I'm looking for a way to convert the [week number, year] back to the date for the 1st day of that week.
Example (assuming DATEFIRST has been set to 1) : Week 3, 2008 = January 14, 2008
Is there a SQL function that will do this?
Thanks,
Mike
How can I get Saturday's date given the week number?
This is my week number, SELECT DATEPART(WEEK, DATEADD(MONTH, +3, ApptDt2)). I need to get Saturday's date from this week.
I want to convert date to week consider saturday is first day of week and friday is end of week. for input is orderdate and output should be week. example orderdate 11.04.15 to 17.04.15 week should be 16. orderdate 18.04.15 week should change to 17.
Order DateWeek
11-Apr-201516
12-Apr-201516
13-Apr-201516
14-Apr-201516
15-Apr-201516
16-Apr-201516
17-Apr-201516
Order DateWeek
18-Apr-201517
hi guys,
How could I convert 'week 9 2008' back into the first day of that week ?
is that even possible ?
I have a query that run every day to update a summary table which has week number and day of week. what I currently do is delete all records from the summary table and then summarize all the data availabe from four tables adn then populate the table daily. I want to know if I can run the update query to run only for the week number and day of week depending on getdate. Can I do this?
Please help..
Hey, Im pretty sure this is possible, but let me know if it isnt.I have a table of dates in the format "DD/MM/YYYY", is there a way of converting it to output the day of the week? for example 16/11/2007 would display Friday insted.Thanks in advance John
View 3 Replies View Related
I have week number and i want to get the date from that
for example Week=52 will be the first day of that day which is monday 12/24/2007
Thanks
I have a column in my dataset that contains the week number.
I would like to use 'Expression' Or code function to do that
how can i get the date from week number? for example the week number is 38
so i wil get this output: 09/17/07 - 09/23/07 (the week starts on Monday and ends on Sunday)
Thanks
Can I get a date from a week number in a certain year, like I know it's week 7 in 2014 (I may know the month.)
View 7 Replies View RelatedHi,
I don't know if this can be done, but hopefully one of the experts in this forum cna help me out.
I have a TimeOff table which contains 5 fields: timeoffID, employeename, startdate, enddate, and timofftype. I need to create a report which shows how many people take sick day (one of the timeofftypes) on each week day (i.e. Monday, Tuesday, Wednesday, and etc.) The problem is that I don't know how to convert the date range (from startdate to enddate) into indvidual week day for each timeoff record.
For example, on the table,
TimeoffID employeename startdate enddate timeofftype
1 Andy 11/02/2006 11/03/2006 Sick Day
2 Bill 11/03/2006 11/03/2006 Sick Day
The report needs to show:
Monday Tuesday Wednesday Thursday Friday Saturday Sunday
0 0 0 1 2 0 0
Thank you in advance!
seriously now
View 1 Replies View RelatedHi,
Can anybody tell me to How to get the week number of a specific Date in SQL Server 2005.
Like : say Date "03/01/2008" belongs to the 1st week of the year 2008, same way "21/02/2008" is 8th week of the year 2008.
So, the same way I need to know the week number of a given (variable) date.
I need to write / use a Function in SQL server which will return the Number (INT) (i.e. 1 or 8 or 10 etc...) against a specific (Parameter) date.
regards,
Saibal
Note : Please feel free to write me if my question is not clear.
We are trying to compare our current calendar week (based on Monday being the first day of the week) with the previous calendar week.
I'm trying to produce a line chart with 2 axis:
- x axis; the day of the week (Mon, Tues, Wed etc - it is fine for this to be a # rather than text e.g. 1 = Mon, 2 = Tues etc)
- y axis; the cumulative number of orders
The chart needs two series:
Previous Week. The running count of orders placed that week.
Current Week. The running count of orders placed this week.
Obviously in such a chart the 'Current Week' series is going not going to have values along the whole axis until the end of the week. This is expected and the aim of the chart is to see the current week compares against the previous week for the same day.
I have two tables:
Orders TableCalendar Table
The calendar table's main date column is [calDate] and there are columns for the usual [calWeekNum], [calMonth] etc.
My measure for counting orders is simply; # Orders: = countrows[orders].
How do I take this measure and then work out my two series. I have tried numerous things such as adapting TOTALMTD(), following articles such as these:
- [URL] ...
- [URL] ...
