Getting Only The Last Date Per Record In A Primary Table

Jul 27, 2007

I need to build the following query:

I have 2 tables:

tblBusiness
tblInspection

tblShops have an ID, an adress, bussines name, owner name, etc
every Shop can be inspected many times. A inspection can be futile if the store is closed. If the store is open, the inspection is made, and as result with can have “with irregularities” “without irregularities”. Two or more inspections can be made the same day (if the n – 1 time the store was close).

So, here is the basic select:

SELECT tblBusiness.idBusiness, tblBusiness.BussinessName, tblInspection.InspectionDate, tblnspeccion.InspeccionTime, tblInspection.Open, tblInspection.Irregularity
FROM tblBusiness INNER JOIN tblInspection ON tblBusiness.idBusiness = tblInspection.idBusiness;

What I need is to get the LAST inspection where the bussines was open and with irregularies. One inspection per Business, but of all business. Ah, and if there ir a newer inspection but the business was close, it doesn´t count.

I tried “Group by MAX” with InspectionDate, but it just didn´t work. For example, it showed me two inspection of the same business, not “the last” of that bussiness (it was easy to filter the Open field and the Irregularity field).

I suspect that what I need to solve this is to use two or more SQL stament, two in one., something like that. But I´m in a hurry and I just can seem to get it right.

I hope you can help me with this. Thanks for reading anyway.

P.S.: the fact that there can be more than one inspection per day can be a bitch =(

but there is a "InspectionTime" that can save that". Mmm the problem is that one inspection can be made 1 july around 20:00, but the seccond on 2 july 01:00. But we store the two inspections in 1 july... so... that mens problem.

But that issue is not so important as the previous problem up there (well, in order to solve the seccond I need to solve the firts...)

PS2: I don´t know about the title...

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