I have a Member table and I have a MemberView.
I want the view to return the "count" from a complex query related to the Member record and I'm looking for a good way to do that.
I was thinking:
select M.*, (select count(*) from UDF)
but that just smells bad.
Any pointers would be great.
Hi all,
I have a table with 3 computed columns, the first two reference a function for there value. The last computed column should be total of the other computed columns, however when trying to write the formula for this column SQL Server rejects it.
Am i correct in thinking it is not possible to reference other computed columns in a computed column's forumla.
My current work around is to call the functions again that the other computed columns use to generate the total, though this seems to me like a performance issue.
Could anyone offer some advise on my situation.
Any input apreciated.
I have a Table Having Date,Opening,Addition,Sale values where opening value comes in the very first row other times it is zero.
In ssrs how can i have a report showing closing value = Opening+Addition-Sale  in current row (it is simple for 1st row ). this closing be the opening value in next row and same formula to be continued...
Date Opening AdditionTotalTank saleClosing Stock
01-11-15 14435 0 14435 8243 20627
02-11-15 0 15000 15000 9433
03-11-15 0 9000 9000 9436
04-11-15 0 12000 12000 8392
05-11-15 0 6000 6000 8157
06-11-15 0 12000 12000 8456
07-11-15 0 15000 15000 10903
08-11-15 0 6000 6000 8485
09-11-15 0 6000 6000 9413
10-11-15 0 21000 21000 6413
Maybe I am missing something very obvious, but I couldn't do it: begin trangocreate table foo (f1 int not null,f2 int not null,f3 as (f1 + f2) not null primary key clustered)gorollback trango This returns:Server: Msg 8183, Level 16, State 1, Line 8Only UNIQUE or PRIMARY KEY constraints are allowed on computed columns.
View 4 Replies View Relatedi have a table that contains 2 columns
A B (B values are only 1 and 2)
-- --
x 1
y 2
z 1
x 2
z 1
j 1
k 2
i want to make a query that will check for dinstinct x what B values it has Ex. It will show result like this
result
A B
-- --
X 1 and 2
Y 2
z 1
K 2
how to make please help
I want to create computed column in table.
Suppose I have three physical column A,B and C
I want to create compute column with computed column.
A+B= X
X+C=Z
Is it possible.
I created a index on a computed column. I did not see any improvementin performance with a join to this column and also my inserts andupdates to this table are failing. Any ideas?Chender
View 2 Replies View Related
Hi,
i have to use a datetime field in all the tables in a database as a updated timestamp.
i.e. : whenever an update happens to a row in a table, this column called LASTUPDATED has to be updated with current date time.Is there any way to implement this without using the trigger ?
can i use COMPUTED column to acheive this ?
Please help me..thnks in advance..
I have a SQL table that maintains a field on the status of a report being completed.
I have in the record the date the report is due (DateDue)
I also have a field called DaysLate which I have set to be a calculated field with formula:
DATEDIFF(dd, DateDue, GETDATE())
Thsi works but when the report is *not* late I'd like this to be null is there I way I can do this conditional calculation in a calculated field?
Regards
Cvive
I have a view that has 2 columns. The first column is associated with a function for the Units. The second column calculates the Market Value:
View
====
Col1: Unit = get_number_of_units()
Col2: MV = get_number_of_units() * get_unit_value()
I need to call get_number_of_units() twice in the view. Is it possible to changes Col2 to something like: MV = Col1 * get_unit_value()?
Is get_unit_value() being called if I do Select Col1 from View?
Thanks.
somehow I am not able to figure this out.
How do I change a computed column using the ALTER TABLE ALTER COLUMN... command?
Hi,
I'm having a problem with a computed field in a table. I have a stored procedure that inserts a row into a table and returns the id and the computed value.
The computed colmn is returned as a decimal (29,6) but for some reason the value is returned with no decimals (confirmed by the Profiler).
The value is calculated and displayed in the database properly with decimals. Also, Is Persisted is OFF.
