'joining' Results Of 2 Queries

Jul 20, 2005

Does anyone know how I can 'join' the results of
one SQL query to the bottom of another?

Eg. I have two queries:


1. SELECT Name, Surname FROM People WHERE Surname = Smith


NAME SURNAME

Adam Smith
John Smith
Michael Smith
Steve Smith


2. SELECT Name, Surname FROM People WHERE Surname = Jones


NAME SURNAME

Bob Jones
Larry Jones
Tom Jones



What I want to produce is:


NAME SURNAME

Adam Smith
John Smith
Michael Smith
Steve Smith
Bob Jones
Larry Jones
Tom Jones


However, if I use UNION like this:

SELECT Name, Surname FROM People WHERE Surname = Smith
UNION
SELECT Name, Surname FROM People WHERE Surname = Jones


it mixes up all the results:

NAME SURNAME

Adam Smith
Bob Jones
John Smith
Larry Jones
Michael Smith
Steve Smith
Tom Jones


(I guess it's sorting by the first field, NAME).

Is there a way to stop it sorting the results, so that it
just tacks the second query results to the bottom of the
first query results?


(I realise I could use "ORDER BY Surname" to get the same result
in this simple example, but for the more complicated queries
I want to use it won't work).

Thanks for any help,

Matt.

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If I run SELECT FULLTEXTCATALOGPROPERTY(N'CatalogName',N'UniqueKeyCount'), I get a result of 2. I have got two full-text indexes in this catalog (one on the FileTable, one on a regular table with FT enabled). Is this result therefore expected? Again, reading online seems to suggest that a result of 0 is desirable, but I don't understand why, and if it is I don't understand why my result is 2!

I've now also run SELECT* FROM sys.dm_fts_index_keywords(DB_ID('DatabaseName'), Object_ID('dbo.FileTableName)), which I believe is supposed to list all of the indexed words from the table specified. I get one row returned, as follows:

keyword: 0xFF
display_term: END OF FILE
column_id: 2
document_count: 40

So basically, it's not indexed any words at all. And why is the document count only 40 when there are 96 documents in the folder and table?

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Right now, I'm doing it this way.

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(
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[Code] .....

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Hi All,
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