SQL Count By Date

I have a query that uses 2 Fields from a large table. Cashier and Date. The problem I am having is I would like the select a time frame, a Start and Stop date, and count how many times the cashier comes up for that day.

Sounds easy, I would think so but having a problem. The dates are automatically imported into the large table as format 01/01/2005 12:00pm (Can't do anything about this).

When writing the SQL and the Count function, it is using the time as well in its calculation, but I simply want it to count on the date only. So unless a cashier existed exactly in the table as 01/01/2005 12:01pm, 01/01/2005/12:01pm it only counts it as a total of 1, instead of twice for that day.

I simply want the SQL function to read the Date field as 01/01/2005, and drop off the Time. I can format it, but only changes it visually and the SQL statement still sees the time.



Any help would be appreciated.


I found this code on the boards here, almost what I want but does not group each Cashier by day and total, it does the total of all cashiers for that day. I need the Cashiers sorted for each day, and totalled.

SELECT Format([Date1],"dd mmm yyyy") AS Day1, Count([ Cashier1].[Cashier1]) AS CountofCashier
FROM CashierQ1
GROUP BY Format([Date1],"dd mmm yyyy"), Format([Date1],"dd mmm yyy")
ORDER BY Format([Date1],"dd mmm yyyy");