Count Overdue Items?

Mar 29, 2006

I have a database for booking items in and out and would like the database to automatically count the number of items that are overdue.

I have a COMPLETED field which is a check box, when ticked completes the booking, if it is not ticked then the booking is incomplete.

I also have the "Date Returned" which is the date the customer is supposed to return the items.

So using these two fields how can I count the number of overdue items?

if COMPLETED=false and Date Returned<Date() +1

that's basically the logical expression I think would work, but I don't know the code/method to implement this into my database :x please help!

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Reports :: Report Listing Overdue Items

Feb 13, 2014

I'm trying to design a report which lists jobs that are overdue. I've got a field called [ExpectedCompletionDate] and a field called [Status]. The Status field is polulated by a combo box, which has the following options

Started
In Progress
Complete

My issue is that i'd like the report to list all the jobs which have exceeded the expected completion date and whose status is not listed as 'Complete'.I'm using the following code in the underlying query

Overdue: IIf([ExpectedCompletionDate]<Date(),IIf([Status] Is Not "Complete","Overdue"))

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Hello all,
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Dec 27, 2007

I'm building an order entry database. It has two tables (amongst others) called tblOrders and tblOrderDetails, related together on the OrderID field. For every order, there is one record in tblOrder, and as many records in tblOrderDetails as there are individual lines in the order (so, if, for example, the order is for 10 pencils and 2 pens, then tblOrderDetails has 2 records).

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Many thanks in advance for any pointers,

Gary

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Feb 19, 2005

Any idea how i can count the number of records that have the same order number of the one on the report list? For example, there are 3 records in my query that have Order# 1001, I would like it to show a "3" next to order 1001 in the report.

Any idea where and how I would make this happen (in the query or the report)?

Let me know!
Thanks!
ovadoggvo

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Code:

For Each Order In q
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Whenever I use this query to create a chart I get the default Access data not the data that's actually in that query.

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Nov 1, 2013

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Incidentally, there are other, solitary elements to the form, but this particular listbox houses a collection of items that are related under a single category.

The score is displayed at the bottom of the form, and it needs to update in real-time.

The problems that I am encountering are that I am unable to count the number of items selected and then I am unable to multiply that count by 2 (the point-value of each item on the list.)

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Jan 29, 2014

I have 2 tables linked with a 1 to many relationship by NAME. Tables look like this....

TBL-STORE

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TBL-PURCHASES

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I want a DISTINCT COUNT of [NAME] if Total[NUMBER OF ITEMS]>0, so the correct number will be 2 in the example.

This is one way I've tried to write the SQL, but I keep getting an error...

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I also tried an Count(IiF( and can't get that to work either..

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as of now, what im getting is only the filtering of Category 1 and Category 1 COUNT.

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Apr 8, 2015

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Jan 14, 2014

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Jul 31, 2013

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B=3000
C=3000
D=3000
F=3000

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Apr 13, 2006

I have a table tblBookings.

In this table it has a bookingID, CustomerID and some other none relevant details.

The CustomerID comes from table tblCustomer. i.e a customerID must exist in the customer table to be allowed in the bookings table tblBookings

A customer can exist in tblCustomer without existing in the booking table.

I am trying to write a query that will list each and every customer ID in the tblCustomer and count the number of bookings that that customer has (even if it is zero).

I have a query that will count the bookings if they exist in the booking table and display the number of times that a customer appears in the bookings table.

SELECT tblBookings.CustomerID, Count(tblBookings.CustomerID) AS NoOfBookings
FROM tblBookings
GROUP BY tblBookings.CustomerID;


How do I create a query that will do this but list all customers even if they don't exist in the bookings table (but obviously occur in the customers table)

I am trying to create a similar query where all bookings per hotel are listed even if no bookings are made for that hotel. I am guessing the answer is the same as above.

The Ritz. Bookings 0
The Hilton. Bookings 3
The Carlton. Bookings 0
The Lowry. Bookings 2

For every hotel.

That kind of thing.

If you need more information please shout.

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Aug 16, 2015

I have a table that has 5M+ accounting line entries. Below is an example of one accounting journal in the table.

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CB0014/07/20140002888269323AUD16797
CB0014/07/20140002888269323AUD-16797
CB0017/07/20140002888269323AUD16797
CB0017/07/20140002888269323AUD-16797

The journal ID above was an accounting entry, debit $16,797 and credit $-16,797. because it was entered as a reversing journal in the system, the table has captured the Journal ID with 2 dates. For my purpose i only want the one date (MIN) date, the total amount of the journal (either the debit or credit amount 16,797) and the total number of lines the journal ID has so in this instance I want the count to be 2 and not 4.

Right now this is what i get

BUSN_UNIT_I JRNL_I CNCY_C SumOfMONY_A CountOfJRNL_I MinOfJRNL_D
CB001 0002888269 AUD 0 4 4/07/2014

This is the output i would like

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CB0010002888269323 AUD16797 2 4/07/2014

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current SQL
SELECT [One Year Data Lines].JRNL_I, [One Year Data Lines].CNCY_C, Count([One Year Data Lines].JRNL_I) AS CountOfJRNL_I, Min([One Year Data Lines].JRNL_D) AS MinOfJRNL_D, [One Year Data Lines].BUSN_UNIT_I, Sum([One Year Data Lines].MONY_A) AS SumOfMONY_A
FROM [One Year Data Lines]
GROUP BY [One Year Data Lines].JRNL_I, [One Year Data Lines].CNCY_C, [One Year Data Lines].BUSN_UNIT_I
HAVING ((([One Year Data Lines].JRNL_I)="0002888269") AND (([One Year Data Lines].CNCY_C)="aud"));

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Hi,

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Private Sub Command18_Click()
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MsgBox "Booking successfully added!", vbInformation, "Booking"

If Month(Me.Date_1) = 1 Then
ListJ.AddItem Me.BoI
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End Sub

If someone could tell me the problem, I'd appreciate it. Thank you. :)

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