Hi there
I have the following field in my access project.
Sno
Name
PortNo
Location
Speed
Package
In the above field i had set Sno is PRIMARY KEY. The problem is after entering all field, then only it will show the duplicate Sno error. What I want is, if Sno is duplicate, when i type SNo , successively i have to get the SNo is duplicate.
Help me to solve this issue
thanx in advance
by
yasi
hi,
the below scrip was taken from another forum member.
i have put this in the Forms / error VBA
but i still a little lost
i have set 3 fields to be indexed not to allow duplicate information (Forename, Surename, DOB)
i was then advised to error trap so it would highlight that i have enterd a duplicate record on typing in the DOB (As that as third feild to be entered)
so i then used the below script, however this doesnt highlight that it is a duplicate it just doesnt let me go on to the next record, the only time the error message is highlighted is when i go into design mode.
anyideas on where to go from here.
Private Sub Form_Error(DataErr As Integer, Response As Integer)
If DataErr = 3022 Then
Response = acDataErrContinue
MsgBox "Tis MerID alredy exist!"
Exit Sub
End If
If DataErr = 2169 Then
Response = acDataErrContinue
MsgBox "Tis record will not be saved!"
Exit Sub
End If
End Sub
I'm trying to make a simple DB that we can enter our time for working on projects.
So far I have a Form with the employees name and the date in it. Then below that is a subform with the project number, name, client name, and hours.
I want to use this whole "sheet" for one days worth of work for 1 employee. New sheets will be used for each day.
When I try to make a new sheet I get an error that it cant change the table because it would be creating a duplicate entry.
How do I solve this?
Also, should it be difficult to be doing what I'm trying to do?
hi everyone,
i have a form that i'm trying to create a button to duplicate the record. i'm using the control wizard which produces the following code:
Private Sub DuplicateRecord_Click()
On Error GoTo Err_DuplicateRecord_Click
DoCmd.DoMenuItem acFormBar, acEditMenu, 8, , acMenuVer70
DoCmd.DoMenuItem acFormBar, acEditMenu, 2, , acMenuVer70
DoCmd.DoMenuItem acFormBar, acEditMenu, 5, , acMenuVer70
Exit_DuplicateRecord_Click:
Exit Sub
Err_DuplicateRecord_Click:
MsgBox Err.Description
Resume Exit_DuplicateRecord_Click
End Sub
When i try to execute the code via a comand button, i get an error and the duplicate record operation does not occur. one thing i noticed is that i have a lot of lookup fields (i.e. FK's to lookup tables one-to-many relationships) in underlying table being populated by the form. i've created combo boxes on the form to populate the FK's in the underlying table. the error that occurs when trying to use the above code produces a "paste errors" table and in that paste errors table instead of the bound column values from the combo boxes (i.e. PK values from the lookup tables) it shows the display values from the combo boxes. i'm not sure if this has do with anything, but i couldn't figure out why it was doing this.
does anyone have any ideas how i could get this duplicate record procedure to work?
many thanks for any help or suggestions.
Hi,
I have a rather large database that was built in Access '97 and recently converted to 2003. I have a couple problems now. I get an error message about not being able to update the form because it would create a duplicate value in the primary key, index, or relationship. (Error 3022) I didn't build this particular database so I'm not totally sure why somethings are done the way they are. I've spent a long time going through everything to try to understand the relationships and I've asked lots of people at work to look at it, but no one seems to understand why it's doing what it's doing. The Access Help information has helped me understand some things better, but not this problem. I've gone through every table and removed all primary keys and set all indexes to allow duplicates. Then, when I was looking at the relationships and object dependancies, I think everything looks to be in order. However, when i add info directly to the table instead of using the form, the form is not updated with the new info. the table keeps the information, but isn't communicating with the form and i suspect reverse is true which is where the error is coming from. But how do I detect that for sure and how can I fix it with out starting over? I've gone through and added data to one field in the form at a time to try and narrow down what field is causing the problem, but no matter what i get the same error. Is there a way to find out exactly what field is causing the error? Thanks for any help you can offer!
Alicia
Just when I thought I had my problem licked...
I created a subforum with an updateable query, and this works. I can view the results of the query, modify them and add new records.
However I shortly realized that once I deleted a record (either by some VBA code, or by SQL) that I could not re-add the same record through the subform.
I've made sure that the record is deleted, so there is no duplication of the key.
