I have a query that run every day to update a summary table which has week number and day of week. what I currently do is delete all records from the summary table and then summarize all the data availabe from four tables adn then populate the table daily. I want to know if I can run the update query to run only for the week number and day of week depending on getdate. Can I do this?
Please help..
I'm looking for a way to convert the [week number, year] back to the date for the 1st day of that week.
Example (assuming DATEFIRST has been set to 1) : Week 3, 2008 = January 14, 2008
Is there a SQL function that will do this?
Thanks,
Mike
We are trying to compare our current calendar week (based on Monday being the first day of the week) with the previous calendar week.
I'm trying to produce a line chart with 2 axis:
- x axis; the day of the week (Mon, Tues, Wed etc - it is fine for this to be a # rather than text e.g. 1 = Mon, 2 = Tues etc)
- y axis; the cumulative number of orders
The chart needs two series:
Previous Week. The running count of orders placed that week.
Current Week. The running count of orders placed this week.
Obviously in such a chart the 'Current Week' series is going not going to have values along the whole axis until the end of the week. This is expected and the aim of the chart is to see the current week compares against the previous week for the same day.
I have two tables:
Orders TableCalendar Table
The calendar table's main date column is [calDate] and there are columns for the usual [calWeekNum], [calMonth] etc.
My measure for counting orders is simply; # Orders: = countrows[orders].
How do I take this measure and then work out my two series. I have tried numerous things such as adapting TOTALMTD(), following articles such as these:
- [URL] ...
- [URL] ...
But I have had no luck. The standard cumulative formulas do work e.g. if I wanted a MTD or YTD table I would be ok, it's just adjusting to a WTD that is causing me big issues.
How can I get Saturday's date given the week number?
This is my week number, SELECT DATEPART(WEEK, DATEADD(MONTH, +3, ApptDt2)). I need to get Saturday's date from this week.
i have the following table I need to select dates grouping them by weeks, my week start is Saturday to Friday
CREATE TABLE weekdays
(
datevalue datetime NOT NULL
, numericvalue INT NOT NULL
);
INSERT INTO weekdays (datevalue, numericvalue) VALUES
[code]....
The output should look like this
weeknototalvalue
362015-09-01 00:00:00.000
362015-09-02 00:00:00.000
372015-09-07 00:00:00.000
372015-09-08 00:00:00.000
382015-09-12 00:00:00.000
382015-09-13 00:00:00.000
382015-09-14 00:00:00.000
392015-09-19 00:00:00.000
Hi all,
I'd like to add a yesterday dimension member to a new dimension, like a "Time Utility" dimension, that references the second last day of non empty data in a cube.
At the moment, I'm doing this:
Code Snippet
create member [MIA DW].[DATE TIME].[Date].[Yesterday]
as [DATE TIME].[Date].&[2007-01-01T00:00:00]
select [Measures].members on 0,
non empty [DATE TIME].[Date].members on 1
from [MIA DW]
But the [yesterday] member does not seem to belong to [DATE TIME].[Date].members?
So I guess there's two questions:
1) Can I have a new empty dimension which contains all these special members like "Yesterday" or "This Week" and "Last Week" (these last two obviously refer to a set of Dates)
2)How come the Yesterday member is not returned by the .members function?
Thanks
Greg
I am adding week hrs using while loop , but it can continue next week hrs also.
I can get every week start hrs while update @tem1 table
employeeidreportdatereportatleftattoaccountwrhrn
12902014-01-29 00:00:00.00009:3019:1556001
12902014-01-28 00:00:00.00009:0018:4555802
12902014-01-27 00:00:00.00009:0018:455585583
12902014-01-25 00:00:00.00008:0010:0012004 -- week end
12902014-01-24 00:00:00.00009:1718:4554105
12902014-01-23 00:00:00.00009:1918:4654606
12902014-01-22 00:00:00.00009:1718:4754507
12902014-01-21 00:00:00.00009:1618:3552608
12902014-01-20 00:00:00.00009:1818:555435439
My loop statement
while(select MAX(wrh) from @tem1 where wrh = 0) < 1
begin
update @tem1
set wrh = (select toaccount from @tem1
where reportdate = (select min(reportdate) from @tem1 where wrh = 0))+(select max(wrh) from @tem1)
where wrh = (select max(wrh) from @tem1 where wrh = 0 )
and reportdate = (select min(reportdate) from @tem1 where wrh = 0)
end
this is the result while executing loop statement .
