Forms :: Button To Find Random Record
Jun 10, 2013How to create a button on my form that would find a random record. I would imagine I will be doing this through VB...
View RepliesHow to create a button on my form that would find a random record. I would imagine I will be doing this through VB...
View RepliesBasically I want to type the ID(key) of a record table in a unbound text box and then by pressing a command button to be able to bring up that record (in form view). I do not want to use a combo-box.
So what do i write as VB code in the Private Sub mybutton_Click()
Table name is [ACTION_ID], ID field name is [ACT_ID] & text box name is [TEXT_BOX]
I'm reworking a db to make it web compatible. Right now I'm working on my Price and Sales tables.There are about 900 Sales records, 450 Price records (for about 45 Items).
I have re-done my Price table with an Autonumber Key field. (It had a multi-key which I understand web db does not support.) Each autonumber key represents a Date with new Price for a Company/Item. The Price change Dates are random.
I have put a Foreign Field in my Sales table for the Price key field.
My dilemma is matching the Sales with the Prices.
When the Price Date and Sales Date do not match (at least half of them don't match), I need to look back in the Price table to the max Date BEFORE the Sales Date in the Sales table for that Company/Item in order to select the correct Price key.
I know you can create a find record command button really simply, which when clicked will display the find and replace window.
What i want to do is create a command button that will search a specific field that i specify in a report for the criteria i enter.
i.e i have a customer information form, which contains
AccountNo
CompanyName
Address
Postcode
Tel etc
what i want is a button that when clicked brings up an input field that allows the user to type the name of the company into this field, then when either the enter key is pressed or another button on this pop up window the matching record will be displayed or a error window stating that there are no matching records. Can anyone help me with this.
Basically I want to type the ID(key) of a record table in a unbound text box and then by pressing a command button to be able to bring up that record (in form view). I do not want to use a combo-box.
So what do i write as VB code in the Private Sub mybutton_Click()
Table name is [ACTION_ID], ID field name is [ACT_ID] & text box name is [TEXT_BOX]
I have a form [Invoice] with a subform [Orderssubform1] in it and they are both linked with the field 'CustomerID' using a parent and child relationship. I have also established that relationship in the tables too. Using a combo box [Combo0], the user can select a customer from the form and then enter details about the invoice in the subform. They then click 'Generate Invoice' and it creates a report for them. This all works fine.
The problem arises when I want the customer to locate a certain invoice using a button. I would like the customer to be able to click a button on the form which would then bring up a box asking them to enter the invoice number [InvoiceNo] and it would then locate that invoice so they can generate it as a report again. The user can find the customer themselves using the combo box, I just want the record related to that customer to be found using the button.
Is it possible on the Find Record button added to a form to adjust the search function so it defaults to a specific box on the form? I have a form for tracking employee's and on my Find Record button I would like it to default to the Last name instead of the Record number.
View 3 Replies View RelatedI am having issues with assigning search criteria for the "Find Next Button". I used the wizard and it does not ask what criteria to use for Find Next. I am assuming there is a bit of VBA I need to add to the generic Find Next button. This is what comes up when I use the wizard to create the button:
Private Sub Command118_Click()
On Error GoTo Err_Command118_Click
Screen.PreviousControl.SetFocus
DoCmd.FindNext
Exit_Command118_Click:
Exit Sub
Err_Command118_Click:
MsgBox Err.Description
Resume Exit_Command118_Click
End Sub
How do I define the criteria for the next record. I want the db to move to the next record with the same [PtMRN].
I am not sure where to start or go about creating message box that would display "No results found" if my queries return no results. My search of the forums hasn't been fruitful.
I have created one form that has a text box and a button that works as a search function to run through the tables and displays the applicable queries. Currently, if no results are returned nothing happens. Preferably I would like a message box to display stating that there were "No results found". I would assume that the code would be associated with the "Find" button. Here is the VBA code as it stands, again, I haven't even attempted to add code for a message box.
Private Sub Find_Click()
On Error GoTo Find_Click_Err
If DCount("Heading", "Service Desk Manual Query") > 0 Then
DoCmd.OpenQuery "Service Desk Manual Query", acViewNormal, acReadOnly
End If
[Code] .....
Find_Click_Exit:
Exit Sub
Find_Click_Err:
MsgBox Error$
Resume Find_Click_Exit
I have a Listbox that I use to find records in the Database. It has two fields, [ShootID] and [ShootDate]. It is curently sorted in the query by [ShootID] but I want the user to be able to change it to sort by [ShootDate] and then back again.
View 1 Replies View RelatedHow can I generate a random string to a text field from a button. I
Say I have a form..
On the form I have:
X1 Button (BTN-Generate-Password)
X1 Text Field (TF-Generated-Password)
How can I make it so when the button is clicked a random string will appear in the text box
HTML Code:
Private Sub BTN-Generate-Password_Click()
(What Do I put here?) (Will it populate the Text Field?)