I've made sure that Index is Duplicates OK, so there is no duplication issues there.
What am I missing?
I have a table with one primary key (ClientID) which is an autonumber (cannot be duplicated), and another field which is a number field which is set to a random 6 digits (also cannot be duplicated) whenever a new client record is created.
Now, the main database is on a desktop, and my partner and i are connected to this main database through our laptops whenever we're in the office. For the last 6 months, I had only the ClientID in the form (from the Client Table), and everything would work fine whenever we created a new record in the Form, even if we created a new record at the same time on our personal laptops, the numbers would automatically be increased by one w/ no error.
I just added the other field now, the regular 6 digit random number field, and sometimes (only sometimes) when we both have a different client and start a new record, we get error messages that says we're creating duplicates. When that error message comes up, one of us has to close down the form completely, and reopen and start a new record again. Not sure why this is happening. Here is the error message.
http://members.shaw.ca/hgkma/errormessage.jpg
Any help appreciated.!!
I have a form - see attached image.
The first text box is called Job_No. When a number is entered here how can I check that the number doesn't already exist when the user tabs to the next box. Then if it does exist display a custom message to the effect "This already exists" and not the Access default duplicate error message.
Thanks
Michael
Hi!
I have a form which is based on student records. What I'm trying to get Access to do is to bring up an error message as soon a duplicate student number has been entered. At present I've managed to replace the Access standard error message 3022 with my own by using the following code:
Private Sub Form_Error(DataErr As Integer, Response As Integer)
Const conDuplicateKey = 3022
Dim strMsg As String
If DataErr = conDuplicateKey Then
Response = acDataErrContinue
strMsg = "Duplicated record. Please recheck your data."
MsgBox strMsg
End If
End Sub
However the error message only appears when you try to leave the form (e.g. start a new record). I would like the error message to appear as soon as the user leaves the Student Number text box on the form. Is there anyway to do this?
I have a table with about 3600 keys, numbered from 1 to 3600. When I try to enter a new record, the autonumber starts in the 20's. I get an error message about duplicate keys, and I have to cancel. If I try again the autonumber goes up by one, but it will take hours to do this with approximately 3600 tries to get past the highest exisiting key number. Is there a way to make Access reset this? THis table is linked to a many-to-many table and I can't start over or I will lose all my relationships.
View 4 Replies View RelatedI am having an issue with one person having trouble getting an error when trying to duplicate a record.
The subform is set up with a button to duplicate a record. This allows most of the data that stays the same to be copied to a new records and then minor changes can be made to update the record for the new month. Since there are memo fields, in these records, this saves a lot of retyping. One person who is using the database gets the following error when clicking on the duplicate record button.
The command or action 'Copy' isn't available now.
It makes a new blank record but won't copy over the information. You can go to the record and copy each field individually and paste it into the new record, but this is not very practical.
I have not been able to duplicate the error and no one else using the database is having this happen.
How to create custom error message for duplicate data? I want this custom message at text box before_update event not at form_error .....
View 1 Replies View RelatedSo now, I'm using the code below to prevent duplicate name entry and it is working great - EXCEPT when I enter a first or last name which contains a ' (ie, O'Tool, O'Malley, O'Hern)...anyone got any ideas for me on how to make this not happen?
The error I get is:
Run Time error '3075'
Syntax error (missing operator) in query expression '[Last Name]='O'Hern' And [First Name]='Lori'.
The code i'm using is:
Private Sub Last_Name_AfterUpdate()
'Check for duplicate first and last name using DCount
If DCount("*", "[Constituents]", "[Last Name]= '" & Me![Last Name] & "' And [First Name] = '" & Me![First Name] & "'") > 0 Then
Beep
MsgBox "This first and last name already exists in the database. Please check that you are not entering a duplicate constituent before continuing.", vbOKOnly, "Duplicate Value"
Cancel = True
End If
CustID_Exit:
Exit Sub
CustID_Err:
MsgBox Error$
Resume CustID_Exit
End Sub
Having a problem when saving a record that has been edited and contains a duplicate field. Here is what I'm doing.
