Cast Real To Money
Dec 26, 2014When I cast Real to Money it makes some changes to the number
DECLARE @i REAL = 989500000.00;
SELECT CAST(@i AS MONEY)
the result is : 989500032.00
what should I do for stop this ?
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How Can I Cast A Money Field In A View To Look Like Money
Oct 16, 2007I have a special need in a view for a money column to look like money and still be a money datatype. So I need it to look like $100.00 (prefered) or 100.00(can make work).
If I convert like this '$' + CONVERT (NVARCHAR(12), dbo.tblpayments.Amount, 1) it is now a nvarchar and will not work for me.
How can I cast so it is still money? by default the entries look like 100.0000.
They must remain a money datatype.
Money In SQL And ASP.NET
May 6, 2007Hi,I'm having some trouble with my asp.net page and my sql database. What I'm trying to do is allow the user to upload an number to the database, the number is a money amount like 2.00 (£2.00) or 20.00(£20.00). I've tried using money and smallmoney datatypes but the numbers usually end up looking like this in the database...I enter 2.00 and in the database it looks like 2.00000, and even if I enter the information directly into the database I get the same results. I'm not going to be using big numbers with lots of decimal places like this 1000,000,0000. Can anyone help me? All I want is to know what to set the value to on my aspx page and what setting to set the field to in my database, I'd just like two pound to appear as 2.00. any help would be great.
I'm using Microsoft Visual Web Developer 2005 Express Edition and Microsoft SQL Server 2005 if that helps.
Thanks.
DataType Money
Dec 28, 2006Please i need to display the money column in DataBase in an asp.net page but i get something like this 786.0000 how can i format it so that i get something like 786.00
Thanx
Money Format ..need Some Help..please
Jan 13, 2007Hi everybody.Here's my Product tableID int,Title nvarchar(50),Price moneyHow can I get value from price field like thisIF PRICE is 12,000.00 it will display 12,000IF PRICE is 12,234.34 it will display 12,234.34Thanks very much...I am a beginner. Sorry for foolish question
View 7 Replies View RelatedMoney, SQL Server And C#
May 19, 2007Argggg....Please help.I need to store money in SQL Server.I am using C# and a stored procedure to insert.How do you accomplish this? Specifically what datatype should the money variable be in C# during the insert? It's initial value is a string as it is entered from a text field.I have been trying for over an hour now to simply insert money into SQL Server using C# and have it stored as a money type!Thanks
View 3 Replies View RelatedMoney Format
Oct 10, 2007hello everyone...,i have problem in money format...i have moneytable is containning: userid money A 20000,0000 B 40000,0000userid type varchar(50)money type money i have store procedure like this:ALTER PROCEDURE [dbo].[paid]( @userid AS varchar(50), @cost AS money, @message as int="1" output)ASbegin transactiondeclare @money as money select @money = moneyfrom moneytablewhere userid=@useridif (@money > @cost)beginset @money = @money - @costUPDATE moneytable SET money = @money WHERE userid=@useridset @message ='1'endelsebeginset @message = '2' endCOMMIT TRANSACTION when i execute this procedure. i insert value to userid Acost 100,0000 it can not decrease, because cost 100,0000 is same with 1000000, why is like that?i want cost 100,0000 is same with 100. how can i do that? thx...
View 6 Replies View RelatedComparing Money
Aug 29, 2004Hi,
I have a field in database money. When I enter value for it the amount entered is for example 20.000. How can I compare this value with noraml vaules i.e. like 20 in my search engine. Will I need to convert it to varchar and then compare it or is there some other way. Also if I need to convert it to varchar, how can I do it?
Thanks in advance,
Uday
SQL Money Convertion,
Apr 24, 2005Hi All,
Here in Belgium, we work with a comma as decimal seperator, also in all the web apps...
