How To Count Column A, If Criteria B Is Met?

Nov 20, 2006

Hello,

I am new to Access and was trying to figure out a simple Count. What I want to do is Count Column A if Column B has "".

I have looked around and am sure this is easy, can anyone point me in the right direction. I use this for another item but dont know what to add to make it work like I would want.

=Count(IIf([CLASSIFICATION]="Preliminary",0))

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Hey, I know this is probably a simple thing to do, but I couldn't find it anywhere on the web so hopefully someone here can help.

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FROM [test Usage]
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Code:

For Each Order In q
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FName
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I have attached a file with Table, Current Result & Desired Result.

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In the past, i created a count query for each category like A to G and then finally link it. So i want to simplify it and i used below SQL but its giving me the result but not in a good format

SQL used

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FROM Tbl_DateMonth LEFT JOIN ([MasterTable_ EngineeringChanges] LEFT JOIN [MHEX Processors Update] ON
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[Code] .....

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May 11, 2005

In forms, I frequenty use the following expression to get the results needed from a field's column:
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What am I doing something wrong?

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I have attempted to use:

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Feb 2, 2005

This is what i whant to do. (I have read other threds but cant seem to help-myself!)!
Please Help!

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example: Record1 = (1)
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Record3 = (1)
Record4 = (1)
Record5 = (7)

so a table will count and display the times (1) was answered

Times1Wasanswered = 3
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was hopint that could place in Design Mode a Query that counts records , but only those with the criteria = to the number I chose !

How can I do this - ! ???

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Friends,

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Example.

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See attachment

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12315 8/1/2013
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Attached accdb sample also.

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I have a report that I am trying to complete based on several queries. I am trying to count the number of records based on certain criteria and using the following DCount.

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I have this

Code:
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I have a list of employees and sort criteria. for example

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1234......F
1234......T
1234......F
1235......F
1236......T
1236......F
1236......F
1236......F
1236......T
1236......T
1237......F

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1237...........0

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