Open Form Not Adding Record And Use An Add Button On Form
Aug 2, 2006
I have a database with three tables
table 1 (form1)
reference (PK) auto number
table 2 (form2)
Reference (fK)
workbook reference (PK) auto number
Table 3 (sub form within in form2)
Reference (FK)
workbook reference (fK)
data Reference (pk) auto number
Each table is a form that is linked via the keys. On form 1 i have a button that is to open the form2, which it does but every time i open the form a new record is added. Why and how do i prevent this.
Then what i want to do is add a button for a new form on table 2 form but use the same reference as the record as presently displayed. How do i add new record using the same Reference but new workbook Reference?
Thanks is advance
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Jul 30, 2014
I have a continuous form in which I put a command button for each record called "detail". I would like to click on the "detail" button and make it open another form containing all (and only) the info on this record.
At first I refused to use an "id" to link both forms, but finally I added the "id" in the table... however still does not work.
continuous form: "04 - GASTOS_BUSQUEDA"
id field on continuous form: "Gastid"
pop-up (details) form: "GASTOS_EDITAR"
id on pop-up (details) form: "editar_id"
This is what I have tried on the "click" properties of the "details" button field (called "btn_editgs"):
1)
DoCmd.OpenForm "GASTOS_EDITAR", acNormal, , "[editar_id] = " & Me.Gastid
2)
DoCmd.OpenForm "GASTOS_EDITAR", , , "[editar_id]=" & Me.Gastid
3)
stLinkCriteria = "[editar_id]=" & Me![Gastid]
DoCmd.OpenForm "GASTOS_EDITAR", , , stLinkCriteria
4)
Private Sub btn_editgs_Click()
On Error GoTo btn_editgs_Click_Err
Dim strWhere As String
strWhere = "[editar_id] = " & Me.Gastid
DoCmd.OpenForm "GASTOS_EDITAR", , , strWhere
btn_editgs_Click_Exit:
Exit Sub
btn_editgs_Click_Err:
MsgBox Error$
Resume btn_editgs_Click_Exit
End Sub
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Oct 2, 2013
Is it possible to open a form to add a child record related to the highlighted record in the subform?
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Aug 8, 2006
hello everyone,
i have 2 tables have Relationships with each other and i have a form with a listbox and has the surnames from table1 in it
i want a button to open the job information form on new record and i want it to have the client number in it all ready if i click on one of the surnames from the listbox
tables names
tbl Client Detials = have clients information
tbl job information = has job information
both have client number feild and have Relationship
form i want the button on is called frm client splash and the form i want it
to open is frm job information
its hard to tell u srry i hope someone can help me
________________
David
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Aug 8, 2013
I have a form called [Add or Edit Tag Numbers]. The primary key for the control source of this form is [TagNumber]. I have created a button on this form that opens a second form, [Add or Edit Calibrations], to a new record and carries the [TagNumber] through to the corresponding field on the [Add or Edit Calibrations] form.
Almost everything works. I click the button and the second form is opened to a new record, with the tag number on the first form carried through to the seond form. The only issue is that when I go back to the first form and try to close it, I get an error saying that I can't save the record. It is error 2169. This is especially strange because even if I exit after seeing this record, additions in both forms are saved. This is the code for the button, called [NewCalibration]
Private Sub cmdNewCalibration_Click()
DoCmd.Save acForm, "Add or Edit Tag Numbers"
DoCmd.OpenForm "Add or Edit Calibrations", acNormal
DoCmd.GoToRecord acDataForm, "Add or Edit Calibrations", acNewRec
Forms![Add or Edit Calibrations]![TagNumber] = [Forms]![Add or Edit Tag Numbers]![TagNumber]
End Sub
How I can avoid getting this message? I would prefer to use a button over a subform.
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May 7, 2014
What I need to do is press a button on a form. When the button is pressed, I want to create a new record in a table not already open and populate some fields with data from the form I am looking at. Then call up a new form with the record I just created on it.
Basically it is a work-order entry issue, the user scrolls through to find the correct piece of equipment when they do they click on "Create work-order" a work order is created and populated and the user can then fine tune the new work-order as required.
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Oct 23, 2013
I have a main form created from a query (FrmQuerySearchResults) which has a sub-form within, (FrmPresentationsTabular) which I am using to show each presentation to our service made by any given client.
For ease of use, I've removed the navigation buttons and want to replace them with my own command buttons. For appearance, I've changed the properties of the sub-form so that 'allow additions' is set to No. This is so that the list of presentations users see does not show the bottom row as a new record.
I'm trying (using macros) to add a button in the footer of the subform that opens a new form (FrmNewPresentation) which opens to a blank record allowing the user to click button, enter info, hit close.
