I have a subform [ctrlLogDetail] on a parent form [incidentdetails] that is opened by the user when they click on a button on a navigation form. These forms are used for a variety of purposes. The problem I'm having is that the user needs to be able to select an incident number and go to the appropriate form (I accomplish this by using this code: DoCmd.OpenForm "IncidentDetails", acNormal, , "Activity_ID = " & Me.cboINum in the on click event of the button.) This works appropriately. The subform is also appropriately linked to the parent form.
I need an additional line of code to have the subform go to a new record when the form opens to an existing incident number. Since I use this form/subform when doing different tasks, having the Docmd.RunCommand acCmdRecordsGoToNew in the Form on open event isn't optimal.
I only want the LogDetail subform to open to a new record when the user wants to add an entry, but not when they need to edit a specific entry. What is the appropriate syntax to use either in the openargs event of the openform command or elsewhere in the procedure so that the gotonew function on the subform only occurs when this button is clicked? I'm having difficulty getting access to understand that I want the subform to open to a new record but not the parent form.
Problem: Visual Basic run-time error 7792: You can't open a subform when it is also open in Design view.
I have a subform with properties for SourceObject, LinkMasterFields, LinkChildFields changing according to objects and events in the master form.
The subform was bound to a query before which meant that the subform load event was happening as soon as the master form is loaded. I needed to restrict the subform loading until a certain point so I removed the SourceObject property for the masterform's subform. The subform on the master form is now Unbound.
(This is because I'm now running some code on the FormLoad event for the subform which needs to be restricted until the LinkMasterFields and LinkChild Fields properties have been assigned correctly otherwise it takes ages to load.)
Now I'm getting the above error. Obviously, i do not have the subform open anywhere in design view. No Visual Basic windows are open. I've closed the db, closed access, reopened it and clicked on nothing except the masterform. The error occurs when I raise the event in the master form which assigns the sourceobject property to the subform, i.e.
Me.sfmQryAllOV.SourceObject = "sfmQryAllOV"
Can anyone help me? I've googled this but finding no answers.
I currently have a button that opens a report. the report pulls from a query that has parameters set to "fromdate" and "todate". instead of using dates and parameters that pop up as blank text boxes, I would like to click the button, have a form pop up with a combo box to select all of the options available (currently 23 options) and then click a button to make a report that only displays the record (1-23) selected. I do not need any time constraints because as the databases get updated with more records, there would be more than 23 options to choose from.
I have a main form which has a subform control in it. when the main form is opened the sub form control contains a list of events in a sub form (a summary view), for the person selected in the main form.
I want to change the subform to a different one which shows the whole event when i click in a field on the subform, based on the event i clicked in. ( i can do it by opening a new form but not with a new subform)
I can make the form change using the following code:
I have made a form. By giving an ID up firstly this form of the concerning person appears. Now I want to make a link to a report on this form. The intention is then that only those data are shown in the report of the concerning person (therefore with the ID that is reflected in the form).
Now I can open the report by means of a button... but then to get the correct data I have now used a query with a parameter value (the ID) (the report has been based on these query). But the situation is now therefore that if you click on the button that you must introduce the parameter value firstly. Is there also a solution where this is no longer necessary??... therefore that you have to click only on the button and then the concerning data of the report are shown. Therefore by giving in or an other manner the ID with. ??
Hopefully it is understandable, (my english is not that good...)
Implementation is going fabu, but I had a request to add a button on the main form to open the HTML FAQ I wrote. I thought I would be able to quickly point the button to the file using the button creation wizard, but that doesn't seem to work so well. (not at all)
Did I miss something or is this something that needs to be coded with VBA (very little knowledge of VBA here... negligible even.)
Is it possible to have a cmdButton open a pre saved image from your hard drive. The images are saved with the same name as the Account Number. (ex: AcctNum -- TA123409 Image -- TA123409.bmp) I want the cmdButton to open the image filtered or based on the Account Number. If so, could someone show me a sample OnClick code. Thanks
Good morning All, I have a form with a command button to open a report ( based on a query ) for the currently displayed record. here is the code I have used:
Private Sub CS_notes_Click() On Error GoTo Err_CS_notes_Click Dim stDocName As String
I believe this came from this forum sometime. When the button is clicked I receive the error: "Syntax error (missing operator) in query expression '(TLAUnit = 26712B')'
TLAUnit is the report field, UnitSN is the form field. Any help with the error? Thanks Kevin
the wizard does not have a button to open tables...i have been using this code to open forms...what needs to be changed in order to make it open tables?