I've tried to update a money table on the sql with following statement
update parts set article = '" & art & "' and price= cast(" & p & " as decimal(5,2)) where supid=202
in this example p is a variable and contains figures like 5,7
This statement always give following error Incorrect syntax near the keyword 'as'
does some have an idea how to fix this one ?
thx
Money Format
Apr 5, 2001Is there a way to format the output of an calculation so that a comma is used as decimal symbaol and a periode after each 3 digits left of the comma ?
We're calculating salary increase like 5000 * 1.025 and the output should look like 5.250,00
Thanks for any help
Charles
Money Datatype
Jan 27, 2003Greetings,
How do you keep or round a money datatype to use only 2 decimal places? I have an instance where I am multiplying a money with a decimal datatype. The decimal has up to 8 decimal places. This is causing the money datattype to extend to 4 decimal places. This makes for problems when I am comparing 2 values.
ex.)
IF 14.88 >= 14.8821
99% of the time this does not happen, but is causing problems. Does anyone have any suggestions?
thanks in advance,
Roger
Money To Varchar
May 8, 2004From query analyzer how can I change the field datatype from money to varchar?
Alter table tablenaame alter column columnname varchar(30)--Is not working.
Money To Varchar
May 11, 2004How can I alter a field datatype from money to varchar?
View 2 Replies View RelatedMoney Format
Jun 3, 2008Hi, I have data in a Payment field:
45.14 - was orig in text format.
Now after converting to money, I see it as this:
45.1400
I need to get rid of the zeros! Anyone please help?
Thanks!
Money Format ..need Some Help..please
Jan 12, 2007Hi everybody.
Here's my Product fields
ID int,
Title nvarchar(50),
Price money
How can I get value from price field like this
IF PRICE is 12,000.00 it will display 12,000
IF PRICE is 12,234.34 it will display 12,234.34
Thanks very much...I am a beginner. Sorry for foolish question
Money/currency
Mar 25, 2007Hi all. Is there a way in SQL to convert the integer to currency format? just for example....
4000 convert to 4,000
1312500 convert to 1,312,500
30000 convert to 30,000
Most of you will say "Do it in your front end"... but the problem is I don't know how to do it in my Report(Business Intelligence Project). If anyone of you knows, tell me please... Thanks. :)
-Ron-
Datatype For US Money
Feb 12, 2008Do you usually use the money or smallmoney datatype for US dollars in a table, or do you use a decimal datatype, and if so which. Any opinions on the advantages and disadvantages of each?
If you use money or smallmoney, do you usually add a constraint to make sure the value is even to the penny (no $24.3487 type amounts)?
CODO ERGO SUM
Scrambling MONEY
Mar 3, 2008
I'm looking for a way to "secure" a column of MONEY values. The idea is to hide the value without resorting to actual SQL encryption services that would require converting the MONEY to a VARBINARY. In short, I want to keep the column type as MONEY, but I want to scramble the value, so its still a valid MONEY type.
The goal is to have a pair of UDF's SCRAMBLE() and UNSCRAMBLE() that work on MONEY.
I've done some searching, but have not found anything along this topic.
Does anyone have any ideas on how to do this?
All My Money In Dollars Please??
May 30, 2007I have a Windows 2003 server, with SQL 2005. How do i change the culture/regional options for the database as on my local test machine (which seems to be exactly the same in terms of windows regional settings and SQL server settings) the currenency fields show with a £ signs as expected, however on my production box they are $. I know this should be simple but its the night before a deadline and my brain is screwed. Please help!!
View 5 Replies View RelatedMoney Conversion
Apr 2, 2006Hi!
When I write:
'SELECT Amount FROM tTransaktion'
I get returnvalues such as '12000.0000'. Instead, I want it to return '12 000'.
The Amount column is of datatype money. Is this possible!?
Thanks!
Can Someone Help With This T-SQL Real Quick?