I have an existing record that is being viewed by the user. I have an edit button on the form that is displaying the record. When the user clicks the edit button I do the following
'User clicked on edit customer record
Private Sub CustEditRec_Click()
'Store current customer key in string so we can cross
'check if user has changed the key during edit
EditCustKey = Me.txtCustomerKey
DoCmd.DoMenuItem acFormBar, acRecordsMenu, acSaveRecord, , acMenuVer70
'Set customer record test string so we can determine
'what the user is doing
CustomerRecStat = "edit"
' Go unlock the customer data fields for editing
UnlockCustomerFields
TxtCompanyName.SetFocus
'Go Unlock the customer editing buttons
UnLockCustomerAddButtons
'Lock the add, delete, edit buttons
CustAddRec.Enabled = False
CustEditRec.Enabled = False
CustDelRec.Enabled = False
'Go Disable the customer navagation buttons
DisableCustomerNavigation
txtCustomerKey.Visible = True
txtCustomerKey.Locked = False
txtCustomerKey.Enabled = True
'Set focus on the customer key
txtCustomerKey.SetFocus
'disable & hide the customer key combobox
cmboCustomerKey.Locked = True
cmboCustomerKey.Enabled = False
cmboCustomerKey.Visible = False
Exit_CustEditRec_Click:
Exit Sub
Err_CustEditRec_Click:
MsgBox Err.Description
Resume Exit_CustEditRec_Click
End Sub
The field which duplicate entries are not allowed in the table is txtCustomerKey. Now remember we are just editing a record NOT ADDING A NEW ONE.
When the user finished making the changes to the record we use the same procedure to save the changes as we when the user is adding a new record...here it is.
'User clicked save customer record
Private Sub CustSaveRec_Click()
On Error GoTo Err_CustSaveRec_Click
SaveCustomerRecord:
'Update the table data fields with the data contained on the form
CustomerKey = Me.txtCustomerKey
CustomerCompany = Me.TxtCompanyName
CustomerFirst = Me.txtCustomerFirst
CustomerLast = Me.txtCustomerLast
CustomerAddress = Me.txtCustomerAddress
CustomerCity = Me.txtCustomerCity
CustomerProvince = Me.txtCustomerProvince
CustomerPostal = Me.txtCustomerPostal
CustomerCountry = Me.txtCustomerCountry
CustomerPhone = Me.txtCustomerPhone
CustomerFax = Me.txtCustomerFax
CustomerEmail = Me.txtCustomerEmail
CustomerWeb = Me.txtCustomerWeb
CustomerNotes = Me.txtCustomerNotes
'Save the record
DoCmd.DoMenuItem acFormBar, acRecordsMenu, acSaveRecord, , acMenuVer70
'*** IF WE GOT THIS FAR WITH OUT ERRORS WE SAVED THE RECORD
'*** GO AHEAD & DISABLE THE FORMS VARIOUS FIELDS
'*** & BUTTONS ONCE AGAIN AS WE ARE JUST BACK TO VIEWING
'*** THE CUSTOMERS DATABASE
'Enable and unlock the customer key field
txtCustomerKey.Visible = True
txtCustomerKey.Locked = False
txtCustomerKey.Enabled = True
'Hide & disable the customer keycombo box
cmboCustomerKey.Locked = True
cmboCustomerKey.Enabled = False
cmboCustomerKey.Visible = False
'Set focus on the customer key field
txtCustomerKey.SetFocus
'Lock the customer fields
LockCustomerFields
'Enable the navigation buttons
EnableCustomerNavigation
'Lock the customer adding buttons
LockCustomerAddButtons
'Clear the record testing status
CustomerRecStat = ""
txtCustomerKey_AfterUpdate
Exit_CustSaveRec_Click:
Exit Sub
Err_CustSaveRec_Click:
'If the error generated was by a duplicate value.
'This can only be caused by the customer key as this
'is the only field which does not allow duplicate values.
'so warn the user of this duplicate value error and set
'the focus on the customer key field
If Err.Number = 3022 Then
'if user is editing a record
If CustomerRecStat = "edit" Then
'And the entered customer key has not changed
If Me.txtCustomerKey = EditCustKey Then
'Return to saving the record as the key is
'not really a duplicate
GoTo SaveCustomerRecord
End If
End If
Select Case MsgBox("This Customer ID was already located in the database. Click OK to enter a new Customer ID or Cancel to stop adding this record?", vbExclamation + vbOKCancel + vbDefaultButton1, "Duplicate Customer ID")
Case vbOK
Me.txtCustomerKey.SetFocus
Resume Exit_CustSaveRec_Click
Case vbCancel
'Go simulate undo record click
CustUndoRec_Click
Resume Exit_CustSaveRec_Click
End Select
End If
MsgBox Err.Description
Resume Exit_CustSaveRec_Click
End Sub
The problem is when the user is editing a record. The database assumes the txtCustomerKey is a duplicate in the table. However we are not adding a new record so the duplicate error is false. Its just that the txtCustomerKey is the same as the record being edited. Its not DUPLICATED its the SAME.....
