Number Of Values Matching Criteria Across A Row

Dear all:

I can't seem to figure this one out on my own; I'm trying to create a query that counts the number of values in fields across a row that match certain criteria. For example, the data I'm querying looks like:


ID 01-1 01-2 02-1 02-2 03-1 03-2 04-1 04-2
1 85 76 68 72 67 63 74 73
2 32 34 70 65 67 80 68 70


and I need to find out, for example, how many numbers for each id are greater than or equal to 70 but less than 80. I've tried using DCount, but it gives me the number overall that match the criteria instead of the number per row (so I'm sure I'm doing it wrong). I've tried using a crosstab query, but I can't suss out how they actually work when you've got more than one column of data that you need to work with unless I put ID as column headers and the other fields as row headers... that would make my query about 1500 columns wide and 10 rows long, though, which just seems wrong... ?

In a slightly different approach, I've done another query on the data that makes it look like:


ID Number First Second
1 01 85 76
1 02 68 72
1 03 67 63
1 04 74 73
2 01 32 34
2 02 70 65
2 03 67 80
2 04 68 70


But again, I keep ending up with silly answers (like the count for the entire set of data, rather than just per ID). I'm *sure* I'm just not quite getting how DCount works... and it's possible I'm trying to use it for something for which it wasn't designed. Any alternative examples would be most helpful.

I'm not sure how to compress the data any further. I could, technically, get it down to two columns (ID and <number to query>), but the only way I can see of doing it is to create a temporary table for the first column and append the second column's data to it, which I'd have to do every time any of the numbers changed.

I would prefer to use the first approach, as that query is useful in other calculations and the second is a bit of a faff (though not too bad, just a union query). Anyway, I'm just stuck and instead of continually banging my head against the wall, I thought I'd ask you kind folk for help. :)

-Jen