Forms :: Calculate Difference Between Start And Finish Time
Jan 30, 2014
I have a subform in which I want to calculate the difference between a start time and finish time, the problem I am having is when the start time is on a different date to the finish time
Start 23:15 on 14th Jan finish 00:015 on 15th Jan, also I want the answer to be the number of minutes. The fields I have are
BatchStartTime Short Time
BatchFinishTime Short Time
BoilTime ([BatchStartTime] - [BatchFinishTime]) General Number.
There are many batches to enter per job and the MainForm has the StartDate as I didn't want to enter the StartDate for each batch.
I'm trying to calculate the difference between start and end time, which works fine with:
Total Time: DateDiff("n",[tblTaskTimes]![StartTime],[tblTaskTimes]![EndTime])
However, this is for a database that calculates billable time in 10th of an hour. So, for example, 1 hours would be 1, 30 minutes would be .5, less than 6 minutes would be .1.
The format for this expression is set up to a general number, if that matters.
It's gotta be something in the formula like multiplying this by 24 (for 24 hours) and then dividing by something. Nothing I'm trying is working.
I,ve made the following date fields in a form: begintime, endtime. I've also made a field Diff that calculates the difference between the two by the code : Diff = Format([begintime] - 1 - ([endtime], "Short Time"). Bij this code you can calculate the difference even over night.
But now I've got to calculate the part of the time someone worked between midnight and 06:00AM if that person indeed worked in those hours.
e.g. someone started at 16:00 end ended at 03:30. The part of time I need = 3:30 e.g. someone started at 01:00 end ended at 11:00. The part of time I need = 5
How can I accomplish this? I hope someone can help me because I'm :confused:
I have to create a query in access that will calculate two Date and time fields [Date & Time Left]/ [Date Returned], need to figure out between the two fields. Trying to identify when the rep returned the call and the number of business hours (6:00am - 4:30pm) it takes to return a message in Ms Access 2010.
Code: SELECT [Message Tracking_tbl].[Date & Time Left], [Message Tracking_tbl].[Date Returned], [Message Tracking_tbl].ID FROM [Message Tracking_tbl];
I have to create a query in access that will calculate two Date and time fields [Date & Time Left]/ [Date Returned], need to figure out between the two fields. Trying to identify when the rep returned the call and the number of business hours (6:00am - 4:30pm) it takes to return a message in Ms Access 2010.
The only issue is the calculation has to be done by time and so I have to calculate what time they left the message(so the difference between [Date & Time Left] and [Date Returned) [Date & Time Left] and when the rep returned the message which is suppose to be [Date Returned] but the problem with this field is the data entry is in date format (10/9/2014, 00/00/0000) of Date and not Date and Time like the [Date & Time Left] field, so I don't know what to do now. Not sure what to do now not a database that create or have allot of control over.
ID Up Time Down Time John 18:00 15:00 Kelvin 08:00 08:05 Melisa 23:00 02:00
This is the Table , i need the Query result show IF [Up Time]-[Down Time] is >=3 hrs
Like Below :
ID Up Time Down Time John 18:00 15:00 Melisa 23:00 02:00
IDUp TimeDown TimeJohn18:0015:00Melisa23:0002:00
I tried DateDiff("h",[Up Time],[Down Time]) in Field but POP out with error "Syntax error (comma) in query expression 'Table1.[DateDiff("h",[Up Time],[Down Time])]' " ...
I am calculating number of weeks between start and finish date. Some of the users have questioned the validity of calculation as they are not too sure if this is being calculated as Monday to Friday week or does it work by calculating 7 days. If the latter is true, then I should see a decimal value. I am using date diff formula.
I have looked all over for a way to calculate the difference between water meeter readings. My brain may be Friday slow, but all I can find is for calculating differences in dates. My water table has 3 fields: ReadDate, Reading, Calc1
ReadDate is the date the water reading occurred Reading is the meter reading Calc1 is calculated (when I find out how!) by subtracting the current reading from the previous day's reading.
I would like to add the write script in my form so when the readings are entered, the calculation auto populates the field for the user.
I am struggling with calculate difference between two query table values, I first created a make a table query(current meter reading) which contains one column called "meter read" , and I created a second make a table query(previous meter reading) which also contains "meter read" column, I linked those two make table queries to calculate the value difference between two date, how can I create a form to calculate diff between any two date?