Nov 11, 2007Hey guys... i cant figure this out for the life of me. I have a long T-sql query, and when i enter the string "Rental" into the Listingtype, it says invalid column name "Rental" ... im not looking for the value to be a column, im looking for it to match the value in the ListingType column... here's the query:
(
@StudioINT = NULL,
@Br1INT = NULL,
@Br2INT = NULL,
@Br3INT = NULL,
@Br4INT = NULL,
@OverBr4INT = NULL,
@CondoINT = NULL,
@ListingTypevarchar(10) = NULL,
@WindowAirINT = NULL,
@CentralACINT = NULL,
@BalconyDeckPatioINT = NULL,
@UseOfYardINT = NULL,
@DishwasherINT = NULL,
@WasherDryerINT = NULL,
@FireplaceINT = NULL,
@EIKINT = NULL,
@HardwoodFloorsINT = NULL,
@BroadbandNetINT = NULL,
@TVINT = NULL,
@ThermostatINT = NULL,
@LandlordNotPresentINT = NULL,
@SmokingINT = NULL,
@NoPetsAllowedINT = NULL,
@CatINT = NULL,
@MoreCatsINT = NULL,
@SmallDogINT = NULL,
@LargeDogsINT = NULL,
@DoorpersonINT = NULL,
@IngroundPoolINT = NULL,
@AboveGroundPoolINT = NULL,
@ElevatorINT = NULL,
@UseOfGarageINT = NULL,
@LaundryFacilitiesINT = NULL,
@HealthCenterINT = NULL,
@StorageAreasINT = NULL,
@WheelchairAccessINT = NULL,
@BusinessCentersINT = NULL,
@RentChargeMinINT = NULL,
@RentChargeMaxINT = NULL,
@DebugBIT = 1
)
AS
SET NOCOUNT ON
DECLARE @SQL VARCHAR(8000)
SET @SQL = '
SELECT
r.REListingID,
r.REListingDate,
r.Username,
r.ZipCode,
r.ListingType,
r.StudioFlag,
r.BRFlag1,
r.BRFlag2,
r.BRFlag3,
r.BRFlag4,
r.OverBRFlag4,
r.CondoFlag,
a.WindowAir,
a.CentralAir,
a.BalconyDeckPatio,
a.UseOfYard,
a.Dishwasher,
a.WasherDryer,
a.Fireplace,
a.EIK,
a.HardwoodFloors,
a.BroadbandNet,
a.TV,
a.Thermostat,
a.LandlordNotPresent,
a.Smoking,
a.NoPetsAllowed,
a.Cat,
a.MoreCats,
a.SmallDog,
a.LargeDogs,
a.Doorperson,
a.IngroundPool,
a.AboveGroundPool,
a.Elevator,
a.UseOfGarage,
a.LaundryFacilities,
a.HealthCenter,
a.StorageAreas,
a.WheelchairAccess,
a.BusinessCenters,
a.RentCharge,
a.RentFrequency
FROMdb_REListings as r
INNER JOINdb_RentalAmenities AS a ON a.REListingID = r.REListingID
WHERE1 = 1
'
IF @Studio IS NOT NULL
SET @SQL = @SQL + ' AND r.StudioFlag = ' + CONVERT(VARCHAR(20), @Studio)
IF @Br1 IS NOT NULL
SET @SQL = @SQL + ' AND r.BRFlag1 = ' + CONVERT(VARCHAR(20), @Br1)
IF @Br2 IS NOT NULL
SET @SQL = @SQL + ' AND r.BRFlag2 = ' + CONVERT(VARCHAR(20), @Br2)
IF @Br3 IS NOT NULL
SET @SQL = @SQL + ' AND r.BRFlag3 = ' + CONVERT(VARCHAR(20), @Br3)
IF @Br4 IS NOT NULL
SET @SQL = @SQL + ' AND r.BRFlag4 = ' + CONVERT(VARCHAR(20), @Br4)
IF @OverBr4 IS NOT NULL
SET @SQL = @SQL + ' AND r.OverBRFlag4 = ' + CONVERT(VARCHAR(20), @OverBr4)
IF @Condo IS NOT NULL
SET @SQL = @SQL + ' AND r.CondoFlag = ' + CONVERT(VARCHAR(20), @Condo)
IF @ListingType IS NOT NULL
SET @SQL = @SQL + ' AND r.ListingType = ' + CONVERT(char, @ListingType)
IF @WindowAir IS NOT NULL
SET @SQL = @SQL + ' AND a.WindowAir = ' + CONVERT(VARCHAR(20), @WindowAir)