Any help anyone? Sorry for the long post but I'm a strong believer in the more information the better when trying to solve a problem....
Thx
Kao
How to control the below message to something like this through VBA:
"The Job: " & JobNumber & " already exists in the table." or to open an alternate form where they can make the change. Allowing duplicates is not appropriate for what I am trying to accomplish. I just want a friendly way of rerouting a user to understandable answer.
instead of this:
"The changes you requested to the table were not successful because they would create duplicate values in the index, primary key, or relationship. Change the data in the field or fields that contain duplicate data, remove the index, or redefine the index to permit duplicate entries and try again."
I need to be able to produce an error on a form where the user attempts to create a new user that already exists. The error needs to be produced when the save button is clicked.
See below for the existing code on my save button which exists in form, 'frmAddEditUser':
Private Sub cmdSave_Click()
If IsNull(cboManagerID) = True Then
MsgBox "Please select a manager", vbExclamation, "Details Missing!"
Me.cboManagerID.Requery
[Code] ....
Currently, if I attempt to create a user with the same Payroll ID as an existing user, my 'User details saved' message box is displayed and to the user it looks like a new record has saved successfully which isn't the case.
I need a message box to appear displaying something like "Payroll ID n already exists" where n is the 'PayrollID' of the duplicate record. (Is it possible to combine a value from a certain control and ones own custom text?)
Note: PayrollID is a combination of letters and numbers, i.e. two letters, followed by 5 numbers, e.g. JD12345.
For reference, the table/field and and control are called, '[tblUser].[PayrollID]' and 'txtPayrollID' (on 'frmAddEditUser') respectively; it is from this field and control that I want the error to be produced if the user is entering the same values which are existing in 'tblUser'.
error message I am getting when I click on my Duplicate Record button (created through the wizard).
I have two combo boxes on the main form that populates data when the user makes a selection from the combo box. First combo box populates project data and the second combo box populates equipment data. The form is working well with the two combo boxes populating the data into the main table.
Now I would like to add a duplicate record button to copy a record and paste the data as a new record. So, I added a duplicate record button using the wizard and I am receiving the following AfterUpdate error.
Run-time error 3020: Update or CancelUpdate without AddNew or Edit.
This is the code I am using to copy and paste a duplicate record:
Private Sub InputForm_DupRec_Button_Click()
On Error GoTo Err_InputForm_DupRec_Click
DoCmd.RunCommand acCmdSelectRecord
DoCmd.RunCommand acCmdSaveRecord
DoCmd.RunCommand acCmdCopy
DoCmd.RunCommand acCmdPasteAppend
Exit_InputForm_DupRec_Click:
Exit Sub
Err_InputForm_DupRec_Click:
MsgBox Err.Description
Resume Exit_InputForm_DupRec_Click
It seems to be duplicating the data from the first combo box, but not the second one where it errors out.
I was using the following code on a field (ItemCode) that was indexed to prevent duplication of records. The intent is that the user will get an error message that a duplicate exists before they enter all the data for the record and get the built in error message that Access 2003 provides when an index violation has occurred.
Code:
Private Sub ItemCode_BeforeUpdate(Cancel As Integer)
Dim Answer As Variant
Answer = DLookup("[ItemCode]", "tblQuestions", "[ItemCode] = '" & Me.ItemCode & "'")
If Not IsNull(Answer) Then
MsgBox "Item Code already exists" & vbCrLf & "Please enter unique Item Code.", vbCritical + vbOKOnly + vbDefaultButton1, "Duplicate"
Cancel = True
Me.ItemCode.Undo
Else:
End If
End Sub
Now, the index for this is based on two fields (ItemCode and Question Group). I would like to display the same message before update but don't know how to include the second field in the syntax.
We are working on an Access (2007) database that is on a SharePoint Site (2007).
Currently the form is operational, but there is one last thing that would be nice to have.