I'm having all sorts of trouble getting this button to do as its told! So far, I have a macro that has 2 steps, first it opens FrmNewPresentation, then it has action GoToRecord, with record set to New, object type set to Table, object name set to Presentations (the name of my table populating this sub-form).
I realise the problem may be the allow additions property being set to No, so I believe I need to add parts to this Macro that goes to that property and changes it on opening the input form - I keep getting a message saying "The object 'Presentations' isn't open.
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May 1, 2012
I have a parent form showing some of the contents of a single record in a parent table. This form contains a button that opens a specific subform (using an IF statement based on the contents of another field in the parent table/form. There are actually any of 8 child forms/tables that could be selected and the related record is in only one of them. The relation between the tables is based on the PK of the parent table and the related FK in the child table. and the data is correct in all tables.
My problem is that when I run this button on the parent form/table it returns the appropriate form/table, but displays the first record rather than the related record. In the past (using this same process) I have been successful in getting to the right record by fiddling with the where statement (sometimes putting in a equal sign or taking it out fixes the problem). However, no matter what I do to the Where statement nothing works. I have not yet placed the final else condition for where the form selection field (VMValIdentType] is empty yet as there is no point at this time.
Here are the button macro contents:
If [VMValIdentType] = "Software"
OpenForm
Form Name: tmpVMValSW
View: Form
Filter Name:
[code]...
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Sep 11, 2013
I have a button on a FORM to print the current record with the following code:
DoCmd.RunCommand acCmdSelectRecord
DoCmd.PrintOut acSelection
But what I need is that before printing, open the preview to set the margins and page size ... or at least to pre-configure so that when you press the button, and comes preformatted.
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Mar 26, 2013
Basically I have a Customer Form, which I have a New party button on it,this button opens up the party form to a new party, what I would like it to do is open up a new party but make the new party for the customer I had selected in the previous form.I have tried the GoTo macro's but cannot seem to get it to work.
I am thinking on clicking the button it will need to get the Customer ID, and then open the party form, create new party, and paste in the Customer ID, which then updates the Name - Date - Address - Company Fields.
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Apr 27, 2005
I currently have two forms: frmE_SAFind and frmE_SAOrder
frmE_SAFind shows results from a query including fields [txtIDPO] and [dtmDate]
Example:
IDPO Date
btnOpnFrm 6543 2/1/05
btnOpnFrm 5681 1/1/05
frmE_SAOrder shows order details including [txtIDPO] and [dtmDate]
I have a open form command button set up on [frmE_SAFind] that opens [frmE_SAOrder]. Is it possible for me to modify its properties so that when the open form command button is clicked, the order details in [frmE_SAOrder] will represent the order that the user is selecting via the btnOpnFrm command?
Example: If I click btnOpnFrm for 6543, [frmE_SAOrder] will show me PO 6543 details.
Hopefully I made myself clear enough to understand. Thanks for your help!
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Aug 28, 2013
I tried Link model "bank_pay" with the main_form << to add details of information >> by "pay_num" in main_form and "num" in "bank_pay" by filter >>
Code:
Private Sub pay_type_AfterUpdate()
Select Case pay_type
Case Is = "1"
DoCmd.OpenForm "bank_pay", acNormal, "", """[forms]![main_many_1]![main_many_sub]![pay_num]="" & [num]", , acNormal
End Select
End Sub
no result :
file in attachments >>
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Jan 27, 2014
I am trying to create a proposal log for my company to make things easier to track. I have made a multiple items form to list the proposals. I want to be able to double click the record to open up another form (that i have already created) that shows the information from the proposal table and the proposal details table. So.....
I want to double click the field named "Proposal Name" and have it open up to form i have called "proposals details form".
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Apr 2, 2014
I have a main form[frmResearchNotes] with combo box controls that filters a query populating [subfrmNotelist] containing several records from the filtered query. From there, I double click on a field within one of the remaining records, [CompanyName] for example, and it opens the new form[frmNoteDetail]. The problem is that second form is not displaying that selected record. The second form's record source has been set to the same query so when it loads, it displays the same info but it's displaying the 1st record out of the entire filtered list, not the record I clicked on in that list.
I figured I could use the strWhere function to copy the record I selected in the event procedure and then open the new form with those details. Not sure how to actually do this with VBA or if it's even the correct approach.
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Apr 17, 2014
I have three objects a Main_Table , ClientDataForm and a MapForm all three share a common ClientID number
From that Main_Table I have created a ClientDataForm form which I enter all Data
From ClientDataForm I wish to create a button on it which runs a Macro that Saves ClientDataForm Record and then populates another form named MapForm with whatever record is currently open in Form One whether a newly created one or previous record.
How would I write this code for that button? Also why I would write it that way?