But I have had no luck. The standard cumulative formulas do work e.g. if I wanted a MTD or YTD table I would be ok, it's just adjusting to a WTD that is causing me big issues.
i have the following table I need to select dates grouping them by weeks, my week start is Saturday to Friday
CREATE TABLE weekdays
(
datevalue datetime NOT NULL
, numericvalue INT NOT NULL
);
INSERT INTO weekdays (datevalue, numericvalue) VALUES
[code]....
The output should look like this
weeknototalvalue
362015-09-01 00:00:00.000
362015-09-02 00:00:00.000
372015-09-07 00:00:00.000
372015-09-08 00:00:00.000
382015-09-12 00:00:00.000
382015-09-13 00:00:00.000
382015-09-14 00:00:00.000
392015-09-19 00:00:00.000
Hi all,
I'd like to add a yesterday dimension member to a new dimension, like a "Time Utility" dimension, that references the second last day of non empty data in a cube.
At the moment, I'm doing this:
Code Snippet
create member [MIA DW].[DATE TIME].[Date].[Yesterday]
as [DATE TIME].[Date].&[2007-01-01T00:00:00]
select [Measures].members on 0,
non empty [DATE TIME].[Date].members on 1
from [MIA DW]
But the [yesterday] member does not seem to belong to [DATE TIME].[Date].members?
So I guess there's two questions:
1) Can I have a new empty dimension which contains all these special members like "Yesterday" or "This Week" and "Last Week" (these last two obviously refer to a set of Dates)
2)How come the Yesterday member is not returned by the .members function?
Thanks
Greg
I am adding week hrs using while loop , but it can continue next week hrs also.
I can get every week start hrs while update @tem1 table
employeeidreportdatereportatleftattoaccountwrhrn
12902014-01-29 00:00:00.00009:3019:1556001
12902014-01-28 00:00:00.00009:0018:4555802
12902014-01-27 00:00:00.00009:0018:455585583
12902014-01-25 00:00:00.00008:0010:0012004 -- week end
12902014-01-24 00:00:00.00009:1718:4554105
12902014-01-23 00:00:00.00009:1918:4654606
12902014-01-22 00:00:00.00009:1718:4754507
12902014-01-21 00:00:00.00009:1618:3552608
12902014-01-20 00:00:00.00009:1818:555435439
My loop statement
while(select MAX(wrh) from @tem1 where wrh = 0) < 1
begin
update @tem1
set wrh = (select toaccount from @tem1
where reportdate = (select min(reportdate) from @tem1 where wrh = 0))+(select max(wrh) from @tem1)
where wrh = (select max(wrh) from @tem1 where wrh = 0 )
and reportdate = (select min(reportdate) from @tem1 where wrh = 0)
end
this is the result while executing loop statement .
employeeidreportdatereportatleftatdehdrhwehwrh
129029 Jan 201409:3019:15008:0009:20024:00065:54
129028 Jan 201409:0018:45008:0009:18016:00056:34
129027 Jan 201409:0018:45008:0009:18008:0009:18
129025 Jan 201408:0010:00005:0002:00045:00047:16 -- week end
129024 Jan 201409:1718:45008:0009:01040:00045:16
129023 Jan 201409:1918:46008:0009:06032:00036:15
129022 Jan 201409:1718:47008:0009:05024:00027:09
129021 Jan 201409:1618:35008:0008:46016:00018:04
129020 Jan 201409:1818:55008:0009:03008:0009:03
How to update only that week hrs , don't continue next week...
In my reports I am extracting the data of number of people joined in all the weeks of the year. And in one of reports I have to extract the data of the number of people joined until the last week from the first week. I am trying out all the logics but nothing is working for me as such. Can any one help me with this issue??????
View 4 Replies View RelatedI need a Select sentence that return me the first week of the month for a given week.
For example If I have week number 12 (Begins 2015/03/16 and Ends 2015/03/22) I need that returns 9, I mean Week number 9 wich is the first week of march (having in mind @@DATEFIRST).
I only need give a week number of the year and then returns the week number of the first week of that month.
Function F_ISO_YEAR_WEEK_DAY_OF_WEEK returns the ISO 8601 Year Week Day of Week in format YYYY-W01-D for the date passed. W01 represents the week of the year from W01 through W53, and D represents the day of the week with 1 = Monday through 7 = Sunday.
The first week of each year starts on the first Monday on or before January 4 of that year, so that the year begins from December 28 of the prior year through January 4 of the current year.
