Queries :: DateDiff Function - Calculate Difference In Dates Between Two Fields
Apr 22, 2013
I am trying to calculate the difference in dates between two fields. How do I find the difference in days between field one which contains the date 04/12/2011 and field two which contains the date 04/12/2013? I have tried to use the datediff function, but it keeps telling me it doesn't recognize the field name, even though the spellings correct.
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Sep 14, 2014
I have the attached database which calculate the Difference between dates.I have also two problems like i shown in the image
Code:
Option Compare Database
Option Explicit
Sub Recalculate()
Dim rst As DAO.Recordset
Dim dff As Long
[code]...
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Jan 22, 2012
DateDiff in a query
I am trying to calculate time difference between two time columns as follows in a query which has a few inner joins
Diff: DateDiff("h",[Table1.TimeStrat],[Table1.TimeStrat])
This gives problem, it is asking [Table1.TimeStrat] to be entered, where is the problem?
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Oct 26, 2014
I have to create a query in access that will calculate two Date and time fields [Date & Time Left]/ [Date Returned], need to figure out between the two fields. Trying to identify when the rep returned the call and the number of business hours (6:00am - 4:30pm) it takes to return a message in Ms Access 2010.
The only issue is the calculation has to be done by time and so I have to calculate what time they left the message(so the difference between [Date & Time Left] and [Date Returned) [Date & Time Left] and when the rep returned the message which is suppose to be [Date Returned] but the problem with this field is the data entry is in date format (10/9/2014, 00/00/0000) of Date and not Date and Time like the [Date & Time Left] field, so I don't know what to do now. Not sure what to do now not a database that create or have allot of control over.
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May 18, 2013
I am trying to calculate how many days are left till end of contract...
whats wrong with this formula
=DateDiff("d",[Completion_Date], Date())
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Sep 20, 2014
Basically, I am trying to calculate a integer number difference from two dates (TAT = Due-Date - Result_Date). The number is calculated and excludes weekends and ideally holidays (for that I have a tblHoliday but not sure how to use it). The function below seems to calculate a number but doesn't exclude weekends.
For example, if Due_Date is 9/26/2014 and Result_Date is 9/30/2014, then TAT is calculated to be 5 (should be 2).Since 9/26/2014 is a Friday only Friday and Monday are used in the calculation.
Code:
Option Compare Database
Public Function WorkingDays(StartDate As Date, EndDate As Date) As Long
Dim intCount As Long
intCount = 0
[code]...
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Jun 8, 2015
How can I calculate the difference between two dates but I only want to count the work days? So if was today and I wanted to go until 6/15/2015 the difference would be 5 and not 7 because I do not want to count Saturday or Sunday. Is there a special %datediff function where I would only count work days?
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Aug 28, 2013
I have built a query to calculate the expiry dates of training courses but I am trying to input a criteria so that only dates within 90 days of todays date show. I am using Date()<90 but it doesn't return the correct information. What the criteria should be for this?
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Mar 17, 2015
So I am working with a table that has 2 text fields called DestructionMonth and DestructionYear. The data in DestructionMonth is a 2 character month (01 through 12), and year is a 4 character field.
What I need to do is find all records where the destructiondate is within 60 days/2 months.
I have tried this many different ways and am still getting an error.
So this query works fine:
SELECT documentstable.destructionmonth, documentstable.destructionyear, documentstable.id, Now() AS Expr1, Date() AS Expr2, DateAdd('m',2,destructionyear+"/"+destructionmonth) AS Expr3, Format(destructionyear+"/"+destructionmonth+"/"+"01","Short Date") AS Expr4, CInt(DateDiff("d",Format(destructionyear+"/"+destructionmonth+"/"+"01","Short Date"),Date())) AS MyDateDiff
FROM documentstable
It gives me MyDateDiff in the last column, the difference between the destructiondate and the current date. That works great.
But if I add a where clause with this:
CInt(DateDiff("d",Format(destructionyear+"/"+destructionmonth+"/"+"01","Short Date"),Date())) < 60
I get "Data Type Mismatch in criteria expression".
The value I am comparing to the 60 is an integer! How is it a mismatch?! Removing the CInt (which I had though was unnecessary anyway) doesn't work.
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Jul 9, 2013
ID Up Time Down Time
John 18:00 15:00
Kelvin 08:00 08:05
Melisa 23:00 02:00
This is the Table , i need the Query result show IF [Up Time]-[Down Time] is >=3 hrs
Like Below :
ID Up Time Down Time
John 18:00 15:00
Melisa 23:00 02:00
IDUp TimeDown TimeJohn18:0015:00Melisa23:0002:00
I tried DateDiff("h",[Up Time],[Down Time]) in Field but POP out with error "Syntax error (comma) in query expression 'Table1.[DateDiff("h",[Up Time],[Down Time])]' " ...
