Copy Latest Diff Backup From One Server To Another

SQL Server 2012-SP2 and Windows 2008R2

I need to copy the last differential backup file from the production server directory to a data warehouse server directory. There are 3 differential backup files on the directory and I need to grab the latest one. I have the following syntax which work from a batch file but it does not work when I put it into a job step as a cmd even though I remove the double %% to only one %.

echo @off
set path1="192.29.305.213$SqlserverProductionBa ckupsKBR_PROD"
set path2=K:SqlserverDatawarehouseBackupPROD
for /f "tokens=*" %%a in ('dir /b /a-d /o-d "%path1%DIFF*.bak"') do copy "%path1%\%%~a" "%path2%" & goto nextstep
:nextstep
Echo File Copied.

Even when I change it to (only one % for the variable),

for /f "tokens=*" %a in ('dir /b /a-d /o-d "%path1%DIFF*.bak"') do copy "%path1%\%~a" "%path2%"

It does not work..........It runs successfully but no file is copied or I get

Message
Executed as user: PROD23Sqladm024. The process could not be created for step 1 of job 0xEAAF943771FF304A9E7AD8ADAC24F96C (reason: The system cannot find the file specified). The step failed.

I know that the file is there. It works with batch file. Poweshell script can be OK. No SSIS - Not installed