Add A Column To Existing Script

Jan 6, 2014

Using Banner and Oracle DB. I have to add pay id to an existing script. One of the table names that pay id exists on is phrhist. I want to add phrhist_pict_code, phrhist_payno to the existing sql below:

select distinct spriden_id as GWID, spriden_last_name as LAST_NAME, spriden_first_name as FIRST_NAME, x.pdrdedn_amount1 as Amount,
x.pdrdedn_bdca_code as BDCA_CODE, x.pdrdedn_ref_no as REF_NO, x.pdrdedn_status as STATUS, x.pdrdedn_effective_date as Eff_Date, pebempl_ecls_code as ECLS
from spriden, pebempl, pdrdedn x, pdrbded, spbpers
where spriden_pidm = pebempl_pidm

[Code] ....

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Integration Services :: Add New Column Based On Existing Column Using Derived Column Task?

Jul 28, 2015

I have a excel file which has a column called "Code" and their values are A,B,C,D,E,F,G,H.  I want to create a new column called "status" based on the values of "Code".

Code:

A
B
C
D
E
F
G
H

If A,C,E,G then "status" = "Active" else if  B,D,F,H then "Status" = "Inactive". I like to do it using "Derived Column".

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Mar 5, 2004

Hi,

I have a column that is unique that I would like to make into an IDENTITIY column after I insert some data into it.

I tried

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alter column <col_name> int Identity (1,1)

but it fails.


Ajay

WORD4LIFE
(http://www.word4life.com)

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Mar 30, 2004

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Thanks.

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Jul 20, 2005

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Nov 28, 2007

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Nov 14, 2007

Hi everyone!

I just started with SQL and SQL Server 2005. I cantfind in my books how to add a column to an existing table. It should be a primary key, auto_increment column.

Hope someone can help, many thanks in advance

Greetings from Vienna Austria

landau

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Mar 1, 2006

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Apr 22, 2008

I have a table for blog comments I want to add a column that counts the number of comments for each article.
existing table looks like this:
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commentAuthor
authorEmail
comment
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Mar 5, 2004

I have an existing table (see below).

-----------
[FormCode] [varchar] (4) NULL ,
[FiscalYear] [char] (4) NULL
-----------

I want to add the column below after the [FormCode] when my SPROC runs.
-----------
[FiscalMonth] [char] (2) NULL
-----------

Any ideas would be a big help?
TIF

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Oct 24, 2007

I Have table Emp contains 3 columns one column is EName that datatype is char. now I want to change char to Varchar(4) . but column is primary key . and it is refernced by othertable columns .


i write query
alter table emp alter column ename varchar(4)
but it throws an error is
Msg 5074, Level 16, State 1, Line 1
The object 'PK_emp is dependent on column 'Ename'.
Msg 4922, Level 16, State 9, Line 1
ALTER TABLE ALTER COLUMN ename failed because one or more objects access this column.

please help me
asap.
Regards
Swamy

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Mar 9, 2000

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This gives me a syntax error.

The column was originally added with a default constraint of 1 to a 2.6 million row table.
I dropped the existing constraint and need to add the new default constraint of 0 for that column.

Anyone have any ideas? Thanks in advance.

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Jul 20, 2004

Hi,
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I know how to change the seed :
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but I need the future id generated with step 2
4233596
4233598
4233600
I would like to do it using T-sql because I will need to do it every day after syncronising with another SQL server .

Thanks,
Natalia

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Dec 5, 2005

Sorry I'm pretty new to SQL so I don't know if this is a simple question. I have a table, and I am trying to add a column to the table and populate this column using what would be called an 'IF' function in Excel.

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Any ideas?

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Mar 30, 2006

Hi All,
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Jan 21, 2014

I want to add new primary key into existing table which already has a primary key. But,I do not want to remove the old primary key, since there are many records and the old primary key also have relationship with other table

When I am using this query:

alter table hem154
add indexNO uniqueidentifier default newid()

alter table hem154
add CONSTRAINT pk_hem154_indexNo PRIMARY KEY (PK_indexNO)
go

Note:
Hem154 ~ Table name
indexNo ~ Column Name

I get this runtime error:

Msg 1779, Level 16, State 0, Line 1
Table 'hem154' already has a primary key defined on it.
Msg 1750, Level 16, State 0, Line 1

Could not create constraint. See previous errors.

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Thanks in advance!

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Sep 11, 2006

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thx

Kat

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Feb 20, 2008



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Thanks in advance.

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Feb 4, 2006

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I am looking for a way to create a temp column who's value would take the value of another column and prepend a value like this to it "domain". This is the Select statement I currently have:

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Mar 7, 2008

Need help,

I'm a newby to SQL and looking for how-to-help.
I have an existing DB and within a certain table, I have created a new Column via Studio manager, but need help with the following:

Need to make the new Col "Unique, and Indexed" but cannot see anywhere in studio manager interface to do it.

Thanks.

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Sep 3, 2015

We want to add a new int identity column as a primary key to an already existing table that has a primary key on Guid. Here is the DDL:

CREATE TABLE [dbo].[VRes](
[VResID] [uniqueidentifier] NOT NULL,
[Mes] [varchar](max) NOT NULL,
[PID] [uniqueidentifier] NOT NULL,
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[code]....

Also we currently have 3 million rows on this table. Is having an integer column as identity column and primary key better or shd I consider using BigInt?

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Mar 7, 2008

How do i drop/remove the identity property for an existing column in all Tables where the Identity column is a primary key.
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select pk.table_name, c.column_name,

from information_schema.table_constraints pk

INNER JOIN information_schema.key_column_usage c ON c.TABLE_NAME = pk.TABLE_NAME

and c.constraint_name = pk.constraint_name

where constraint_type = 'PRIMARY KEY'

and COLUMNPROPERTY(object_id(pk.table_name), column_name, 'IsIdentity') = 1

ORDER BY pk.table_name, c.column_name

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Jun 22, 2015

Currently I have a column with multiple postcodes in one value which are split with the “/” character along with the corresponding location data. What I need to do is split these postcode values into separate rows while keeping their corresponding location data.

For example
PostCode            Latitude               Longitude
66000/66100       42.696595            2.899370
20251/20270       42.196471            9.404951

Would become
PostCode            Latitude               Longitude
66000                    42.696595            2.899370
66100                    42.696595            2.899370
20251                    42.196471            9.404951
20270                    42.196471            9.404951

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