Subtracting Dates From Adjacent Dates In Same Column

Sep 7, 2006

Hiya-

I have a database with 5000 entries, corresponding to about 10 entries for about 500 people. Each of the entries is dated, and I need to calculate the time intervals between each person's sequential entries in the table.

One way of doing this is to create another column that contains the date of the previous entry. I can then use DateDiff to subtract one date from the other and give me the difference in days.

This approach falls down if I then work with only a subset of the entries - I would have to re-enter the previous entry dates as the time intervals would have changed.

What I really need is a way of subtracting the date from the date in the cell directly above it. Will Access let me do this, or is there a better way?

Many thanks, Jules.

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May 12, 2014

Any way to have a form with Dates as column headers to update a table where the dates are stored in rows???

The table set up is like this:
tblOpHdr
DiaryID (PK) - OpDate (Date)

tblOpDetail
DiaryID (FK) - CostCode - MachineNumber - MachineHours - etc

I'm just wondering if there's any way I can do this with a datasheet or a crosstab type setup?

It's Access 2010.

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Dec 12, 2005

I found the following code on this site in a search for a method to subtract two dates ie [Startdate] and [EndDate] and display the result as a whole number. ie 2, 6 etc. This code finds the difference but displays the results as 1 year 5 months 2 days, where I need the equivalent as 17.
Can this code be modified to produce the desired result and if so how would I go about it. Thanks for the help.

Option Compare Database
Option Explicit

Public Function getTimeElapsed(StartDate, Optional EndDate As Date) As String
On Error GoTo Err_Handler

If IsNull(StartDate) Then
getTimeElapsed = "No startdate"
Exit Function
End If

Dim YY As Integer
Dim MM As Integer
Dim DD As Long

' use current day if EndDate is not supplied,
' + 1 makes both days inclusive.
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DD = DateDiff("d", DateAdd("m", MM, StartDate), EndDate)

' recalculate if DD is negative.
If DD < 0 Then
MM = MM - 1
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YY = MM 12 ' integer division.
MM = MM Mod 12 ' remainder.

getTimeElapsed = YY & IIf(YY < 2, " year ", " years ") & _
MM & IIf(MM < 2, " month ", " months ") & _
DD & IIf(DD < 2, " day", " days")
Exit Function

Err_Handler:
MsgBox Err.Description
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End Function

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Feb 1, 2013

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I'm using access 2010, and I'm fairly new at it.

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Is it possible to perform calculations across 2 adjacent rows in SQL?

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In this example, the Since Last Updates should be found by
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Thanks for looking

W1dge

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Jul 6, 2007

Jus thought I'd offer this code to the forum as spent a long time finding a suitable solution..

SELECT DischargeTime.ID, [Arrival Times].ID, [Arrival Times].[A&EArrivalDate], [Arrival Times].[A&EArrivalTime], DischargeTime.[Date of outcome], DischargeTime.[Time of outcome], DateDiff("d",[A&EArrivalDate],[Date of outcome]) AS DateDifference, [Time of outcome]-[A&EArrivalTime] AS TimeDifference, IIf([DateDifference]>=1,([DateDifference]*(1/24)*576)+[TimeDifference]*(1/24)*576,([DateDifference]*(1/24)*576)+[TimeDifference]*24) AS hours3
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Basically I had an admission date and in a seperate box an admission time and then I had a discharge date and discharge time again in seperate boxes. The information was spread over two tables hence the join. How I solved the problem was by gaining both the days difference between and then the difference in hours and then I created an iff function and played around with it till it worked. Dont really know how i got it working in the end but it does so hopefully this code will save some1 alot of time!

(I know that if id shown my dates as date/time in 1 box the problem would have been much easier solved, however I dont personally like displaying dates and times that way especially when you have inexperienced people entering data)

Find below a result from the query

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1111
1112
2116
2117
3119
3121
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4126
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03-Apr-2015
04-Apr-2015
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