Automatic ID In A Primary Key?

CREATE TABLE [dbo].[tblProve](
[ID][varchar](50)NOT NULL,
[tempCountrys][varchar](100) NULL,

CONSTRAINT [PK_tblProve] PRIMARY KEY CLUSTERED
([ID] ASC) WITH (PAD_INDEX = OFF, IGNORE_DUP_KEY = OFF) ON [PRIMARY]
) ON [PRIMARY]
GO

I have a table "dbo.tblProve" that have a Primery Key ID of type
varchar(10) and this primary key have a Default value or Binding like this:
([dbo].[fnc_ProveNewID]())

This function "dbo.fnc_ProveNewID()" finds the max(ID) in the same table and creates the next ID.

When I insert a record into the table dbo.tblProve the function creates the new ID automatically (this is the format of the ID '0000000001' or '000000010' etc. ). But when I insert a lot of records from a Select Query it displays this message below:

Msg 2627, Level 14, State 1, Line 2
Violation of PRIMARY KEY constraint 'PK_tblProve'. Cannot insert duplicate key in object 'dbo.tblProve'.
The statement has been terminated.

Is there any way to create a new ID into a table automatically without to be inserted by the user or client?.