Opening One Form From Another Using Current Record

Mar 25, 2005

I would like to create the following functionality on a form in my database:

When the form is open, and a record is displayed on the screen, I want to add a button that will open up a second form displaying information related to that record.

To be specific, I have a form called "Contracts". Each contract record contains a customer name in the field "Customers." I want to create a button labeled "Customer Details" that will open a new form, "ViewCustomers" displaying the record associated with the value entered in the "Customers" field for the current (displayed) record only.

I have been trying to use a hyperlink to a macro that uses "OpenForm," form name "ViewCustomers," but I don't know how to filter it down to just the current record.

I hope any of this makes sense. Any insight would be really helpful.

Thanks! -Matt

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Opening Popup Form With Current Subform Record

Sep 7, 2005

Hello,

I am trying to run a macro on doubleclick in a subform (dataview) that will open the same record in a popup form (tabular).

I've enter in the macro Where Condition the following statement to only show the record I doubleclicked on in the popup. The only problem is it's asking me for a parameter value for the LogID. Its apparently not picking up the LogID I doubleclicked on. Is there any way I can fine-tune this WHere statement so that it knows the record LogID I clicked on. (The pop up form should show only the same record).

[LogID]=[Forms]![CommunicationLog Subform]![LogID]

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Mar 14, 2013

I am using Access 2010 - Version 14.0.61.29.5000 (32-bit)

I am building a custom Export Wizard to export data to Excel using the Report Wizard for the basic ideas.

All I am trying to do is have a [Back] button on a form to open another form and close the current form.

Private Sub cmdBack_Click()
DoCmd.OpenForm "frm_ExportWizardPage2", , , , , , Nz(Me.OpenArgs)
DoCmd.Close acForm, "frm_ExportWizardPage3"
End Sub

The new form is opening but then the current form is not closing. All forms are the same size, shape and positioned centrally although this should not make any difference.

Could this be anything to do with which form has the focus when I open the new form?

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Sep 16, 2011

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May 12, 2005

I have a table called tblFinishedGoods. There are 3 fields in the table:Serial Number, Model Number and Location.

I would like to have a form that will take input from my barcode reader and input the data for the 3 fields, if the serial number is not already in the table.(I have this already working).
But now I would like the same form to also check the table for any serial number that is scanned in...and if it is in the table already, have it bring up the model number and location for that record.

I'm thinking maybe there is something I can do with Serial Number afterupdate. Basically I'm looking for a way to not require the user to input anything via a mouse or keyboard.

If the 1 form could accept the 3 scans:Serial Number,Model Number and Location, and either 1)enter a new record if that serial number isnt in the table or 2)find that the serial number already exists and overwrite the model number and location with whatever the next 2 scans are.

Thanks

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Oct 28, 2005

Another Simple one From jeff.

Upon opening a form how do you get it to open to a new record rather hen the first record. Thanks All. Jeff

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Opening A New Form At A New Record

Dec 24, 2005

looking for help again!!

i am trying to switch between 2 forms using a command button..

i have 2 things i am trying to achieve

i want the form to open up at a new record as at the moment it seems to be opening at the last record created.. i have tried to use an open form function for new records but that doesnt seem to work.

secondly i have tried to use the code below to go to the next record then close the form and open a new one...

DoCmd.GoToRecord , , acNewRec
DoCmd.Close
DoCmd.OpenForm ("Welcome Page")

but so far all it does is open the new form it doesnt go on to the new record in the current one!!!


hope it makes sense

cheers

si

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Opening A New Form At A New Record

Dec 24, 2005

looking for help again!!

i am trying to switch between 2 forms using a command button..

i have 2 things i am trying to achieve

i want the form to open up at a new record as at the moment it seems to be opening at the last record created.. i have tried to use an open form function for new records but that doesnt seem to work.

secondly i have tried to use the code below to go to the next record then close the form and open a new one...

DoCmd.GoToRecord , , acNewRec
DoCmd.Close
DoCmd.OpenForm ("Welcome Page")

but so far all it does is open the new form it doesnt go on to the new record in the current one!!!


hope it makes sense

cheers

si

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Feb 2, 2006

I have a switchboard form that opens with the database. One of the buttons on it opens up a standard form for entering names and addresses.

I created the button with the button wizard, so the standard code:

Dim stDocName As String
Dim stLinkCriteria As String

stDocName = "Enter Details"
DoCmd.OpenForm stDocName, , , stLinkCriteria

However, this opens the form with record 1 loaded. There is a danger that someone might accidentally enter data over that, so I would like it to open up to a blank record (at the moment, users have to know to press the ">*" button). How can I do this?

