Queries :: DateDiff Everyday In Interval Day To Day
Feb 20, 2014Let's say I have a StartDate: 02/02/2014 10:00 and EndDate: 01/30/2014 15:00
Is it possible to have this result in a query?
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Queries :: Date Interval In Same Field
May 24, 2014I need to show the interval between dates. The dates are all held in the same field.
A/CDate
52601-Mar-14
52601-Feb-14
52601-Jan-14
Queries :: Breaking Out (Timestamp And Total Duration) Into 15 Minute Interval?
Dec 20, 2013I am trying to figure out how to take a table of timestamps and activity duration and break it into intervals, where it groups the duration into the time spent in each 15 minute interval. I have included a sample of the data and output. Is there any way to pull this in Access (or SQL)?
Raw Data
EmployeeActivityTimeStampStartTimeStampEndTotalDuration
Doe,JohnSomeActivity12/16/13 9:06:02 AM12/16/13 9:57:14 AM0:51:12
Smith,JaneOtherActivity12/16/13 9:22:15 AM12/16/13 10:06:55 AM0:44:40
Query to break out the total duration time in to the 15 minute interval it fell into
EmployeeActivityIntervalIntervalDuration
Doe,JohnSomeActivity12/16/13 9:00:00 AM0:08:58
Doe,JohnSomeActivity12/16/13 9:15:00 AM0:15:00
Doe,JohnSomeActivity12/16/13 9:30:00 AM0:15:00
Doe,JohnSomeActivity12/16/13 9:45:00 AM0:12:14
Smith,JaneOtherActivity12/16/13 9:15:00 AM0:07:45
Smith,JaneOtherActivity12/16/13 9:30:00 AM0:15:00
Smith,JaneOtherActivity12/16/13 9:45:00 AM0:15:00
Smith,JaneOtherActivity12/16/13 10:00:00 AM0:06:55
Queries :: Using Criteria For Formatted DateDiff Value
Aug 17, 2015I've successfully created a DateDiff calculation that is generated with a d:h:nn format. Now the question:
How can i select or identify specific values, such as <= 2 days using those outcomes generated by the expression? Is it possible?
Example: a value is generated as 3:14:35. I would want to indicate this more than two days by putting a "N" in a separate column.
How is this done?
Queries :: Datediff From Previous To Current Record
Oct 10, 2013I want to get the datediff of the last returned date from vacation and the current vacation start date. But how to get difference from the previous record's date to this current record's date. I want to show date difference in an unbound textbox. I have a contiuous form which shows all vacation list of employees. It shows how many times he went vacations and when he went and when he returned.
View 14 Replies View RelatedGeneral :: Auto Generate NO And Reset It Everyday
Jan 17, 2014I Want to automatic Generate the Numbers (Me.RID) when everytime loading the form.
EXAMPLE "14011701", "14011702", "14011703", "14011704"....
140117 mean "yymmdd" and the last 2 digit mean autorun Number.
But in the next day 140118 I want the last 2 digit auto Reset and start form 01 example "14011801", "14011802", "14011803", "14011804"....
Same also for day 140119, "14011901", "14011902", "14011903", "14011804"....
Below is my incomplete VB code, i dont know how to reset the last 2 digit every day.
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
Private Sub Form_Load()
Dim RNos As String
RNo = DLookup("[RNos]", "Temp_Table")
Me.RID.SetFocus
Me.RID = Format(Date, "yymmdd") & Format(Val(Right$(RNo, 2) + 1), "00")
DoCmd.SetWarnings False
DoCmd.RunSQL "update Temp set Temp_Table.RNos = '" & Me.RID & "'"
End Sub
>>>>>>>>>>>>>>>>>>>>>>>>>>>>
Forms :: Automatically Update Date Field Everyday
Jan 29, 2015I am using Access2007. Attached is my database.
I am attempting to track the duration of days since an initial date.
A individual has 3 business days to have their bloodwork/labs drawn after given instructions to do so. 'StartDate'= the initial date. 'LabsDate'= current date(would like it to automatically update to the current date everytime the database is open). BD ElapsedLabs= # of days that has elapsed between the initial day and todays date.
I am able to calculate the #days elapsed no problem, but I am having a problem with 'LabsDate' automatically updating to todays date. I am able to automatically place the current date in the first/ fresh entry, but it fails to update the next day.
I have tried placing the code Me.LabsDate= date() in the Before Update Form Property Sheet. Cannot get it to work.
Queries :: DateDiff Function - Calculate Difference In Dates Between Two Fields
Apr 22, 2013I am trying to calculate the difference in dates between two fields. How do I find the difference in days between field one which contains the date 04/12/2011 and field two which contains the date 04/12/2013? I have tried to use the datediff function, but it keeps telling me it doesn't recognize the field name, even though the spellings correct.
View 3 Replies View RelatedQueries :: DateDiff And Varchar Dates - Data Type Mismatch
Mar 17, 2015So I am working with a table that has 2 text fields called DestructionMonth and DestructionYear. The data in DestructionMonth is a 2 character month (01 through 12), and year is a 4 character field.