IF @CentralAC IS NOT NULL
SET @SQL = @SQL + ' AND a.CentralAir = ' + CONVERT(VARCHAR(20), @CentralAC)
IF @BalconyDeckPatio IS NOT NULL
SET @SQL = @SQL + ' AND a.BalconyDeckPatio = ' + CONVERT(VARCHAR(20), @BalconyDeckPatio)
IF @UseOfYard IS NOT NULL
SET @SQL = @SQL + ' AND a.UseOfYard = ' + CONVERT(VARCHAR(20), @UseOfYard)
IF @Dishwasher IS NOT NULL
SET @SQL = @SQL + ' AND a.Dishwasher = ' + CONVERT(VARCHAR(20), @Dishwasher)
IF @WasherDryer IS NOT NULL
SET @SQL = @SQL + ' AND a.WasherDryer = ' + CONVERT(VARCHAR(20), @WasherDryer)
IF @Fireplace IS NOT NULL
SET @SQL = @SQL + ' AND a.Fireplace = ' + CONVERT(VARCHAR(20), @Fireplace)
IF @EIK IS NOT NULL
SET @SQL = @SQL + ' AND a.EIK = ' + CONVERT(VARCHAR(20), @EIK)
IF @HardwoodFloors IS NOT NULL
SET @SQL = @SQL + ' AND a.HardwoodFloors = ' + CONVERT(VARCHAR(20), @HardwoodFloors)
IF @BroadBandNet IS NOT NULL
SET @SQL = @SQL + ' AND a.BroadbandNet = ' + CONVERT(VARCHAR(20), @BroadbandNet)
IF @TV IS NOT NULL
SET @SQL = @SQL + ' AND a.TV = ' + CONVERT(VARCHAR(20), @TV)
IF @Thermostat IS NOT NULL
SET @SQL = @SQL + ' AND a.Thermostat = ' + CONVERT(VARCHAR(20), @Thermostat)
IF @LandlordNotPresent IS NOT NULL
SET @SQL = @SQL + ' AND a.LandLordNotPresent = ' + CONVERT(VARCHAR(20), @LandLordNotPresent)
IF @Smoking IS NOT NULL
SET @SQL = @SQL + ' AND a.Smoking = ' + CONVERT(VARCHAR(20), @Smoking)
IF @NoPetsAllowed IS NOT NULL
SET @SQL = @SQL + ' AND a.NoPetsAllowed = ' + CONVERT(VARCHAR(20), @NoPetsAllowed)
IF @Cat IS NOT NULL
SET @SQL = @SQL + ' AND a.Cat = ' + CONVERT(VARCHAR(20), @Cat)
IF @MoreCats IS NOT NULL
SET @SQL = @SQL + ' AND a.MoreCats = ' + CONVERT(VARCHAR(20), @MoreCats)
IF @SmallDog IS NOT NULL
SET @SQL = @SQL + ' AND a.SmallDog = ' + CONVERT(VARCHAR(20), @SmallDog)
IF @LargeDogs IS NOT NULL
SET @SQL = @SQL + ' AND a.LargeDogs = ' + CONVERT(VARCHAR(20), @LargeDogs)
IF @Doorperson IS NOT NULL
SET @SQL = @SQL + ' AND a.Doorperson = ' + CONVERT(VARCHAR(20), @Doorperson)
IF @IngroundPool IS NOT NULL
SET @SQL = @SQL + ' AND a.IngroundPool = ' + CONVERT(VARCHAR(20), @IngroundPool)
IF @AboveGroundPool IS NOT NULL
SET @SQL = @SQL + ' AND a.AboveGroundPool = ' + CONVERT(VARCHAR(20), @AboveGroundPool)
IF @Elevator IS NOT NULL
SET @SQL = @SQL + ' AND a.Elevator = ' + CONVERT(VARCHAR(20), @Elevator)
IF @UseOfGarage IS NOT NULL
SET @SQL = @SQL + ' AND a.UseOfGarage = ' + CONVERT(VARCHAR(20), @UseOfGarage)
IF @LaundryFacilities IS NOT NULL
SET @SQL = @SQL + ' AND a.LaundryFacilities = ' + CONVERT(VARCHAR(20), @LaundryFacilities)
IF @HealthCenter IS NOT NULL
SET @SQL = @SQL + ' AND a.Health Center = ' + CONVERT(VARCHAR(20), @HealthCenter)
IF @StorageAreas IS NOT NULL
SET @SQL = @SQL + ' AND a.StorageAreas = ' + CONVERT(VARCHAR(20), @StorageAreas)
IF @WheelchairAccess IS NOT NULL
