Modules & VBA :: Opening File Based On Directory Location
Feb 15, 2015
When creating an incoming inspection database, I want to set it up so when I am in a form to add data, I want to have a command button where I can pull up the associated CAD drawing based on part number and drawing number. I would like to enter the directory location into a table so I could change it if I need to.
I want to create a button on my form that when pressed will scan my multi page document (ADF) from my Epson WF-3540 and save it as a specified file name and folder.
I have created a database that tracks the locations of all the faxes we receive in a day. We have a dedicated employee that enters them into the database as well as who they are assigned to and other pertinent information. At the end of the day, I monitor the network folders where the faxes are saved to change the status of the fax in the database to done, still needs processing, or awaiting approval. Is there any way that I could set up some VBA that would automatically update the status column for the record based on the location of the file? The file name is recorded in the database so then if it sees that that file is in the end folder it could automatically update the status to finished.
The response I got on another forum is as follows:
-The impression I'm getting is that you've got a database of information over here. -And it lists the file name, but not location. -And then you have a physical folder structure with the fax files in it. -And there are folders for done, awaiting approval, or processing. -So what you're looking for is something to read those folders and update the status column based on which folder it is in? -So at the start of the day we have:
New -Fax1.tiff -Fax2.tiff -Fax3.tiff -Fax4.tiff Finished - In progress -
And at the end of the day the folders look like this: New -Fax1.tiff Finished -Fax3.tiff -Fax4.tiff In progress -Fax2.tiff
And you want your code to browse those folders, and update the status of each filename based on it's folder?If the filenames are unique, you can just use VBA to open the folder, create an array of the files and then set the status. Create two separate functions, one for in progress, one for completed and call them one after the other. There'd be no need to check the current status, but you could store the wrong status if a file is duplicated, or a filename repeated.
i had a database that allowed me from a form to store a file location for a record on a form, so i any time i could access the record, and then open the file, usually a pdf, it wasnt stored as a hyperlink, but as long text
i made the mistake of not copying the files for safe keeping when i got a permanent position..i am now back self employed, i need to recreate the database.
Is it possible in access, to create a button that will copy a file to a new directory? Specifically, the data field in question is an access hyperlink that we can click on to open a PDF drawing of a part. I just want to copy the file the hyperlink points to, into a new directory.
I have been searching all over on how to create an import button on a form in access 2010 where I can set which table it should copy the data into but the user could locate the import file.
NOTE: the reason being I have locked all the ribbons...
If necessary I could make a specific import template file which would have all the headings locked...
I'm currently working on a database to track and inventory documents in my organization similar to a library catalog, but with a digital archive as well. I'll need the ability to "attach" documents to records in the main inventory (though using links instead of storing it in the db) and have the documents live in a centrally accessible location on our shared server.
I will need to have this function work through a few different tables and in a few different iterations, but I'm trying to work on the simplest part first, which is attaching a thumbnail/preview of a given document to the record for that document.
I've got some VBA working well which opens the file picker and copies the file to a directory relative to the DB. It also creates a folder with each employee's ID number if it doesn't exist already (which it gets from the Windows log in) and adds "Copied_" to the front of the file.
Now I'm trying to get the VBA code to interact with the record. Presumably I need to tell the form button I'm using to launch the VBA code to pass the primary key of the record being displayed to VBA. Then, at the end of the VBA code I need to take that value and find the record again from VBA so I can update the MediaThumbnailLink in the original record.
Does this order of operations make sense? If so, how should I go about passing these values back and forth and writing the new link value?
Here's the VBA I'm using so far...
Code: Option Compare Database Public Sub GoCopyThumbnail() Dim fDialog As FileDialog Set fd = Application.FileDialog(msoFileDialogFilePicker) Dim varFile As Variant Dim LUser As String
Question: Is it possible, using VBA, to determine the actual Excel file type without opening the file?