employeeidreportdatereportatleftatdehdrhwehwrh
129029 Jan 201409:3019:15008:0009:20024:00065:54
129028 Jan 201409:0018:45008:0009:18016:00056:34
129027 Jan 201409:0018:45008:0009:18008:0009:18
129025 Jan 201408:0010:00005:0002:00045:00047:16 -- week end
129024 Jan 201409:1718:45008:0009:01040:00045:16
129023 Jan 201409:1918:46008:0009:06032:00036:15
129022 Jan 201409:1718:47008:0009:05024:00027:09
129021 Jan 201409:1618:35008:0008:46016:00018:04
129020 Jan 201409:1818:55008:0009:03008:0009:03
How to update only that week hrs , don't continue next week...
In my reports I am extracting the data of number of people joined in all the weeks of the year. And in one of reports I have to extract the data of the number of people joined until the last week from the first week. I am trying out all the logics but nothing is working for me as such. Can any one help me with this issue??????
View 4 Replies View RelatedI need a Select sentence that return me the first week of the month for a given week.
For example If I have week number 12 (Begins 2015/03/16 and Ends 2015/03/22) I need that returns 9, I mean Week number 9 wich is the first week of march (having in mind @@DATEFIRST).
I only need give a week number of the year and then returns the week number of the first week of that month.
seriously now
View 1 Replies View RelatedFunction F_ISO_YEAR_WEEK_DAY_OF_WEEK returns the ISO 8601 Year Week Day of Week in format YYYY-W01-D for the date passed. W01 represents the week of the year from W01 through W53, and D represents the day of the week with 1 = Monday through 7 = Sunday.
The first week of each year starts on the first Monday on or before January 4 of that year, so that the year begins from December 28 of the prior year through January 4 of the current year.
This code creates the function and demos it for the first day, first date+60, and first date+364 for each ISO week/year from 1990 to 2030.
drop function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
GO
create function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
(
@Datedatetime
)
returnsvarchar(10)
as
/*
Function F_ISO_YEAR_WEEK_DAY_OF_WEEK
returns the ISO 8601 Year Week Day of Week
in format YYYY-W01-D for the date passed.
*/
begin
declare @YearWeekDayOfWeekvarchar(10)
Select
--Format to form YYYY-W01-D
@YearWeekDayOfWeek =
convert(varchar(4),year(dateadd(dd,7,a.YearStart)))+'-W'+
right('00'+convert(varchar(2),(datediff(dd,a.YearStart,@Date)/7)+1),2) +
'-'+convert(varchar(1),(datediff(dd,a.YearStart,@Date)%7)+1)
from
(
select
YearStart =
-- Case finds start of year
case
whenNextYrStart <= @date
thenNextYrStart
whenCurrYrStart <= @date
thenCurrYrStart
elsePriorYrStart
end
from
(
select
-- First day of first week of prior year
PriorYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,-1,aaa.Jan4))/7)*7,-53690),
-- First day of first week of current year
CurrYrStart =
dateadd(dd,(datediff(dd,-53690,aaa.Jan4)/7)*7,-53690),
-- First day of first week of next year
NextYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,1,aaa.Jan4))/7)*7,-53690)
from
(
select
--Find Jan 4 for the year of the input date
Jan4=
dateadd(dd,3,dateadd(yy,datediff(yy,0,@date),0))
) aaa
) aa
) a
return @YearWeekDayOfWeek
end
go
-- Execute function on first day, first day+60,
-- and first day+364 for years from 1990 to 2030.
