DateDiff Function - Calculate How Many Days Left Till End Of Contract
May 18, 2013I am trying to calculate how many days are left till end of contract...
whats wrong with this formula
=DateDiff("d",[Completion_Date], Date())
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Getting DateDiff To Calculate Half Days
Jun 8, 2006I have an access database used for recording training events. I was able to calculate the number of days each training event took by using
Datediff("d",[Training Date From],[Training Date To]+1)
I was really chuffed with this until my boss asked what happens when the training only lasts half a day! I added the time to the above fields to make them date/time fields but can't see a way to calculate in half days.
As well as this the other problem is that training could be over a few days. As an example I'd like to be able to input that the training started at 9am on Monday 29th May and ended at 12 noon on Thursday 1st June and get the result of 3.5 days. The full days would all end at 5pm but I wouldn't be recording that, just the total days. I tried changing the datediff function to hours in the hope I could somehow discount the non working hours but that didn't work! I'd ideally like the final result to be in days, ie 0.5, 1 etc. It would always be in whole or half day increments - don't need things to be overly complicated!
Any help will be very gratefully received. I'm definitely not an expert as you can probably tell!! :eek:
Queries :: DateDiff Function - Calculate Difference In Dates Between Two Fields
Apr 22, 2013I am trying to calculate the difference in dates between two fields. How do I find the difference in days between field one which contains the date 04/12/2011 and field two which contains the date 04/12/2013? I have tried to use the datediff function, but it keeps telling me it doesn't recognize the field name, even though the spellings correct.
View 3 Replies View RelatedQueries :: Function To Calculate Date Diff In Network Days
Aug 7, 2014I'm using the following function to calculate date diff in network days (excluding weekends)
Public Function NetWorkdays(dteStart As Date, dteEnd As Date) As Integer
Dim intGrossDays As Integer
Dim dteCurrDate As Date
Dim i As Integer
intGrossDays = DateDiff("d", dteStart, dteEnd)
NetWorkdays = 0
[Code] ....
So when using this function in a query to get number of networkdays between 2 date columns ...it works fine but throws a #Error where there is blank entries in either of 2 date columns...
I need to find a way to display Null instead of #Error...
I have tried this expression but no luck...
IIf(IsError(NetWorkdays([Date1],[Date2])),"",NetWorkdays([Date1],[Date2]))
Calculate Days In Advance Or Days In Arrears
Dec 26, 2006I rent out a property , on the rental statement I have a field [Datepaid], [RentpaidFrom] and [rentpaidTo]. I would to have a field that can calculate the rent that is paid to show if the rent is in arrears or in Advance. I guess the code would be something like (datediff ???? etc) but i have no idea what it should be. the calculation should appear on the query as i.e.2 days in arrears or 12 days in advance etc
your help would be much appreciated
merry christmas to you all
Jabez
DateDiff Count Only Business Days?
Oct 15, 2004Hi, I'm trying to get some date tracking stats...
trying to get the average number of days between two dates using formula:
=Avg(DateDiff("d",[DateRec],[DateNumb]))
where datenumb was the first date app was entered into db and
where daterec is the date the first part of app was recorded.
this works but I'm assuming it's counting straight calendar days. I was wondering is there a way to get it to count only business days and not weekends or holidays in access???
Calculate Working Days Between 2 Days
Mar 14, 2006Dear All,
I'm new to VBA coding. A code below is copied from a friend of mine and I can't make it work. How to call up this function in my form. In my form I have 3 text boxes (StartDate, EndDate and NumOfWorkDays). My form is based on a table.
Please anyone who would help me on this, kindly give me the step by step procedure as I am really novice. Thanks in advance.
'*********** Code Start **************
Public Function WorkingDays(StartDate As Date, EndDate As Date) As Integer
On Error GoTo Err_WorkingDays
Dim intCount As Integer
StartDate = StartDate + 1
'If you want to count the day of StartDate as the 1st day
'Comment out the line above
intCount = 0
Do While StartDate <= EndDate
'Make the above < and not <= to not count the EndDate
Select Case WeekDay(StartDate)
Case Is = 1, 7
intCount = intCount
Case Is = 2, 3, 4, 5, 6
intCount = intCount + 1
End Select
StartDate = StartDate + 1
Loop
WorkingDays = intCount
Exit_WorkingDays:
Exit Function
Err_WorkingDays:
Select Case Err
Case Else
MsgBox Err.Description
Resume Exit_WorkingDays
End Select
End Function
'xxxxxxxxxxxxxxxxxxxxxxxx
Can someone please direct me to the right path.
