Sep 15, 2013
I have the following code and I am trying to show a COUNT of duplicate ID numbers, so for example
ID ID_COUNT
2000 2
2000 2
2001 1
2002 1
2003 1
Code:
SELECT [DaisyServiceData-Import].*, Companies.CompanyName, Company_vs_Services.[Tariff Code], IIf([ClashForce]=True,"",IIf([ClashOveride]=False And [ClashClear]=False,IIf([DaisyServiceData-ClashExc].[DaisyServiceData-Import].[ID] Is Null,"",1),"")) AS ClashExc, IIf([Sell Price]="","",IIf([SellRateForce]=True,"",IIf([CompanyName] Is Null,"",IIf([SellRateOveride]=False And [SellRateClear]=False,IIf([Total Cost]>[Sell Price]+0.001,1,""))))) AS SellRateExc, IIf([Tariff Code]='1',[T1Rate],
[Code] ...
A GROUP BY query will not work for me as the recordset needs to remain updatable.
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Dec 3, 2004
Hey all!
I'm having issues trying to create a query that will take data from two tables and summarize it based on ID, Count(ID), Sum(Score), Sum(Xs). I don't have an issue doing the combining, just the summing and counting (actually, just the counting). I've tried playing directly with the SQL statement, but I keep getting errors.
This is what I have:
tblRoster
ID, Name, Sex, Youth
tblScores
ID, WeekNo, A1, A2, A3, A2X, A3X, B1, B2, B3, B2X, B3X
Sample Data for tblScores would look like this (scores actually are not the same, but you get the idea)
10, 1, 90, 89, 87, 3, 7, 87, 92, 99, 4, 7
10, 2, 90, 89, 87, 3, 7, 87, 92, 99, 4, 7
10, 3, 90, 89, 87, 3, 7, 87, 92, 99, 4, 7
10, 4, 90, 89, 87, 3, 7, 87, 92, 99, 4, 7
23, 1, 90, 89, 87, 3, 7, 87, 92, 99, 4, 7
23, 2, 90, 89, 87, 3, 7, 87, 92, 99, 4, 7
23, 3, 90, 89, 87, 3, 7, 87, 92, 99, 4, 7
23, 4, 90, 89, 87, 3, 7, 87, 92, 99, 4, 7
23, 5, 90, 89, 87, 3, 7, 87, 92, 99, 4, 7
67, 1, 90, 89, 87, 3, 7, 87, 92, 99, 4, 7
67, 2, 90, 89, 87, 3, 7, 87, 92, 99, 4, 7
67, 3, 90, 89, 87, 3, 7, 87, 92, 99, 4, 7
What I would like to do is summarize the info in the following manner:
ID, Name, Sex, Youth, Count(WeekNo), Sum(A1+A2+A3+B1+B2+B3), Sum(A2X+A3X+B2X+B3X) such that I would get the following results:
10, John Smith, M, , 4, 2176, 84
23, Jane Doe, F, , 5, 2720, 105
67, Johnny Jones, M, Y, 3, 1632, 63
I have been able to get the summed part done, but my attempts to do the count have failed. I know that the resulting query will be straight forward, but right now I'm cross-eyed.
Thanks.
-BT.
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