In my query called "test" I have the following fields: EmpID & DEPT, below is an example.
EMPLOYEEDEPTcounter1016321101101632125210163222033557031501355703120235570313033557031404
I would like to add a column to my query called "counter" and count starting with 1 each time the employee number is listed, when the employee number changes I would like the counter to start over again at 1 and continue this throughout the query.
Hey guys,
I have a questions for all you experts out there. I need to create a record counter. I have found documentation on how to create a simple record counter, but of course it needs to be a little more complicated than that.
I need to beable to count the records that contain a certain value in a certain field. For example, I need a count on all records which contain the value "Orland" and so on.
I assume this is do able. Just dont know how.
Any help would be appreciated!
Mateo
Hi - I'm fairly new to Access and have jumped in head first. I do not know much about it, but I am very familiar with the other MS programs. I also don't know anything about visual basic.
I found an article online that described how to put in a custom record counter by using the Oncurrent Event. I have a form with a subform and I'd like have a custom record counter on both, however, when I open a new record, I get an error telling me there is no current record. This is more a problem for the subform, as the message pops up repeatedly until I put something into it to make it a current record.
The error is run-time error '3021': No Current Record.
This is the code that I used (keep in mind that I only copied this and used it, I didn't write it):
Private Sub Form_Current()
' Provide a record counter for using with
' custom navigation buttons (when not using
' Access built in navigation)
Dim rst As DAO.Recordset
Dim lngCount As Long
Set rst = Me.RecordsetClone
With rst
.MoveFirst
.MoveLast
lngCount = .RecordCount
End With
'Show the result of the record count in the text box (txtRecordNo)
Me.txtRecordNo = "Record " & Me.CurrentRecord & " of " & lngCount
End Sub
Any help is appreciated. Thanks!! :D
Hi,
The user wants all of the records in the database to have continuous numbering. I have used AutoNumber in the past but if you delete a record, it produces gaps in the numbering.
I was wondering if there is a way to number the records so they are always numbered continuously (1,2,3,etc.) even if some record is deleted.
I have tried using the following:
Set db = CurrentDb()
Set recordlist = db.Openrecordset("SELECT Max(tblContactHistory.ItemID) AS MaxID FROM tblContactHistory")
ItemID = (recordlist!MaxID + 1)
recordlist.Close
Set recordlist = Nothing
but I still cannot get the records to have continuous numbering after a record is deleted.
Any helped would be appreciated.
Thanks!
I have a custom record counter on a form using the below code:
Private Sub Form_Current()
If Me.NewRecord Then
Me.lblRecordCounter.Caption = _
"Record " & Me.CurrentRecord & " of " & Me.Recordset.RecordCount + 1
Else
Me.lblRecordCounter.Caption = _
"Record " & Me.CurrentRecord & " of " & Me.Recordset.RecordCount
End If
End Sub
I think at some stage the form was saved with a filter on and this may be causing the issue. The problem I have is:
There are 1749 records. Everytime I open the form the custom record counter displays "Record 1 of 501". The built in record counter shows 1 of 1749. The moment I hit the next record arrow the custom record counter displays "2 of 1749" and if I go back again it displays "1 of 1749.".
I know it's a filter causing the problem because I have a macro that does a clear search. As soon as I hit the clear search the custom counter goes back to "1 of 501" again (even though the built in one stays at 1 of 1749).
I have Filter on Load set to No.
what I am doing wrong?
I have an export query that has number of distribution and CM distribution for invoices generated. The objective is to count the number of invoices based on the account number for each customer ID. Since the table has no primary key, the I assigned field number of distribution to 0 in hopes the counter will assign the value of the row number. The attached file shows how the current export displays and how it should display in the highlighted correct way section. I tried COUNT and DCOUNT methods which is the current setup, and they aren't working. This will eliminate the need to go into the file and change the 2 fields.
View 2 Replies View RelatedHello. I'm trying to add a counter to the fields of a query. Purpose is to have a second query choose from this a selected record and next x records, which, of course have been already sorted by first query itself.
