Windows 8.1 64 and Office 2013 64). I have used PtrSafe where necessary and have compiled with no errors, but this code always returns false even though Outlook 2013 is open.

On further investigation, if I comment out the 'On Error Resume Next line I get the error Active X component cannot create the object (or similar) Error 429. This is the same regardless of whether Outlook is open or not

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Here is my code:

Code:
Private Sub CmdSavePDF_Click()
Dim MyFileName As String
Dim MyPath As String
'Dim CompanyName As String

[code]...

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I would like to be able to check if a db is open and if it is to prevent the user from proceeding.

I use the Access 2013 Runtime. I can check if a db is open by trying to open Exclusively, using something like

Code: [URL] ....

But if the db is already open Not exclusively and I try to open it exclusively it does not raise an error and it allows the user to open the db in Read Only mode.

I would like to be able to prevent this, because careless and/or inexperienced users may open several instances of the db.

Of course, if the db is already open exclusively it does not allow you to open it exclusively another time.

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I am storing values of pictures and the location of them in a table, this works fine!... using OpenRecordset. The problem is that when the function is called to store the information, it just keeps adding the same values of each file in the folder over and over again in a word "Duplicating" the information.

I have tried various methods using the OpenRecordset, but cannot seem to find the correct manor of applying the code.

Below is the function I have for storing the data...

Code:
Public Sub GetFilesNamesFromFolder(strFolderPath As String)
On Error GoTo ErrorHandler
Dim objFSO As Scripting.FileSystemObject
Dim objFolder As Scripting.folder
Dim objFile As Scripting.File

[Code] .....

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Code:
Private Sub Report_Open(Cancel As Integer)
Me.CheckNotPaid = False
End Sub

but it just says 'Runtime Error -214..You can't assign a value to this object'

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Sep 17, 2004

halloo everybody
Here is my code to check an excel sheet wether it is open or not.
It is working good in the following situations.

1.if the excel file is not yet opened. then it is opening and bringing a value from some cell of the sheet1.
2.If the file is already opened and not yet closed. it is not opening again it is understanding that the file is already openrd and bringing the cell value.
3.It is working when it is closed by the user and again clicked the button to open. It is opening and bringing the value.
4.NOW the problem starts.
IT IS NOT WORKING , If I click the button again to open. It is opening another copy of the same file. I did't understand why is it working perfectly? before I close the file and not working if I close the File.

please kindly check my code and respond to me .
here is my code but it is not working when the file is already opened.


Private sub Cmd_Click()

Dim XL As New Excel.Application
Dim wbk As New Excel.Workbook
Dim ws As New Excel.Worksheet


WorkBookName = "Book2.xls"
If Not WorkbookOpen(WorkBookName) Then
chk = 1
Set wbk = XL.Workbooks.Open("C:Dokumente und EinstellungenKiran KarnatiDesktopEXCELBook2.xls")
Else
Set wbk = Workbooks(WorkBookName)
End If

Set ws = wbk.Worksheets("Sheet1")
If chk = 0 Then
With ws
Label48.Caption = .Cells(1, 2).Value
.Cells(1, 3).Select
End With
Else
With ws
Text49.Value = .Cells(1, 2).Value
End With
End If
XL.Visible = True

Set SA = Nothing
Set XL = Nothing
Set wbk = Nothing
End Sub
_________________________________________________


Function WorkbookOpen(WorkBookName As String) As Boolean
'Returns TRUE if the workbook is open
WorkbookOpen = False
On Error GoTo WorkBookNotOpen
If Len(Excel.Workbooks(WorkBookName).Name) > 0 Then
WorkbookOpen = True
Exit Function
End If

WorkBookNotOpen:
End Function

Thank you.
Kiran.

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Jun 16, 2005

Dim objExcel As Excel.Application
Set objExcel = New Excel.Application
Dim strFileName As String
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If "FILE IS ALREADY OPEN" Then
MsgBox "File is currently open. Please close and re-run this program.", vbInformation, "Program Error"
GoTo end_:
Else
Set objworkbook = objExcel.Workbooks.Open(strFileName, , False)
objExcel.Columns("A:B").Insert Shift:=xlToRight
objExcel.Range("A5").FormulaR1C1 = "Account No"
objExcel.Range("B5").FormulaR1C1 = "Invoice No"
objExcel.Range("A6:A" & Range("C65536").End(xlUp).Row).FormulaR1C1 = Range("D1").Value
objExcel.Range("B6:B" & Range("C65536").End(xlUp).Row).FormulaR1C1 = Range("F1").Value
objExcel.Rows("1:4").Delete Shift:=xlUp

objExcel.Application.ActiveWorkbook.Close True
MsgBox "CSV file formatted.", vbInformation
End If

end_:
Set objExcel = Nothing
Set objworkbook = Nothing

Hi there,

I use the above code to open any CSV file, format it as required, then close/save it.

What I need to do is to find out if the file I have selected is already open and, if so, not to proceed with the code (see If "FILE NOT OPEN" line above).

I have tried several statements but am having no luck.

Thanks in advance,
Paul.

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Jul 26, 2006

Hi, sorry but i have a new issue. Ok, here it goes.

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Here is the VBA for what i have done so far.

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Dim intAnswer As Integer
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orgMisc = False
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This works fine except for 1 problem. It prompts me if i change my mind and uncheck the check box. So basically, if (default) is False Then OnClick i want the above VBA to execute. If the check box already isset to TRUE then ignore the above VBA and orgMisc (checkbox) change to FALSE.

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