Create A Rank Column In A View
Jan 14, 2008
Hi all!
I'm trying to script a view that does a simple query to some tables.
The catch is 2 of the columns are created on run time.
The first column is filled with a calculation with values of other columns. The 2nd column I would like to fill with the ranking of this calculated column
Example: (imagine caculatedcol is Sum(Col1+Col2+Col3)
Col1 Col2 Col3 CalculatedCol Ranking
10 10 10 30 1
9 9 9 27 2
8 8 8 24 3
7 7 7 21 4
How can I get the Ranking column filled based on the calculated column?
I'm desperate.
Thanks for any help.
---
Mário Ramos
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Jun 30, 2005
If I have a column like this
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Jan 9, 2008
I have two tables, one a data table, the other a product table. I want to perform a join on the two tables with values distributed into columns based on the value in the month field.
data_table
product_code month value
350 1 10
350 2 20
350 3 30
product_table
product_code profit_center
350 4520
result_view
product_code profit_center mon1 mon2 mon3
350 4520 10 20 30
My current query gives the following result
result_view
product_code profit_center mon1 mon2 mon3
350 4520 10 0 0
350 4520 0 20 0
350 4520 0 0 30
Any direction toward a solution would be appreciated. Am using SS2005.
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Feb 28, 2008
Hey everyone,
I have a view that shows the email address and first name of a Membership table. I need to add a column to this view that doesn't have a corresponding column in the original table that has some default value.
i.e. the view currently shows:
John john@something.com
I need it to say:
John john@something.com EmailBlast
The third column will always have that value.
Anyone have a suggestion?
Thanks in advance!
--J
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Aug 1, 2012
i am trying to create a rank formula.i just need to return the highest MCC count for the mcc code and return the seller code...So eg row 3 and 4, there are two MMC CODE called 4772, i need the formula to return the seller code r10, this is because r10 has 9 counts against that mcc code, and r03 has 9,
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Oct 17, 2007
I am creating a view for the table:
bellus=# select * from host_application_definition;
id | type_value | connection_value | group_value | application_value | host
----+------------+------------------+-------------+-------------------+----
From the table meta_host_types;
id | value | types | name
----+-------+-----------+--------
1 | agm | host-type | Rencid
I would like to seperate value into type_value and connection_value, because it holds both values.
Any tip?
bellus=# d host_application_definition;
Table "public.host_application_definition"
Column | Type | Modifiers
-------------------+---------+--------------------------------------------------------------------------
id | integer | not null default nextval('host_application_definition_id_seq'::regclass)
type_value | integer |
connection_value | integer |
group_value | integer |
application_value | integer |
host | integer |
Indexes:
"host_application_definition_pkey" PRIMARY KEY, btree (id)
Foreign-key constraints:
"host_application_definition_application_value_fkey" FOREIGN KEY (application_value) REFERENCES appsmarteye(id)
"host_application_definition_connection_value_fkey" FOREIGN KEY (connection_value) REFERENCES meta_host_types(id)
"host_application_definition_group_value_fkey" FOREIGN KEY (group_value) REFERENCES meta_host_grouptypes(id)
"host_application_definition_host_fkey" FOREIGN KEY (host) REFERENCES master_hosts(id)
"host_application_definition_type_value_fkey" FOREIGN KEY (type_value) REFERENCES meta_host_types(id)
d meta_host_types;
Table "public.meta_host_types"
Column | Type | Modifiers
-------------+---------+---------------------------------------------------------------------
id | integer | not null default nextval('meta_types_application_id_seq'::regclass)
application | integer |
value | text |
comments | text |
types | text |
Indexes:
"meta_types_application_pkey" PRIMARY KEY, btree (id)
"meta_host_types_id_key" UNIQUE, btree (id)
"meta_host_types_value_key" UNIQUE, btree (value, application)
"meta_host_types_value_key1" UNIQUE, btree (value)
Foreign-key constraints:
"meta_types_application_application_fkey" FOREIGN KEY (application) REFERENCES appsmarteye(id)
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Apr 9, 2008
I have a View created from 2 tables. How do I add an autoindex (0,1,2,3,..) to a new column?
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Mar 14, 2007
Hi,I'm trying to create views on all my existing tables and for that I'dlike to create a script or so.I don't want to specify the '*' for the columns in the create viewstatement. I prefer to specify the column names.I have the column names int sys.columns table but Do not know how tohandle them to have a statement like that:CREATE VIEW myVIEWWITH SCHEMABINDINGASSELECT col1name, col2name, col3name, etc...from sys.columns....?????.....Anyone can help?thx,Chris
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Dec 20, 2007
Hi,All,
I have one table like this
UserID,Name,GameScore
1 A 25
2 B 23
3 C 22
4 D 25
5 E 23
6 F 26
Now i want the query which return like this
Name Score Rank
F 26 1
A 25 2
D 25 2
B 23 3
E 23 3
C 22 4
Can anyone give me the sql 2000 query for this
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Nov 8, 2015
I have a table that has the definition from the picture. Let's suppose I will sort the list based on last column (DATA.ORA - DESC). That means the last row inserted is the first one in the sorted list.
What I would like to do is to get only the records when the value of a specific column is different from the row below.
For instance I would like to get the rows where the column WHITE has different values. When the status for column WHITE changes from 0 to 1 or from 1 to 2 etc., then I need that row no matter if next 5 rows has the same status (1).