Below is the stored procedure, computed column foruma (both give same result), and the profiler trace.
Thanks
Stored Procedure
================================================== ==============
ALTER PROCEDURE [Purchasing].[ntp_PurchaseOrderDetail_Insert]
(
@PurchaseOrderDetailId int OUTPUT,
@PurchaseOrderId int ,
@OrderQty decimal (11, 4) ,
@VendorProductId int ,
@Description nvarchar (255) ,
@UnitPrice decimal (18, 6) ,
@PackingQty decimal (14, 4) ,
@DueDateValue nvarchar (50) ,
@ModifiedDate datetime ,
@IsUnitPriceManual bit ,
@LineTotal decimal (29, 6) OUTPUT
)
AS
INSERT INTO [Purchasing].[PurchaseOrderDetail]
(
[PurchaseOrderID]
,[OrderQty]
,[VendorVendorProductID]
,[Description]
,[UnitPrice]
,[PackingMethod]
,[PackingQty]
,[DueDateValue]
,[ModifiedDate]
,[IsUnitPriceManual]
)
VALUES
(
@PurchaseOrderId
,@OrderQty
,@VendorVendorProductId
,@Description
,@UnitPrice
,@PackingMethod
,@PackingQty
,@DueDateValue
,@ModifiedDate
,@IsUnitPriceManual
)
-- Get the identity value
SET @PurchaseOrderDetailId = SCOPE_IDENTITY()
-- Select computed columns into output parameters
SELECT
@LineTotal = [LineTotal]
FROM
[Purchasing].[PurchaseOrderDetail]
WHERE
[PurchaseOrderDetailID] = @PurchaseOrderDetailId
Computed Column Formula
================================================== ==============
isnull(CONVERT(DECIMAL (29,6),[OrderQty]*([UnitPrice]*[PackingQty])),0.000000)
or
isnull([OrderQty]*([UnitPrice]*[PackingQty]),0.000000)
Profiler Trace
================================================== ==============
declare @p1 int
set @p1=115
declare @p16 numeric(29,0) <- should be numeric(29,6)
set @p16=5 <- value should be 5.259200
exec Purchasing.PurchaseOrderDetail_Insert @PurchaseOrderDetailId=@p1 output,@PurchaseOrderId=68,@OrderQty=4,@VendorProd uctId=28,@Description=N'93678975 - GL-2222',@UnitPrice=0.657400,@PackingMethod=N'Bags (2)',@PackingQty=2.0000,@DueDateValue=NULL,@Modifi edDate=''2008-05-19 15:06:37:610'',@LineTotal=@p16 output
select @p1, @p16
I have a question about Computed Column Specification which you can specify as a formula for each column inside a table.
I have now columns named Age and Class.
Classes are "Kids" (ID #1) , "Junior" (ID #2) and "Senior" (ID #3)
Kids, which is for age of 6 till 12
Junior, which is for 12 till 16
Senior, 16 and above.
I have already searched for hours (I really did) on the internet for a solution, but ended with more questions because of the complicated solutions.
Now the Age is shown as a result of a formule of DOB (Date of Birth column), now I want the exact same thing, but the age must specify which Class the user is in.
Example, when I add a user with the birthdate 25/03/1988 (DD/MM/YYYY) he/she gets 24 as age.
With this formula : (datediff(year,[age],getdate()))
Now I want that the user gets "Senior" as Class (same table).
Senior is ID 3 in this case.