This code creates the function and demos it for the first day, first date+60, and first date+364 for each ISO week/year from 1990 to 2030.
drop function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
GO
create function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
(
@Datedatetime
)
returnsvarchar(10)
as
/*
Function F_ISO_YEAR_WEEK_DAY_OF_WEEK
returns the ISO 8601 Year Week Day of Week
in format YYYY-W01-D for the date passed.
*/
begin
declare @YearWeekDayOfWeekvarchar(10)
Select
--Format to form YYYY-W01-D
@YearWeekDayOfWeek =
convert(varchar(4),year(dateadd(dd,7,a.YearStart)))+'-W'+
right('00'+convert(varchar(2),(datediff(dd,a.YearStart,@Date)/7)+1),2) +
'-'+convert(varchar(1),(datediff(dd,a.YearStart,@Date)%7)+1)
from
(
select
YearStart =
-- Case finds start of year
case
whenNextYrStart <= @date
thenNextYrStart
whenCurrYrStart <= @date
thenCurrYrStart
elsePriorYrStart
end
from
(
select
-- First day of first week of prior year
PriorYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,-1,aaa.Jan4))/7)*7,-53690),
-- First day of first week of current year
CurrYrStart =
dateadd(dd,(datediff(dd,-53690,aaa.Jan4)/7)*7,-53690),
-- First day of first week of next year
NextYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,1,aaa.Jan4))/7)*7,-53690)
from
(
select
--Find Jan 4 for the year of the input date
Jan4=
dateadd(dd,3,dateadd(yy,datediff(yy,0,@date),0))
) aaa
) aa
) a
return @YearWeekDayOfWeek
end
go
-- Execute function on first day, first day+60,
-- and first day+364 for years from 1990 to 2030.
select
DT= convert(varchar(10),DT,121),
YR_START_DT =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT),
YR_START_DT_60 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+60),
YR_START_DT_365 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+364)
from
(
select DT = getdate()union all
select DT = convert(datetime,'1990/01/01') union all
select DT = convert(datetime,'1990/12/31') union all
select DT = convert(datetime,'1991/12/30') union all
select DT = convert(datetime,'1993/01/04') union all
select DT = convert(datetime,'1994/01/03') union all
select DT = convert(datetime,'1995/01/02') union all
select DT = convert(datetime,'1996/01/01') union all
select DT = convert(datetime,'1996/12/30') union all
select DT = convert(datetime,'1997/12/29') union all
select DT = convert(datetime,'1999/01/04') union all
select DT = convert(datetime,'2000/01/03') union all
select DT = convert(datetime,'2001/01/01') union all
select DT = convert(datetime,'2001/12/31') union all
select DT = convert(datetime,'2002/12/30') union all
select DT = convert(datetime,'2003/12/29') union all
select DT = convert(datetime,'2005/01/03') union all
select DT = convert(datetime,'2006/01/02') union all
select DT = convert(datetime,'2007/01/01') union all
select DT = convert(datetime,'2007/12/31') union all
select DT = convert(datetime,'2008/12/29') union all
select DT = convert(datetime,'2010/01/04') union all
select DT = convert(datetime,'2011/01/03') union all
select DT = convert(datetime,'2012/01/02') union all
select DT = convert(datetime,'2012/12/31') union all
select DT = convert(datetime,'2013/12/30') union all
select DT = convert(datetime,'2014/12/29') union all
select DT = convert(datetime,'2016/01/04') union all
select DT = convert(datetime,'2017/01/02') union all
select DT = convert(datetime,'2018/01/01') union all
select DT = convert(datetime,'2018/12/31') union all
select DT = convert(datetime,'2019/12/30') union all