What I need to do is find all records where the destructiondate is within 60 days/2 months.
I have tried this many different ways and am still getting an error.
So this query works fine:
SELECT documentstable.destructionmonth, documentstable.destructionyear, documentstable.id, Now() AS Expr1, Date() AS Expr2, DateAdd('m',2,destructionyear+"/"+destructionmonth) AS Expr3, Format(destructionyear+"/"+destructionmonth+"/"+"01","Short Date") AS Expr4, CInt(DateDiff("d",Format(destructionyear+"/"+destructionmonth+"/"+"01","Short Date"),Date())) AS MyDateDiff
FROM documentstable
It gives me MyDateDiff in the last column, the difference between the destructiondate and the current date. That works great.
But if I add a where clause with this:
CInt(DateDiff("d",Format(destructionyear+"/"+destructionmonth+"/"+"01","Short Date"),Date())) < 60
I get "Data Type Mismatch in criteria expression".
The value I am comparing to the 60 is an integer! How is it a mismatch?! Removing the CInt (which I had though was unnecessary anyway) doesn't work.
5 Minutes Interval
Apr 20, 2006I have a query that shows a list from GPS software (car fleet management), unfortunately the software is not capable of doing a decent reports thus I'm trying to use its data and do it myself.
The table structure is as follow:
Car, Date, Time, Position.
The time interval I have now is 1 minute (short time format), I don't need it so detailed, that's why I was thinking to limit this into 5 minutes interval.
Is it possible?
Thanks for any suggestions.
Number Of Days In One Interval And Not In Another
Feb 8, 2007How would I find if 2 dates fall between 2 other dates?
For example:
This would evaluate to True
StartDate 02/08/2007
EndDate 02/11/2007
StartTestDate 02/09/2007
EndTestDate 02/10/2007
This would also evaluate to true
StartDate 02/08/2007
EndDate 02/11/2007
StartTestDate 02/07/2007
EndTestDate 02/12/2007
This would evaluate to false
StartDate 02/08/2007
EndDate 02/09/2007
StartTestDate 02/10/2007
EndTestDate 02/11/2007
Controlling Autonumber Field - Start Autonumber From 1 Everyday (Composite Key)
Nov 21, 2013I have two tables linked to each other in one to many relationship. Instead of auto number, the date and shift (Text) is being used as the primary keys (Composite Primary Key). Here is the tables structures,
Payouts Table:
Date: Primary Key
Shift (Day or Night) : Primary Key
Bills Table:
Date: Primary Key
Shift (Day or Night): Primary Key
Autonumber: Primary Key
The tables Payouts and Bills has one to many relationship. One payout row can have many bills. The problem is that I want to start the Autonumber in bills table everyday from 1. As date and shift are different for every day so even if i start bills from 1 everyday, it wont make same primary key. I can do it manually but I want to make it automatically.
Tables :: Interval Or Range Of Values
Oct 2, 2014In a table, i have a field called operating draft (ships). I would like to be able to put an interval of data in this field, for example between 3 meters and 6meters. Indeed, for few ships the draft is flexible.
What kind of data type should i select and how can I set up an interval data.
How To Create Date Interval Using Combo Box
Jan 13, 2013How to create a date interval using combo box?
For example, i have a receipt form consisting of receipt date from 1/1/2012 to 31/06/2012.
But I want to view the receipt form to just show the date from 1/3/2012 (can be changed) onwards or 1/4/2012(can be changed) onwards.
Excel-export Date Interval Problem
Sep 2, 2006Hi!
I'm currently facing a wierd problem, and I really hope you can help me!
I have a query called "fsRapportSalgsoverblik2" which contains a list of all sales made from a company. I want to export that list to excel, which is no problem at all... But when I try to set a date interval, so that only the sales made in a certain period is exported, I get errors. I've tried to implement the interval-limitation in two different ways:
1) Inserting "WHERE date BETWEEN "field A in form" AND "field B in form" in the query from which the data is exported (when using the data-view to view the query output i can see that it works perfectly).
2) Inserting "WHERE date BETWEEN "field A in form" AND "field B in form" in the OnClick-code of the "export to Excel" button, where the export-code is written. So instead of saying:
Set rst = CurrentDb.OpenRecordset("SELECT * FROM fsRapportSalgsoverblik2;")
I change it to:
Set rst = CurrentDb.OpenRecordset("SELECT * FROM fsRapportSalgsoverblik2 WHERE date BETWEEN "field A in form" AND "field B in form";")
But no matter which solution I choose, I get the error: "Too few parametres. At least two was expected..." (free translation from danish version of Access). I really don't get it. When exporting to Excel without a date-interval, it works perfectly. But when inserting a date interval, it doesn't work, no matter how I do it....
Please help!!
// JR
General :: Generate Numbers With Fixed Interval
Sep 9, 2014I have a range say 12.03 to 13.11.