I receive data files from other departments. Seems like every time someone changes their download structure, I end up with file types that do not match the download extension (example: xlm file with a xls extension). The files can't even be opened because of this. I think I can fix it if I could figure out how to determine what the file type really is.
In the access form I want to add a button with a special functionality.
After clicking "Select file" button special window should be open (or something else). It should give user a possibility of files locating (doc, pdf, rtf, txt ...).
After selecting the file and confirm the choice in the table "File_location" in database path to the file should be saved .
I need some simple code that will copy an Excel file or a table in Access to a specific location on an FTP server. I would think this would be a very simple task, but I have yet to find any sample code that is *simple*. I have seen lots of code that requires downloading this dll or that mda, but the examples don't work. There must be something built into MS Access 2010 that will allow a file to be uploaded to an FTP site.
All the variables are known:
The FTP location (it never changes) The FTP Username and Password (they never change) The destination folder on the FTP site (it never changes) The File type (it never changes) The File name (available from the form in Access from which this will be executed)
I can either produce an output file, then copy it to the FTP site, or I can export the table directly to the FTP site with the file name for that day.
This seems to be a very simple task with no simple solution. Currently I am using an FTP app to get the file to the FTP site, but I would like to automate this. The process that creates the output file is already automated, so I would just like to add this to the existing code as its own module.
just made all that above up and none of it is a real function/command in VBA, but is just the kind of thing I'm looking for.
I would think that since I can download and XML file from an FTP site that it should be child's play to upload a simple file to an FTP site, but I can't figure it out.
I want to open files from a networklocation from VBA, only normal users don't have access to that location (and should preferably not get it).
I instead of using shell("explorer.exe filepath") to open files using windows standard app for the file, which needs userpermissions to the path the file is located, for the currently logged in user.
I'm trying to use CPAU in combination with Shell, because using CPAU you can pass a user/password that has permission to open a process
The only problem is that the filepaths have spaces in them and that is Always a bit of a tricky thing to tackle.
The last command start explorer, but doesn't open the file (just as the first line I posted, it opens Explorer, but not the file. Must be something with the way I pass the filename?)
I have been trying to get an image to open from its location.... but it keeps trying to open "C:C:example.bmp" instead of "C:example.bmp" does anyone know how to take out the first directory location tag automatically?
I am trying to program a button on my ms access form to open up an excel file.. So far the simplest code ive found online was from URL....
<code>
Private Sub Command57_Click() Dim xlTmp As Excel.Application Set xlTmp = New Excel.Application xlTmp.Workbooks.Open "C:Excel1.xls" xlTmp.Visible = True
[code]...
However the code doesn't work, any way to open a file from within access?
I have a macro in access that will create a folder and create a word doc in the folder with the name of the folder. I would like to add to the same folder an excel file. The excel file is in a folder and needs to be copied every time in a new folder when created. where to add the excel file from the below folder:
C:Excel CopyCombine_PDF.xls
this is the macro:
Code:
Private Sub Command22_Click() 'this will register the letter and create folder, word doc and open all Me.[DateRegistered] = Date Me.[PersonRegister] = Environ("Username") Me.Refresh
I would need removing the lines from an .xls file(stored in shared folder) and saving the same. I used the below code and not successful in removing and saving the file stored in the shared area..When I execute the code, Cursor hangs at this line
Set objWB = objXL.Workbooks.Open(filename)
Code:
Set objXL = CreateObject("Excel.Application") Set objWB = objXL.Workbooks.Open(filename) Set objWS = objWB.Worksheets("Sheet1") objWS.Rows("1:6").Delete
I have the following code, which works the way I want it to when I click the button the first time. However, if I close out the excel and click the button again, it errors at the line "ActiveWorkbook.Worksheets("Ref").UnProtect", with the message "Run-time error '91', Object variable or With block variable not set". I can not figure this out, why in the world does it work the first time, but not the second???