select
DT= convert(varchar(10),DT,121),
YR_START_DT =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT),
YR_START_DT_60 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+60),
YR_START_DT_365 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+364)
from
(
select DT = getdate()union all
select DT = convert(datetime,'1990/01/01') union all
select DT = convert(datetime,'1990/12/31') union all
select DT = convert(datetime,'1991/12/30') union all
select DT = convert(datetime,'1993/01/04') union all
select DT = convert(datetime,'1994/01/03') union all
select DT = convert(datetime,'1995/01/02') union all
select DT = convert(datetime,'1996/01/01') union all
select DT = convert(datetime,'1996/12/30') union all
select DT = convert(datetime,'1997/12/29') union all
select DT = convert(datetime,'1999/01/04') union all
select DT = convert(datetime,'2000/01/03') union all
select DT = convert(datetime,'2001/01/01') union all
select DT = convert(datetime,'2001/12/31') union all
select DT = convert(datetime,'2002/12/30') union all
select DT = convert(datetime,'2003/12/29') union all
select DT = convert(datetime,'2005/01/03') union all
select DT = convert(datetime,'2006/01/02') union all
select DT = convert(datetime,'2007/01/01') union all
select DT = convert(datetime,'2007/12/31') union all
select DT = convert(datetime,'2008/12/29') union all
select DT = convert(datetime,'2010/01/04') union all
select DT = convert(datetime,'2011/01/03') union all
select DT = convert(datetime,'2012/01/02') union all
select DT = convert(datetime,'2012/12/31') union all
select DT = convert(datetime,'2013/12/30') union all
select DT = convert(datetime,'2014/12/29') union all
select DT = convert(datetime,'2016/01/04') union all
select DT = convert(datetime,'2017/01/02') union all
select DT = convert(datetime,'2018/01/01') union all
select DT = convert(datetime,'2018/12/31') union all
select DT = convert(datetime,'2019/12/30') union all
select DT = convert(datetime,'2021/01/04') union all
select DT = convert(datetime,'2022/01/03') union all
select DT = convert(datetime,'2023/01/02') union all
select DT = convert(datetime,'2024/01/01') union all
select DT = convert(datetime,'2024/12/30') union all
select DT = convert(datetime,'2025/12/29') union all
select DT = convert(datetime,'2027/01/04') union all
select DT = convert(datetime,'2028/01/03') union all
select DT = convert(datetime,'2029/01/01') union all
select DT = convert(datetime,'2029/12/31') union all
select DT = convert(datetime,'2030/12/30')
) a
Function Test Results:
DT YR_START_DT YR_START_DT_60 YR_START_DT_364
---------- ----------- -------------- ---------------
2006-01-18 2006-W03-3 2006-W11-7 2007-W03-3
1990-01-01 1990-W01-1 1990-W09-5 1991-W01-1
1990-12-31 1991-W01-1 1991-W09-5 1992-W01-1
1991-12-30 1992-W01-1 1992-W09-5 1992-W53-1
1993-01-04 1993-W01-1 1993-W09-5 1994-W01-1
1994-01-03 1994-W01-1 1994-W09-5 1995-W01-1
1995-01-02 1995-W01-1 1995-W09-5 1996-W01-1
1996-01-01 1996-W01-1 1996-W09-5 1997-W01-1
1996-12-30 1997-W01-1 1997-W09-5 1998-W01-1
1997-12-29 1998-W01-1 1998-W09-5 1998-W53-1
1999-01-04 1999-W01-1 1999-W09-5 2000-W01-1
2000-01-03 2000-W01-1 2000-W09-5 2001-W01-1
2001-01-01 2001-W01-1 2001-W09-5 2002-W01-1
2001-12-31 2002-W01-1 2002-W09-5 2003-W01-1
2002-12-30 2003-W01-1 2003-W09-5 2004-W01-1
2003-12-29 2004-W01-1 2004-W09-5 2004-W53-1
2005-01-03 2005-W01-1 2005-W09-5 2006-W01-1
2006-01-02 2006-W01-1 2006-W09-5 2007-W01-1
2007-01-01 2007-W01-1 2007-W09-5 2008-W01-1
2007-12-31 2008-W01-1 2008-W09-5 2009-W01-1
2008-12-29 2009-W01-1 2009-W09-5 2009-W53-1
2010-01-04 2010-W01-1 2010-W09-5 2011-W01-1
2011-01-03 2011-W01-1 2011-W09-5 2012-W01-1
2012-01-02 2012-W01-1 2012-W09-5 2013-W01-1
2012-12-31 2013-W01-1 2013-W09-5 2014-W01-1
2013-12-30 2014-W01-1 2014-W09-5 2015-W01-1
2014-12-29 2015-W01-1 2015-W09-5 2015-W53-1
2016-01-04 2016-W01-1 2016-W09-5 2017-W01-1
2017-01-02 2017-W01-1 2017-W09-5 2018-W01-1
2018-01-01 2018-W01-1 2018-W09-5 2019-W01-1