Your help is highly appreciated.
qwerty70
DateDiff In A Query - Calculate Time Difference Between Two Columns
Jan 22, 2012DateDiff in a query
I am trying to calculate time difference between two time columns as follows in a query which has a few inner joins
Diff: DateDiff("h",[Table1.TimeStrat],[Table1.TimeStrat])
This gives problem, it is asking [Table1.TimeStrat] to be entered, where is the problem?
Taking One Date From Another To Give Number Of Days Left
Dec 11, 2006HI, this should be relatively simple, but for some reason I cannot figure it out.
I have a field titled "DEADLINE" - a user inputs a date in this field (the datatype for this filed id date/time)
What I want to do is, on the form create a text box which takes the deadline date - todays date to give me the number of days to the deadline date. Once the dealine date has passed I then want to turn the counter to Red to show it is overdue. If there is no dealine then I want the field to say something like "No Deadline Set"
DateDiff Function
Jan 18, 2008Hello,
I am trying to create a query that subtracts "TimeOUT" from "TimeIN" fields to calculate the total time worked.
The "TotalTime" is a new field that is not in the table, only in the query.
I am attempting to use the DateDiff function to calculate this, but I need to return both hours and minutes.
Currently, it looks like this:
Total Time: DateDiff("h",[Time IN],[Time OUT])
It works this way to return the total time in hours only.
The DateDiff function works to return either hours (h) or minutes (n) but I cannot figure out how to get both!
Perhaps someone has an answer or possibly a better way to get the results in hour:minute format for me??!!
DateDiff Function?
Sep 16, 2005I'm trying to add a txtfield that the control source is 65 years prior the current date.
So the control source should come up with "1940". I've tried the datediff function, but not having any luck...any suggestions?
Thanks.
DateDiff Function?
May 9, 2007Hello,
I would like to ask if I would like to count the number of days between two date, but EXCLUDE Fridays, Saturdays, Sundays since the workers ONLY work Monday thru Thursday. I am using the function DateDiff as follow:
DateDiff("d",[Date1],[Date2]) with Date 2 is later than Date 1.
However, the results count calendar days. HOW do I exclude Fridays thru Sundays fall within Date 1 AND Date 2?
Please help!
Thanks so much,
DateDiff Function Sample Database
Aug 29, 2005Hey, its been a while since I've posted here, wow.
I had a database that contained samples on different date functions
(first of the month, last of the month, first weekday, etc...)
I can not find it, I have tried searching. I am pretty sure I got it from here.
Does anyone know where this is?
Problem With Rounding With DateDiff Function
Dec 11, 2005Hi all
l'm running a query that has a field with the following formula;
[Anniv_date]=01/03/2006
[NextEBDay]=01/07/2006
[LastPayToDate]= In this case is 25/11/2005
To_Anniv_wks: IIf([Anniv_date]<[Forms]![DateEB]![NextEBDay],(DateDiff("w",[Forms]![DateEB]![LastPayToDate],[Anniv_date])),0)
The result returns 13. However l know the answer should be 14. Coz when l enter the information in excel l get 13.71.
l've tried using the round function with no luck. Any suggestions would be appreciated.
Forms :: Datediff And IIF Function In Form
Jan 21, 2014Basically my database is for a library based on borrowing/returning books ect
Everything works except this one thing, in one of my forms I can ask the user to input a book number of the book they want to check if it has been returned or not, if it hasnt been returned within 30 days then it will come up with overdue.
The statement im trying to use i cant get it to work.
=IIf([DateDiff("d",[Borrow Date],Now()>30)
I want it to display overdue if the book isn't returned in 30 days of the borrow date.
Forms :: DateDiff Function In A Calculated Field
Sep 15, 2013I am struggling with the DateDiff fuction in a calculated field. After some study, I have used several variations of:
=(DateDiff("d",[DUED],Date())/7)
to calculate the time (in weeks) until a due date starting from today's date.