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Feb 11, 2015
I would like to add a button to a form that will print the form with the current record in it. Also, to add a level of difficulty, there are 8 subforms attached to the form. As I already have the form developed, I don't want to reinvent the wheel and go off and create a report with 8 subreports. Is this possible? If so, Can we force all the data on the form to one page?
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Apr 18, 2006
Hi people,
I have made a form. By giving an ID up firstly this form of the concerning person appears. Now I want to make a link to a report on this form. The intention is then that only those data are shown in the report of the concerning person (therefore with the ID that is reflected in the form).
Now I can open the report by means of a button... but then to get the correct data I have now used a query with a parameter value (the ID) (the report has been based on these query). But the situation is now therefore that if you click on the button that you must introduce the parameter value firstly. Is there also a solution where this is no longer necessary??... therefore that you have to click only on the button and then the concerning data of the report are shown. Therefore by giving in or an other manner the ID with. ??
Hopefully it is understandable, (my english is not that good...)
thanks!
Ankie
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Feb 8, 2005
Good morning All,
I have a form with a command button to open a report ( based on a query ) for the currently displayed record. here is the code I have used:
Private Sub CS_notes_Click()
On Error GoTo Err_CS_notes_Click
Dim stDocName As String
stDocName = "InternalSNwithRMAprodMASData"
DoCmd.OpenReport stDocName, acPreview, , "TLAUnit = " & Me.UnitSN & "'"
Exit_CS_notes_Click:
Exit Sub
Err_CS_notes_Click:
MsgBox Err.Description
Resume Exit_CS_notes_Click
End Sub
I believe this came from this forum sometime. When the button is clicked I receive the error:
"Syntax error (missing operator) in query expression '(TLAUnit = 26712B')'
TLAUnit is the report field, UnitSN is the form field.
Any help with the error?
Thanks
Kevin
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Apr 7, 2008
Dear All:
Does anyone know how to use a command button to open a Pdf form in access?
This Pdf form is on the "c" drive called "portfolio".
Thanking in advance,
Dion
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Oct 11, 2006
I have a form with a drop down list that is coming from a query (City Query)
I have a command button to open a form for data entry to the City table -
When I open the form for city add a record - close the form.
I then go to the drop down list (city query) to select the record that was just added to the city table and the record is not in the query.
What do I need to do for the newly added record to show in the query drop down?
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Mar 20, 2013
I have a form that uses a query to filter out records to show basic info of records (each one has a unique ID) only pertaining to today that are listed one under the other using a whole row. What I'm looking for is a way to design a button for these filtered records within that row that when clicked, will open up a new form that I've already designed for just that ID.
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Nov 7, 2006
I have code for a button click event. Essentially I have a main table form that I use to enter customer data and info. I also have a button that I use to add that customer to a separate table that I use for special Customers. My code copies all the data I need copied to my other table, so I wont waste space here typing my code that actually copies the data to the new table. What I will list are the two commands I am using after that code, to close the current form (the one with the button) and open the form for entering special customer information (the form to edit data on my other table). It works flawlessly, but when it opens the other form, it opens to the first record. I want to know how to make it open to the record which I was viewing when I clicked the button to copy the data.
DoCmd.OpenForm "Special Customer Data Entry", , , Number = Me.Number
DoCmd.Close acForm, "Customer Data"
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Nov 4, 2014
i am trying to add an import command button to a form so that personnel not familiar with Access can simply push the button and then select the file to import. I want it to import information to a specific table by replacing all records in the current table with the import. I am not the best at coding, but I can understand enough to figure out what I may need to do.
I will be exporting a table to excel from the database. Multiple people will have this database and often times will not be able to access a shared database, so I need to export the table and then set up a way for them to import the excel document into their database by deleting the information in the old one and then updating to the new one.
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Jun 25, 2013
Is there a macro that I can create so when a button on a form is clicked it would add a timestamp (or least the current day's date) to a date field?
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Mar 12, 2005
I have based a form on a parameter query, so that when the user is prompted to enter a 'Hobby' to search on, the relevant records will be displayed on the form.
Now, I have created a command button designed to open a template letter in MS Word for a particular hobby. The problem is, I need the command to open certain file depending upon the value input in the parameter box intially. How would I go about doing this?
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Oct 2, 2004
Hi
I'm not sure if this is a dumb question or not but is it possible for me to have a button on a form that will open the Query Builder?
I have a form that has 3 buttons on it - 1 to access records, 1 to access reports and another which I would like to open the Query Builder when clicked. The database will be used by beginners so I've hidden the design view button and also the database window which appears at startup. All that appears when I open my database is the 3-button form which is what I want.
I thought maybe I could save a blank query and then create a macro to open that whenever the button was clicked and stipulate in the macro to change the view to design view but that didn't work.
Thanks to any help or advice anyone can give and sorry if it turns out to be a really stupid simple solution I've missed (I'm good at that!)
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