Calculating The Size Of A Table In A Db

Aug 10, 2006

If I have a database with a list of tables is there a way to calculate the size of each table individually and
then calculate the size all the tables. If you have 1 table with say 10 rows and 3 columns and the width of the
columns are of variable length you could do something like

( column1width + column2width + column3width ) * No.of Rows = Tablesize

So my question is can I reference the column width of different columns in a
table using sql ?

Another issue is that some of the columns are different datatypes so I should be taking that
into consideration as well.

From searching the internet so far I have seen little on SQL showing how to
reference column width in a table.

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Calculating Size Of A Table

Aug 7, 2000

I would like to calculate the size of a table eg. 100 rows, 5 columns.

Any suggestions?? Thanks Vic

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Calculating Size Of Database

Aug 11, 2000

I need to calculate the size of a database. Is the following formula correct??
(a) The size of a record (i.e. sum of all the columns) divide by 8Kb.
(b) Divide number of records by answer from (a)
(c) Multiple (b) by 8Kb
(d) Sum up the tables


Thanks,
Vic

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Calculating The Record Size.

Feb 8, 2000

How do I calculate the Record size? I mean the Row size for each table.
I heard that there are formulas to do that and the calculation is different for Fixed lenght Columns and Variable length Columns.

I need to calculate the record size for nearly 500 tables.This will help me to decide on the DISk capacities.

Suggest me if any scipts or calculations already available.

Thanks in advance.

Samson

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Jan 1, 2004

Hi , everyone !

I need help . Is anybody can help me to finde transact-SQL code of calculating the database size.

Thanks in advnce , Alex

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Calculating Row Size Including Blobs

Jul 20, 2005

I've seen plenty of posts regarding the estimation of table size,usually in the processing of planning for server storage needs.Well, I've got a different problem. I need to know how much data eachof our Customers are using in a Database. (1 SQL DB stores multiplecustomers).Basically, I want to be able to say: Customer A: 45.5 MB, Customer B:655 MB.So, how can I ask SQL Server how much data each Row in each table istaking up? I want to be able to calculate nightly the total size, so Iwould take each row in each table that belong to the customer, and addall the sizes together. I want to take into account blobs that arestoring images and PDF files also.Thanks in advance,Jesse Wolgamott

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SQL Server Admin 2014 :: Possible To Find Table Size And In That Table Each Row Size

Jun 10, 2014

It is possible to find table size and in that table each row size.

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Calculating Value From Two Separate Rows In The Same Table And Inserting As New Row In The Same Table

Jan 19, 2008

Code Block


Hi,

I'm working on a database for a financial client and part of what i need to do is calculate a value from two separate rows in the same table and insert the result in the same table as a new row. I have a way of doing so but i consider it to be extremely inelegant and i'm hoping there's a better way of doing it. A description of the existing database schema (which i have control over) will help in explaining the problem:

Table Name: metrics_ladder

id security_id metric_id value
1 3 80 125.45
2 3 81 548.45
3 3 82 145.14
4 3 83 123.32
6 4 80 453.75
7 4 81 234.23
8 4 82 675.42
.
.
.

Table Name: metric_details

id metric_id metric_type_id metric_name
1 80 2 Fiscal Enterprise Value Historic Year 1
2 81 2 Fiscal Enterprise Value Current Fiscal Year
3 82 2 Fiscal Enterprise value Forward Fiscal year 1
4 83 2 Fiscal Enterprise Value Forward Fiscal Year 2
5 101 3 Calendar Enterprise value Historic Year 1
6 102 3 Calendar Enterprise Value Current Fiscal Year
5 103 3 Calendar Enterprise value Forward Year 1
6 104 3 Calendar Enterprise Value Forward Year 2

Table Name: metric_type_details

id metric_type_id metric_type_name
1 1 Raw
2 2 Fiscal
3 3 Calendar
4 4 Calculated

The problem scenario is the following: Because a certain number of the securities have a fiscal year end that is different to the calendar end in addition to having fiscal data (such as fiscal enterprise value and fiscal earnings etc...) for each security i also need to store calendarised data. What this means is that if security with security_id = 3 has a fiscal year end of October then using rows with ids = 1, 2, 3 and 4 from the metrics_ladder table i need to calculate metrics with metric_id = 83, 84, 85 and 86 (as described in the metric_details table) and insert the following 4 new records into metrics_ladder:

id security_id metric_id value
1 3 101 <calculated value>
2 3 102 <calculated value>
3 3 103 <calculated value>
4 3 104 <calculated value>

Metric with metric_id = 101 (Calendar Enterprise value Historic Year 1) will be calculated by taking 10/12 of the value for metric_id 80 plus 2/12 of the value for metric_id 81.