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Oct 25, 2013
I have a list of client activity - client name, loan ID and loan date. I would like to create a new field that shows the number of days between one loan and the next. If I was doing it in excel, I would need to sort the data by client name and loan date and then calculate the number of days between the loan date of one loan and the loan date of the loan immediately prior to this.
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Aug 10, 2015
I have a database that I need to calculate a query that is based on 3 dates. For example...I have an admission date and a discharge date in my database.
If there is no date in the discharge date then I need it to calculate the number of days between the admission date and "today's date." If there is a discharge date then I need to calculate the difference between admission date and discharge date.
Basically i need a length of stay figure. I can figure the formula in excel but cannot get it to work in access. Here is my formula in excel
=If(ISBLANK(DischargeDate),Sum(today()),sum(Discha rgeDate-AdmissionDate)
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Jul 3, 2015
I am using Access 2013.I am trying to create a query that will count the days difference between two dates. The dates are in the same field. I want to group by Region.So:
tblRegion = RegionID
tblStatus = StatusDate
I know how to use the DateDiff when it is two different fields, but I can't figure out how to do it from the same field.
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May 6, 2014
I am wanting to get an expression that will return the difference in years and months between 2 dates. Specifically, I want to know peoples ages in years and months based on a person's D.O.B and todays date. I have managed to do it in years:
Expr1: DateDiff("yyyy",[TBL_EmployeeDetails]![D_O_B],Date())
and in months but I would like to know how to return the difference in years and months.
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Jun 27, 2013
In my table I have the following 4 fields with the associated date field:
Bronze: 11/1/2013
Silver: 5/1/2014
Gold: 11/1/2014
Platinum: 5/1/2015
I am trying to calculate a value based on comparing the current date to the dates in these fields. I am using the below formula. However, using 6/27/2013 as the current date, my formula keeps resulting in "Bronze" when it should result in "Standard" Am I doing something wrong?
=IIf(Date()<[Bronze],"Standard",IIf((Date()>=[Bronze]) And (Date()<[Silver]),"Bronze",IIf(Date()>=[Silver] And Date()<[Gold],"Silver",IIf(Date()>=[Gold] And Date()<[Platinum],"Gold","Platinum"))))
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Jan 27, 2015
I am designing mileage database in access 2010.
table:
1- maintbl (date, truckNo fillinQty,rate,cost, odometer, mileage)
Query:
1- mainquery (based on maintbl)
Form:
1- mainfrm (Based on mainquery)
i want to calculate mileage :
example:new odometer reading - previous odometer reading / filled in qty
example: 2000 km - 1000 km / 200 liters = 5 liters /km
Objective: How query will automatically calculate the difference of new odometer reading and last odometer reading for a specific truck number and divide it with filled in qty of fuel?
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Jun 25, 2013
My database includes two separate dates related to a vehicle purchase and default payments resulting in repossession. I need to find out how many weeks passed between those dates.
Example:
03/14/12 Date of automobile purchase
06/06/13 Date of last payment before default
How many weeks in between? And then I need to average all of those figures so my company can see the usual week-term time frame that our customers are defaulting and getting repossessed.
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Nov 21, 2014
I'm trying to calculate the number of days between two dates using the iif statement
Fields:
[LDW] "Last Day Worked"
[ReturnedDate]
DESCRIPTION: If ReturnedDate is null, then calculate the datediff "d" between LDW with Now(), if not, then calculate the datediff "d" between LDW with ReturnDate.
I tried this but it didn't work at all.
Days Absent: Iif(isnull([ReturnedDate],(DateDiff("d",[LDW],Now())),(DateDiff("d",[LDW],[ReturnedDate])))
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Jun 15, 2015
I'm trying to build a query with an iif statement to calculate expiration dates within a query. For some reason what i'm trying to do is not working as expected.
Here's the situation. Every employees with an exception of two employees in the company has an expiration 2 years after the class took place. The two exceptions are the certified instructors who's training certification is good for three years.
I've created a query with the employeeid, training subject, and maxoftraining date.
I'm trying to write an if statement to give me the expiration date based on the above information. Here's what I have so far; however its not calculating based on the criteria.
