I have a form that uses a query to filter out records to show basic info of records (each one has a unique ID) only pertaining to today that are listed one under the other using a whole row. What I'm looking for is a way to design a button for these filtered records within that row that when clicked, will open up a new form that I've already designed for just that ID.
View RepliesI have a form called [Add or Edit Tag Numbers]. The primary key for the control source of this form is [TagNumber]. I have created a button on this form that opens a second form, [Add or Edit Calibrations], to a new record and carries the [TagNumber] through to the corresponding field on the [Add or Edit Calibrations] form.
Almost everything works. I click the button and the second form is opened to a new record, with the tag number on the first form carried through to the seond form. The only issue is that when I go back to the first form and try to close it, I get an error saying that I can't save the record. It is error 2169. This is especially strange because even if I exit after seeing this record, additions in both forms are saved. This is the code for the button, called [NewCalibration]
Private Sub cmdNewCalibration_Click()
DoCmd.Save acForm, "Add or Edit Tag Numbers"
DoCmd.OpenForm "Add or Edit Calibrations", acNormal
DoCmd.GoToRecord acDataForm, "Add or Edit Calibrations", acNewRec
Forms![Add or Edit Calibrations]![TagNumber] = [Forms]![Add or Edit Tag Numbers]![TagNumber]
End Sub
How I can avoid getting this message? I would prefer to use a button over a subform.
I am tying to create a cmd btn called "Report" that when clicked opens a form [quick report] in dialog window. I have that done easy enough. But what I want is if that form [quick report] is open, and you click the same button "Report" for it to then close the form.
View 3 Replies View RelatedBasically I have a Customer Form, which I have a New party button on it,this button opens up the party form to a new party, what I would like it to do is open up a new party but make the new party for the customer I had selected in the previous form.I have tried the GoTo macro's but cannot seem to get it to work.
I am thinking on clicking the button it will need to get the Customer ID, and then open the party form, create new party, and paste in the Customer ID, which then updates the Name - Date - Address - Company Fields.
I have a continuous form in which I put a command button for each record called "detail". I would like to click on the "detail" button and make it open another form containing all (and only) the info on this record.
At first I refused to use an "id" to link both forms, but finally I added the "id" in the table... however still does not work.
continuous form: "04 - GASTOS_BUSQUEDA"
id field on continuous form: "Gastid"
pop-up (details) form: "GASTOS_EDITAR"
id on pop-up (details) form: "editar_id"
This is what I have tried on the "click" properties of the "details" button field (called "btn_editgs"):
1)
DoCmd.OpenForm "GASTOS_EDITAR", acNormal, , "[editar_id] = " & Me.Gastid
2)
DoCmd.OpenForm "GASTOS_EDITAR", , , "[editar_id]=" & Me.Gastid
3)
stLinkCriteria = "[editar_id]=" & Me![Gastid]
DoCmd.OpenForm "GASTOS_EDITAR", , , stLinkCriteria
4)
Private Sub btn_editgs_Click()
On Error GoTo btn_editgs_Click_Err
Dim strWhere As String
strWhere = "[editar_id] = " & Me.Gastid
DoCmd.OpenForm "GASTOS_EDITAR", , , strWhere
btn_editgs_Click_Exit:
Exit Sub
btn_editgs_Click_Err:
MsgBox Error$
Resume btn_editgs_Click_Exit
End Sub
I have a main form created from a query (FrmQuerySearchResults) which has a sub-form within, (FrmPresentationsTabular) which I am using to show each presentation to our service made by any given client.
For ease of use, I've removed the navigation buttons and want to replace them with my own command buttons. For appearance, I've changed the properties of the sub-form so that 'allow additions' is set to No. This is so that the list of presentations users see does not show the bottom row as a new record.
I'm trying (using macros) to add a button in the footer of the subform that opens a new form (FrmNewPresentation) which opens to a blank record allowing the user to click button, enter info, hit close.
I'm having all sorts of trouble getting this button to do as its told! So far, I have a macro that has 2 steps, first it opens FrmNewPresentation, then it has action GoToRecord, with record set to New, object type set to Table, object name set to Presentations (the name of my table populating this sub-form).
I realise the problem may be the allow additions property being set to No, so I believe I need to add parts to this Macro that goes to that property and changes it on opening the input form - I keep getting a message saying "The object 'Presentations' isn't open.
How to open a search form with a mouse click on Button_Search
My idea is to pop up a form where user can enter the search text and select the required name and get back to the old form with all details about the entry. This form alone is workign fine. I want to call it in a mouse click. and pass the data back to old form.
I have a main form [Job Quote Form 10-2205] and I am trying to add a command button to open up [Job Process Form-MKD] and have the [Job Process Form-MKD] open up and only show the records that match a certain field, in this case what I call "JobTrackNo" in the [Job Process Form-MKD]. (see attached .jpg)
This problem started to happen only recently, namely you will see that the left column under [Job Quote Form 10-2205] is blank, where normally there had been a number of fields to choose from. The fields are all still available, they are just not opening when I try to match two fields.
