Forms :: Button To Add New Record To Form
Mar 5, 2014
I am using a table to hold data relating to 3 very similar products, one distinction is that one of these items has a value in that remains constant. If I set this field to have a default value at table design level - all 3 units get this same value, which is incorrect.
I am using continuous forms and if I use VBA code in the Current() event I can prefill the corresponding text field with the default value .... but, it is quite easy to add additional rows without meaning to, the problem here is that if the user creates records in error selection of the record pointer will not permit its removal from within the form - even through AllowDeletions is enabled.
So, if I disable AllowAdditions in the form properties - the form now prevents any new rows being added to the form at all... which is what I expect.
However, I was hoping to add a command button to other form footer for the user to physically confirm before the record is added to the form but I dont know what function to call to add the new record to the form....
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Jul 30, 2014
I have a continuous form in which I put a command button for each record called "detail". I would like to click on the "detail" button and make it open another form containing all (and only) the info on this record.
At first I refused to use an "id" to link both forms, but finally I added the "id" in the table... however still does not work.
continuous form: "04 - GASTOS_BUSQUEDA"
id field on continuous form: "Gastid"
pop-up (details) form: "GASTOS_EDITAR"
id on pop-up (details) form: "editar_id"
This is what I have tried on the "click" properties of the "details" button field (called "btn_editgs"):
1)
DoCmd.OpenForm "GASTOS_EDITAR", acNormal, , "[editar_id] = " & Me.Gastid
2)
DoCmd.OpenForm "GASTOS_EDITAR", , , "[editar_id]=" & Me.Gastid
3)
stLinkCriteria = "[editar_id]=" & Me![Gastid]
DoCmd.OpenForm "GASTOS_EDITAR", , , stLinkCriteria
4)
Private Sub btn_editgs_Click()
On Error GoTo btn_editgs_Click_Err
Dim strWhere As String
strWhere = "[editar_id] = " & Me.Gastid
DoCmd.OpenForm "GASTOS_EDITAR", , , strWhere
btn_editgs_Click_Exit:
Exit Sub
btn_editgs_Click_Err:
MsgBox Error$
Resume btn_editgs_Click_Exit
End Sub
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Aug 8, 2013
I have a form called [Add or Edit Tag Numbers]. The primary key for the control source of this form is [TagNumber]. I have created a button on this form that opens a second form, [Add or Edit Calibrations], to a new record and carries the [TagNumber] through to the corresponding field on the [Add or Edit Calibrations] form.
Almost everything works. I click the button and the second form is opened to a new record, with the tag number on the first form carried through to the seond form. The only issue is that when I go back to the first form and try to close it, I get an error saying that I can't save the record. It is error 2169. This is especially strange because even if I exit after seeing this record, additions in both forms are saved. This is the code for the button, called [NewCalibration]
Private Sub cmdNewCalibration_Click()
DoCmd.Save acForm, "Add or Edit Tag Numbers"
DoCmd.OpenForm "Add or Edit Calibrations", acNormal
DoCmd.GoToRecord acDataForm, "Add or Edit Calibrations", acNewRec
Forms![Add or Edit Calibrations]![TagNumber] = [Forms]![Add or Edit Tag Numbers]![TagNumber]
End Sub
How I can avoid getting this message? I would prefer to use a button over a subform.
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Oct 23, 2013
I have a main form created from a query (FrmQuerySearchResults) which has a sub-form within, (FrmPresentationsTabular) which I am using to show each presentation to our service made by any given client.
For ease of use, I've removed the navigation buttons and want to replace them with my own command buttons. For appearance, I've changed the properties of the sub-form so that 'allow additions' is set to No. This is so that the list of presentations users see does not show the bottom row as a new record.
I'm trying (using macros) to add a button in the footer of the subform that opens a new form (FrmNewPresentation) which opens to a blank record allowing the user to click button, enter info, hit close.