SET @SQL = @SQL + ' AND a.WheelchairAccess = ' + CONVERT(VARCHAR(20), @WheelchairAccess)
IF @BusinessCenters IS NOT NULL
SET @SQL = @SQL + ' AND a.BusinessCenters = ' + CONVERT(VARCHAR(20), @BusinessCenters)
IF @RentChargeMin IS NOT NULL AND @RentChargeMAX IS NOT NULL
SET @SQL = @SQL + ' AND a.RentCharge BETWEEN ' + CONVERT(VARCHAR(20), @RentChargeMin) + ' AND ' + CONVERT(VARCHAR(20), @RentChargeMax)
IF @RentChargeMin IS NOT NULL AND @RentChargeMAX IS NULL
SET @SQL = @SQL + ' AND a.RentCharge >= ' + CONVERT(VARCHAR(20), @RentChargeMin)
IF @RentChargeMAX IS NULL AND @RentChargeMAX IS NOT NULL
SET @SQL = @SQL + ' AND a.RentCharge <= ' + CONVERT(VARCHAR(20), @RentChargeMax)
IF @Debug = 1
PRINT @SQL
EXEC (@SQL)
Newbie Needs Real Help
Feb 14, 2001Hi. I am trying to setup php4 to talk to MSSQL 7, but am having no luck. Both are on a Win2k server. I get the error below. Please can someone tell me what to do, or even a step by step guide to setting up php to connect to a MSSQL7 database. I originally created the database in access 2000 and now want to use MSSQL to use it. This is the error i get:
Warning: MS SQL message: Could not locate entry in sysdatabases for database 'customers'. No entry found with that name. Make sure that the name is entered correctly. (severity 16) in C:Websiteewsiteestdb.php on line 13
Warning: MS SQL: Unable to select database: customers in C:Websiteewsiteestdb.php on line 13
Database unavailable
The REAL Problem
Oct 3, 2000I was running a server with TempDB in RAM (please don't comment on why that's not a good idea). Well, everything was fine until one of our administrator install teh backup exec agent and restarted the server. Since then the server won't start giving an error the Tempdb coulld not be moved into ram. Well, I started the server using the -f parameter and reset the Tempdb in RAM setting to zero. Howeever, it still won't start and gives the same error about not being able to move Tempdb into RAM. Is my only option to rebuild the master database? This is just a backup server but I'd like to avoid the hassle of rebuilding master and reinitializing the databases.
--Buddy
A Real SQL Mindblower
May 18, 2004Hi,
I'm trying to work out how to extract the information that I need from a set of database tables and can't think of a way of doing it with SQL.
The database forms the basis for a diary/calendar system for part-time employees and has two tables:
- One is called 'Availability' and holds info on each available hour slot in the calendar. The table just has fields 'time' and 'date', where the time is an integer representing an hour and date is datetime. The calendar runs from 07.00 to 23.00 each day, so there could be 16 rows in 'Availability' for one day. If any part of a day is unavailable (i.e. the employee doesn't work then) there will be no corresponding rows in the table.
