Can't See Designer View In Asp.net 2005

Aug 29, 2006

Hi All,

I am using VS2005 Trial version, In my website project i can't able to see Designer View of all .aspx files but i can able to view code part. Earlier days i can able to see Designer page but now i can't do why? This problem occurs even new website project also.

Can any one help me?

Thanks in advance

Regards

Nat Raja



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-- Create Test Data Table CustomerListTom and Views

USE AdventureWorks
GO

IF EXISTS (SELECT * FROM sys.views WHERE object_id = OBJECT_ID(N'ViewATom'))
DROP VIEW [ViewATom]

IF EXISTS (SELECT * FROM sys.views WHERE object_id = OBJECT_ID(N'ViewBTom'))
DROP VIEW [ViewBTom]

IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'CustomerListTom') AND type in (N'U'))
DROP TABLE CustomerListTom
GO

CREATE TABLE [dbo].[CustomerListTom](
[CustomerID] [varchar](6) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL,
[RegionID] [varchar](3) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL,
[FirstName] [dbo].[Name] NOT NULL,
[LastName] [dbo].[Name] NOT NULL,
[EmailAddress] [nvarchar](50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
[AddressLine] [nvarchar](60) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL,
[AddressCity] [nvarchar](30) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL,
[AddressState] [nchar](3) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL,
[AddressZip] [nvarchar](15) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL,
[AddressCountry] [dbo].[Name] NOT NULL,
[Phone] [dbo].[Phone] NULL,
[BillAddressLine] [nvarchar](60) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL,
[BillAddressCity] [nvarchar](30) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL,
[BillAddressState] [nchar](3) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL,
[BillAddressZip] [nvarchar](15) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL,
[BillAddressCountry] [dbo].[Name] NOT NULL,
[BillPhone] [dbo].[Phone] NULL,
[ModifiedDate] [datetime] NOT NULL,
)

INSERT INTO CustomerListTom
SELECT
CustomerID = RIGHT(cu.AccountNumber,6),
RegionID = RIGHT('000'+CAST(cu.TerritoryID AS VARCHAR(3)),3),
FirstName = ct.FirstName,
LastName = ct.LastName,
EmailAddress = ct.EmailAddress,
AddressLine = ad.AddressLine1,
AddressCity = ad.City,
AddressState = sp.StateProvinceCode,
AddressZip = ad.PostalCode,
AddressCountry = sp.[Name],
Phone = ct.Phone,

BillAddressLine = ad.AddressLine1,
BillAddressCity = ad.City,
BillAddressState = sp.StateProvinceCode,
BillAddressZip = ad.PostalCode,
BillAddressCountry = sp.[Name],
BillPhone = ct.Phone,

ModifiedDate = cu.ModifiedDate
--,*
FROM Sales.Customer cu
JOIN Sales.Individual id ON id.CustomerID = cu.CustomerID
JOIN Person.Contact ct ON ct.ContactID = id.ContactID
JOIN Sales.CustomerAddress ca ON cu.CustomerID = ca.CustomerID
JOIN Person.Address ad ON ad.AddressID = ca.AddressID
JOIN Person.StateProvince sp ON sp.StateProvinceID = ad.StateProvinceID


-- Create a big enough set of data for testing
DECLARE @i INT
SET @i = 1
WHILE (@i < 30)
BEGIN
INSERT INTO CustomerListTom
SELECT TOP 15 PERCENT
CustomerID = RIGHT(cu.AccountNumber,6),
RegionID = RIGHT('000'+CAST(cu.TerritoryID+@i AS VARCHAR(3)),3),
FirstName = ct.FirstName,
LastName = ct.LastName,
EmailAddress = ct.EmailAddress,
AddressLine = ad.AddressLine1,
AddressCity = ad.City,
AddressState = sp.StateProvinceCode,
AddressZip = ad.PostalCode,
AddressCountry = sp.[Name],
Phone = ct.Phone,

BillAddressLine = ad.AddressLine1,
BillAddressCity = ad.City,
BillAddressState = sp.StateProvinceCode,
BillAddressZip = ad.PostalCode,
BillAddressCountry = sp.[Name],
BillPhone = ct.Phone,