I'm having all sorts of trouble getting this button to do as its told! So far, I have a macro that has 2 steps, first it opens FrmNewPresentation, then it has action GoToRecord, with record set to New, object type set to Table, object name set to Presentations (the name of my table populating this sub-form).
I realise the problem may be the allow additions property being set to No, so I believe I need to add parts to this Macro that goes to that property and changes it on opening the input form - I keep getting a message saying "The object 'Presentations' isn't open.
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Jul 2, 2013
I have a form that opens from a different form based on the primary key within the original form. Unfortunately it seems to be opening a new record every time I open the form--not only from the original form but also straight from the sidebar.
The command button that opens the second form from the first uses the following VBA:
DoCmd.OpenForm "ZooMobile Incomplete Booking-Return Client", , , "[Event_ID] = " & Me.EventID
This exact coding worded perfectly in a similar set of forms that I had created; the only difference is a change in the form name & primary key field.
Add onto this, I think that the code DOES work, but then it immediately opens another new record. When I open the second form from the command button, then change to Design View, the form's Filter property is set to [Event_ID]=X (where X is the proper key from the first form) and Filter On Load is set to Yes. The X in the Filter changes accordingly when it changes in the first form. Also, every time I open the form a new record is added to the underlying table.
I've tried setting "Allow Additions" in the second form to No, but then when I open the form nothing appears. Literally; the entire form is blank, no labels, textboxes, combos, buttons or anything. When going to Design View it's still all there.
I've also checked the On_Load, On_Current & Form_Current events and found nothing. I even deleted them and the problem still occurred.
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Oct 30, 2014
I have continuous form in Access 2010. I highlight selected record. Now I would like when user will select record, that record will display button to give ability user delete it. For not selected records button not visible and disable. How to display button only in selected record in continuous form?
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Apr 3, 2014
Access 2010. I have a form pulling from a query to create a "To Do' list of sorts. On this form is a button to open an input form for the corresponding record (I hope). When this button is used I want it to pull certain data for that specific line from the query and input it into the new record opened by the button. I know this is possible as I use another db that does this but I have not been able to figure out how to make it work in the new db.
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May 24, 2013
I currently have a database where new records can be entered in a "New Part" Form and Records can be viewed(but not altered) in a "Part Search" Form. The forms are the same except one is allowed to edit. I have also created another form where I am trying to search the "Part Search" Form via a tracking number. I want to have a text box where users enter a tracking number then click the button to take them to the record on the "Part Search" Form.
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May 11, 2014
My database has a table 'CCProgress' which contains just 3 fields (ID, Level, Date), and I have a form which I want to use for adding new records to this table.The form contains the 3 fields plus 2 combo boxes for choosing the relevant ID and Level codes. Date is just entered manually.Up to this point everything is fine, but I can't figure out how to write the 3 fields to 'CCProgress' when I click the 'Add New' button.I have tried various ways via the OnClick event for the button but without success. I am sure the answer is quite obvious but I just can't seem to see it.
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Jun 25, 2014
I created a table about films and i made a form so i can see each movie in a different record. I wanted to create a button which generates a link to the movie's internet website. But when i create a button i cant put a different hyperlink for each record of the form.
My idea is the button to have a logo of the site so that is why i cant just put a link in a text box. I also tried embedding a hyperlink to a picture but again i had the same problem.. there was only one hyperlink for all the records .
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Mar 25, 2015
I am using Access 2007 and am a former user of an old flat-file 32 bit program under Windows 3.x. I am fairly new to MS Access 2007. I run a filter or query, which will return X number of records. Then, I will search those X records by specific text, such as "assist" from the record navigation buttons. I search for "assist" and the text will be highlighted each time it is found in any text or memo field in the record. Hitting Enter takes me to the next occurrence and highlights the text. If "assist" occurs in 4 fields in a record, for instance, it will be highlighted in each of those 4 fields one by one as I hit Enter. The next Enter takes me to the next record and will then continue to the next occurrence of assist" in any of its fields. It will continue to highlight "assist" in those fields, in succession, until the last occurrence in all of those records is found, in which case Enter does not return "assist" anymore because the last occurrence has already been found.