I thought the simplest way was with a simple automatic-generated counter, but perhaps I'm making it complicated and there's a simpler way. Any idea?
thanks
I have an existing database, in whichi I've been asked to implement a counter, of sorts, which could count a store the number of times the database has been opened (including reports being viewed) , in a month. (I'm using access 97). Can this be done? How would I accomplish this?
View 3 Replies View RelatedHi everyone,
Here is my problem:
I Have a form that shows bills in a continuous form. My problem is that I want to put a textbox or a label that will display a kind of counter for each bills. For example, If I have 3 bills to display, I want my label or textbox to display 1 for the first bill, 2 for the second, 3 for the third, and so on.
But I don't know how to do that with a continuous form.
Could someone help me, please...
Thanks in advance!
I have a counter text box that was set up exactly like the help instructions say to set it up and it is not counting correctly. I have it set up to where it is counting subgroups in the report. It counts for if one record has one or two errors, but I have one record in there that has 3 errors and it says that it only has two errors. Can anyone explain this to me?
learnasugo
a couple of questions...
1) what can i do in order to get a form to open when a database is loaded?
2) what is the automatic counter?
thanks in advance
Hey all, here is my problem. I have a form with my 5 different counters on there and well they are not updating. I can update them on the main page but not on the other pages. I have a page called PID where there are 4 command buttons and counters. I click on the first command button, and add a record there now I would go back to the main page PID and the counter needs to update. How do I do this?? the code I have for to create the counter on the main page is as follows, However I need to enter the building form, and add or delete a record and have the counter on the main page update once finnished with that form. I hope I explained this good enough for someone to help. Thanks in advance.
'Building recordset
On Error Resume Next
If bdg.EOF And bdg.BOF = True Then
bdgcount = 0
Else
With bdg
.MoveFirst
.MoveLast
bdgcount = .RecordCount
End With
End If
Hello all
this is my first post, so i hope i'm in the right bullettin.
I need help with this problem:
I have to work on this mdb that has been imported from Access 2000 to Access 2003. The guys did it some months ago, and of course they deleted the old .mdb and there are no backups.
However, the db still works, except that the ID of some tables are now "random id" than "incremental id", and since they used it for some months, now they are full of new records with random IDs.
Since they use THAT id for internal use, you understand that is not very easy to communicate stuff like "please send me document # -3189175187" and so they asked me to get it back to incremental, i tried from the table menu to change the dropdown, as i thought it was that easy. Bad luck, access now complains that the data aren't now contiguous (might be different error, it's a localized version, so i don't know how it is the exact error message, sorry), and i'm not really sure on what to do to avoid problems.
I've explained the best way i could, so if you need more info just ask, thanks everyone in advance!
Hi folks,
can anyone help with what is probally a simple task?
How can I find the Data Type Counter in Access 2003? I am not sure entirely sure if this version is supported, if not what else can I use as a substitute? This is what I am trying to acheive:
http://support.microsoft.com/default.aspx?scid=kb;en-us;245074
I would be greatful of a response.
regards,
Steve
Hello everyone, new member here. I am in charge of a student sign in sign out database at the college where I work. This database has two forms and one table. What I would like to do is include a text box on the first form, which is the sign in form that will display a running total of the students that are signed in. This text box should count 1, 2, 3 etc. each time a student clicks the sign in button. Thanks for the help
View 4 Replies View RelatedI'm trying to use a query in a recordset and I'm getting errors. The query was created in Access using a SQL table. The query and table are in my current database. I get runtime error 3061 (expected 3 parameters) at line in red.
Public Sub UpdateLotsizes()
Dim curDatabase As Object
Dim rstQryLot As Recordset
Dim rstInvLoc As Recordset
Set curDatabase = CurrentDb
Set rstQryLot = curDatabase.OpenRecordset("QryLotsize3")
[code]....
but then I get a compiler error "user defined type not defined". Do I need another add-in?
After compacting my Access2000 database it usually is impossible to add new records. The automatic counter does not continue with a new value but seems to have "forgotten" some of the recently added records and tries to use a value that is already allocated. After pressing <ESC> the next value is applied and so - after adding and escaping the appropriate times - it finally reaches a valid new value and the record is accepted. Ugly workaround. Any known solution?
