Toggle Button, Focus, Switching Back And Forth

Feb 6, 2006

Here's a little design problem, all of my VB script works fine, it's just a design problem:

Toggle Button (onClick) {
if pressed in, unlock protected field, pass focus to protected field
else (if not pressed in), lock protected field
}

Protected Field (lostFocus){
When Focus is lost, protect field then reset toggle button
}
See, there's no way that I know of for Access to tell what field has focus at any given moment. It lies inert until an event fires off then it responds. You can't wake Access up and tell it to go do something. So, Protected Field has to lock itself when it loses focus.

Here's the problem. If a user unlocks the field but then decides not to make a change and clicks the toggle again to lock the field, first Access fires the script to protect the field (locking it), then it resets the toggle button, then it registers the toggle button click which unlocks the field. See the problem? If the user changes their mind about changing the field and then tries to lock the field, it ends up unlocked. I need something that will work whether the user is good about it or whether the user is in a rush and forgets about it.

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Have a Great Weekend, one and all


Dave

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Toggle Button

Aug 18, 2006

Hi all,
I have a form with two subform on it and two toggle buttons.
Clicking each toggle button will open one of subform, and clicking it again will close that subform. But the problem is that I need to click the toogle button two time to open the sub form.
So, what is the problem??

This is the code under On Click event:
Private Sub Toggle0_Click()
If Me.TendComm_Label.Visible = False Then
Me.TendComm_Label.Visible = True
Me.TendComm.Visible = True
Else
Me.TendComm_Label.Visible = False
Me.TendComm.Visible = False
End If
End Sub

Private Sub Toggle1_Click()
If Me.AuthorizedSignature_Label.Visible = False Then
Me.AuthorizedSignature_Label.Visible = True
Me.AuthorizedSignature.Visible = True
Else
Me.AuthorizedSignature_Label.Visible = False
Me.AuthorizedSignature.Visible = False
End If
End Sub

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how do these work syntactically? there's no wizard for them.

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Jun 13, 2007

Hi, I'm very new to programming and i have very little knowledge about it. My problem is probably more simple than I may think, but for some reason I haven't been able to find a solution for it.

In MS Office, I'm making a form with a few toggle buttons which are linked to Yes/No fields on a seperate table. What I would like to do with the buttons is in their default state, which is "No", I want for the word "No" to appear on the top of the button. When the button is pressed, I need for the button to display the word "Yes". I know that it's possible to set the caption on the button to "No". Is there a way to have the caption change to display "Yes" with the press of the same button it's on? If so how? Also to have the fields reset to default with a new page on the form.
Please explain it to me as if I'm a 5 year old trying to learn programming.

Thanks in advance.

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Code:
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[code]....

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Jan 21, 2005

I am one of the guys that the dept. drops 1k to send to the beginner through expert level courses for Access, so I ask patience as I am new to VB coding.

I am working on a database to track patient surgical information. I am using a toggle button to control "patient surgery site" visibility, depending on the number of sites associated with them. They are labeled Site A Site B, Site C

What I want is if a patient only has one site, I press the appropriate toggle (Site_A_Button, Site_C_Button, and Site_C_Button) and only fields pertaining to Site A appear. If they have 2 sites, I can press both of the toggles for A and B, but the C will remain hidden, etc.

Each toggle controls 3 fields -
For the Site A button - Site_A, Diagnosis_A, A_Blocks_Check
For the Site B button - Site_B, Diagnosis_B, B_Blocks_Check
For the Site C button - Site_C, Diagnosis_C, C_Blocks_Check

The *_Blocks_Check also controls visibility for a respective fourth field - Site_A_Blocks , Site_B_Blocks , Site_C_Blocks

So far, I have A and B working just fine. By default, the toggle for A is set to -1 so it is visible by default. Site B and C are default 0. Both A and B work exactly as I want them to, however, site C does NOT. It has identical coding as B, however, it is visible by default (despite the "default 0") and the Site_C_Blocks visibility (controlled by the Check Box) also does not work properly. Here is the VB-

