DateDiff Function
Jan 18, 2008
Hello,
I am trying to create a query that subtracts "TimeOUT" from "TimeIN" fields to calculate the total time worked.
The "TotalTime" is a new field that is not in the table, only in the query.
I am attempting to use the DateDiff function to calculate this, but I need to return both hours and minutes.
Currently, it looks like this:
Total Time: DateDiff("h",[Time IN],[Time OUT])
It works this way to return the total time in hours only.
The DateDiff function works to return either hours (h) or minutes (n) but I cannot figure out how to get both!
Perhaps someone has an answer or possibly a better way to get the results in hour:minute format for me??!!
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Sep 16, 2005
I'm trying to add a txtfield that the control source is 65 years prior the current date.
So the control source should come up with "1940". I've tried the datediff function, but not having any luck...any suggestions?
Thanks.
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May 9, 2007
Hello,
I would like to ask if I would like to count the number of days between two date, but EXCLUDE Fridays, Saturdays, Sundays since the workers ONLY work Monday thru Thursday. I am using the function DateDiff as follow:
DateDiff("d",[Date1],[Date2]) with Date 2 is later than Date 1.
However, the results count calendar days. HOW do I exclude Fridays thru Sundays fall within Date 1 AND Date 2?
Please help!
Thanks so much,
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Aug 29, 2005
Hey, its been a while since I've posted here, wow.
I had a database that contained samples on different date functions
(first of the month, last of the month, first weekday, etc...)
I can not find it, I have tried searching. I am pretty sure I got it from here.
Does anyone know where this is?
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Dec 11, 2005
Hi all
l'm running a query that has a field with the following formula;
[Anniv_date]=01/03/2006
[NextEBDay]=01/07/2006
[LastPayToDate]= In this case is 25/11/2005
To_Anniv_wks: IIf([Anniv_date]<[Forms]![DateEB]![NextEBDay],(DateDiff("w",[Forms]![DateEB]![LastPayToDate],[Anniv_date])),0)
The result returns 13. However l know the answer should be 14. Coz when l enter the information in excel l get 13.71.
l've tried using the round function with no luck. Any suggestions would be appreciated.
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Jan 21, 2014
Basically my database is for a library based on borrowing/returning books ect
Everything works except this one thing, in one of my forms I can ask the user to input a book number of the book they want to check if it has been returned or not, if it hasnt been returned within 30 days then it will come up with overdue.
The statement im trying to use i cant get it to work.
=IIf([DateDiff("d",[Borrow Date],Now()>30)
I want it to display overdue if the book isn't returned in 30 days of the borrow date.
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Sep 15, 2013
I am struggling with the DateDiff fuction in a calculated field. After some study, I have used several variations of:
=(DateDiff("d",[DUED],Date())/7)
to calculate the time (in weeks) until a due date starting from today's date.
It continually turns up a specific date in the late 18 and early 1900's. It does not give me the number in weeks which was what I was hoping for.
Earlier I used a very simple: =DateDiff("m",[Birthdate],Date()) to calculate the age from a date of birth perfectly with no problems.
I do not understand why the formula is not working. Does it have to do with format or the fact that I am working with a future date and how can I rectify this problem?
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Aug 14, 2014
I have a specific question on the datediff function.
My example is =DateDiff("d",[Policy Issue Date],Date()) where [Policy Issue Date] is the inception date of an Insurance Policy.
I need to determine how many days the policy has been inforce. The formula works great in a query and I can see the number of days in that field when the query is run.
However, my dilemma is I want the same function to run off of a text box using its control source property and have the number of days calculate and be visible for each record on the form. This part is not working and the field is returning the #Error? message.
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Apr 11, 2008
Hi All
I've created a database where a query who'se result is loaded on a form uses following function --
DateDiff('d',Date(),[Target Date])-(DateDiff('ww',Date(),[Target Date])*2)-(Select Count(*) from [tblHolidays] where [HolidayDate] between Date() and [Target Date])
I've notice that 2 ppl get an error message when they try to open database, with thatt function coming on an error message
Does this mean they have older access version ?
How can I tell ? Any advise on what to do ?
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Dec 28, 2007
I am finishing up a database that logs basic activities/tasks for my coworkers. As they go in to the database and log an activity in it stays open until they end their day or they start a new task. All this works fine, but the problem comes when I try to determine the total time spent (in hours) on each activity/task. I have written similar queries before and they worked just fine, but for some reason I am having trouble getting this one to work. Here is the expression I'm using...
Time Diff (in hrs): DateDiff("h",[Sample_TM_Table_1]![Time_In],[Sample_TM_Table_1]![Time_Out])
Unfortunately, say Time_In = 8:32:38 am and Time_Out = 8:33:03 am
The expression says that is equal to 946632.
For another Time_In = 8:33:00 am and Time_Out = 3:18:19 PM.
The expression says this equals 946639.
I have tried changing the format of the date/time in both Time_In and Time_Out fields to ensure they were the same and cross checked the expression but still get the same answers each time. Even when I try to use "n" for the interval or "s" it is still highly incorrect. The only thing that makes me think I still have a formatting issue is that the Time_In shows a long date on the results table while Time_Out shows it in a general date format. However, when I go into both the table and the queries to check the formatting they both show general date. Any ideas? I'm all out! Thanks in advance.
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Apr 22, 2013
I am trying to calculate the difference in dates between two fields. How do I find the difference in days between field one which contains the date 04/12/2011 and field two which contains the date 04/12/2013? I have tried to use the datediff function, but it keeps telling me it doesn't recognize the field name, even though the spellings correct.