select DT = convert(datetime,'2021/01/04') union all
select DT = convert(datetime,'2022/01/03') union all
select DT = convert(datetime,'2023/01/02') union all
select DT = convert(datetime,'2024/01/01') union all
select DT = convert(datetime,'2024/12/30') union all
select DT = convert(datetime,'2025/12/29') union all
select DT = convert(datetime,'2027/01/04') union all
select DT = convert(datetime,'2028/01/03') union all
select DT = convert(datetime,'2029/01/01') union all
select DT = convert(datetime,'2029/12/31') union all
select DT = convert(datetime,'2030/12/30')
) a
Function Test Results:
DT YR_START_DT YR_START_DT_60 YR_START_DT_364
---------- ----------- -------------- ---------------
2006-01-18 2006-W03-3 2006-W11-7 2007-W03-3
1990-01-01 1990-W01-1 1990-W09-5 1991-W01-1
1990-12-31 1991-W01-1 1991-W09-5 1992-W01-1
1991-12-30 1992-W01-1 1992-W09-5 1992-W53-1
1993-01-04 1993-W01-1 1993-W09-5 1994-W01-1
1994-01-03 1994-W01-1 1994-W09-5 1995-W01-1
1995-01-02 1995-W01-1 1995-W09-5 1996-W01-1
1996-01-01 1996-W01-1 1996-W09-5 1997-W01-1
1996-12-30 1997-W01-1 1997-W09-5 1998-W01-1
1997-12-29 1998-W01-1 1998-W09-5 1998-W53-1
1999-01-04 1999-W01-1 1999-W09-5 2000-W01-1
2000-01-03 2000-W01-1 2000-W09-5 2001-W01-1
2001-01-01 2001-W01-1 2001-W09-5 2002-W01-1
2001-12-31 2002-W01-1 2002-W09-5 2003-W01-1
2002-12-30 2003-W01-1 2003-W09-5 2004-W01-1
2003-12-29 2004-W01-1 2004-W09-5 2004-W53-1
2005-01-03 2005-W01-1 2005-W09-5 2006-W01-1
2006-01-02 2006-W01-1 2006-W09-5 2007-W01-1
2007-01-01 2007-W01-1 2007-W09-5 2008-W01-1
2007-12-31 2008-W01-1 2008-W09-5 2009-W01-1
2008-12-29 2009-W01-1 2009-W09-5 2009-W53-1
2010-01-04 2010-W01-1 2010-W09-5 2011-W01-1
2011-01-03 2011-W01-1 2011-W09-5 2012-W01-1
2012-01-02 2012-W01-1 2012-W09-5 2013-W01-1
2012-12-31 2013-W01-1 2013-W09-5 2014-W01-1
2013-12-30 2014-W01-1 2014-W09-5 2015-W01-1
2014-12-29 2015-W01-1 2015-W09-5 2015-W53-1
2016-01-04 2016-W01-1 2016-W09-5 2017-W01-1
2017-01-02 2017-W01-1 2017-W09-5 2018-W01-1
2018-01-01 2018-W01-1 2018-W09-5 2019-W01-1
2018-12-31 2019-W01-1 2019-W09-5 2020-W01-1
2019-12-30 2020-W01-1 2020-W09-5 2020-W53-1
2021-01-04 2021-W01-1 2021-W09-5 2022-W01-1
2022-01-03 2022-W01-1 2022-W09-5 2023-W01-1
2023-01-02 2023-W01-1 2023-W09-5 2024-W01-1
2024-01-01 2024-W01-1 2024-W09-5 2025-W01-1
2024-12-30 2025-W01-1 2025-W09-5 2026-W01-1
2025-12-29 2026-W01-1 2026-W09-5 2026-W53-1
2027-01-04 2027-W01-1 2027-W09-5 2028-W01-1
2028-01-03 2028-W01-1 2028-W09-5 2029-W01-1
2029-01-01 2029-W01-1 2029-W09-5 2030-W01-1
2029-12-31 2030-W01-1 2030-W09-5 2031-W01-1
2030-12-30 2031-W01-1 2031-W09-5 2032-W01-1
(43 row(s) affected)
CODO ERGO SUM
Hi all!
I'm working on a report that will look like this.
WeekNb - Item - QtySold
1 - Item1 - 25
1 - Item2 - 6
2 - Item1 - 10
2 - Item3 - 73
etc...
I use this function to get the week number DATEPART(wk, transactionDate)
But now I have a problem,
Lets says I want the sells for 2008.
The 1st of January is a Tuesday, but I also want the sells that I made on the 31st of December 2007 as it's on the 2008 1st week (monday).
How can I get this to work ?
Help please
Regards,
Or Tho
In a table, I store an integer to represent a day of the week (1 = sunday ) and then in procedures, compare that to datepart(dw, getdate()) to do alternative tasks on certain days.
If I have the number 1, is there a built in function to convert that to sunday or should one just write a function to do just that?
I am working with Week Numbers and was wondering if there is a way to display Week 1 as 01.