I currently have a button that opens a report. the report pulls from a query that has parameters set to "fromdate" and "todate". instead of using dates and parameters that pop up as blank text boxes, I would like to click the button, have a form pop up with a combo box to select all of the options available (currently 23 options) and then click a button to make a report that only displays the record (1-23) selected. I do not need any time constraints because as the databases get updated with more records, there would be more than 23 options to choose from.
View 1 Replies View RelatedMaking a small database, Got 1 Table.
1. ContactDetailTable
Got 3 forms.
1. ContactIDForm
2. ContactInfoForm
3. NewContactFrom
In ContactIDForm it contain 1 textbox name 'TextBox' with Button Name 'Btn'
In ContactIDForm there is only 1 Text Box ContactIDTextBox and 1 Button. User Enters ID in TextBox and On Button Click Event it should check data from TextBox in Table name (ContactDetailTable) in field ContactID and if there is record matching, ContactInfoForm should Open else NewContactForm should open with ContactIDTextBox value in it.
Hi all,
I am new to microsoft access. I've got one question that can't solve.
I am making database with several items. Under each item, there got different field lists to fill in. So I made several forms for each of them.
In main form, I put one combo box to choose the item and one common button. So how can I write the code to open the several different forms,one at a time, by clicking one button according to the value that is chosen from combo box??
thank in advance.
I have a subform [ctrlLogDetail] on a parent form [incidentdetails] that is opened by the user when they click on a button on a navigation form. These forms are used for a variety of purposes. The problem I'm having is that the user needs to be able to select an incident number and go to the appropriate form (I accomplish this by using this code: DoCmd.OpenForm "IncidentDetails", acNormal, , "Activity_ID = " & Me.cboINum in the on click event of the button.) This works appropriately. The subform is also appropriately linked to the parent form.
I need an additional line of code to have the subform go to a new record when the form opens to an existing incident number. Since I use this form/subform when doing different tasks, having the Docmd.RunCommand acCmdRecordsGoToNew in the Form on open event isn't optimal.
I only want the LogDetail subform to open to a new record when the user wants to add an entry, but not when they need to edit a specific entry. What is the appropriate syntax to use either in the openargs event of the openform command or elsewhere in the procedure so that the gotonew function on the subform only occurs when this button is clicked? I'm having difficulty getting access to understand that I want the subform to open to a new record but not the parent form.
I currently have two forms: frmE_SAFind and frmE_SAOrder
frmE_SAFind shows results from a query including fields [txtIDPO] and [dtmDate]
Example:
IDPO Date
btnOpnFrm 6543 2/1/05
btnOpnFrm 5681 1/1/05
frmE_SAOrder shows order details including [txtIDPO] and [dtmDate]
I have a open form command button set up on [frmE_SAFind] that opens [frmE_SAOrder]. Is it possible for me to modify its properties so that when the open form command button is clicked, the order details in [frmE_SAOrder] will represent the order that the user is selecting via the btnOpnFrm command?
Example: If I click btnOpnFrm for 6543, [frmE_SAOrder] will show me PO 6543 details.
Hopefully I made myself clear enough to understand. Thanks for your help!
Hi people,
I have made a form. By giving an ID up firstly this form of the concerning person appears. Now I want to make a link to a report on this form. The intention is then that only those data are shown in the report of the concerning person (therefore with the ID that is reflected in the form).
Now I can open the report by means of a button... but then to get the correct data I have now used a query with a parameter value (the ID) (the report has been based on these query). But the situation is now therefore that if you click on the button that you must introduce the parameter value firstly. Is there also a solution where this is no longer necessary??... therefore that you have to click only on the button and then the concerning data of the report are shown. Therefore by giving in or an other manner the ID with. ??
Hopefully it is understandable, (my english is not that good...)
thanks!
Ankie
Good morning All,
I have a form with a command button to open a report ( based on a query ) for the currently displayed record. here is the code I have used:
Private Sub CS_notes_Click()
On Error GoTo Err_CS_notes_Click
Dim stDocName As String
stDocName = "InternalSNwithRMAprodMASData"
DoCmd.OpenReport stDocName, acPreview, , "TLAUnit = " & Me.UnitSN & "'"
Exit_CS_notes_Click:
Exit Sub
Err_CS_notes_Click:
MsgBox Err.Description
Resume Exit_CS_notes_Click
End Sub
I believe this came from this forum sometime. When the button is clicked I receive the error:
"Syntax error (missing operator) in query expression '(TLAUnit = 26712B')'
TLAUnit is the report field, UnitSN is the form field.
Any help with the error?
