A Simple TSQL To Find The Last N RUN Status Of The SQL Jobs / Job History

Replace the <<job name>> with the actual job name
---Last n RUN status of the job------


SELECT TOP 20

SJ.name 'JOB Name'

,'Run date : ' +

REPLACE(CONVERT(varchar,convert(datetime,convert(varchar,run_date)),102),'.','-')+' '+

SUBSTRING(RIGHT('000000'+CONVERT(varchar,run_time),6),1,2)+':'+SUBSTRING(RIGHT('000000'+CONVERT(varchar,run_time),6),3,2)+':'+SUBSTRING(RIGHT('000000'+CONVERT(varchar,run_time),6),5,2) 'Start Date Time'

,SUBSTRING(RIGHT('000000'+CONVERT(varchar,run_duration),6),1,2)+':'+SUBSTRING(RIGHT('000000'+CONVERT(varchar,run_duration),6),3,2)+':'+SUBSTRING(RIGHT('000000'+CONVERT(varchar,run_duration),6),5,2) 'Duration'

,CASE run_status WHEN 1 THEN '1-SUCCESS' WHEN 0 THEN '0-FAILED' ELSE CONVERT(varchar,run_status) END AS 'Status'
,Step_id

,[Message]

,[Server]

FROM MSDB..SysJobHistory SJH

RIGHT JOIN MSDB..SysJobs SJ

ON SJ.Job_Id = SJH.job_id

WHERE SJ.name LIKE '%<<job name>>%'

AND Step_ID = 0 --Comments this line if you want to see the status of each step of the job

ORDER BY run_date DESC, run_time DESC, step_ID DESC

---Last n RUN status of the job---------