Associative Entity - Combining Result

Mar 12, 2008

Hi,

I have the following table

(1) Item Table
ItemID Name
1 Sample Item

(2) Brand Table
BrandID Name
1 Sample Brand - 1
2 Sample Brand - 2


(3) ItemBrand Table
ItemID BrandID
1 1
1 2


Desired Output

ItemID ItemName Brand1 Brand2
--------------------------------------------------------
1 Sample Item Sample Brand - 1 Sample Brand - 2

How to get the desired output?

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I'm trying to generate a list of that shows customer counts before and after for each program, some which may be null for one, but have counts for the other. I have tries creating 2 separating views and joining them but that doesn't work because it only returns the ones they have in common.

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May 14, 2014

Below is my sample table and data

With Item as(
Select 1 as ItemId,'ItemName1' as ItemName,100 as position union all
Select 2 as ItemId,'ItemName2' as ItemName,200 as position union all
Select 3 as ItemId,'ItemName3' as ItemName,300 as position union all
Select 4 as ItemId,'ItemName4' as ItemName,400 as position union all
Select 5 as ItemId,'ItemName5' as ItemName,500 as position union all
Select 6 as ItemId,'ItemName6' as ItemName,600 as position union all
Select 7 as ItemId,'ItemName7' as ItemName,700 as position),

Mapping as (
Select 1 as Parent, 2 as child union all
Select 1 as Parent, 3 as child union all
Select 1 as Parent, 4 as child union all
Select 5 as Parent, 6 as child union all
Select 5 as Parent, 7 as child )Expected Result:

ParentItemIdParentItemNameParentpositionChildItemIdChildItemNameChildposition
1ItemName11002ItemName2200
1ItemName11003ItemName3300
1ItemName11004ItemName4400
5ItemName55006ItemName6600
5ItemName55007ItemName7700

I was thinking to achieve using union all but if i use union all it will combine the result in rows level. but i need in column level.

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Aug 1, 2006

First of all, we are using SQL Server 2005 with a SQL Mobile subscriber and we are attempting to use Data Partitions on our current database
schema which contains associative tables for many-to-many relationships.

We have two tables, a User table
and an Audit table. A user can be
assigned more than one Audit. An Audit
can be assigned to more than one User.
So an AuditUser associative table exists. If data partitions are used based on User,
then any Audits that are assigned to one or more users should be copied to the
proper partition for each User (the msmerge_current_partition_mappings table
with the proper partition_id values).



In order to insert records with such a schema, the following
steps occur in order:

Insert
new row into Audit table with new rowguidInsert
entry into AuditUser table associating the auditguid with every userguid that
is assigned this audit.



Merge replication triggers are fired on insert of the Audit
row and another one for the insert of the AuditUser row.



When the Audit row is inserted, the replication trigger follows
the following logic:

Inserts
a copy of that row into the msmerge_contents table. Evaluates
the row to determine which partition(s) this row should be copied to as
well (msmerge_current_partition_mappings table). To do this, it checks to see if the
AuditGuid is referenced in one or more AuditUser rows. Since we haven€™t inserted the AuditUser
row at this point, the trigger€™s logic doesn€™t find a partition to copy
this row to.



When the AuditUser row is inserted, the replication trigger performs
the same logic as with the Audit row, it:

Inserts
a copy of that row into the msmerge_contents table.Evaluates
the row to determine which partition(s) this row should be copied to as
well (msmerge_current_partition_mappings table). Since the row meets the criteria for one
or more partitions, it is copied to the msmerge_current_partition_mappings
table for each partition that exists.



When replication occurs, we see only the AuditUser rows
copied down to our device, and not the corresponding Audit rows. Now that we understand the triggers, it is
plain to see why. If the AuditUser row
could be inserted first, then the trigger on the Audit row would copy that row
into the proper partitions and all would work well. However, the Audit row must be inserted
first, so that foreign key relationship constraints are preserved.



It seems that the Update trigger on the AuditUser row
actually walks the relationships and copies any related child rows to the
msmerge_current_partition_mappings table.

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USE [CGB]
GO
/****** Object: Table [dbo].[ePID_BHID] Script Date: 04/15/2015 15:48:14 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON

[code]....

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|_________> Hospital Entity

| | |

| | V

| | Clinic A

| | - Jane Doe MD

| | - Janette Brown MD

| | ACME Clinic

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UDF_table.sql:

USE AdventureWorks;

GO

IF OBJECT_ID(N'dbo.ufnGetContactInformation', N'TF') IS NOT NULL

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GO

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(

-- Columns returned by the function

ContactID int PRIMARY KEY NOT NULL,

FirstName nvarchar(50) NULL,

LastName nvarchar(50) NULL,

JobTitle nvarchar(50) NULL,

ContactType nvarchar(50) NULL

)

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@LastName nvarchar(50),

@JobTitle nvarchar(50),

@ContactType nvarchar(50);

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SELECT

@ContactID = ContactID,

@FirstName = FirstName,

@LastName = LastName

FROM Person.Contact

WHERE ContactID = @ContactID;

SELECT @JobTitle =

CASE

-- Check for employee

WHEN EXISTS(SELECT * FROM HumanResources.Employee e

WHERE e.ContactID = @ContactID)

THEN (SELECT Title

FROM HumanResources.Employee

WHERE ContactID = @ContactID)

-- Check for vendor

WHEN EXISTS(SELECT * FROM Purchasing.VendorContact vc

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ON vc.ContactTypeID = ct.ContactTypeID

WHERE vc.ContactID = @ContactID)

THEN (SELECT ct.Name

FROM Purchasing.VendorContact vc

INNER JOIN Person.ContactType ct

ON vc.ContactTypeID = ct.ContactTypeID

WHERE vc.ContactID = @ContactID)

-- Check for store

WHEN EXISTS(SELECT * FROM Sales.StoreContact sc

INNER JOIN Person.ContactType ct

ON sc.ContactTypeID = ct.ContactTypeID

WHERE sc.ContactID = @ContactID)

THEN (SELECT ct.Name

FROM Sales.StoreContact sc

INNER JOIN Person.ContactType ct

ON sc.ContactTypeID = ct.ContactTypeID

WHERE ContactID = @ContactID)

ELSE NULL

END;

SET @ContactType =

CASE

-- Check for employee

WHEN EXISTS(SELECT * FROM HumanResources.Employee e

WHERE e.ContactID = @ContactID)

THEN 'Employee'

-- Check for vendor

WHEN EXISTS(SELECT * FROM Purchasing.VendorContact vc

INNER JOIN Person.ContactType ct

ON vc.ContactTypeID = ct.ContactTypeID

WHERE vc.ContactID = @ContactID)

THEN 'Vendor Contact'

-- Check for store

WHEN EXISTS(SELECT * FROM Sales.StoreContact sc

INNER JOIN Person.ContactType ct

ON sc.ContactTypeID = ct.ContactTypeID

WHERE sc.ContactID = @ContactID)

THEN 'Store Contact'

-- Check for individual consumer

WHEN EXISTS(SELECT * FROM Sales.Individual i

WHERE i.ContactID = @ContactID)

THEN 'Consumer'

END;

-- Return the information to the caller

IF @ContactID IS NOT NULL

BEGIN

INSERT @retContactInformation

SELECT @ContactID, @FirstName, @LastName, @JobTitle, @ContactType;

END;

RETURN;

END;

GO

----------------------------------------------------------------------
I executed it in my SQL Server Management Studio Express and I got: Commands completed successfully. I do not know where the result is and how to get the result viewed. Please help and advise.

Thanks in advance,
Scott Chang

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