This does not always work. Often, I get every occurrence of "assist," but in the current record only, even though the word exists in other remaining records that were returned with my original filters/query.
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Feb 2, 2014
Basically I want to type the ID(key) of a record table in a unbound text box and then by pressing a command button to be able to bring up that record (in form view). I do not want to use a combo-box.
So what do i write as VB code in the Private Sub mybutton_Click()
Table name is [ACTION_ID], ID field name is [ACT_ID] & text box name is [TEXT_BOX]
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Sep 30, 2014
I have a form named CORRES_TYP with 3 text boxes and a list box. I also have a separate table with 3 field from where the information I put in the form was saved.
In my form whenever I put information on the textbox at hit add record button, these information are saved in my table and will reflect on the listbox on my form below the textboxes. Also if I select a record in the Listbox the record I selected will apprear on the corresponding textbox in the same form.
My problem is that I have been trying to create a command button that will save and change the existing record everytime I select an item in the list box and modify the information through the textbox. Here are some infromation about my table and form:
Table name = CORRES_TYP
Field 1 = CODE (Primary key, No Duplicates)
Field 2 = DESCRIPTION
Field 3 = FOLDER
Form name = CORRES_TYP
Textbox 1 = CODE
Textbox 2 = DESCRIPTION
Textbox 3 = FOLDER
Listbox name = LIST14
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Jun 10, 2013
How to create a button on my form that would find a random record. I would imagine I will be doing this through VB...
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Jan 15, 2014
I have created Command buttons on forms with VBA code. Records GoTo previous and GoTo Next Record so both of working is good. But Next Record command is force to a new record. If suppose when we clicking on last record. It is go to new record without any message. So No need to force a new record with Next Record Command. Only just move to next record if there is no records show a message. Below mentioned both VBA codes so there is any changes on GoTo Next Record Code?
VBA Code:
Go To Previous Record : DoCmd.GoToRecord , , acPrevious
Go To Next Record : DoCmd.GoToRecord , , acNext
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Nov 5, 2013
I am designing a database to manage hospital patient data. I will have to enter info at various points, e.g. when a patient is referred, admitted, discharged...
So for example, I have a main form with the patient's name and two subforms, one with the referral details (e.g. date, name of referrer...), and one with the admission details (e.g. date, diagnosis). They are linked through Parent-child links to the main form by PatientID. So, when I enter a new PatientID in the main form, the ID in the subforms is automatically added/synchronized.
However, I would like it not to be...since not all patients that are referred are then admitted. Therefore I would like to have a command button in the main Form that allows me to control when a new patient record is added to the admission subform. In other words, I would like an "Add a new Record in the admissions subform" button, which then creates a new record, with matching PatientID in the admissions subform (and in the related table). Is this possible???
I have tried using the command button wizard but it either requires a record to be already present in the subform, or it takes me to the first record of the form, and not the matching PatientID one.
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Oct 29, 2013
I have a database that involves a lot of data about ppl and I'd like to prevent duplicate entries.
I have a form that gathers data. I'd like to have a button after name, surname and birthday are written.
A click on the button would display a msgbox that says that person already exist, maybe even with the added - edit the old entry/add new record anyway/abort options.
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Jun 24, 2015
I want to show/hide a button on my form.The button is for entering a new record in the table of the database.Now when i Load the form, i want to check if there are already records in the table for a specific lanID. When there are no records, the butten has to be displayed. When there are already records for that lanID the button has to be hidden.
I have found some code to tackle that, but When i use the rs.MoveLast it hides the button when there are records, but when there are no records it gives an error that there are no records found. I almost forgot to say that i use Access 2010..Here is the code that i use:
Code:
Private Sub Form_Load()
Dim SQL As String
Dim rs As DAO.Recordset
Dim landmeterID As String
landmeterID = [Forms]![MainForm]![LanIDTxt]
SQL = "select * from dbo_Lan_Opleiding where Id_landmeter ='" & landmeterID & "'"
Set rs = CurrentDb.OpenRecordset(SQL)
[code]....