Now I do know how Case, When and Then works, but the validation fails. After reading some forums I understood that I should use a create function method. I am not really experienced with creating functions. Also the coding looks more different as I am used to. How to link the Computed Column to a created formula.
need help ,
i have a table called "Loans" where i need to compute a column i.e. NoofDays based on which other calculation like interest calculation needs to be done.
my query goes like this
"select datediff(dd,VDate, MDate) as NoOfDays ,NoOfDays * Principal * Rate /100 * 365 from Loans".
if i run the above query it says
"Invalid column name 'NoOfDays'".
this executes fine if i use Access but not in SQL Server.
can anybody say what might be the problem and how i can solve it.
regards
Rajesh :)
hi
i want to create a table that has a computed column like this :
create table resources(
id int identity(0,1) primary key,
currentDate int not null,
currentMonth int default 0,
monthBefore as (currentMonth - (select top 1 currentMonth from resources where (currentDate - resources.currentDate) = 1)))
as u can see, monthBefore is computed column, and i want get currentMonth value of previous month, for this work, i define a column as currentDate that hold only year+month (like 971,082,083,...) and by this expression, i want to get currentMonth of previous record (previous month), but the following error has shown me :
Subqueries are not allowed in this context. Only scalar expressions are allowed.
how to solve this problem to get currentMonth of previous record ?
thanks
I have downloaded the SQL Server Books online and found the section on Computed columns. In my small banking program I have columns named Deposit/Withdrawel and Balance. If I am reading this right I need to set the Computed Column Specification of my Balance Column in order to perform the calculation. My problem now is that I have no idea how to word the formula and other than telling me what a formula is the SQL Server Books online is no help whatsoever, so any help would be awesome.
If i've misunderstood what I am meant to do somebody please please tell me. Thanks
how do you change the allow null on a column to be 0,
so instead of having null when empty, it would be 0,
I tried default value or binding to 0 to -1, and to 1
and in 0 or -1, it stays null, in 1 it puts the 1
for example if is quantity, it puts as if I would have 1 quantity,
so it's either null, or whathever number I put visides -1 or 0
how can I make it be 0 as defult?
I'm using it to add and substract with computed column, formula;
and the problem is that if it's the first time it's used it does not add or substract, becsause it does not add null with a number, if it has 0 than it works,
whata I had to do is add it manually, but of course it doesn't suppoesed to be that way
any suggestions will be appriciated:
If i want to split a computed column into two or more columns based onthe the length (its a varchar) of the computed column, how often willsql server determine what the computed column is? roughly along thelines ofselect comp_col,'comp_col 2'=case when datalength(comp_col)<=100 then comp_colelse left(comp_col,99) + '~' end,datalength(comp_col)from aTableAs you can see, in this scenario we use the computed coulumn,comp_col, in a few places, so does SQL server need to calculate thiseach time? I'm playing with this on the basis that it does and thustrying to shift the computed column out to a variable and thenmanipulte and return from their, but that has its own problems whenyou throw in additional parameters (trying to join table udf's) so ifSQL server is smart enough to not calculate the column each time Iwould save a lot of hassle?Cheers Dave
View 9 Replies View RelatedCan I create an index on a variation of a column that isn't actually inthe table?I have a ParcelNumber column, with values like123 AB-67012345ABC 000-00-04012-345-67AP34567890The blanks and non-alphanumeric characters cause problems with users,because sometimes they're there, and sometimes they aren't. So I wouldlike to create an index based on this column, with the non-alphanumericcharacters squeezed out. Of course I can add such a column to thetable and index it, but I'm wondering if it can be done withoutactually adding the column.Thanks,Jim
View 6 Replies View RelatedHello,I want to assign a column a computed value, which is the multiplicationof a value from the table within and a value from another table.How can I do that?Say the current table is A, column1; and the other table is B, column3.What should I write as formula?I tried someting like;column1 * (SELECT column3 FROM B WHERE A.ID = B.ID)but it didn't work.
View 2 Replies View Related hi
i want to create a table that has a computed column like this :
Code Snippetcreate table resources(id int identity(0,1) primary key,currentDate int not null,currentMonth int default 0,monthBefore as (currentMonth - (select top 1 currentMonth from resources where (currentDate - resources.currentDate) = 1)))
as u can see, monthBefore is computed column, and i want get currentMonth value of previous month, for this work, i define a column as currentDate that hold only year+month (like 971,082,083,...) and by this expression, i want to get currentMonth of previous record (previous month), but the following error has shown me :
Code SnippetSubqueries are not allowed in this context. Only scalar expressions are allowed.
how to solve this problem to get currentMonth of previous record ?
thanks
Is it possible to use a cursor in computed column?