It continually turns up a specific date in the late 18 and early 1900's. It does not give me the number in weeks which was what I was hoping for.
Earlier I used a very simple: =DateDiff("m",[Birthdate],Date()) to calculate the age from a date of birth perfectly with no problems.
I do not understand why the formula is not working. Does it have to do with format or the fact that I am working with a future date and how can I rectify this problem?
Forms :: DateDiff Function Not Working In A Form
Aug 14, 2014I have a specific question on the datediff function.
My example is =DateDiff("d",[Policy Issue Date],Date()) where [Policy Issue Date] is the inception date of an Insurance Policy.
I need to determine how many days the policy has been inforce. The formula works great in a query and I can see the number of days in that field when the query is run.
However, my dilemma is I want the same function to run off of a text box using its control source property and have the number of days calculate and be visible for each record on the form. This part is not working and the field is returning the #Error? message.
Calculate Number Of Days
May 4, 2006In a database, I have the following date fields that I use to track projects that start and stop.
START1
STOP1
START2
STOP2
START3
STOP3
Is there a way I can use a query to calculate the total days the project was worked on? For example if I enter 1/1/06 in START1, 1/10/06 in STOP1, 2/1/06 in START2 and 2/15/06 in STOP2, 3/1/06 in START3 and 3/30/06 in STOP3, I need to calculate the total days. I need it to work regardless if there are 3 start/stops, 2 or just one start/stop.
I really appreciate the help.
Jim
Calculate Days When There Are 4 Variables
Jul 7, 2006I have a query that has four date variables:
Admit Date
Discharge Date
Report Begin Date
Report End Date
I can calculate the number of days with the DateDiff function when the "Admit Date" and "Dischage Date" are within the range of the report with no problem.
The problem arises when the "Admit Date" is prior to the "Report Begin Date". In this case, the difference needs to be "Report Begin Date" and "Discharge Date".
To make this more complicated, in some cases there is no "Discharge Date", so the calculation needs to look at the first two senerio's and then calculate the days based on the "Report End Date".
Expr2: IIf([Admission Date]<[Beginning of Report],DateDiff("d",[Beginning of Report],[D/C Date / Time]),DateDiff("d",[Admission Date],[D/C Date / Time]))
Expr2: IIf([Admission Date]<[Beginning of Report] And [D/C Date / Time]>[End of Report],DateDiff("d",[Beginning of Report],[D/C Date / Time]),DateDiff("d",[Admission Date],[D/C Date / Time]))
Expr3: IIf(IsNull([D/C Date / Time]) And [Admission Date]<[Beginning of Report],DateDiff("d",[Beginning of Report],[End of Report]),DateDiff("d",[Admission Date],[End of Report]))
expr4: IIf([Admission Date]>[Beginning of Report],DateDiff("d",[Admission Date],[D/C Date / Time],0))
Above are failed attempts to get the formula right.
Can anyone assist me in getting this to work correctly.
Thanks
Dan:mad:
Calculate Working Days
May 11, 2007I hope you can help. I have a database and I am trying to work out the working days between the start date and the end date of a programme. This will not take into account any weekends or bank holidays. I have created a separate table called tblHolidays which has a list of the Bank Holidays. The majority of it works but out of 1700 records 50 don’t. These are ones in which it starts on 1 month finished on another or has a bank holiday. It works with certain bank holidays but not all of them. Bank holidays go back to the beginning of 2006
The following is the code I have used:
Public Function WorkingDays2(Start_Date As Date, End_Date As Date) As Integer
On Error GoTo Err_WorkingDays2
Dim intCount As Integer
Dim rst As DAO.Recordset
Dim DB As DAO.Database
Set DB = CurrentDb
Set rst = DB.OpenRecordset("SELECT [HolidayDate] FROM tblHolidays", dbOpenSnapshot)
Start_Date = Start_Date + 1
intCount = 0
Do While Start_Date <= End_Date
rst.FindFirst "[HolidayDate] = #" & Start_Date & "#"
If Weekday(Start_Date) <> vbSunday And Weekday(Start_Date) <> vbSaturday Then
If rst.NoMatch Then intCount = intCount + 1
End If
Start_Date = Start_Date + 1
Loop
WorkingDays2 = intCount
Exit_WorkingDays2:
Exit Function
Err_WorkingDays2:
Select Case Err
Case Else
MsgBox Err.Description
Resume Exit_WorkingDays2
End Select
End Function
I then used the SQL
Select WorkingDays2 ([start_Date], [End_Date]) As CountDays
This is driving me crazy!!:mad:
Calculate Only Business Days
Feb 10, 2005I have a date range of 1/01/2005 to 12/25/2005 for example. I need a formula to return the number of days between these dates excluding weekends. Basically I need to know how many business days are between these dates. Thanks for the help.
