Cobol Conversion

Aug 23, 2007

This nifty function convert COBOL value to equivalent integer.

If last characer is one of these alphanumeric charactersJ -1
K -2
L -3
M -4
N -5
O -6
P -7
Q -8
R -9
} -0it means that complete value is negative and last character is the equivalent numeric in table above.CREATE FUNCTION [dbo].[fnCobol2Int]
(
@Item VARCHAR(18)
)
RETURNS BIGINT
AS
BEGIN
RETURNCAST(
CASE
WHEN @Item LIKE '%[^}jklmnopqr0123456789JKLMNOPQR]%' THEN NULL
WHEN LEFT(@Item, LEN(@Item) - 1) LIKE '%[}jklmnopqrJKLMNOPQR]%' THEN NULL
WHEN RIGHT(@Item, 1) LIKE '[}jklmnopqrJKLMNOPQR]' THEN '-'
ELSE ''
END + LEFT(@Item, LEN(@Item) - 1) + CHAR(47 + CHARINDEX(RIGHT(@Item, 1), '}JKLMNOPQR0123456789}jklmnopqr') % 10) AS BIGINT)
END
E 12°55'05.25"
N 56°04'39.16"

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Line 339: End SubThanks for any help.

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