I have two table (Table1 and Table2). Table 2 is child of Table 1.
Table 2 has more than one record for each record in table 1. What I want is, to concat records from table 2 and show it as a column value for Table1.
e.g.
Code Block
Table 1:
Col1 Col2
1 ABC
1 DEF
Table 2
T1Col1 Col2
1 A
1 -
1 B
1 1
1 -
1 C
I want to see the Results as
Table 1
Col1 Col2 Col3
1 ABC A-B1-C
Is it possible to add computed column for the table1 to get the result as shown in above block.
Thanks
Hello everybody!
I have question about indexed and not indexed Persisted columns on sql server 2005. It's a bug?
First?, my version of SQL Server is
Microsoft SQL Server 2005 - 9.00.3186.00 (Intel X86) Aug 11 2007 03:13:58 Copyright (c) 1988-2005 Microsoft Corporation Developer Edition on Windows NT 5.1 (Build 2600: Service Pack 2)
Now I create two tables and try four select queries:
Code Snippet
SET ANSI_NULLS ON
SET ANSI_PADDING ON
SET ANSI_WARNINGS ON
SET ARITHABORT ON
SET CONCAT_NULL_YIELDS_NULL ON
SET NUMERIC_ROUNDABORT OFF
SET QUOTED_IDENTIFIER ON
GO
create table t1 (id int primary key, id_bigint as cast(id as bigint))
GO
create table t2 (id int primary key, id_bigint as cast(id as bigint) persisted)
GO
select * from t1 -- (1)
-- Clustered index scan with two times Compute Scalar
GO
select * from t2 -- (2)
-- Clustered index scan with one times Compute Scalar
GO
create index IX_t2 on t2 (id_bigint)
GO
select * from t2 -- (3)
-- Index Scan with one times Compute Scalar
GO
select * from t2 where id_bigint = 0 -- (4)
-- Index Seek with one times Compute Scalar
GO
drop table t1
GO
drop table t2
GO
SET ANSI_PADDING OFF
1. I don't understand why access to computed column raise scalar computation wto times?
2. I don't understand why access to persisted computed column raise any scalar computation?
3. I don't understand why access to persisted computed column over index required any scalar computations?
Can anyone from Microsoft SQL Server Team told me about this mistake?
It's a BUG or I incorrect understand value of the "PERSISTED" word?
--
Thanks with avanced.
WBR, Roman S. Golubin
grominc[at]gmail.com
Is it possible to retrieve the formula associated with a computed column using t-SQL? I can use COLUMNPROPERTY( id, column, 'IsComputed') to find the computed columns, but how do I get the formula itself?
Thanks,
Mable
I've got two integer columns in the table, third one is computed by previous two ones division. That's fine, however sometimes can happen that divided by column is set to zero. How can i avoid division by zero exception, please? TIA
View 5 Replies View RelatedHi, hoping someone can
give me a heads up on best sysyem to employ to manage this
scenario.Sorry if this is not the correct forum to post in.Our primary
software is a standalone VB6 app used by some 50 clients, each with
thier own MSDE backend. Their business basically is Packing and
distribution of fresh produce. Each of our clients have multiple
suppliers on which they have data stored. I have decided to write
a web app (VS2005) that will allow the supplier to enter critical
information about produce quality, testing etc. This data will be kept
on our local webserver database.My use case scenario is that
when a supplier enters a new record via web page I can somehow update the Packers
SQL database via internet, http,tcp.Ideally I imagine a trigger on our server db can connect to their databaseover WAN. HOW??The packer must also be able to add
suppliers to our server db. As they already have that data stored
stored at their end I was hoping to have a web page with drop down
lists that accesses their local db and, upon Save, updates our
webserver ddb. Thereby saving them the need to manually enter the
data twice. I know this is a little long winded but I'm new to .Net and
web programming so have no idea on the simplest and best method to do
this.Any help greatly appreciated.