End Sub
- 9 Characters
- Upper and Lower Case
- Numeric & Alpha Numeric
- These Characters (!@#$%)
On a from ("Customers") with tabs I have on the second tab a subform ("Orders") as a single form with a field "Ordernumber". "Customers" and "Orders" are linked through "CustomerID".
On the mainform I have a "searchfield" in which a enter the Ordernumber, I want to find.I cannot manage it, that After_Update of the "searchfield" the ordernumber is found on the subform and the focus is on that subform.The focus only shows me the CustomerID on the first tab, but does not jump to the second tab exactly to thes searched ordernumber.
Code:
Private Sub searchfield_AfterUpdate()
Dim rs As Recordset
Me.CustomerID.SetFocus
Set rs = Me.Orders.Form.RecordsetClone
rs.FindFirst "ordernumber = " & Me.searchfield
If Not rs.EOF Then Me.Orders.Form.Bookmark = rs.Bookmark
End Sub
Is it possible to put a listbox on a subform where it will allow you to find a record on the subform? The wizzard dosen't sem to allow me to do it!
View 5 Replies View RelatedI have a main form (unbound) and a main form (bound) and then a subform (or a main form;subform;subform).The main form has the following SQL;-
SELECT Detail.*, Hazards.*, HowHarmed.*, Section.*
FROM PSR RIGHT JOIN (Hazards INNER JOIN ([Section] INNER JOIN (HowHarmed INNER JOIN Detail ON HowHarmed.ID = Detail.HowHarmedID) ON Section.ID = Detail.[Subject Area]) ON Hazards.ID = Section.detailID) ON PSR.ID = Detail.PSR;
This form appears to work fine. Essentially, there is a control on the unbound form whereby the user selects the section and it populates the respective form with the various 'detail' of the various records.My tables are as follows;-
Risk Assessments
Detail
Section
HowHarmed
Hazards
PSR
PLR
Staff
In the subform there are records from Riskassessments, which is the table in the source property of this subform (and not on the main form) with a link to PSR of which is on the mainform. Again, these appear to work if the record is entered via the tables - all the tables appear to be linked correctly from their respective dropdowns (+ sign) but when I go to add a new record in this subform, I get the error "The link masterfields property has produced this error: 'The object doesn't contain the automation object ID'." When I try to update from this entry the following message is presented;-"The ms Office access database engine cannot find a record in the table 'Detail' with key matching field(s) 'DetailID'.
The SQL for this subform is as follows;-
SELECT Detail.*, PLR.*, RiskAssessments.*
FROM (Detail INNER JOIN RiskAssessments ON Detail.ID = RiskAssessments.DetailID) LEFT JOIN PLR ON RiskAssessments.PLR = PLR.ID;
Lets say,
Form A has fields: ID, LN and FN
ID LN FN
1 A F
2 B G
3 C H
4 D I
5 E J
Form B has fields: ID, LN and TR
ID LN TR
1 A Y
2 B N
3 C Y
4 D Y
5 E N
I would like to be able to switch between these two forms and the form automatically set focus to the record that I was on the form prior. Meaning if I am on record 3 on Form A and navigate to Form B, I would like to automatically set focus to record 3. Is this possible?
A possible issue after this gets sorted out is what happens if with the same scenario above record 3 does not exits? is it possible in that instance to simply requery the form?
I Have a forms which brings up a record in textboxes when you hit a search Button using a value that you type into a Textbox called BarTxt. My problem is that this value may not be unique. Therefore I'm trying to find and update the table using 2 values from the table (Barcode and PurchaseOrder).I have entered the code
Code:
Private Sub SearchBtn_Click()
PNTxt = DLookup("PartNumber", "BookInTable", "BarCode ='" & [BarTxt] & "'" And "PurchaseOrder ='" & [POTxt] & "'")
End Sub
This however is just bringing up a Type mismatch error. Even though both are text fields.Also even if I just use Barcode to search which works. My update Code
Code:
DoCmd.RunSQL "Update BookInTable SET DateBookedOut = '" & Me!DateTxt & "' WHERE BarCode ='" & [BarTxt] & "'" AND PurchaseOrder ='" & [POTxt] &
I get an Compile error saying "expected expression".
I have a form that has a FIND button. I want the user to enter the 3 fields that make up the primary key, then find the associated record. How can I do this in Access - not VBA?
View 1 Replies View RelatedI'm trying to build a search form.- Access 2007
I have a table (Table1), contains a 'part' field.
I wan to build a form with a blank text box (txtbx1) where users can enter a part description, this will search records in Table1>part and return a list of parts that match the textbox input.
Here's what I've done -
txtbx1 - property sheet - control source - part
event - on enter - ...
I've built an expression -
[Table1]![part] = [txtbx1]
hoping that this would match records 1n Table1 to txtbx1
I'm trying to find a subform record from a separate pop-up form based on its ContractID. When I click the button, I get the following error:
"A macro set to one of the current field's properties failed because of an error in a FindRecord action argument."