The problem that I am having is that when I list the weeks from Week 1 to Week 12 is that the sorting is 1, 10, 11, 12, 2, 3 and I would like to get it to look like 01, 02, 03....09, 10.
Thanks......
Hi Chaps,
I want to calculate the week number by the following rule
"For the week that has the 1st January included if any days are not in January then set the next week as week number 1"
Can any tell me the piece of code
thanx
Anas
hi friends,
how to get the date of the first/last day of the week in sql...
can any one help me
Cheers,
raj
Any easier way to do what I am trying, without having a table with all the dates and week numbers.
Scenario: Week number of a DateTime Field where the year does not start on January 01<sup>st</sup> but April 1<sup>st</sup> to 31 Mach.
Issue: A week always starts on a Monday so if the 1<sup>st</sup> is on Tuesday, the first week is Tuesday – Sunday, if the 1<sup>st</sup> April is on Friday, the 1<sup>st</sup> week is Friday – Sunday and 7 day periods from there.
CREATE
TABLE [dbo].[DailyCanx](
[ID] [int] IDENTITY(1,1)
NOT NULL,
[DateCancelled] [datetime] NULL
)
ON [PRIMARY]
[code]....
I could create a table with all the start date and end dates of all the week numbers but I think there must be a better way. using SQL Server 2008 R2.
I need to write a user defined function that will return the date of the first day of a week when provided with the week number. I had an idea of using a while loop with that will keep adding 1 day from January 1st until the week number (found via the DATEPART function) is equal to the supplied week number. Not sure if this is the best way though - any ideas?
Donald.
I'm wanting to see if there is a simpler way to accomplish the retrival of the first day of the week Date. What I currently have is:
CASE
WHEN DATEPART(DW, GETDATE()) = 1 THEN DATEADD([D], - 7, GETDATE())
WHEN DATEPART(DW, GETDATE()) = 2 THEN DATEADD([D], - 8, GETDATE())
WHEN DATEPART(DW, GETDATE()) = 3 THEN DATEADD([D], - 9, GETDATE())
WHEN DATEPART(DW, GETDATE()) = 4 THEN DATEADD([D], - 10, GETDATE())
WHEN DATEPART(DW, GETDATE()) = 5 THEN DATEADD([D], - 11, GETDATE())
WHEN DATEPART(DW, GETDATE()) = 6 THEN DATEADD([D], - 12, GETDATE())
WHEN DATEPART(DW, GETDATE()) = 7 THEN DATEADD([D], - 13, GETDATE()) END AS StartWeek1
I'm trying to figure if there might be an easier way to code this. Thanks.
Hi,
How would it be possible to calculate the next date of a given week day.
So if today is 6th April 2008 find the date of the next wednesday (i.e. the up and coming wednesday) of the next saturday etc.
You help is appreciated.
Cheers
SQL express 2012. I am trying to case in the where part and having a syntax errors - This is what i am trying to do:
select all the days in week number x including last year if necessary... so if the year start not at the beginning of the week then look in last year as well ( for the same week number of this year and last week nu of last year)
declare
@yyyy int = 2014,-- THE YEAR
@mm int = 1,-- THE MONTH
@week1No int = 1,-- THE WEEK NUMBER IN THE YEAR
@week2No int = 37-- THE last WEEK NUMBER IN last YEAR
select count(tblDay.start)-- tblDay.start IS smallDatetime
[Code] ....
SQL express 2012
I am trying to case in the where part and having a syntax errors - this is what i am trying to do:
Select all the days in week number x including last year if necessary... so if the year start not at the beginning of the week then look in last year as well ( for the same week number of this year and last week nu of last year)
declare
@yyyy int = 2014,-- THE YEAR
@mm int = 1,-- THE MONTH
@week1No int = 1,-- THE WEEK NUMBER IN THE YEAR
@week2No int = 37-- THE last WEEK NUMBER IN last YEAR
select count(tblDay.start)-- tblDay.start IS smallDatetime
[Code] ...
Hi,
I want to convert a date to a weeknumber in my view.
How is this possible with SQL?
If I use Datepart(wk, getdate()) to get the current week, is there a way to get the date for the first day of the week that is returned?
I have a query that I group everything by week number, but would like to show the actual date for the beginning of the week.
Any help or guidance would be appreciated....
Greetings,
Any tips on using datediff to get last dat of week( in this case saturday) from a date input in SQL?
Thanks for any help!