Checking Values Of Textbox With Table Values

Sep 15, 2005

There is a text box in a form that user can enter the value.
How can I check if the value entered by user is already existed in the record of the linked table or not?
If the value (or record) do not exist, that new value/record will be added to
the table.
If the value do exist, just show the msgbox to indicate.

How can I do that ? :confused:

Thanks

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Hi,

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I want to be able to warn the user if they are trying to save this newly created record with a product number that already exists so that they can alter the number to be unique. It will also warn them if they re-number an existing record to another already existing product number. Since the field is defined as unique, at present the system says absolutely nothing and just doesn't save the newly created record which seems is a touch annoying!

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An Example of Textboxes values on the search criteria form:
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SQL code:
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SQL CODE:
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Dec 5, 2014

I have the following dataset in a table called NR_PVO_120. How do i pick out a number (which can change but let's say, 6) of UNIQUE OtherIDs without excluding any OtherIDs under any fax numbers?

So, if you pick OtherID from Row7 you then also must pick OtherIDs from rows 8 and 9 because they have the same fax number. Basically, once you pick an OtherID you're then obligated to pick all OtherIDs that have the same fax number as the one you picked.

If the number requested (6 for this example) isn't possible then "the closest number possible but not exceeding" would be the rule.

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A few notes.

1.Getting as close as possible to the requested number is a requirement.

2.Some OtherIDs will have a blank fax, they should only be included as a last resort (not enough OtherIDs for the requested number).

my table (NR_PVO_120)
Row OtherID Fax
1 11098554 2063504752
2 56200936 2080906666
3 11098554 7182160901
4 25138850 7182160901
5 56148974 7182232046
6 56530104 7182234134

[code]....

A few sample outputs

one solution is taking rows 1-6 and 26.

OtherID
11098554
56200936
25138850
56148974
56530104
56148975

Another solution is taking rows 1-4 and 10-14.

OtherID
11098554
56200936
25138850
56024315
56115247
56148974

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