View 1 Replies View RelatedDateDiff Function - It Doesn't Work In Some Version Of Acces ?
Apr 11, 2008Hi All
I've created a database where a query who'se result is loaded on a form uses following function --
DateDiff('d',Date(),[Target Date])-(DateDiff('ww',Date(),[Target Date])*2)-(Select Count(*) from [tblHolidays] where [HolidayDate] between Date() and [Target Date])
I've notice that 2 ppl get an error message when they try to open database, with thatt function coming on an error message
Does this mean they have older access version ?
How can I tell ? Any advise on what to do ?
DateDiff Function Giving Results With Numbers Way Too Large
Dec 28, 2007I am finishing up a database that logs basic activities/tasks for my coworkers. As they go in to the database and log an activity in it stays open until they end their day or they start a new task. All this works fine, but the problem comes when I try to determine the total time spent (in hours) on each activity/task. I have written similar queries before and they worked just fine, but for some reason I am having trouble getting this one to work. Here is the expression I'm using...
Time Diff (in hrs): DateDiff("h",[Sample_TM_Table_1]![Time_In],[Sample_TM_Table_1]![Time_Out])
Unfortunately, say Time_In = 8:32:38 am and Time_Out = 8:33:03 am
The expression says that is equal to 946632.
For another Time_In = 8:33:00 am and Time_Out = 3:18:19 PM.
The expression says this equals 946639.
I have tried changing the format of the date/time in both Time_In and Time_Out fields to ensure they were the same and cross checked the expression but still get the same answers each time. Even when I try to use "n" for the interval or "s" it is still highly incorrect. The only thing that makes me think I still have a formatting issue is that the Time_In shows a long date on the results table while Time_Out shows it in a general date format. However, when I go into both the table and the queries to check the formatting they both show general date. Any ideas? I'm all out! Thanks in advance.
Calculate Days Between Billing Dates
Oct 6, 2005I am woking on a project full of nightmares. My latest, and the one I am currently unable to solve, involves trying to calculate the number of days between Billing Dates.
I have a table named "Date" - I didn't design this!
It contains a field named "Date"
If I query for just that Field I get the following:
Date
9/8/2005
8/8/2005
7/8/2005
6/8/2005
5/9/2005
...
I need to figure out a way to determine the number of days between the bills so I can calculate the average cost per day.
It seems like it should be an easy thing using like the datediff function or something, but since they are in separate records (rows), I can't figure it out. I have tried and tried and tried.
Any suggestions would be VERY much appreciated.
Calculate Days Between Dates & Other Criteria
Dec 9, 2007I have a database with 10-12 fields containing dates certain things were completed. There is also a field for the 3 different locations we have and a program year 2006, 2007, or 2008. What they would like to do is click a button and get a list to choose the first date they which to compare, then a list to choose the second date, calculate the number of days between the two dates, select the program year from a list, and a location from a list. Can anyone help me with how to do this if it's possible?
The fields look something like this:
Prog Year Location DateA Date B DateC DateE
2006 G date date date date
2006 G date date date date
2006 P date date date date
2008 D date date date date
2007 P date date date date
For Example, I might want 2006 Program Year, Location P, calculating days between DateA and DateB, except that the next time I might want to choose a different set of criteria.
Any ideas?
THANK YOU!
General :: Calculate Days Using 2 Arguments
Dec 18, 2012I have a database to monitor incoming emails from our contractor & my superior wants it to have control like the following situations:
1. If no respond yet, to calculate today's date minus received date
2. If responded, to calculate respond date minus received date
If i use the following expression, it does not relate to if the emails have no respond yet or have been responded.
IIf(IsNull([Reply Date]),DateDiff("d",[Due Date], Now()))