I need to generate all numbers falling within this range with 0.01 increment.
(This increment is based on the numbers; if the numbers have 2 decimals, it should be 0.01. If the numbers have 3 decimals, the increment should be 0.001. Both the numbers will have the same number of decimals)
The answer is: 12.03, 12.04, 12.05, etc. etc. till 13.10, 13.11.
Is there a way we can do it in MS Access ?
DateTime Period Between Last Record In Table And Given Time Interval
Jul 5, 2005HI all,
I am still new in Access databases :o
I have a table with 'General Date' column. So I have to create query wich extracts records between Last record (via Date field) and 'for example' 10 days before. But Last record in Date column may differ from Now().
When this is done I have create calculations with extracted records using agregate functions.
I'm trying to use Last function for Criteria putting it into Date field and substracting with -10 (for 10 days) but it doesn't work.
Please help! :confused:
Generate A Field In Query With Hourly Incremented Data Between MIN MAX Interval
Aug 12, 2015How can I put a field in my query, with all data hourly incremented between 01 January 2015 to 31 December 2015.
View 5 Replies View RelatedCount Instances Of Records At Each Hourly Interval Within A Selected Date Range
Sep 30, 2014I've got a single table with multiple fields, three of which are a date field ('DDate'), a time field ('TimeET') and a unique identifying field ('Unique Call Key'). I'm attempting to write a query in the QBE that will allow me to count the number of instances of 'UniqueCallKey' for each hourly time interval (7:00:00 AM - 7:59:59 AM, 8:00:00 AM - 8:59:59 AM, 9:00:00 - 9:59:59 AM, etc) for any selected date range (BETWEEN 'DDate'(1) AND 'DDate'(2)). When I try to simply use the Count function on 'UniqueCallKey' as an Expression and 'TimeET' with 'Like '7:*AM' as a Where criteria then do the same with another instance of 'UniqueCallKey' and 'Like 8:*AM' as the criteria for a second Where criteria for 'TimeET' the query returns an empty set. What I'm trying to accomplish would be a column of dates, a second column that counts the number of instances of 'UniqueCallKey' at the 7AM interval for each date in column 1, a third column that counts the number of instances of 'UniqueCallKey' at the 8AM interval for each date in column 1, etc to a final column for counts at 7PM.
View 3 Replies View RelatedAutomatic Recurring Entry Based On Start Date And Nominal Interval Period
Feb 15, 2012How to create a table that has a recurring entry, based on a start date and a nominal interval period of e.g. one calendar month?
Is it possible to have these entries applied automatically each time so that they appear, as required, when the table is opened?
For example, for the entry of regular payments due per month.
A Query To SELECT A Columen Within An Interval Which Conatains TEXT+DIGIT+TEXT
Dec 28, 2006I have a column which contains "text digit text" as "AAA 222 BBB". The numbers of letters or digits can vary.
I need to SELECT the column which contains digits in a specific interval. For Example I have
"DFS 673 JKK"
"A 3454 LJLJ"
"SD 854 JKLJD"
I need to SELECT the column which contains 600 < Digit < 700 the result of the query in this case would be "DFS 673 JKK" because 673 is between 600 and 700.
Thanx for any clue or suggestion...
DateDiff
Jun 16, 2006Is there a way in a query to write a datediff that looks at all the possibilities month, day, year? I have 10 different fields that I need to do a date diff on. I would like to have the fields checked in one place rather than 10 day checks then 10 month checks and 10 year checks. I don't need to use the data any where but I need it to let me know if there is a difference between a calculated date and a date that was input by a user. If there is then I know the user input the wrong date, and it shows as an error.
Thanks
How Do You Use Datediff?
Jan 2, 2008I have heard of this datediff thing on access. How do you make it work? I also want to do a calculate between the date of birth and date of death? Bearing in mind they are all different. I am wanting if possible to list the age at death either as for example 70years and 85 days or 70.233 years
View 5 Replies View RelatedNeed Help With Datediff
May 14, 2007Hi,
I am trying to calculate the number of days between 'today' and a 'date of birth' field. In the field properties Default Value I am using =(DateDiff('y',Date(),[dob]) where Date() gives today's date and [dob] is my 'date of birth' field. However, this is not working. I get an error "(The database engine does not recognize either the field 'dob' in a validation expression, or the default value in the table 'Table1')"
I have set the data type for both fields to 'Date/Time'. What am I doing wrong? Is there any alternate method?
Also, how can I calculate height in feet & inches (5'6" or 5.6 or 5-6) from a given height in meters?
Thanks
Raj
DateDiff Help
Dec 2, 2005I need to caculate the difference in days between to dates. I would like to include only Business days but would settle for any help at this point
Thanks in advance
-WM
DateDiff
Jul 16, 2007Hi there.
I'm using the following code in my Access aplication:
DateDiff("h", IncStart, txtrts)
My problem is i need the exactly time difference and if the difference is 2hours and 15 mins it will display only 2 hours. Is there any way to do that? I've tryed in min but it display 135 mins.