View 2 Replies View RelatedHi all, i trying to design a date / time (hrs:mins) down counter. I want to put say my holiday date e.g 27/07/07, and then the access form will show how many days hrs and minutes left from the present date /time to the start of holiday. How can this be done easily? Thanks
View 3 Replies View RelatedThe problem that I have is that when I add a new field to my form at runtime I get the following error
Runtime Error '2424'
The expression you entered has a field, control, or property that Microsoft Access can't find.
This error appears when I try to update any field.
I posted this before and was informed that access has a field counter limit up to 750 on a form, this includes fields which were deleted or hidden. I dont deliberately add and remove fields, but this is the main form in my database so it is not unbelieveable that this may be at the limit and this is why the error is occurring. Does anyone know how to reset this?, or what I should do to get around this.
Thanks
is there anyway to make a counter field that is automatically filled (1,2,3,...) rather than filling it manually and also it resets each new day?? I'm not talking about autonumber field because of its nature also because I use it as a uniqe field "VisitID",
View 9 Replies View RelatedI made a simple access project and I want to make a count for my visits, this counter MUST starts from one each morning "every new day", I use autonumber field to give each visit its unique code, I'm ok with that, but i need additional counter that resets each new day,, i watched some videos for making the autonumber starts from different number like 1000 for example using Append query but i didn't figure out how to use this method for resetting counter everyday.
View 6 Replies View RelatedWe have a query that pulls information from four tables. What we need to do is do a query or something else to pull the data from the existing query into a table/excel file. The problem we are having is that we want just one record for each person with all of their class selections in one field. Is this doable?
View 4 Replies View RelatedOur local radio station has a database that records which user plays which track and when, manually entered.
I'm looking into making a query that can tell them the top 5 most played tracks this month. So basically I need a query that returns the 5 most frequent records within the current month.
I can do this in like 5 seconds in SQL Server but I can't get the query to even ALLOW me to update records.
Table1 - Columns
Query1 - ColumnDesc
Code:
SELECT DISTINCT C.Column
FROM Columns C INNER JOIN (
SELECT Cols.Column, Count(Cols.DataType)
FROM (SELECT DISTINCT Columns.Column, Columns.DataType FROM Columns) Cols
WHERE Cols.DataType = 'char' OR Cols.DataType = 'varchar'
GROUP BY Cols.Column
HAVING Count(Cols.DataType) > 1
) C2 ON C.Column = C2.Column;
Simple, straight forward query, that grabs all the rows from table Columns where there are more than one DataType per Column [name], and either one of those datatype strings are 'char' or 'varchar'.Now I want to UPDATE table Columns to set all of the columns whose "column" value is in the above query, and set all those DataType values to 'VarChar'. Thus I run that UPDATE query, and the above query should come back empty afterwords in SQL Server I would simply write:
Code:
UPDATE Columns
SET DataType = 'varchar'
WHERE EXISTS (
SELECT 1 FROM ColumnDesc INNER JOIN Columns ON ColumnDesc.COlumn = Columns.Column
)
And this would already have been done.But Access doesn't like that syntax. using the designer it created sql like this:
Code:
UPDATE Columns INNER JOIN ColumnDesc ON Columns.Column = ColumnDesc.Column
SET Columns.DataType = 'varchar'
But that wasn't an "Updateable" query.I have to run this on several patterns and right now I'm completely screwed if I can't get this to work.
My end goal is to have:
SELECT DISTINCT Columns.Column FROM Columns
return the same # of rows as
SELECT DISTINCT Columns.Column, Columns.DataType FROM Columns
for each duplication I will have to do different algorithm, but I can't even get one update query to work so I'm currently frustrated (and ready to reaffirm my belief that Access should have been discontinued 5 versions ago).
how can i make a custom counter in a table where records are appended from another table.
i have already used custom counter method in my database before by using this technique.
[URL]
but i want to make counter in a appended table.
I need Create a new counter on my Customer form for each day, using an Autonumber and print it
View 6 Replies View Related