- The second table is 'Appointments', which holds details of appointments that the employee is booked for. The main fields are 'date', 'time' and 'duration' (integer for minutes). All appointments will cover a time span that is also covered by an available period, but they are not actually linked in any way.
I need an SQL query that will return all available time slots that start at least 60 minutes after any appointments have FINISHED and at least 120 minutes before any appointment STARTS.
Since there is no link between the 'Appointments' table and the 'Availability' table, I can't think of any way of doing this.
Any ideas?
Real To Datetime - How To...?
Mar 5, 2007Hi,I would like to convert real data type to datetime type. Example:I have a real data type which is: 23,613456 (23 hours and 0,613456). Iwould like to have it in hh:mm:ss format. How to do this? Can I useconvert/cas function?Thanks for helpRgdsMario
View 1 Replies View RelatedFinding If A REAL Is LIKE '%[49]9'
Jul 20, 2005Timings... sometimes there are almost too many ways to do the same thing.The only significant findings I see from all the below timings is:1) Integer math is generally fastest, naturally. Bigint math isn't muchslower, for integers that all fit within an integer.2) Converting float to varchar is relatively slow, and should be avoided ifpossible. Converting from integer to varchar or varchar to int is severaltimes faster.3) Most significantly, and less obvious, CASE expr WHEN .... recomputes exprfor each WHEN condition, unfortunately, and is the same speed (or perhapsslightly slower) as listing WHEN expr = value for each condition. Perhaps anindexed computed column (somehow materialized) would be advisable whenpossible to avoid repeated computations in CASE..WHEN expressions (if thathelps..).Note that if you divide by COUNT(*), most timings below are below onemicrosecond per row, so this all may not be very significant in mostapplications, unless you do frequent aggregations of some sort.COUNT(*) FROM [my_sf_table] = 477446 rowsThe result from each query = either 47527 or 47527.0Platform: Athlon 2000 XP w/512MB RAM, table seems to be cached in RAM, SQL2000, all queries run at least 3 times and minimum timings shown (msec).SRP is a REAL (4 bytes)Fastest ones are near the end.CPU SQL(ms)-- Convert to varchar (implicitly) and compare right two digits-- (original version -- no I didn't write it)4546 select sum(case right(srp,2)when '99' then 1 when '49' then 1 else 0 end)from sf-- Use LIKE for a single comparison instead of two, much faster-- Note that the big speedup indicates that-- CASE expr WHEN y then a WHEN z then b .-- recalculates expr for each WHEN clause2023 select sum(case when srp like '%[49]9' then 1 else 0 end)from sf-- Floating point method of taking a modulus (lacking fmod/modf)2291 select sum(case round(srp - 100e*floor(srp*.01e),0)when 99 then 1 when 49 then 1 else 0 end)from sf-- Round to nearest 50 and compare with 491322 select sum(case round(srp-50e*floor(srp*.02e),0)when 49 then 1 else 0 end)from sf-- Divide by 49 by multiplying by (slightly larger than) 1e/49e811 select sum(floor((cast(srp as integer)%50)*2.04082E-2))from sf-- Integer approach without using CASE731 select sum(coalesce(nullif(sign(cast(srp asinteger)%50-48),-1),0))from sf-- My original integer approach651 select sum(case cast(srp as integer)%100when 99 then 1 when 49 then 1 else 0 end)from sf-- Modulus 50 integer approach without CASE481 select sum((cast(srp as integer)%50)/49)from sf-- Modulus 50 integer approach460 select sum(case cast(srp as integer)%50when 49 then 1 else 0 end)from sf-- bigint without CASE531 select sum((cast(srp as bigint)%50)/49)from sf-- bigint with CASE521 select sum(case cast(srp as bigint)%50when 49 then 1 else 0 end)from sf-- get SIGN to return -1 or 0, then add 1-- much better than the coalesce+nullif approach500 select sum(sign(cast(srp as integer)%50-49)+1)from sf-- SIGN with BIGINT551 select sum(sign(cast(srp as bigint)%50-49)+1)from