Thanks in advance for any help... and for putting up with me of late! ;)

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May 4, 2007

hello,
I have form "QUOTE" (which has a check box "GenerateOrder") and form "WORK_ORDER". Once I click on "GenerateOrder", I want form "WORK_ORDER" to open, and I want to assign a value from a txtBox in form "QUOTE" to another txtBox in form "WORK_ORDER" creating in this way a new record on form "WORK_ORDER". I want to make clear that as soon as the value is passed or assigned to the txtBox in form "WORK_ORDER", a new record for this form should be created.

I tried this code:

Private Sub GenerateOrder_Click()
If (Me.GenerateOrder.Value = True) Then
DoCmd.OpenForm (WORK_ORDER)
[Forms]![WORK_ORDER]![QID] = [Forms]![QUOTE]![QID] 'assignment
End If
End Sub

but it doesn't work

Thank you very much

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Dec 23, 2005

Hi all

Im currently designing one of my first databases!

I've initiated a log on procedure, with a password.

A user enters their ID and password. Once the correct password is entered, the next form is then loaded up, to which they make some choices.

My problem is that I have lots of users, and I would like them to only access the page that is relevant to themse, and NOT be able to see anyone elses.

I gather there is a little bit of tweaking to go on the
docmd.openform...

line, and somehow incorporate the userID, but not entirely too sure what it is.

Apologies if this seems really easy!

All help appreciated - many thanks!

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Feb 16, 2006

Guys

I've searched the database and found similar problems but don't understand the replies (mainly DCount()).

I have a control form where a user can search the database by entering information. The form asks them to type some text that will appear in a description field, and match any records with the same text.

However, when the user types the text and clicks the button to open the form (which is linked to a query searching the description field), I want a message box to say no records found before opening the form. Mainly because when it doesn't find a matching record, the form opens with a new autonumber.

I either want a matching record to appear, or a dialog box saying no matching records found and the form not opening therefore not creating a number that is not used.

I tried in the command button entering if recordcount>0 then openform but it doesn't like the else statement or doing a if recordcount=0 underneath.

Any ideas?

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Oct 5, 2006

Hi,

I am opening a form, from another form, that is based on a table of 20000 records.

I am using the WHERE criteria to do this, code is included below. I need to provide database access to several users on a network (and only want to lock the record that the user has searched for), and was wondering if this mode of data access will lload and or lock all 20 000 records on the users sytem, or if it will just load and lock the specific record that has been opened using the WHERE condition to open the form...

Advice appreciated.

Regards

Mack

--------
CODE
--------
stDocName = "frmCONTACT"
stLinkCriteria = "[contactID]=" & Me![ContactID]

DoCmd.OpenForm stDocName, acNormal, , stLinkCriteria


End Sub

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Oct 31, 2006

HELP
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anyone know a simple way of doing this?

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I have a table with a schedule of tasks that are required weekly for the next year. Each record has Monday's date as the Scheduled_Date" for the task. From my main form, I have a command button to open a form linked to the table, so that amendments can be added to the table for each record (i.e. - If a task is complete/incomplete/progressing etc. the user marks it so.

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Jan 30, 2013

Self tought in Access07 but I'm trying to do the following:

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I am creating an order processing system and am using 2 tables

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OrderLines

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Jan 23, 2006

Hi,

on a form with several subforms i have ran into some trouble. I have the subforms use code to determine if a scrollbar is needed. As a recordselector I use a listbox on the main form.

When i close the mainform, it sometimes makes a popup box appear saying that there is no current record.

Sofar I have determined the following :

- Removing the code from the form, removes the error.

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I dont know if altering the code would have any success, cause it won't run anyway when I select the last record (with no related records).

I guess moving the code to another section would be better, but I've tried other options like 'on focus' etc, but could not find one that responded.

HELP PLZ :)


Private Sub Form_Current()
On Error GoTo Error

'kijken of verticale scrollbar nodig is
maxRegels = 14

Dim rstCount As DAO.Recordset
Set rstCount = Me.Recordset
If rstCount.RecordCount > maxRegels Then
Me.Form.ScrollBars = 2
Else
Me.Form.ScrollBars = 0
End If

Error:
If Err.Number <> "0" Then
Else
MsgBox Err.Number & " " & Err.Description
End If
Exit Sub

End Sub

ps. I've tried to catch err.Number = "3021" in the Error: section, but without success

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Oct 19, 2007

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I have a database that includes the following items related to my question:

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Code:
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Hi,

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Any thoughts/ideas would be much appreciated.

Thanks in advance
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