Thanks
Kevin
hello everyone,
i have 2 tables have Relationships with each other and i have a form with a listbox and has the surnames from table1 in it
i want a button to open the job information form on new record and i want it to have the client number in it all ready if i click on one of the surnames from the listbox
tables names
tbl Client Detials = have clients information
tbl job information = has job information
both have client number feild and have Relationship
form i want the button on is called frm client splash and the form i want it
to open is frm job information
its hard to tell u srry i hope someone can help me
________________
David
Dear All:
Does anyone know how to use a command button to open a Pdf form in access?
This Pdf form is on the "c" drive called "portfolio".
Thanking in advance,
Dion
I have a form with a drop down list that is coming from a query (City Query)
I have a command button to open a form for data entry to the City table -
When I open the form for city add a record - close the form.
I then go to the drop down list (city query) to select the record that was just added to the city table and the record is not in the query.
What do I need to do for the newly added record to show in the query drop down?
I need to open a specific pdf file per record by using a command button. The pdf files will all reside in a specific folder in a partition on my hard drive. Each pdf file will have a unique four digit file name e.g 1234.pdf.The file name will match a unique number allocated to each record. This number is generated by adding 1000 to the record ID.Record 10 will therefore have an associated pdf file name of 1010.pdf.I have created a text box field , named 'TestReportID', to capture the unique four digit number per record that I assume is needed to be referred to when setting up the code to find and display the correct related pdf file.
I have set up a command button on the records form and as simple test using the hyperlink address to the folder where the pdf files reside, I can open a pdf file by clicking on the command button but it does not matter what record is open when I click the command button, it will always open the same pdf file.If I don't identify a specific file name in the hyperlink address, when I click on the button it will display a file open dialog which lists all the relevant pdf files and I can then select and open the required file.I would like to cut out that step and get the correct file to open when I click the button.
I am creating a database. I have all my forms, queries, tables, reports just as I need them. However, I would like to have a command button on my switchboard that will pull from a query to feed to a Word document (that's actually a letter on my company letterhead). I know a Macro has to be involved with this, but again, I have little to no knowledge of Macros. Also, I would like to be prompted to enter a client ID number when I click on this command button (because I only want to print a letter for a new client, not all of them).
View 4 Replies View RelatedI am trying to add a command button to my main menu to open the contact names as a datasheet, I have changed the properties on the contact names form to datasheet as well as changing the properties on the button to the below:
Private Sub Command48_Click()
DoCmd.OpenForm "Contact Names", acFormDS
End Sub
at first after I saved it, the button did nothing. Now after a bit of playing around (probably not a good idea) I have a new message that states:"The expression On Click you entered as the event property setting produced the following error: Ambiguous name detected: Contacts_Click.To add some additional information, in the vba sheet above the code i wrote above it says:
Option Compare Database
Private Sub Contacts_Click()
DoCmd.OpenForm "Contact Names", acFormDS
End Sub
Private Sub Contacts_Click()
DoCmd.OpenForm "Contact Names", acFormDS
End Sub
should I delete this?
I have based a form on a parameter query, so that when the user is prompted to enter a 'Hobby' to search on, the relevant records will be displayed on the form.
Now, I have created a command button designed to open a template letter in MS Word for a particular hobby. The problem is, I need the command to open certain file depending upon the value input in the parameter box intially. How would I go about doing this?
Hi
I'm not sure if this is a dumb question or not but is it possible for me to have a button on a form that will open the Query Builder?
I have a form that has 3 buttons on it - 1 to access records, 1 to access reports and another which I would like to open the Query Builder when clicked. The database will be used by beginners so I've hidden the design view button and also the database window which appears at startup. All that appears when I open my database is the 3-button form which is what I want.
I thought maybe I could save a blank query and then create a macro to open that whenever the button was clicked and stipulate in the macro to change the view to design view but that didn't work.
Thanks to any help or advice anyone can give and sorry if it turns out to be a really stupid simple solution I've missed (I'm good at that!)
I have a database with three tables
table 1 (form1)
reference (PK) auto number
table 2 (form2)
Reference (fK)
workbook reference (PK) auto number
Table 3 (sub form within in form2)
Reference (FK)
workbook reference (fK)
data Reference (pk) auto number
Each table is a form that is linked via the keys. On form 1 i have a button that is to open the form2, which it does but every time i open the form a new record is added. Why and how do i prevent this.
Then what i want to do is add a button for a new form on table 2 form but use the same reference as the record as presently displayed. How do i add new record using the same Reference but new workbook Reference?
Thanks is advance
I am simply trying to create a command button to open a folder on my desktop
Cannot seem to find this code
This is the path to the folder I want to open
C:UsersJONATHANDesktopCMS FILES
Hi all,
Not sure if this is in the right section but heres my question.
How can i gett a button to open a word document and put in specific information. for example. to send a client a letter, the button would open a word doc with the specfic client data in it.
Also a button to start a mail merge with all client records held on the db.
Thanks for any help