sfBTW, I know srp should be int to begin with for this to be faster... Okay,so...select cast(srp as int) srp into sf from [my_real_sf_table]720 select sum(case when srp like '%[49]9' then 1 else 0 end) from sf339 select sum(1+sign(srp%50-49)) from sf310 select sum(srp%50/49) from sf300 select sum(case srp%50 when 49 then 1 else 0 end) from sfWhat if it were a char(7)?select cast(cast(srp as integer) as char(7)) srp into sf2 from[my_sf_table]801 select sum(case right(rtrim(srp),2) when '49' then 1when '99' then 1 else 0 end) from sf2717 select sum(case when srp like '%[49]9' then 1 else 0 end) from sf2405 select sum(srp%50/49) from sf2391 select sum(case srp%50 when 49 then 1 else 0 end) from sf2How about varchar(7)?drop table sf2select cast(cast(srp as integer) as varchar(7)) srp into sf2 from[my_sf_table]581 select sum(case right(srp,2) when '49' then 1when '99' then 1 else 0 end) from sf2569 select sum(case when srp like '%[49]9' then 1 else 0 end) from sf2LIKE is faster on VARCHAR than on CHAR columns...Apparently it has to effectively RTRIM the trailing spaces during the LIKEoperation.Is binary collation any faster?drop table sf2select cast(cast(srp as integer) as varchar(7))COLLATE Latin1_General_BIN srpinto sf2 from tbl_superfile561 select sum(case right(srp,2) when '49' then 1when '99' then 1 else 0 end) from sf2530 select sum(case when srp like '%[49]9' then 1 else 0 end) from sf2Binary collation comparisons are slightly faster, though it's not a bigdifference (with just two characters being compared).662 select sum(case convert(binary(2),right(srp,2))when 0x3439 then 1 when 0x3939 then 1 else 0 end) from sf2-----------5037 select right(srp,2) srp,count(*) from my_sf_tablegroup by right(srp,2)order by right(srp,2)920 select cast(srp as int)%100 srp,count(*) from my_sf_tablegroup by cast(srp as int)%100order by cast(srp as int)%100---On the one hand, premature optimization can be a waste of time and energy.On the other hand, understanding performance implications of variousoperations can help write more efficient systems.In any case, an indexed computed column or one updated on a trigger couldvirtually eliminate the need for any of these calculations to be performed,except upon insertion or update, so maybe my comparisons aren't verymeaningful for most applications, considering we're talking about less than3 microseconds per row here worst-case.But the results remind me, some recommend avoiding Identity when it's notnecessary. I find Identity(int,1,1) to be a nice, compact surrogate key thatis useful for quick comparisons, grouping, etc, and so on. Also, it seemsmost appropriate as the primary key to all lookup tables in a star schema inOLAP data warehousing. (?) Of course, in some situations, it's notappropriate, particularly when having a surrogate key violates dataintegrity by allowing duplicates that would not be allowed with a properprimary key constraint, or when the surrogate key is completely redundantwith (especially a short) single-column unique key value that would be abetter selection as the primary key. With multi-column primary keys, I thinkit's sometimes convenient to have a surrogate Identity if only for INclauses that reference that identity column (though EXISTS can usuallyreplace those, so maybe that's a weak excuse for an extra column.)
View 4 Replies View RelatedHow Does The Real SQL String Look Like?
Aug 22, 2007Hello,
I define the sql-query:
SELECT myColumn FROM myPersonsTable WHERE myColumn=@FirstName
then I declare some SqlParameters like:
SqlParameter par=new SqlParameter();
par.ParameterName="@FirstName";
par.Value="John";
mySqlCommand.Parameters.Add(par);
Showing the mySqlCommand.CommandString it will look like:
(A) SELECT myColumn FROM myPersonsTable WHERE myColumn=@FirstName
Is this the real string that is send to the Database (among with some hidden string "John")?...
...or does the real string which is send to the Database look like:
(B) SELECT myColumn FROM myPersonsTable WHERE myColumn='John'
???