2018-12-31 2019-W01-1 2019-W09-5 2020-W01-1
2019-12-30 2020-W01-1 2020-W09-5 2020-W53-1
2021-01-04 2021-W01-1 2021-W09-5 2022-W01-1
2022-01-03 2022-W01-1 2022-W09-5 2023-W01-1
2023-01-02 2023-W01-1 2023-W09-5 2024-W01-1
2024-01-01 2024-W01-1 2024-W09-5 2025-W01-1
2024-12-30 2025-W01-1 2025-W09-5 2026-W01-1
2025-12-29 2026-W01-1 2026-W09-5 2026-W53-1
2027-01-04 2027-W01-1 2027-W09-5 2028-W01-1
2028-01-03 2028-W01-1 2028-W09-5 2029-W01-1
2029-01-01 2029-W01-1 2029-W09-5 2030-W01-1
2029-12-31 2030-W01-1 2030-W09-5 2031-W01-1
2030-12-30 2031-W01-1 2031-W09-5 2032-W01-1
(43 row(s) affected)
CODO ERGO SUM
Hey, Im pretty sure this is possible, but let me know if it isnt.I have a table of dates in the format "DD/MM/YYYY", is there a way of converting it to output the day of the week? for example 16/11/2007 would display Friday insted.Thanks in advance John
View 3 Replies View RelatedIn a table, I store an integer to represent a day of the week (1 = sunday ) and then in procedures, compare that to datepart(dw, getdate()) to do alternative tasks on certain days.
If I have the number 1, is there a built in function to convert that to sunday or should one just write a function to do just that?
I want to convert date to week consider saturday is first day of week and friday is end of week. for input is orderdate and output should be week. example orderdate 11.04.15 to 17.04.15 week should be 16. orderdate 18.04.15 week should change to 17.
Order DateWeek
11-Apr-201516
12-Apr-201516
13-Apr-201516
14-Apr-201516
15-Apr-201516
16-Apr-201516
17-Apr-201516
Order DateWeek
18-Apr-201517
Hi,
I don't know if this can be done, but hopefully one of the experts in this forum cna help me out.
I have a TimeOff table which contains 5 fields: timeoffID, employeename, startdate, enddate, and timofftype. I need to create a report which shows how many people take sick day (one of the timeofftypes) on each week day (i.e. Monday, Tuesday, Wednesday, and etc.) The problem is that I don't know how to convert the date range (from startdate to enddate) into indvidual week day for each timeoff record.
For example, on the table,
TimeoffID employeename startdate enddate timeofftype
1 Andy 11/02/2006 11/03/2006 Sick Day
2 Bill 11/03/2006 11/03/2006 Sick Day
The report needs to show:
Monday Tuesday Wednesday Thursday Friday Saturday Sunday
0 0 0 1 2 0 0
Thank you in advance!
hi guys,
How could I convert 'week 9 2008' back into the first day of that week ?
is that even possible ?
hi friends,
how to get the date of the first/last day of the week in sql...
can any one help me
Cheers,
raj
select convert(varchar(16), getdate(), 101)+LEFT(REPLACE(convert(varchar, getdate(), 108), ':', ''),4)
From above query I get
mmddyyyyhhmm
but it' s yyyy and hour can not be separated
04/12/200702:05
How can I separated the year and hour ?
Thanks
Daniel
How to find the saturday in the current week using sql server 2000
View 5 Replies View RelatedI am trying to convert a field that has a Date and Time in smallDateTime format into something that will give me the day of the week that each Date corresponds to. For example, if my Date/Time field says "Jun 7 2001 09:30:00" I want my Day field to automatically say "Thursday". Is there a function that will do this? Or is there something close that will convert a variable of smalldatetime format into a number 0-6 which then can be converted to a day of the week?
View 3 Replies View RelatedIs it possible to write a sql querry to display day of the week?
If it is what is the syntax Pls.
Elsie Reed
Is there a way I can filter dates for last week (May 4 - 10)? This mean that every Mondays, I'll be getting last week's date range. Thanks
View 17 Replies View RelatedHow do I see which is the first day of the week setting in my server?
I was reading about @@DATEFIRST and SET FIRSTDATE, etc. But I don't want to set anything, I just want to know what is the first day of the week set on my server.
Any help will be appreciated.