I have an input form for production. I need to be able to have a unbound box look at the start time and end time. I need it to determine if the times fall during a break or lunch. My fields in my table are - ID, Start Time, End Time. Example of what I need the control source formula to do is this. If I start at 6:00 AM and work till 10:00.AM and my break is Start Time 9:00 AM... End Time 9:10 AM. I need it to then show 10 in the box as result of the break. I have this so far as in my formula builder.
IIF([Start Time]<9:00 AM AND [End Time]<9:10 AM, 10, 0)
When I press enter it says I have an syntax error and I have checked to make sure the fields are correct. Also how would I go about adding on to this formula to add a lunch break on to it.
I want to be able to display the result of a difference between Date/Time values in "HH.MM" format (i.e. yes I want the result in decimals and I don't want Access to round up or down just because it feels like doing it!). I have used the following:
Example 1:
Dim ActualManHours as Long ActualManHours = (txtEndTime.Value - txtStartTime.Value) * 86400 txtActualManHours.Value = ActualManHours
Example 2:
Dim ActualManHours as Long ActualManHours = DateDiff("h",txtStartTime.Value, txtEndTime.Value) & "." & Format(DateDiff("n",txtStartTime.value,txtEndTime. value) Mod 60, "00")
Example 3:
Dim StartTime as Double Dim EndTime as Double Dim ActualManHours as Long StartTime = CDbl(txtStartTime.Value) EndTime = CDbl(txtEndTime.Value) ActualManHours = EndTime - StartTime txtActualManHours.Value = ActualManHours
How do I calculate the values between two columns and populate a third column with those new values? I have an ''Actual Cost'' column and ''Budget Cost'' column and I would like to create a third column ''Margin.''
Is this something that needs to be done with a query or can it be handeled in the design view of a table? I'm starting to learn that Access works nothing like Excel.
Thank you in advance for any help. I scanned some of the threads in this forum, but many were beyond my comprehension. Any walk-through of this procedure would be much appreciated.
so i created a system to have events booked, and i am trying to check time availability of the event room available, but i dont know what wrong. it either my query or vba code. i have attached the attachment,
I'm new to building databases and I wouldn't think that this is difficult but it has stumped me and everyone that I have approached to elegantly perform this calculation.
Essentially I have a table of meters (the best real world example is the watermeter that your community uses to measure how much water you use each month.) Each meter in the table has a "child table" of the date/time that the meter was read and the reading on the meter (stored as a number). I need to calculate the difference between the last two readings in the child table for each meter(essentially how much water each meter has used since the last reading.)
I have been able to sum, average, etc. the meter readings, but I can't seem to find a way to get a difference.
How to implement a functionality into my access database. The related tables required for this functionality can be found as an attachment.
When the information has been entered into the tables by the user, I would like to calculate the difference between the information for each part within the same table. The main columns for which the difference have to be calculated are: [RefObsInfo->RefSources] and [AltObsInfo->StatusAltSource] and [GenObsInfo->GenSources]. The values for these fields are restricted to 3 or 4 different ones. I also would like to show if the GenEstAvailable columns are changed, but that's for later.
In order to calculate this difference a query has to select for each Part the information related to the last date AND a date which has been specified by the user (with the previous date as max). For this the user is asked to give a from date, which she/he can select from a combobox. This combobox has a standard selected value which is the MaxDate-1, i.e. the previous date. The difference should be calculated from the previous date to the last date. I would prefer to give each (predefined) difference a specific action to show the user the difference in a matter of seconds.
Basically, I am trying to calculate a integer number difference from two dates (TAT = Due-Date - Result_Date). The number is calculated and excludes weekends and ideally holidays (for that I have a tblHoliday but not sure how to use it). The function below seems to calculate a number but doesn't exclude weekends.
For example, if Due_Date is 9/26/2014 and Result_Date is 9/30/2014, then TAT is calculated to be 5 (should be 2).Since 9/26/2014 is a Friday only Friday and Monday are used in the calculation.
Code:
Option Compare Database Public Function WorkingDays(StartDate As Date, EndDate As Date) As Long Dim intCount As Long intCount = 0
How can I calculate the difference between two dates but I only want to count the work days? So if was today and I wanted to go until 6/15/2015 the difference would be 5 and not 7 because I do not want to count Saturday or Sunday. Is there a special %datediff function where I would only count work days?
I am trying to calculate the difference in dates between two fields. How do I find the difference in days between field one which contains the date 04/12/2011 and field two which contains the date 04/12/2013? I have tried to use the datediff function, but it keeps telling me it doesn't recognize the field name, even though the spellings correct.