When I step through the code, it works just fine. Here is my code:
Code:
'Find contract
With Forms!frmContractForm.frmContractSub
.Form.ContractID.Enabled = True
.SetFocus
.Form.ContractID.SetFocus
DoCmd.FindRecord Me.ContractID
.Form.Business.SetFocus
.Form.ContractID.Enabled = False
End With
is there anyway to have the database autogenerate a random 8 digit reference number for each record.. this of course must be unique..
maybe something like
7C7CYU99, or HJUHU889... im sure you get the picture.
I have two tables, one table Data has member(SUBSCRIBER_ID) data including service rep(UserName). Another table ServCoord has data including service rep and their manager. What I am trying to do is pull 5 random accounts per service rep. I can pull 5 random accounts, but not per service rep. I have currently 77 service reps. Is there any way I can pull 5 random accounts per service rep? Here is my starting point so far.
SELECT TOP 385 [Data].SUBSCRIBER_ID, Rnd(1) AS Expr1, [Data].UserName, Rnd(Len([UserName])) AS Expr2
FROM ServCoord INNER JOIN [Data] ON ServCoord.ServCoord = [Data].UserName
GROUP BY [Data].SUBSCRIBER_ID, Rnd(1), [Data].UserName, Rnd(Len([UserName])), [Data].SUBSCRIBER_ID, [Data].UserName
HAVING ((([Data].UserName)<>"NULL"))
ORDER BY [Data].UserName, [Data].SUBSCRIBER_ID;
My database has a table 'CCProgress' which contains just 3 fields (ID, Level, Date), and I have a form which I want to use for adding new records to this table.The form contains the 3 fields plus 2 combo boxes for choosing the relevant ID and Level codes. Date is just entered manually.Up to this point everything is fine, but I can't figure out how to write the 3 fields to 'CCProgress' when I click the 'Add New' button.I have tried various ways via the OnClick event for the button but without success. I am sure the answer is quite obvious but I just can't seem to see it.
View 5 Replies View RelatedI created a table about films and i made a form so i can see each movie in a different record. I wanted to create a button which generates a link to the movie's internet website. But when i create a button i cant put a different hyperlink for each record of the form.
My idea is the button to have a logo of the site so that is why i cant just put a link in a text box. I also tried embedding a hyperlink to a picture but again i had the same problem.. there was only one hyperlink for all the records .
I am using Access 2007 and am a former user of an old flat-file 32 bit program under Windows 3.x. I am fairly new to MS Access 2007. I run a filter or query, which will return X number of records. Then, I will search those X records by specific text, such as "assist" from the record navigation buttons. I search for "assist" and the text will be highlighted each time it is found in any text or memo field in the record. Hitting Enter takes me to the next occurrence and highlights the text. If "assist" occurs in 4 fields in a record, for instance, it will be highlighted in each of those 4 fields one by one as I hit Enter. The next Enter takes me to the next record and will then continue to the next occurrence of assist" in any of its fields. It will continue to highlight "assist" in those fields, in succession, until the last occurrence in all of those records is found, in which case Enter does not return "assist" anymore because the last occurrence has already been found.
This does not always work. Often, I get every occurrence of "assist," but in the current record only, even though the word exists in other remaining records that were returned with my original filters/query.
I am using a table to hold data relating to 3 very similar products, one distinction is that one of these items has a value in that remains constant. If I set this field to have a default value at table design level - all 3 units get this same value, which is incorrect.
I am using continuous forms and if I use VBA code in the Current() event I can prefill the corresponding text field with the default value .... but, it is quite easy to add additional rows without meaning to, the problem here is that if the user creates records in error selection of the record pointer will not permit its removal from within the form - even through AllowDeletions is enabled.
So, if I disable AllowAdditions in the form properties - the form now prevents any new rows being added to the form at all... which is what I expect.
However, I was hoping to add a command button to other form footer for the user to physically confirm before the record is added to the form but I dont know what function to call to add the new record to the form....
I've been building a CRM in Access that allows for creating profiles for our accounts. When we add a new account, I'd like an Account ID to automatically generate and look like this: CRMXXXXX where the X's represent a random number. I originally wanted to set the field as autonumber to just count up, but unfortunately I need to append this value to another sales database we have; you can't store the text "CRM" with an autonumber in a table.
Right now, all I've done is place an equation in the default value of a textbox I have on my 'Add Account' form. I then made the control source of the text box the Account ID field. My equation is as follows:
="CRM" & CStr(Int(Rnd(Now())*10000))
This appears to work, as it generates a value in the correct format. However, I've realized that each time I open the CRM, the random numbers start over again and I run into issues of trying to create a new record with the same ID as a previously created record. I assume I need to incorporate some sort of timestamp to it in order to change it.