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May 18, 2013
I am trying to calculate how many days are left till end of contract...
whats wrong with this formula
=DateDiff("d",[Completion_Date], Date())
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Jun 16, 2006
Is there a way in a query to write a datediff that looks at all the possibilities month, day, year? I have 10 different fields that I need to do a date diff on. I would like to have the fields checked in one place rather than 10 day checks then 10 month checks and 10 year checks. I don't need to use the data any where but I need it to let me know if there is a difference between a calculated date and a date that was input by a user. If there is then I know the user input the wrong date, and it shows as an error.
Thanks
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Jan 2, 2008
I have heard of this datediff thing on access. How do you make it work? I also want to do a calculate between the date of birth and date of death? Bearing in mind they are all different. I am wanting if possible to list the age at death either as for example 70years and 85 days or 70.233 years
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May 14, 2007
Hi,
I am trying to calculate the number of days between 'today' and a 'date of birth' field. In the field properties Default Value I am using =(DateDiff('y',Date(),[dob]) where Date() gives today's date and [dob] is my 'date of birth' field. However, this is not working. I get an error "(The database engine does not recognize either the field 'dob' in a validation expression, or the default value in the table 'Table1')"
I have set the data type for both fields to 'Date/Time'. What am I doing wrong? Is there any alternate method?
Also, how can I calculate height in feet & inches (5'6" or 5.6 or 5-6) from a given height in meters?
Thanks
Raj
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Dec 2, 2005
I need to caculate the difference in days between to dates. I would like to include only Business days but would settle for any help at this point
Thanks in advance
-WM
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Jul 16, 2007
Hi there.
I'm using the following code in my Access aplication:
DateDiff("h", IncStart, txtrts)
My problem is i need the exactly time difference and if the difference is 2hours and 15 mins it will display only 2 hours. Is there any way to do that? I've tryed in min but it display 135 mins.
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Oct 3, 2007
hello all,
would really appreciate some extra help with this,
many thanks,, the story is as follows,,,,,,,
hello all,
i have a very simple databse with two table in it,, both table share a lot of common information, including a primary key called jobcard number,, i want to know if there is a simple query i can run that will find any differences in the start date fields that are found in both tables
any help would be much appreciated
cheers
wardy
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Look at DateDiff function in the help for the time differences.
Thus for example in a new column in your query you can type:
DifferenceInDays: DateDiff("d",[Table 1 Name].[DateField Name], [Table 2 Name].[DateField Name])
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thank you DrSnuggles,
could you explain in idiot proof instructions?
do i enter the diffdate code in the criteria row of the select query? also, what do i need in the field and table rows? is it the table and filed i'm comparing the data against?
once again
many thanks
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Apr 9, 2008
I have a call tracker database.
What I'm trying to create a query to view all my calls' time average (opened date and resolved date). Basically, how long it took to fix a call or problem... whatever...
I tried with datediff(), but had problems getting the Total Avg.
I would need the query to look like this...
Total Calls | Avg Call Time
100 | 5.33 (min.sec)
Thank you
Lucas
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Sep 20, 2004
I have a form that has a start time end time and total time. I am using date diff to calculate the total time and it is working fine, but i want the output to be placed into Total time field of a table. I am new to access and DB in general. Any help would be appriciated.
Greg
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Aug 30, 2005
I am trying to calculate the total number of days between a date (i.e, csdate) and todays date in a Query for a Report.
I have tried the DateDiff command in the query line and in an unbound box on the report but it is not returning the right values.
Can Someone tell me what I have done wrong. I have checked that the date is in long format and tried it in short format as well with the same results. Below is what I have tried.
csdays:=DateDiff("d", [csdate], Date()) I have tried the Now() command as well, but it is not right either.
Please help!
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Mar 21, 2006
My company recently switch us from Access 2000 to Access 2003. A query that previously worked, no longer works. I've searched the previous posts and Access help and updated the query based on the search results, but still receive the error message. "Undefined function 'Date' in expression."
Here's the query calculation:
AppOut: DateDiff("d",[AppMailed],Date())
Would someone please let me know where I am going wrong?
I've gotten it to work with this calcualtion, but the user has to manually enter today's date each time. But I know there has got to be an easier route.
AppOut: DateDiff("d",[AppMailed],[date])
Thanks =)
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May 12, 2006
I am using Expr1: DateDiff("d";Date();[Expiry Date])
I am having a problem , the date diff uses the date in this format " mm,dd,yyyy"
but in my program I enter the date dd,mm,yyyy, is there is way to change it, I know that in sql you can do it, ms access is abit different, any solutions to that.
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Jul 26, 2006
Have a table which has 4 fields PatientID FirstName,LastName,BalanceDue,Due Date
Trying to create a query that will show all fields of the accounts that have due dates that are under 30 days. I tried this Under30: DateDiff("d",[DueDate].Now())criteria >0 And <30. But can't put anything in the parameter dialog box which after clicking ok shows any data. If I can get this to work my hope is to have 3 more catagories. over 30 days, over 60 days and over 90 days. I'm new at access and could really use some help.
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Mar 28, 2007
Morning
Pretty new to all this, so forgive my ignorance but i'm having problems with DateDiff. I have a table with 2 dates in it, and I want to work out how many working days (or working hours if possible) are between the 2 dates
SELECT DateDiff("d",[Date Opened]+[Date Closed])
FROM Dashboard;
I want it to print it the number of working days/ hours in a new column in the Dashboard table if possible.
Any ideas?
Thanks
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Jan 24, 2008
Hello,
I create query that subtract “schedule date” (mm/dd/yyyy) and “deliver date” (mm/dd/yyyy) to calculate difference deliveries days. I used function DateDiff different ways but query doesn’t work.
Expr1: DateDiff("mm/dd/yyyy","SCHEDULE DATE","DELIVERY DATE »")
And I have error: “data type mismatch in criteria expression” or doesn't work.
Thanks for helping.
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