Similarly, metric_id 102 will be equal to 10/12 of the value for metric_id 81 plus 2/12 of the value for metric_id 82,

metric_id 103 will be equal to 10/12 of the value for metric_id 82 plus 2/12 of the value for metric_id 83 and finally

metric_id 104 will be NULL (determined by business requirements as there is no data for forward year 3 to use).

As i could think of no better way of doing this (and hence the reason for this thread) I am currently achieving this by pivoting the relevant data from the metrics_ladder so that the required data for each security is in one row, storing the result in a new column then unpivoting again to store the result in the metrics_ladder table. So the above data in nmetrics_ladder becomes:

security_id 80 81 82 83 101 102
----------- -- -- -- -- -- --
3 125.45 548.45 145.14 123.32 <calculated value> <calculated value>
4 ...
.
.
.

which is then unpivoted.

The SQL that achieves this is more or less as follows:

*********
START SQL
*********

declare @calendar_averages table (security_id int, [101] decimal(38,19), [102] decimal(38,19), [103] decimal(38,19), [104] decimal(38,19),etc...)


-- Dummy year variable to make it easier to use MONTH() function
-- to convert 3 letter month to number. i.e. JAN -> 1, DEC -> 12 etc...
DECLARE @DUMMY_YEAR VARCHAR(4)
SET @DUMMY_YEAR = 1900;

with temp(security_id, metric_id, value)
as
(
select ml.security_id, ml.metric_id, ml.value
from metrics_ladder ml
where ml.metric_id in (80,81,82,83,84,85,86,87,88,etc...)
-- only consider securities with fiscal year end not equal to december
and ml.security_id in (select security_id from company_details where fiscal_year_end <> 'dec')
)
insert into @calendar_averages
select temppivot.security_id
-- Net Income
,(CONVERT(DECIMAL, MONTH(cd.fiscal_year_end + @DUMMY_YEAR))/12*[80])
+((12 - CONVERT(DECIMAL, MONTH(cd.fiscal_year_end + @DUMMY_YEAR)))/12*[81]) as [101]
,(CONVERT(DECIMAL, MONTH(cd.fiscal_year_end + @DUMMY_YEAR))/12*[81])
+((12 - CONVERT(DECIMAL, MONTH(cd.fiscal_year_end + @DUMMY_YEAR)))/12*[82]) as [102]
,(CONVERT(DECIMAL, MONTH(cd.fiscal_year_end + @DUMMY_YEAR))/12*[82])
+((12 - CONVERT(DECIMAL, MONTH(cd.fiscal_year_end + @DUMMY_YEAR)))/12*[83]) as [103]
,NULL as [104]
-- Share Holders Equity
,(CONVERT(DECIMAL, MONTH(cd.fiscal_year_end + @DUMMY_YEAR))/12*[84])
+((12 - CONVERT(DECIMAL, MONTH(cd.fiscal_year_end + @DUMMY_YEAR)))/12*[85]) as [105]
,(CONVERT(DECIMAL, MONTH(cd.fiscal_year_end + @DUMMY_YEAR))/12*[85])
+((12 - CONVERT(DECIMAL, MONTH(cd.fiscal_year_end + @DUMMY_YEAR)))/12*[86]) as [106]
,(CONVERT(DECIMAL, MONTH(cd.fiscal_year_end + @DUMMY_YEAR))/12*[86])
+((12 - CONVERT(DECIMAL, MONTH(cd.fiscal_year_end + @DUMMY_YEAR)))/12*[87]) as [107]
,NULL as [108]
-- Capex
-- Sales
-- Accounts payable
etc...
..
..
from temp
pivot
(
sum(value)
for metric_id in ([80],[81],[82],[83],[84],[85],[86],[87],[88],etc...)
) as temppivot
inner join company_details cd on temppivot.security_id = cd.security_id

*********
END SQL
*********

The result then needs to be unpivoted and stored in metrics_ladder.

