Making Label With More Than One Field Per Line

Dec 16, 2012

I previously used an older Access version under XP, but I switched to Windows 7 (64-bit) and Access V10. In general, most everything appears to work as expected, but I can't be sure because I have not gotten past the "previously simple" task of making a simple label !!!!

When I construct a LABEL layout, if I use ONLY one field per line, everything appears to work OK.When I put MORE than one field per line, the additional lines are "accepted", but when I click "finished" to preview the finished labels, I get an #error on every line that has more than one field, but the lines with only one field print out as expected.If I then go into the DESIGN mode, each line with more than one field displays:

=Trim([field-x] & " " & [field-z]), where the " " is related to the space I place between field-x and field-z.

During this process I also get a box with the message "Enter Parameter Value", and below that is the text, "Trim", with a box in which to insert some kind of "parameter". I have absolutely no clew what to put into the "box", and no where in the 812 page, "The Missing Manual" is the question answered.I have wasted approximately five hours trying to solve this issue, including google searches for potential answers, some of which seem reasonable, but do not work when implemented. At this point I am ready to trash ACCESS and move on to some other process.

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I have the following info in a table - I am trying to make a file to import into a label printing program. I have qty 5 of item X13 and so need 5 labels for it, 3 of X24's and so on. The output is basically a print file that will print the right quantity of labels for each of the names equipment.

Name; number
X13; 5
X24; 3
X77; 1

I need an output file as follows, in excel or query result:


X13
X13
X13
X13
X13
X24
X24
X24
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How do i achieve this in a query or do I need code and if so what would it look like..

Thanks

Steve

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Hi guys,

I have a form (frmMain) which contains 3 subforms and they are being set to visible at different stages of application run (depending on the options selected).

In subfrm_Main_options i have 3 buttons, clicking on 'Job Review' will make the subfrm_Search visible. In the subfrm_Search i have 2 labels, 'View Jobs' and 'View Report' and I only want the 'View Jobs' to be visible!

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Can any1 please help me out with this. I would be really grateful!

PS. The buttons appearing on the form are placed on the frmMain, I did that to see if it appears on the main form but they must be in subfrm_Search!

The database is attached!

Thanks, Maisam

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I sent a post earlier today about making a label visible in a subform! I am still working on it but still no progress!

I have a different scenario (its the same thing but trying to explain the method i'm working on):

I have one main form (frmMain) that contains 3 subforms, say subfrm1, subfrm2 and subfrm3. On Open only 1 is visible and 2 and 3 are invisible (however they are open and loaded).

By choosing an option on 1 subfrm2 becomes available! When choosing an option on subfrm1 a boolean called 'XXX' is set to true. Now i want one particular label to become visible in subfrm2 if 'XXX' is true! To do this i need to write a code to be executed when subfrm2 is appears on screen! The problem is this form is already open so how and on which event of subfrm2 can i write the code???

At the moment i'm trying to refresh subfrm2 (by using code in subfrm1) and I have placed my code on the On Load event of subfrm2. I thought this way the form will reload and the On Loand event will pick up the new value for boolean XXX and set the label to visible! Thats the idea anyway... here is the code i have in subfrm1:

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Forms![frmMain].subfrm2.Form.Refresh

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I'm not sure if refreshing the subform will result in On Load event to be executed! And i'm not even sure that the code for refreshing subfrm2 is correct. Can any1 help me with this?

I have attached the actual database on my previous post sent today, if you prefer to look at the whole thing and get a feel of the problem!

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Here's the statement

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