Private Sub cmdReport_Click() Dim path As String Dim XL As Object Dim oBook As Excel.Workbook Dim pic As Excel.Shape Set XL = CreateObject("Excel.Application")
Simple example is I have say 3 recordsets open (they are opened once as they are refered to many times) - they are open early in the form (in this example 3 price lists that are applicable for a customer) (if the syntax of the select is slightly wrong I'm just showing to 'prove' the concept).
Dim db As Database Dim rs1 As Recordset Dim rs2 As Recordset Dim rs3 As Recordset Set db = CurrentDb() Set rs1 = db.OpenRecordset("SELECT * FROM Prices WHERE (((Prices.ID)=1));") Set rs2 = db.OpenRecordset("SELECT * FROM Prices WHERE (((Prices.ID)=2));") Set rs3 = db.OpenRecordset("SELECT * FROM Prices WHERE (((Prices.ID)=3));")
What I want to do is have a central function that I can pass a list I wish to process/do something with aka. The 3 recordsets are the same except for the where criteria.
private sub GETPRICEFROMLIST(pricelist as long)
dim rs as recordset
set rs = Recordset("rs" & pricelist) .....
I put the above to show what I'm trying to do but of course that doesn't work There won't be any updates to these recordsets only reading of data.
Using Access 2007, can I return a value for CurrentProject.FileFormat WITHOUT opening the database?
I'm looking for a way to determine the file version of a given Access database without actually "opening" the database in Access (I don't want it to ever be visible at all or in any way).
So to open a database in Access 2007 "without opening it," I'm using:
Code: Dim db As DAO.Database Set db = DBEngine.Workspaces(0).OpenDatabase("C:Path-ToFile.accdb")
From here, there are at least two different "version" indicators that can be used, as in this example:
Now, if you run this code on an Access 2002/2003 .MDB file, you will get:
Code: 4.0 09.50
If you run this code on an Access 2007 .ACCDB file, you get:
Code: 12.0 09.50
Note two important factors:The db.Properties("Version") seems to be returning the JET version from what I can see in research. This is NOT what I'm after.
The db.Properties("AccessVersion") returns THE SAME VALUE for an '07 ACCDB as it does for an '02-'03 MDB, since Microsoft never updated it, apparently.
Now.... the one way that I have found that ACCURATELY describes the version of a given access database file is to use:
Code: Debug.Print CurrentProject.FileFormat
...as this will always return, for example, 2.0 for an Access 2.0 .MDB file; 10 for an Access 2002/03 .MDB file; and 12 for and Access 2007 .ACCDB file (and there are others; these are AcFileFormat bitmask constants as described in Access support).
BUT, this CurrentProject object doesn't seem to be available (so far as I can see) when using the "open without opening" method described above.
SO, is there any way to return the FileFormat value without opening the database visibly? (Merely basing it in the extension isn't right either.... that would be easy but not accurate as several formats use MDB.
I have some code in my database that will open a form based on the result of , I think, a union query.
Private Sub resultbox_DblClick(Cancel As Integer)
'Open report based on the ID from resultbox listbox
DoCmd.OpenReport "ResultsStan", acViewReport, , "[ID] = " & Me.resultbox, , acDialog 'End If End sub
What I need to do is open one of a number of reports. The report that needs to be opened depends on another value that is passed from the union query - DOCCAT
Being still a bit of a novice I tried...
'If "[DOCCAT]= " & Me.resultbox Like "Standards" Then DoCmd.OpenReport "ResultsStan", acViewReport, , "[ID] = " & Me.resultbox, , acDialog 'End If
I am currently developing a calendar and am trying to open a recordset based off of a SQL string. When I deleted the Where part of the SQL statement, the code ran fine. So I am pretty sure that the problem lies within the Where part of the code. I use this code to filter my query based on txtTaskTypeID but if the value is null then the query is suppose to return all values. I keep getting Run-time error"3061: Too few parameters. Expected 1".
hello good day. hope im inthe right place. can someone point out to me if there is a way to do a file upload using ms access 2003 and not just stor the file path...thanks
