Problem With Rounding With DateDiff Function

Dec 11, 2005

Hi all

l'm running a query that has a field with the following formula;

[Anniv_date]=01/03/2006
[NextEBDay]=01/07/2006
[LastPayToDate]= In this case is 25/11/2005

To_Anniv_wks: IIf([Anniv_date]<[Forms]![DateEB]![NextEBDay],(DateDiff("w",[Forms]![DateEB]![LastPayToDate],[Anniv_date])),0)

The result returns 13. However l know the answer should be 14. Coz when l enter the information in excel l get 13.71.

l've tried using the round function with no luck. Any suggestions would be appreciated.

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Hello,
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hello all,
would really appreciate some extra help with this,
many thanks,, the story is as follows,,,,,,,

hello all,
i have a very simple databse with two table in it,, both table share a lot of common information, including a primary key called jobcard number,, i want to know if there is a simple query i can run that will find any differences in the start date fields that are found in both tables
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cheers
wardy
---------------------------------------------------------------------
Look at DateDiff function in the help for the time differences.

Thus for example in a new column in your query you can type:
DifferenceInDays: DateDiff("d",[Table 1 Name].[DateField Name], [Table 2 Name].[DateField Name])
--------------------------------------------------------------------
thank you DrSnuggles,
could you explain in idiot proof instructions?
do i enter the diffdate code in the criteria row of the select query? also, what do i need in the field and table rows? is it the table and filed i'm comparing the data against?
once again
many thanks

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