Duplicated Values Problem

May 16, 2005

Hello! I'm in the process of creating a report, but am running into a problem. I have a number of clients that include fields such as ID, last name, first name, address, etc. and then their account numbers. Each client has a number of different accounts. The problem is that each client's last name, etc is listed again for each different account they have, so the query results looks like this:

ID Last Name Account #
1 Smith 123-56
1 Smith 4458-66
2 Jones 523-63
2 Jones 4525
2 Jones 5236
3 Roberts 5225-56
4 Johnson 523-55

I want the names and client contact info to appear only once in the report and all of the account #s to show also. Any suggestions would be GREATLY appreciated!

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Quote:

--- Table1 ---

Original:
col1 col2
-----------
text1 Stext1

[Code]...

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Jan 20, 2005

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Any ideas?

This is not a FE,BE database, and also, i'm utilizing a .dll file called MouseHook.dll which I have previously heard about in this forum.

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Hi, I have a table contains 5 fields are shown as below, how I can write a query to find out the duplicate of the records? I have created a couple of queries by using Find Duplicates Query Wizard to do it. But the results are not accurate enough.

Field 1: ID
Field 2: Trading Name
Field 3: Location No
Field 4: Location Street
Field 5: Location Suburb

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41350Arabica Café Grey St
263Arabica Cafe` 1GREY STREET
41294Arashi Japanese Resturant41Courtenay PL
150Arashi Kushi Yaki Bar41COURTENARY PLACE



From the data sample, I could like to find out the duplicated records. One of the queries is shown as below. But they cannot pick up these records. Any better way to find the duplicated records? Please help.

SELECT DISTINCTROW [C&B-will].[trading name], [C&B-will].[location street], [C&B-will].Field1, [C&B-will].[location no]
FROM [C&B-will]
WHERE ((([C&B-will].[trading name]) In (SELECT [trading name] FROM [C&B-will] As Tmp GROUP BY [trading name],[location street] HAVING Count(*)>1 And [location street] = [C&B-will].[location street])))
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Hi
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Table 1

Table 2

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Project
Project Amount

Project
Budget
Budget Amount

Project
Project Amount
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Aug 6, 2014

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Dec 5, 2014

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So, if you pick OtherID from Row7 you then also must pick OtherIDs from rows 8 and 9 because they have the same fax number. Basically, once you pick an OtherID you're then obligated to pick all OtherIDs that have the same fax number as the one you picked.

If the number requested (6 for this example) isn't possible then "the closest number possible but not exceeding" would be the rule.

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There will be many possibilities (the real dataset has tens of thousands of rows and the number of people requested will be around 10K), as long all OtherIDs connected to all faxes on the result set are part of the requested number (6 in this case) any combination would do.

A few notes.

1.Getting as close as possible to the requested number is a requirement.

2.Some OtherIDs will have a blank fax, they should only be included as a last resort (not enough OtherIDs for the requested number).

my table (NR_PVO_120)
Row OtherID Fax
1 11098554 2063504752
2 56200936 2080906666
3 11098554 7182160901
4 25138850 7182160901
5 56148974 7182232046
6 56530104 7182234134

[code]....

A few sample outputs

one solution is taking rows 1-6 and 26.

OtherID
11098554
56200936
25138850
56148974
56530104
56148975

Another solution is taking rows 1-4 and 10-14.

OtherID
11098554
56200936
25138850
56024315
56115247
56148974

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Code:

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Code:

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