Thanks
OPi
I need to write a user defined function that will return the date of the first day of a week when provided with the week number. I had an idea of using a while loop with that will keep adding 1 day from January 1st until the week number (found via the DATEPART function) is equal to the supplied week number. Not sure if this is the best way though - any ideas?
Donald.
Is there anyway to get SQL to convert a date to days of the week?
Example, I have a query where the date is "01/01/2006" but I would like it to display "Sunday". Thank you.
this might not be considered a sql problem but here goes anyways.
it was 53 weeks in 1998. however it seems like my computer considered week 53 last year as week 1 in 1999.
so when i perform an operation like this:
select datepart(wk, getdate())
next weeks number is returned. what to do?
Hi,
Is there an easy way to get the position (or number) of the week from a date? By position, I mean week number 1 if we are january 1st. For example:
Date | Week postion
=====================
2001-01-05 | 1
1996-12-28 | 52
1987-06-15 | 26
Thanks a lot,
Skip.
How would you write a query to create a report based on weeks ?
i want to use the reporting services dropdown parameter
to query between weeks as in 01/09/06 to 01/13/06 ?
Hi all,
I have this code below and it appears to work, but I wondered if there was a better way.
Basically I have a table with some sales. The amount sold is stored in a varchar (for a very stupid reason) called ticketNo, the date of the sale is stored in txDate (thankfully this is a date).
We need to report out the total amount sold for a period in weekly groupings with the week starting on Monday. If a week starts within the period specified but does not finish we extend the period to include the whole week.
As I said the code below appears to work (no I have not tested extensively), but it looks like it will be pretty resouce intensive.
Any suggestions?
declare @minTxDate DateTime
declare @maxTxDate DateTime
set @minTxDate = '02-Jul-2007'
set @maxTxDate = '31-Aug-2007'
declare @StartOfYear DateTime
declare @LocalMaxTxDate DateTime
declare @WeekDay int
declare @StartWeek int
declare @EndWeek int
set @StartOfYear = '01-Jan-' + Convert(varchar(4),Year(getDate()))
set @WeekDay = DatePart(weekday,@StartOfYear)
set @StartWeek = DatePart(week, @minTxDate)
set @EndWeek = DatePart(week, @maxTxDate)
set @LocalMaxTxDate = DateAdd(d,10,@maxTxDate)
set DATEFIRST 1
select
DateAdd(d,((DatePart(week, tmpSale.txDate)-1)*7)+@WeekDay-1, @StartOfYear) 'FirstDayOfWeek',
DatePart(week, tmpSale.txDate) 'WeekOfSale',
COALESCE(sum (Convert(decimal, ticketNo)),0) 'TonnesSold'
from
(select
Sale.txDate,
Sale.ticketNo
from Sale
where Sale.txDate between @minTxDate and @LocalMaxTxDate)
tmpSale
where DatePart(week, tmpSale.txDate) between @StartWeek and @EndWeek
group by DatePart(week, tmpSale.txDate),
DateAdd(d,((DatePart(week, tmpSale.txDate)-1)*7)+@WeekDay-1, @StartOfYear)
Hi all!
I'm working on a report that will look like this.
WeekNb - Item - QtySold
1 - Item1 - 25
1 - Item2 - 6
2 - Item1 - 10
2 - Item3 - 73
etc...
I use this function to get the week number DATEPART(wk, transactionDate)
But now I have a problem,
Lets says I want the sells for 2008.
The 1st of January is a Tuesday, but I also want the sells that I made on the 31st of December 2007 as it's on the 2008 1st week (monday).
How can I get this to work ?
Help please
Regards,
Or Tho
This seems like a difficult one ..
I am trying to calculate the number of the week within a month of a given date. in other words, given a date I need to find out whether it's the 1st week or 2nd or 3rd or 4th or 5th week of that given month.
for instance let's call my function "weekOfMonth()":
weekOfMonth(4/19/2004) should return 4 (it's the fourth week of april)
weekOfMonth(4/7/2004) should return 2 (it's the second week of april)
etc ..
Hi, I have a table ABC. It has 2 columns, A and B. At column A i have 3 rows, Week,Goal,Used. Let say for column B at row Week is WW15 now, after 7 days i want the row to be updated to WW16. How do i do that? Advice please.
View 14 Replies View RelatedHow can I filter Current Weeek Date? For example today week dates starts on April 27 and ends on May 3. Thanks
View 20 Replies View Related