ModifiedDate = cu.ModifiedDate + CASE WHEN @i > 3 THEN 10 ELSE -25 END + @i

FROM Sales.Customer cu
JOIN Sales.Individual id ON id.CustomerID = cu.CustomerID
JOIN Person.Contact ct ON ct.ContactID = id.ContactID
JOIN Sales.CustomerAddress ca ON cu.CustomerID = ca.CustomerID
JOIN Person.Address ad ON ad.AddressID = ca.AddressID
JOIN Person.StateProvince sp ON sp.StateProvinceID = ad.StateProvinceID

SET @i = @i + 1
END


-- Cleanup - Delete Dups for PK
DELETE FROM CustomerListTom
WHERE CustomerID+RegionID IN (
SELECT CustomerID+RegionID
FROM CustomerListTom cu
GROUP BY CustomerID, RegionID
HAVING COUNT(*) > 1)

ALTER TABLE [CustomerListTom]
ADD CONSTRAINT [PK_CustomerListTom] PRIMARY KEY CLUSTERED
(
[CustomerID] ASC,
[RegionID] ASC
)

GO

-- Create Views
GO
CREATE VIEW ViewATom
AS
SELECT *
FROM CustomerListTom cu
WHERE cu.RegionID = '004'
UNION
SELECT *
FROM CustomerListTom cu
WHERE CustomerID NOT IN
(SELECT CustomerID FROM CustomerListTom c2 WHERE c2.RegionID = '004')
AND (CustomerID + CONVERT(char(8), ModifiedDate, 112) + RegionID IN
(SELECT MAX(CustomerID + CONVERT(char(8), ModifiedDate, 112) + RegionID)
FROM CustomerListTom
GROUP BY CustomerID))

GO
CREATE VIEW ViewBTom
AS
SELECT DISTINCT CustomerID
FROM CustomerListTom
GO

QUERY:

USE AdventureWorks

-- FAILURE
-- This query FAILS to return in over 15 mins, cancelled
SELECT TABLEB.CustomerID,
TABLEC.RegionID,
TABLEC.LastName,
TABLEC.FirstName
FROM ViewATom TABLEA
RIGHT OUTER JOIN ViewBTom TABLEB ON TABLEA.CustomerID = TABLEB.CustomerID
RIGHT OUTER JOIN CustomerListTom TABLEC ON TABLEC.CustomerID = TABLEB.CustomerID
WHERE TABLEB.CustomerID IN
('012870','012997','011000','011001','011002','011003','011004','011005','011006','011007',
'011008','011009','011010','011011','011012','011013','011014','011015','011016','011017',
'011018','011019','011020','011150','011153','011144','017230','017220','017254','017257',
'025338','025333','025338','025397','025389','025424','025483','025485','025682','025673',
'029478','029405','029402','029317','029109','018393'
)

return

-- SOLUTIONS
-- Change WHERE TABLEB to WHERE TABLEA, this query returns in less than 1 second
SELECT TABLEB.CustomerID,
TABLEC.RegionID,
TABLEC.LastName,
TABLEC.FirstName
FROM ViewATom TABLEA
RIGHT OUTER JOIN ViewBTom TABLEB ON TABLEA.CustomerID = TABLEB.CustomerID
RIGHT OUTER JOIN CustomerListTom TABLEC ON TABLEC.CustomerID = TABLEB.CustomerID
WHERE TABLEA.CustomerID IN
('012870','012997','011000','011001','011002','011003','011004','011005','011006','011007',
'011008','011009','011010','011011','011012','011013','011014','011015','011016','011017',
'011018','011019','011020','011150','011153','011144','017230','017220','017254','017257',
'025338','025333','025338','025397','025389','025424','025483','025485','025682','025673',
'029478','029405','029402','029317','029109','018393'
)

return

-- Remove RIGHT OUTER on TABLEB, this Query returns in less than 2 seconds
SELECT TABLEB.CustomerID,
TABLEC.RegionID,
TABLEC.LastName,
TABLEC.FirstName
FROM ViewATom TABLEA
JOIN ViewBTom TABLEB ON TABLEA.CustomerID = TABLEB.CustomerID
RIGHT OUTER JOIN CustomerListTom TABLEC ON TABLEC.CustomerID = TABLEB.CustomerID
WHERE TABLEB.CustomerID IN
('012870','012997','011000','011001','011002','011003','011004','011005','011006','011007',
'011008','011009','011010','011011','011012','011013','011014','011015','011016','011017',
'011018','011019','011020','011150','011153','011144','017230','017220','017254','017257',
'025338','025333','025338','025397','025389','025424','025483','025485','025682','025673',
'029478','029405','029402','029317','029109','018393'
)

return

-- Drop PK and run ORIGINAL query, returns in less than 4 seconds

IF EXISTS (SELECT * FROM sys.indexes WHERE object_id = OBJECT_ID(N'[dbo].[CustomerListTom]') AND name = N'PK_CustomerListTom')
ALTER TABLE [dbo].[CustomerListTom] DROP CONSTRAINT [PK_CustomerListTom]
GO