And FINALLY, the question! Is there a more elegant way of achieving this??? I have complete control over the database schema so if creating mapping tables or anything along those lines would help it is possible. Also, is SQL not really suited for such operations and would it therefore be better done in C#/VB.NET.

Many thanks (if you've read this far!)

M.

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Nov 16, 2007

I currently have 8,000 rows in the orders table and it is estimated that it will have in average 50 orders daily. The orders need to be kept for 6 months, before it is archived and deleted from the database. I calculated the amount of space that needs to be reserved for the table but unsure if I am on the right track in calculating the table size.

would there be anything wrong in my calcultation that i missed?

int
datetime
tinyint
nvarchar(15)
int
int
int
int
money
money
money
money
datetime

4
4
2
15
4
4
4
4
4
4
4
4
4
4
= 65 bytes
+ rowoverhead = 7

total = 72

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Feb 19, 2012

I need to calculate a median on a column in a table. The code I have is:

Code:
Select gender,
CASE
when gender = 'F' then 'Female'
when gender = 'M' then 'Male'
else 'Unknown'
end as test,
datediff(day, [admit_date], getdate()) as 'datediffcal',
from [tbl_record]
How do I calculate the median on the datediffcal column?

It doesn't matter if the resultset only shows the median result. So if the output shows:

median
15

that's fine. Minimally, I need the median value.

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Table Size And Database Size

Mar 2, 2008

Hi,
i use this script that show me the size of each table and do the sum of all the table size.

SELECT
X.[name],
REPLACE(CONVERT(varchar, CONVERT(money, X.[rows]), 1), '.00', '') AS [rows],
REPLACE(CONVERT(varchar, CONVERT(money, X.[reserved]), 1), '.00', '') AS [reserved],
REPLACE(CONVERT(varchar, CONVERT(money, X.[data]), 1), '.00', '') AS [data],
REPLACE(CONVERT(varchar, CONVERT(money, X.[index_size]), 1), '.00', '') AS [index_size],
REPLACE(CONVERT(varchar, CONVERT(money, X.[unused]), 1), '.00', '') AS [unused]
FROM
(SELECT
CAST(object_name(id) AS varchar(50)) AS [name],
SUM(CASE WHEN indid < 2 THEN CONVERT(bigint, [rows]) END) AS [rows],
SUM(CONVERT(bigint, reserved)) * 8 AS reserved,
SUM(CONVERT(bigint, dpages)) * 8 AS data,
SUM(CONVERT(bigint, used) - CONVERT(bigint, dpages)) * 8 AS index_size,
SUM(CONVERT(bigint, reserved) - CONVERT(bigint, used)) * 8 AS unused
FROM sysindexes WITH (NOLOCK)
WHERE sysindexes.indid IN (0, 1, 255)
AND sysindexes.id > 100
AND object_name(sysindexes.id) <> 'dtproperties'
GROUP BY sysindexes.id WITH ROLLUP) AS X
ORDER BY X.[name]

the problem is that the sum of all tables is not the same size when i make a full database backup.
example of this is when i run this query against my database i see a sum of 111,899 KB that they are 111MB,but when
i do full backup to that database the size of this full backup is 1.5GB,why is that and where this size come from?

THX

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ALTER DATABASE <DBNAME> MODIFY FILE ( NAME = <DBLOGFILENAME, SIZE = 2 ) "



And I'm getting "MODIFY FILE failed. Specified size is less than current size." I tried going into the database properties and setting the log file to 2M, but it doesn€™t keep the changes.



Any help with this process?

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Mar 1, 2002

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Thank you very much.

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Hello, Everyone,

Can anyone tell me how to find the size of a table in a DB?

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hello all,

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-------------------------------------------------------------------------------------------------------------------------------- ----------- ------------------ ------------------ ------------------ ------------------
DUNS_SITE 100000 401288 KB 400000 KB 1264 KB 24 KB

its using only 97.3 MB

name rows reserved data index_size unused
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