If so, where can I retrieve that last string (B)?
Or is (A) the way 'transact sql' operates?
Henk
Sa Real Login Name
Nov 8, 2006Greetings,
I have a SQL Server 2000 database using Integrated Security. Users are added directly to the database from their domain name. In the Login section of the Security node in Enterprise Manager they show up as DomainNameUserName. I have four users that have the System Administrator database role. When I use the user function to get their user name they show up as dbo. Is there a way to get their actual domain user name?
Thanks.
Help For A Real Newbie
Oct 23, 2006A problem so simple I'm a little embarrassed to post it... I am setting up a trigger in which I want to, among other things, record the network ID of the user who performs the action that triggers the trigger. I know there is a variable or function out there to pull that information, but I can't find it, and have tried every variation of "login logname usr_id network_id....." I can find.
So first.... could somebody please tell me the variable or function that will return that piece of information. And second, if you also could point me to a good place, either in print or on line, to look up that kind of information, I would be most grateful.
Thanks.
Money Format Error
Oct 10, 2006I use asp.net 2.0 and sql server 2005 for a web site (and Microsoft enterprise library).When I run aplication at local there is no problem but at the server I take this error:Disallowed implicit conversion from data type varchar to data type money, table 'dbname.dbo.shopProducts', column 'productPrice'. Use the CONVERT function to run this query.productPrice coloumn format is money. It was working correctly my old server but now it crashed.How can I solve this problem? And why it isn't work same configuration? My code:decimal productPrice;Database db = DatabaseFactory.CreateDatabase("connection");string sqlCommand = "update shopProducts set ......................,productPrice='" + productPrice.ToString().Replace(",", ".") + "',..................... where productID=" + productID + " ";db.ExecuteNonQuery(CommandType.Text, sqlCommand)
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Jun 25, 2007Hi there,I have a table products with product_price money(8) field. I have a stored procedure,CREATE procedure p_dat_update_product( @product_id int, @product_price decimal) asset nocount ondeclare @msg varchar(255) -- error message holder-- remove any leading/trailing spaces from parameters select @product_id = ltrim(rtrim(@product_id)) select @product_price = ltrim(rtrim(@product_price))-- turn [nullable] empty string parameters into NULLs if (@product_id = N'') select @product_id = null if (@product_price = N'') select @product_price = null-- start the validation if @product_id is null begin select @msg = 'The value for variable p_dat_update_product.@product_id cannot be null!' goto ErrHandler end-- execute the query if exists (select 'x' from product where product_id = @product_id) begin update dbo.product set product_price = @product_price where product_id = @product_id end if (@@ERROR <> 0) goto ErrhandlerreturnErrHandler: raiserror 30001 @msg returnGO And a class function public void Edit_Product(string product_id,string product_price) { decimal dec_product_price = decimal.Parse(product_price); SqlDataServ oMisDb = new SqlDataServ("LocalSuppliers"); oMisDb.AddParameter("@product_id", product_id); oMisDb.AddParameter("@product_price", dec_product_price.ToString()); oMisDb.ExecuteCmd("p_dat_update_product"); }But i keep getting this error,Error converting data type nvarchar to numericoMisDb.ExecuteCmd("p_dat_update_product"); I do not know what to do and solve this. Is there something that i have done wrong.thanks in advance. PS: still learning aspx and ms sql
View 12 Replies View RelatedDiff Between Money And Smallmoney
Mar 15, 2008What is the difference between money and smallmoney, and is there a way to format these?
View 3 Replies View RelatedMoney Data Type
Jul 15, 2004Hi,
I have a Price column which has 'money' as the data type.
Then I populated some data into the table. I enter '1.00' in the Price column, then I used the following code to get the data:
Label2.Text = "$" + dataSet1.Tables["products"].Rows[0]["price"].toString();
However, the price is displayed as "$1.0000". But I believe it should display "$1.00". So how can I get rid off the two zeros at the end.
regards