Cannot Get Values For Using Exec(@query)

Aug 31, 2006

hello friends!!
i am getting values from front end application as 1,2

i am using it as '''1'',''2'''

i am writing stored procedure

create proc [dbo].[test_1]
@id varchar(40)
as
begin
declare @str as varchar(500)
select * from table_1 where convert(varchar,uid )in (select @id)
end

and another is

create proc [dbo].[test_1]
@id varchar(40)
as
begin
declare @str as varchar(500)
set @str = 'select * from table_1 where convert(varchar,uid )in ('+@id+')'
exec(@str)
end

my table structure is name : table_1
columns datatype
uid int
uname varchar(10)

why i am getting null values for first stored procedure and if i am using second one i am getting values in query analyser but not in front end i am using ms visual studio 2005 and getting @return_value as 0 but not actual data

is there any link where i find code source for getting data through stored procedure using exec(@querystr)

T.I.A

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Code Snippet

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Code Snippet

@Category - Will be passed as a parameter to the stored proc


DECLARE @vsBulkSQL VARCHAR(MAX)

DECLARE @LastUpdate varchar(20)

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+ ' FORMATFILE ' + '=' + ''''+ '\remotemachineFormatFile.fmt'+ ''''+ ',' +
' FIRSTROW ' + '=' + '2' + ')' + ' AS a'

Print @vsBulkSQL - This prints the folliwing statement


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SCRIPT

declare @var1 varchar(10)
set @var1 = '1,4,9,10'
select @var1
select TGNO, TGNAME from carriers where TGNO in (@var1)

RESULT

----------
1,4,9,10

(1 row(s) affected)

Server: Msg 245, Level 16, State 1, Line 4
Syntax error converting the varchar value '1,4,9,10' to a column of data type smallint.

I want to pass a list of values to a column of DATA Type smallint.

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Four Different Values In The 'where' Clause (was SQL Query Question)

Sep 28, 2006

Hello everyone. This is my first post here, so be gentle =)

I need to construct a query, that would return roughly 6000 rows of data.

There are some conditions, or joins, that I can't figure out. Maybe you could help me?

This is the first one.

Invoice.ID-DocParty.DocumentID -> DocParty.OtherID-Party.ID -> Party.IDNumber

This can be achieved with inner join, no problem. Pretty simple.

However, there's a catch =)

DocParty.Role can have four different values in the 'where' clause. Is there a
way to fetch all of these four values without returning four duplicates with
only one field differing?

There are multiple fields in the query that are to be fetched in similar ways. Therefore,
using a IN('value1','value2','value3','value4') would increase the number of selected rows
a lot.

In addition, there is another type of condition that needs to be fullfilled.

Invoice.Type1Account-Account.ID -> Account.Number
Invoice.Type2Account-Account.ID -> Account.Number

Basically, there two fields in the 'main' table that are joined to the same field in another table
with different conditions. Can this be fetched with the same row as all the other data without duplicates?

Should I use a view somehow? How can I construct a view with these complex conditions if I can't
construct an SQL query, that would return no duplicates (pseudo-du

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Query To Get Range Of Values Missing

Mar 7, 2008

I have two columns, where I have the start and stop numbers (and each of them ordered asc). I would like to get a query that will tell me the missing range.

For example, after the first row, the second row is now 2617 and 3775. However, I would like to know the missing values, i.e. 2297 for start and 2616 for stop and so on as we go down the series. Thanks in advance to any help provided!

StartStop
---------
20452296
26173775
568936948
3727084237
84409178779
179013179995
180278259121
259292306409
307617366511

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INSERT Multiple Values With One Query

Oct 26, 2004

I want to know if MS SQL has ability to INSERT multiple values with one statement. For example MySQL is able to do it like so

INSERT INTO myTable (col1,col2,col3)
VALUES
('1','1','1'),
('2','2','2'),
('3','3','3'),
('4','4','4');

and this will insert four rows.

Does MS SQL Have anything similar or do I have to repeat the INSERT statement if I need to generate a dynamic insert?

Thanks,
Lito

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