Expiration: IIf([tblemployee]![EmpID]=1 Or 2,DateAdd("yyyy",3,[maxoftrainingdate]),DateAdd("yyyy",2,[maxoftrainingdate]))
At this point in time, all "expiration" dates are showing + 3 years rather than just the Employee ID's 1 and 2 and the rest +2 years.
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Jun 8, 2006
I have an access database used for recording training events. I was able to calculate the number of days each training event took by using
Datediff("d",[Training Date From],[Training Date To]+1)
I was really chuffed with this until my boss asked what happens when the training only lasts half a day! I added the time to the above fields to make them date/time fields but can't see a way to calculate in half days.
As well as this the other problem is that training could be over a few days. As an example I'd like to be able to input that the training started at 9am on Monday 29th May and ended at 12 noon on Thursday 1st June and get the result of 3.5 days. The full days would all end at 5pm but I wouldn't be recording that, just the total days. I tried changing the datediff function to hours in the hope I could somehow discount the non working hours but that didn't work! I'd ideally like the final result to be in days, ie 0.5, 1 etc. It would always be in whole or half day increments - don't need things to be overly complicated!
Any help will be very gratefully received. I'm definitely not an expert as you can probably tell!! :eek:
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Jul 20, 2013
i have a access table (AUTH) with following field
Company Auth Held
Tata 12
Dell 11
HP 21
Opera 11
Bangour 10
i used the following query to calculate the Held from a table named pers.
SELECT AUTH.company, AUTH.Auth, Count(AUTH.company) AS Held
FROM pers INNER JOIN AUTH ON pers.company = AUTH.company
GROUP BY AUTH.company,AUTH.Auth
then i got the result as under
Company Auth Held
Tata 12 02
Dell 11 08
HP 21 20
Opera 11 12
Bangour 10 12
now i want the difference between Auth and Held as Sur/Defi
how can be it done.
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Feb 18, 2015
Basically I have a report that shows any 'Issues' that wasnt closed within the KPI Target.
I have the report working, but I simply want to do a count of how many days the observations overran the 'Target Date of Closure'.
The report also shows observations that are not closed but passed their Target Date of Closure. These observations will not have a 'Actual Closure Date', but I would like to still have a count of how many days its overrun closure.
This is a formula I tried to piece together but obviously not correct as it's not returning anything;
IIf(IsNull([Issues]![Actual Closure Date]),DateDiff("d",[Issues]![Target Date of Closure],
Date()),DateDiff("d",[Issues]![Target Date of Closure],[Issues]![Actual Closure Date]))
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May 8, 2013
I have a database with two tables, one for the amount that was estimated in each cost section, and one for the actual amount billed for each cost section. The tables have the same number of fields, all with the same names. They can be linked together with event ID. Each table has over 100 fields and I would like to find the difference between what was estimated and what the actual was for each event. I would also like to see which cost section has the most and least variance. I am trying to do this without going through each cost and putting [tEst].[CostName]-[tActual].[CostName].
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Aug 6, 2015
I have a Query contains field that is :
Code : AllNv: Concatenate("SELECT NAll FROM NormalsQ WHERE SerName='" & [SerName] & "'" & " ORDER BY NormID")
but [SerName] is a text type field that is not Primary Key.
I have in the FamilyTbl , [ServiceID] is numeric type field, and a primary key. I try :
Code ; AllNv: Concatenate("SELECT NAll FROM NormalsQ WHERE ServiceID='" & [ServiceID] & "'" & " ORDER BY NormID")
but this returns all [NAll] records. I use concatenate :
Code:
Function Concatenate(pstrSQL As String, _
Optional pstrDelim As String = ", ", _
Optional pstrLastDelim As String = "") _
As Variant
[Code] .....
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Aug 7, 2014
I'm using the following function to calculate date diff in network days (excluding weekends)
Public Function NetWorkdays(dteStart As Date, dteEnd As Date) As Integer
Dim intGrossDays As Integer
Dim dteCurrDate As Date
Dim i As Integer
intGrossDays = DateDiff("d", dteStart, dteEnd)
NetWorkdays = 0
[Code] ....
So when using this function in a query to get number of networkdays between 2 date columns ...it works fine but throws a #Error where there is blank entries in either of 2 date columns...
I need to find a way to display Null instead of #Error...
I have tried this expression but no luck...
IIf(IsError(NetWorkdays([Date1],[Date2])),"",NetWorkdays([Date1],[Date2]))
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Jan 20, 2014
Looking to have a count function which calculate data in sense like if records found on 1-jan-2014 the it give answer as 1, same as records for 2-jan-2014 it should return 2 and so on .. in short the criteria must look and give same number for same dates starting from 1
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