SELECT TABLEB.CustomerID,
TABLEC.RegionID,
TABLEC.LastName,
TABLEC.FirstName
FROM ViewATom TABLEA
RIGHT OUTER JOIN ViewBTom TABLEB ON TABLEA.CustomerID = TABLEB.CustomerID
RIGHT OUTER JOIN CustomerListTom TABLEC ON TABLEC.CustomerID = TABLEB.CustomerID
WHERE TABLEB.CustomerID IN
('012870','012997','011000','011001','011002','011003','011004','011005','011006','011007',
'011008','011009','011010','011011','011012','011013','011014','011015','011016','011017',
'011018','011019','011020','011150','011153','011144','017230','017220','017254','017257',
'025338','025333','025338','025397','025389','025424','025483','025485','025682','025673',
'029478','029405','029402','029317','029109','018393'
)

return


-- Create PK with NONCLUSTERED and run ORIGINAL query, returns in less than 1 second

IF EXISTS (SELECT * FROM sys.indexes WHERE object_id = OBJECT_ID(N'[dbo].[CustomerListTom]') AND name = N'PK_CustomerListTom')
ALTER TABLE [dbo].[CustomerListTom] DROP CONSTRAINT [PK_CustomerListTom]
GO
ALTER TABLE [CustomerListTom]
ADD CONSTRAINT [PK_CustomerListTom] PRIMARY KEY NONCLUSTERED
(
[CustomerID] ASC,
[RegionID] ASC
)
GO

SELECT TABLEB.CustomerID,
TABLEC.RegionID,
TABLEC.LastName,
TABLEC.FirstName
FROM ViewATom TABLEA
RIGHT OUTER JOIN ViewBTom TABLEB ON TABLEA.CustomerID = TABLEB.CustomerID
RIGHT OUTER JOIN CustomerListTom TABLEC ON TABLEC.CustomerID = TABLEB.CustomerID
WHERE TABLEB.CustomerID IN
('012870','012997','011000','011001','011002','011003','011004','011005','011006','011007',
'011008','011009','011010','011011','011012','011013','011014','011015','011016','011017',
'011018','011019','011020','011150','011153','011144','017230','017220','017254','017257',
'025338','025333','025338','025397','025389','025424','025483','025485','025682','025673',
'029478','029405','029402','029317','029109','018393'
)

return

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SELECT *
FROM dbo.tx1
ORDER BY seq DESC

go

f1 seq
zz 1003
uu 1002
kk 1001
yy 1000


create view vx1 as
SELECT top 100 percent *
FROM dbo.tx1
ORDER BY seq DESC
go
select * from vx1

yy 1000
kk 1001
uu 1002
zz 1003







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Dec 18, 2006

Background - I have a publication that propigates schema changes. I have a view in which I want to remove a column.

Error - Going by what the BOL says, I use Alter View and delete the column from my select statement. I issue the alter view command against the Publication database and it just "churns". I do not get any locking errors or any other type of error, but the statement never completes execution. I watched it run for 10 minutes and cancelled the query. Executing the same statement against a copy of the database that is not being published executes in 1, 2 seconds.

Here is what I am doing:

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table2.txt_sort_order

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The query I am executing:

SET ANSI_NULLS ON

GO

SET QUOTED_IDENTIFIER ON

GO

ALTER VIEW myview

AS

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FROM table1 join table2 on table1.status_code = table2.status_code

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Apr 17, 2008

Hello,
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This feature (Single record view) is available in other database client like TOAD.
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Feb 7, 2007

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The view returns a column that could be null (as the result of a left outer join).
The coulmn that is returned is an integer.
Everything works fine if I run the view from SQL 2005 Management Studio.
My column value is always null if I use ADO.NET's SqlAdapter to return a DataTable.
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Regards,
Paul.

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Hi.

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Is there a way to open the tree view upwards and not downwards so that the children of level 2, 3 etc come over the parent row?

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Thanks
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