Alignment Problem With SQL Server 2000

Jan 9, 2004

Greeting
I have more than one language installed on my computer, and I tried to use my Enterprise Manager yesterday... What Im getting is with all the GUI im using Im having everything is Right Aligned.....
Any help as to what I should change?
Thanks
This is my first post so would be great to have a qucik and handy answer :D

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SQL Server 2008 :: Index Alignment In Partitioning?

Apr 1, 2015

I've yet to use partitioning in a production environment, and pretty much last ran any partitioning related code a few years back when looking at certification; so I'm definitely not an expert on the matter and only loosely clued up on the concepts.

I've recently started with a new employer, and they have just implemented a new system for sms messaging. The database tables tracking the sms messages being sent are going to get big and so they have created decided to implement partitioning on some of the tables using a partition scheme on the CreatedDate column; the DBA involved in designing the partitioning has left and I'm picking this up.

The relevant DDL for the table is below:-

CREATE TABLE [Message].[Sms](
[SmsId] [bigint] IDENTITY(250000001,1) NOT NULL,
[CreatedDate] [datetime] NOT NULL CONSTRAINT [DF_Sms:CreatedDate] DEFAULT (getdate()),
CONSTRAINT [PK_Sms:SmsId] PRIMARY KEY NONCLUSTERED

[code]....

There are some issues with the above that I will be addressing seperately (e.g. the clustered index should be unique as it contians the unique key, and the fillfactors are daft), but my concerns for this post are below.

1) How to define the Primary Key and enforce it's uniqueness whilst trying to ensure it's aligned with the partition in order to be able to switch out old data once an as yet undefined retention period has passed. In books online it states:- "If it is not possible for the partitioning column to be included in the unique key, you must use a DML trigger instead to enforce uniqueness. " Books online - Special Guidelines for Partitioned Indexes. However, I'm not sure what this means, nor how I create the primary key to use the partition function seeing as it doesn't have the CreatedDate in the unique key?

2) The original partition function was envisaged as the following:-

CREATE PARTITION FUNCTION [DateFunction](datetime) AS RANGE
LEFT FOR VALUES (N'2014-01-01T00:00:00.000'
, N'2014-04-01T00:00:00.000'
, N'2014-07-01T00:00:00.000'
, N'2014-10-01T00:00:00.000'
, N'2015-01-01T00:00:00.000'
, N'2015-04-01T00:00:00.000'
, N'2015-04-02T00:00:00.000'
, N'2015-04-03T00:00:00.000'
, N'2015-04-04T00:00:00.000'
, N'2015-04-05T00:00:00.000')
GO

There is a procedure that has been created and scheduled daily that will create a new partition for each day, and then merge these together at the end of the quarter. My understanding of partitioning is that this is a bad idea, as it will result in merging several populated partitions together. Is my understanding correct? If so, I'm planning on removing the day partitions at the end of the function, and simply adding quarterly partitions, maintaining a spare empty partition at the end of the table. Would this make more sense?

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Disk 0 is now the selected disk.
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  Partition ###  Type              Size     Offset

[code]....

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Report in question is an invoice form. It requires an absolutely bottom-of-page aligned footer that has databound elements. This is so that whatever page that footer finally appears on will print in such a way that the address will align in a windowed envelope. Ironically, Books Online gives this exact scenario in explaining headers and footers in SSRS, but they cleverly don't explain how an absolutely bottom-of-page-aligned and data-bound footer can be made to happen. Headers at absolute page top is obviously no problem. Footers at page bottom, not so much.So, this is not a "page footer"--page footers are employed in the body. Also this footer is databound, so a page footer as it's known in SSRS is out the window anyway.

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Parameter
Access 2000/XP
SQL Server 7.0
SQL Server 2000
MSDE 2000

Number of instances per server
n/a
n/a
16
16

Number of databases per instance / server
n/a
32,767
32,767
32,767

Number of objects per database
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2,147,483,647
2,147,483,647

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16,379
16,379

Number of roles per database
n/a
16,367
16,367
16,367

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1,048,516 TB
1,048,516 TB
2 GB

Number of columns per table
255
1024
1024
1024

Number of rows per table
limited by storage
limited by storage
limited by storage
limited by storage

Number of bytes per row





(Excluding TEXT/MEMO/IMAGE/OLE)
2 KB
8 KB
8 KB
8 KB

Number of columns per query
255
4,096
4,096
4,096

Number of tables per query
32
256
256
256

Size of procedure / query
64 KB
250 MB
250 MB
250 MB

Number of input params per procedure / query
199
1,024
2,100
2,100

Size of SQL statement / batch
64 KB
64 KB
64 KB
64 KB

Depth of subquery nesting
50
32
32
32

Number of indexes per table
32
250 (1 clustered)
250 (1 clustered)
250 (1 clustered)

Number of columns per index
10
16
16
16

Number of characters per object name
64
128
128
128

Number of concurrent user connections
255
32,767
32,767
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