Private Sub A_Blocks_Check_Click()
If A_Blocks_Check = 0 Then
Site_A_Blocks.Visible = False
End If

If A_Blocks_Check = -1 Then
Site_A_Blocks.Visible = True
End If
End Sub

Private Sub B_Blocks_Check_Click()
If B_Blocks_Check = 0 Then
Site_B_Blocks.Visible = False
End If

If B_Blocks_Check = -1 Then
Site_B_Blocks.Visible = True
End If
End Sub

Private Sub C_Blocks_Check_Click()
If C_Blocks_Check = 0 Then
Site_C_Blocks.Visible = False
End If

If C_Blocks_Check = -1 Then
Site_C_Blocks.Visible = True
End If
End Sub

Private Sub Site_A_Button_Click()
If Site_A_Button = -1 Then
Site_A.Visible = True
End If
If Site_A_Button = -1 Then
Diagnosis_A.Visible = True
End If
If Site_A_Button = -1 Then
A_Blocks_Check.Visible = True
End If

If Site_A_Button = 0 Then
Site_A.Visible = False
End If
If Site_A_Button = 0 Then
Diagnosis_A.Visible = False
End If
If Site_A_Button = 0 Then
A_Blocks_Check.Visible = False
End If

End Sub

Private Sub Site_B_Button_Click()
If Site_B_Button = 0 Then
Site_B.Visible = False
End If
If Site_B_Button = 0 Then
Diagnosis_B.Visible = False
End If
If Site_B_Button = 0 Then
B_Blocks_Check.Visible = False
End If

If Site_B_Button = -1 Then
Site_B.Visible = True
End If
If Site_B_Button = -1 Then
Diagnosis_B.Visible = True
End If
If Site_B_Button = -1 Then
B_Blocks_Check.Visible = True
End If
End Sub

Private Sub Site_C_Button_Click()
If Site_C_Button = 0 Then
Site_C.Visible = False
End If
If Site_C_Button = 0 Then
Diagnosis_C.Visible = False
End If
If Site_C_Button = 0 Then
C_Blocks_Check.Visible = False
End If

If Site_C_Button = -1 Then
Site_C.Visible = True
End If
If Site_C_Button = -1 Then
Diagnosis_C.Visible = True
End If
If Site_C_Button = -1 Then
C_Blocks_Check.Visible = True
End If
End Sub

Now I know this is probably sloppy coding, but it was the only way I could get this to work properly at all, so feel free to critique as well.

I want to actually add additional sites (Site D and Site E), but not until I can figure out why the problem is with just A B and C.

I apologize if this seems a bit confusing, but if anyone could help out, I would be most appreciative!

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Code:

Private Sub Toggle_Filter_DOB_Click()
If Me.Toggle_Filter_DOB = True Then
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[Forms]![Phase 2]![FormPhase2_sub].Form.FilterOn = True
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[Code] ......

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Access 2010 64bit

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[tblOrders] - (Key) [ID] - [Date] - [Consignee] (Text) - [OrderComplete] (Yes/No)
[tblPurchaseOrders] - (Key) [ID] - (Key) [AssignedID] - [ProductName] - [Weight]

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tblOrders and tblPurchaseOrders are related One-to-Many ( tblOrders.[ID]->tblPurchaseOrders.[AssignedID]).

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Code:
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Dim stDocName As String
Dim stLinkCriteria As String
Dim intLinkID As String
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Exit_Command23_Click:
Exit Sub
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Now, for whatever reason - either something I've changed or a bug somewhere... when I double-click the list item, it opens as a new record rather than the corresponding record. I noticed that the "Toggle Filter" button on the access ribbon was ticked so I unchecked it and it immediately switched to the proper record. Why does this happen and what (if common) changes can make this appear or work this way? I am a novice with Access and I am still learning VBA. I struggle with not knowing parameters by heart, although the syntax seems to be similar to other languages I've worked with.

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Code:
<customUI xmlns="http://schemas.microsoft.com
/office/2006/01/customui">
<ribbon startFromScratch="true">
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[Code] ....

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