The table is "Updated Headcount" which contains "EMP_ID" which are unique numbers stored as text.
In the event a new employee is entered in the system by another user on this site we would like to prevent any duplicate "EMPID"s from being entered and saved on the SharePoint, we would also like to alert the user and prevent the data from being saved.
All data is currently bound, so once the user makes a change it is made, no submit button is required.
We are running into some difficulties in doing a dlookup from the value entered and comparing to a column in the table.
TABLE - UPDATED HEADCOUNT
COLUMN in UPDATED HEADCOUNT - EMPID
FORM CELL user will input an EMPID - newEMPID
FORM CELL used for a dlookup to compare what user has entered to what is already in the table - duplicateEMPID
So below is what we are trying to do, we are sure there are a few commands missing....
=IIF(newEMPID=dlookup([UPDATED HEADCOUNT]![EMPID]), newEMPID, "Error, EMPID already exists")
Hi,
Im new to asp and access and have been having this problem for serveral weeks.
Every couple of days, all the asp pages on my site that communicate with the database start having 500 internal errors. i turned off the "Show friendly error messages" and one page gave me this specific error:
Microsoft JET Database Engine error '80004005'
Unspecified error
/admin/submitlogin.asp, line 8
I have tried a million things and have no idea why this is happening. Im not sure what other information i should post in order to see the problem. Any help would be greatly appreciated. Thank you,
Patrick
How I can get rid of Disk or network error with error code 3043? What this error indicates.
View 4 Replies View Relatedhi all
i have the following peice of code ...
Private Sub NextApplication_Click()
On Error GoTo Err_NextApplication_Click
DoCmd.GoToRecord , , acNext
Exit_NextApplication_Click:
Exit Sub
Err_NextApplication_Click:
If Err.Number = 2105 Then
MsgBox "Cannot navigate to the next record. This is the last record."
Else
MsgBox Err.Description
End If
Resume Exit_NextApplication_Click
End Sub
but even when this error occurs nothing is being properly handled the way i specified - any ideas ?
Does anybody know what this error message refers to?
"Reserved Error (-1517); there is no message for this error."
It just started happening today, and I haven't even made any changes to the database. It occurs when I hit a button I have to run a macro.
the macro does the following:
1) Shows all records
2) Requery
3) ApplyFilter.
The Where Condition for the filter is:
Right([tblContracts].[JobNum],4)=Right([Forms]![FrmContProc].[txtFindJobNum],4)
The weird thing is that it only occurs if the Form window is taller than 1/2 of my viewable area. If the Form window is 1/2 the viewable area or shorter, it works OK. This was running fine earlier today, but about 4:00 pm (03/31/06) this started happening.
If anybody knows what this error means, or how to get rid of it (I really need to use this window in full-screen) then please let me know.
-Thanks, Sean
Okay, I'm kind of stumped here.I have a subform that has a button that sends a user to a "sibling" subform on another tab page, pass some information to ensure they are adding more details to the same records rather than creating two separate record.First time I programmed it, I got an error 3022 (keys cannot have duplicate values). I checked the query of the sibling subform and saw that the ID is from the one side table. I changed it so many table's foreign key is used. Second try, I got an error 3341 (there isn't a matching key in one side table).After some thinking, it also occured to me that I had set the query this way to allow addition of new record which wouldn't be possible if I had the query pulling the many side key, not the one side key.How do I get the subform to accept the ID that is being passed and create a new record using that ID?:confused:
View 5 Replies View RelatedCode:
Private Sub Consolidate_Click()
Dim temp As Variant
Excel.Application.Visible = True
temp = Dir(CurrentProject.Path & "Inputs")
Do While temp <> vbNullString
[Code] ....
From the second iteration its not picking the error.
Every form has an on error property.
Is it enough for error handling to code the on error property for each form?
With enough I mean error handling which lets you resume the program.
Ontherwise I have to code (or call a procedure) for each coded event which i wouldn't prefer
For instance now I'm putting error handling in each event but would consider it more efficient if it can be placed once in each form
Private Sub cmdReport_Click()
On Error GoTo Err_cmdReport_Click
Dim stDocName As String
stDocName = "rptOfme"
DoCmd.OpenReport stDocName, acPreview
Exit_cmdReport_Click:
Exit Sub
Err_cmdReport_Click:
MsgBox Err.Description
Resume Exit_cmdReport_Click
End Sub