Private Sub Command5_Click() On Error GoTo Err_Command5_Click
Dim stDocName As String Dim stLinkCriteria As String
http://www.heathrowminicab.com/xxx.JPGI have a blank form.. with 2 controls..Textbox - name is 'text'Button - name is 'button'my user will type in something like this..pictures/db1/db1.jpgall i want is that when they press the button.. the url 'http://www.mysite.com/"is added to the data in the textbox and the url is opened.. this of course will allow my user to test whether the image they are referring to exists..can this be done.. if so what code do i need to add to my controls.
hello everyone, i have 2 tables have Relationships with each other and i have a form with a listbox and has the surnames from table1 in it i want a button to open the job information form on new record and i want it to have the client number in it all ready if i click on one of the surnames from the listbox tables names tbl Client Detials = have clients information tbl job information = has job information both have client number feild and have Relationship
form i want the button on is called frm client splash and the form i want it to open is frm job information its hard to tell u srry i hope someone can help me ________________ David
Hi all, I am new to microsoft access. I've got one question that can't solve. I am making database with several items. Under each item, there got different field lists to fill in. So I made several forms for each of them. In main form, I put one combo box to choose the item and one common button. So how can I write the code to open the several different forms,one at a time, by clicking one button according to the value that is chosen from combo box?? thank in advance.
I am using the following event code to open a database from another. Everything works fine but, I would like add a mxgbox letting the user know the database does not exists and to contact me for assistance.
Private Sub cmdOpenTime_Click() Dim accapp As Access.Application Set accapp = New Access.Application accapp.OpenCurrentDatabase ("c:PILOT_ApplicationTIME.Accdb") accapp.Visible = True End Sub
I'm having a little trouble getting this accomplished. I can instruct access to print the report, however I just want to be able to view the report after I select a button. I will attach a picture so you can see what I have thus far. I do have an older version of this and it works flawlessly and as far as I can tell everything is a carbon copy of the working version.
I have a form that uses a query to filter out records to show basic info of records (each one has a unique ID) only pertaining to today that are listed one under the other using a whole row. What I'm looking for is a way to design a button for these filtered records within that row that when clicked, will open up a new form that I've already designed for just that ID.
I have created A command button (OK) on the form but can't figure out the code. My Scenario is:
1) I have 2 cascading combo boxes 2) I have a text field as attachment
What I want is to select the value from second combo box then I want to click command button to view the attachments instead of double clicking the attachment and also I wanna ask is there any way to modify the display view of attachments in access a part from paperclip and image icon.
Does anyone know the code for opening a specific notepad file from a button? I know there's a default button but it only opens a blank notepad page. I need to open some written instructions from a button you see.
I have based a form on a parameter query, so that when the user is prompted to enter a 'Hobby' to search on, the relevant records will be displayed on the form.
Now, I have created a command button designed to open a template letter in MS Word for a particular hobby. The problem is, I need the command to open certain file depending upon the value input in the parameter box intially. How would I go about doing this?
i have created a form that has data in a field as a referance, i want to use that ref to open a page or PDF file to that referance ,
The idea is that the form is the data input for hard copy documents, i will scan the documents and store them on a hard drive i then want to open the documents as word, or PDF files from the form to the ref of the field in that form
Hello everybody, it's been a while since i wrote on the forums and yet again I am in the need to ask for the help of this wonderful community. I have a form on which is a button that I want when pressed to open a Windows Explorer window displaying the contents of a directory. The exact way that I want this thing to work is like this : The user is browsing a form of lets say client details and on the form lies the button that when pressed will take the client's name and apply it to the path in order to open that Windows Explorer window and create a path like C:program filesclient name and display the contents of that window. I would like if possible someone who can point me as to how I can construct this button to work cause I cant see to get it done. Many thanks for your time :)
I have set up a database that houses file locations. The form that I have made shows a job # and the files that correlate with it. I would like to set up a command button that will read the file name and open it in Excell. If any one know how to do this I would greatly appreciate the help.