I want to use an if statement to compute the value of a column in SQL Database using other columns. I am supposed to check if a column is null or not and do the computations accordingly. Can anyone help?
Hi.
I have this method in a class, it produces a string value based on the value of another property in the object (which represents a field in the database). I would like to turn this into a computed column in SQL server... but need help converting the formula if this is even possible. Thanks in advance.public string GetVendorEvalRating(int vendorevaltotal)
{
string vendorevalrating = "";if (vendorevaltotal >= 26)
{vendorevalrating = "Critical";
}else if ((vendorevaltotal >= 10) && (vendorevaltotal <= 25))
{vendorevalrating = "Material";
}else if ((vendorevaltotal >= 0) && (vendorevaltotal <= 9))
{vendorevalrating = "Minor";
}return vendorevalrating;
}
I'm new to computed columns so heres the issue.I have four fields in particlur which I am trying to use:
LeaseStart - smalldatetimeLeaseEnd - smalldatetimeLeaseDuration - Calulation = (datediff(year,[LeaseStart],[LeaseEnd]))YearlyExpense -TotalExpense - numeric(18,0)
Now I am trying to divide the field in LeaseDuration by a numeric column (totalExpense) in the column YearlyExpense.
convert(numeric(LeaseDuration)) / totalExpense
Any help would be great!
I've 2 columns after executing query,
one column from those 2 is calculated column.
I am getting resultset as follows
ACCOUNT ¦(calculated column)
------------------------------
100 ¦alpha
100 ¦NULL
My concern is how should I remove record with NULL from final resultset ?
If I give some name to that calculated column say 'Name'
and tried to put in main query as
"where 'Name' IS NOT NULL"; it doesnot work.
Can you have any workaround for it?
:confused:
Hi.
I was wondering how I should go about doing this thing. I need to put a value in a column that is based on values on other columns in the same row.
When this statement executes I need to put a value in Col3.
insert into myTable(Col1, Col2)
values(25, -14)
Something like so:
if(Col1 >0 AND Col2 <0)
set Col3 = Col1 - Col2
else
set Col3 = Col1;
I don't now quite how to solve this. I am really going to need this value in a column. Calculating the value at retrieval is not on option...
I appreciate all help. I'm using SQL Server 2005.
Thanks!
Hi
I need suggestion for a query. Consider following 2 tables.
Table-1 "T1"
-----------
|ID|Name
|1 |abc
|2 |def
|3 |erw
|4 |rwg
|5 |her
Table-2 "T2"
----------
|ID|Qty
|1 |12
|1 |2
|2 |22
|3 |10
|2 |14
I want a query which displays ID, Name and MAX(Qty) for each item where Max(Qty)>=10 i.e. result should be
Result
----------
|ID|Name|Qty
|1 |abc |12
|2 |def |22
|3 |erw |10
I tried:
Select t1.*, (Select Max(Qty) From T2 where ID=t1.ID) as MaxQty
FROM T1 t1
WHERE MaxQty>=10
But it fails as computed or inline query columns can not be added in where clause.
However following works:
Select t1.*, (Select Max(Qty) From T2 where ID=t1.ID) as MaxQty
FROM T1 t1
WHERE (Select Max(Qty) From T2 where ID=t1.ID) >=10
BUT IS IT OPTIMIZED?
Please suggest an optimized way to handle such scenarios.
Suppose a table being
Create table myTable (ID int, col1 int, col2 int)
I know how to make a computed column being the sum of other column for the same ID e.g. "computed_column = col1 + col2".
Getting the average would be "computed_column = (col1 + col2)/2" But how to get the Max, Min?
Even "Sum(col1,col2)" or AVG(col1, col2) does not work as the formula for a computed column...