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Jan 13, 2014
I've rebooted my copy record button and just used the macro wizard for now, it seems to work as far as I can tell but there is something strange about it.
I've added in some text boxes so I've got some confirmation, but when I click this copy button I get the following error;
"The command or action 'RecordsGoToNew' isn't available now."
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Jun 28, 2013
I want to recall a record by it's primary key in a form with a command button
I mean write a primary key in a textbox and press the button then it shows the record.
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Feb 24, 2014
I am trying to create a button that clears a field in a record. (Using linked images and need to give the user a way to remove an image if not correct/needed - the record in the table has a field that keeps track of the address of the stored image and I want to remove that info)
The following is the code I have written but I get a datamismatch. The Prepack ID is an autonumber field.
DoCmd.RunSQL "UPDATE [Prepack TBL] SET ImageName = Null WHERE [Prepack TBL].[Prepack ID] = '" & ID & "' "
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Dec 3, 2014
I currently have a command button to run the following...
DoCmd.OpenQuery "Credit Card Report", , acAdd
Which is an appended query.
However, I don't want it to add the whole table each time this is pushed but when trying to use...
DoCmd.RunSQL "INSERT INTO [Credit Cards] ([Provider's Name], [Patient Name], [Patient Account Number] ... VALUES ([Provider's Name.Value], [Patient Account Number.Value], [Patient Account Number.Value]"
It doesn't want to add the single record and gives me an error. I'm pretty sure my syntax is wrong but not sure how to correct it.
The fields I want added are ... Provider's Name , Patient Name, Patient Account Number...
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Mar 3, 2015
I have a subform [ctrlLogDetail] on a parent form [incidentdetails] that is opened by the user when they click on a button on a navigation form. These forms are used for a variety of purposes. The problem I'm having is that the user needs to be able to select an incident number and go to the appropriate form (I accomplish this by using this code: DoCmd.OpenForm "IncidentDetails", acNormal, , "Activity_ID = " & Me.cboINum in the on click event of the button.) This works appropriately. The subform is also appropriately linked to the parent form.
I need an additional line of code to have the subform go to a new record when the form opens to an existing incident number. Since I use this form/subform when doing different tasks, having the Docmd.RunCommand acCmdRecordsGoToNew in the Form on open event isn't optimal.
I only want the LogDetail subform to open to a new record when the user wants to add an entry, but not when they need to edit a specific entry. What is the appropriate syntax to use either in the openargs event of the openform command or elsewhere in the procedure so that the gotonew function on the subform only occurs when this button is clicked? I'm having difficulty getting access to understand that I want the subform to open to a new record but not the parent form.
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Feb 12, 2015
I have a form with a duplicate record button to allow records to be copied. I used this code (I think from Allen Browne), but it only copies the last record in the recordset?
If Me.Dirty Then 'Save any changes
Me.Dirty = False
End If
If Me.NewRecord Then 'Check there is a record.
MsgBox "Select a record to duplicate"
[Code] .....
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Aug 1, 2013
What to do, I have a form that will reset online user of my system the field is yes or no type boolean and i using combo box that will show only online people but my problem is how to reset the yes to no when i choose from the combo box a username I want to logout. I use command button also.
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Sep 17, 2013
I have a form which displays some product details and a stock level. The subform below it allows entry of a quantity to issue and a control button to run a small macro, write a movement record to a stock movement table and then close the form. This works fine.
But the user can also cause the movement record to be written just by keying in a quantity and tabbing out. If this is done several times it writes several movement records and doesn't close the form. I want to ensure that record is only written when the command button is pressed.
Perhaps there is a more conventional or better way of achieving what I want but I can't think of it.
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