In the picture you see what the result of query should be:
Result: only the lines where the value of column WHITE is different than the row below.
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Apr 2, 2008
Assuming that I have a table similar to this simplified version:
CREATE TABLE [SomeTable] ([Field1] NVARCHAR(50));
How could I count and rank the instances of specific values in the "field1" column? For example, let's say that I want to show the frequency of the column values like so:
field1 count
some value 24
another word 20
a value 5
(and so on...)
How can I do this?
- - - -
- Will -
- - - -
http://www.strohlsitedesign.com
http://blog.strohlsitedesign.com/
http://skins.strohlsitedesign.com/
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Jul 13, 2015
I am looking to add a column to one of my tables that displays a running rank of how many times a customer has ordered in a given period.
I currently have such a column however this column ranks against ALL of the orders that a customer has placed and ignores filters, whereas I need one that ranks based on the filters that are active at any given time.
The current formula is:
CustOrderCountPersistant=RANKX(FILTER('Q1 Data Set',[k1_customer_id]=EARLIER([k1_customer_id])),[order_id],[order_id],1,DENSE)
For example, if I am looking at a full years worth of data and a customer has placed 10 orders in that period this formula will add a 1 in the column for first order, a 2 for the second and so forth all the way to 10, the last order.
However it will give me exactly the same results if I filter the data to just one month of that year where they may have order only 2 orders.
In this scenario I want to have another column with a table that is filter sensitive and would show 1 for the first order and 2 for the second order.
Now, I do understand that the issue here is probably the FILTER() I have on as, if I understand correctly, that means all other filters are ignored. My attempts at reworking the formula to remove this have been unsuccessful (such as using a CALCUALTE and trying to use filter properties within that forumula).
To explain the context - I want to create a measure that counts how many customers have placed x amount orders in y number of days e.g. how many customers have placed 2 orders in 30 days.
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Jul 24, 2012
Write a CREATE VIEW statement that defines a view named Invoice Basic that returns three columns: VendorName, InvoiceNumber, and InvoiceTotal. Then, write a SELECT statement that returns all of the columns in the view, sorted by VendorName, where the first letter of the vendor name is N, O, or P.
This is what I have so far,
CREATE VIEW InvoiceBasic AS
SELECT VendorName, InvoiceNumber, InvoiceTotal
From Vendors JOIN Invoices
ON Vendors.VendorID = Invoices.VendorID
[code]...
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Aug 4, 2004
Hi All,
I'm trying to create a proc for granting permission for developer, but I tried many times, still couldn't get successful, someone can help me? The original statement is:
Create PROC dbo.GrantPermission
@user1 varchar(50)
as
Grant create table to @user1
go
Grant create view to @user1
go
Grant create Procedure to @user1
Go
Thanks Guys.
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Apr 12, 2006
Hi,
I have currently a problem with setting up the permissions for some developers. My configuration looks like this.
DB A is the productive database.
DB B is a kind of "development" database.
Now we have a couple of users call them BOB, DAVID, ...
who are members of the db role db_reader and db_writer for the productive db a but they should be allowed to do nearly everything on db b.
Therefor I added them to the db role db_owner for db b.
For testing purposes I tried to "CREATE" a view TEST as BOB in database B but I received the error message
'Msg 262, Level 14, State 1, Procedure Test, Line 3
CREATE VIEW permission denied in database 'b'.'
I cross checked the permissions on db level and I even granted all available permissions on db level but nevertheless I receive this error message.
What's my mistake?
Of course it worked fine when I give them sysadmin rights but then they have far too much permissions.
Regards,
Stefan
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Aug 14, 2000
I had given one of our developers create view permissions, but he wants to also modify views that are not owned by him, they are owned by dbo.
I ran a profiler trace and determined that when he tries to modify a view using query designer in SQLem or right clicks in SQLem on the view and goes to properties, it is performing a ALTER VIEW. It does the same for dbo in a trace (an ALTER View). He gets a call failed and a permission error that he doesn't have create view permissions, object is owned by dbo, using both methods.
If it is doing an alter view how can I set permissions for that and why does it give a create view error when its really doing an alter view? Very confusing.
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Jan 8, 2001
When I use following command it works fine.
CREATE VIEW dbo.[ikw_custom]
AS
SELECT * FROM rns_keyword.dbo.ikw_custom
but if I use following command with condition it gives me an error.
if not exists(select * from sysobjects where name ='ikw_custom' and type='V')
begin
CREATE VIEW dbo.[ikw_custom]
AS
SELECT * FROM rns_keyword.dbo.ikw_custom
end
help will be appriciated.
Thanks in advance
-Balbir
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Apr 15, 2006
I am learning how to work with MSSQL
here is what I like to do
I have a table with URLs like this "www.urls.com" I need to create a view that will insert this "http://" before "www.urls.com" can some please let me know what I need to do
Thank you
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Sep 25, 2005
Hello All;
I'm new to SQL, and developing my first application using SQL 2000 as the back end for my data.
Can anyone tell me if I can create an SQL View from VBA?
I'm trying to create a data view that access various records from a single table, and it has to distribute that data 2 14 different subforms, representing different days in a 2 week period, which is distingiushed by a field called "Day", that is numbered from 1 to 14.
I also have a summary subform that has the weekly summary (days 1 to 7 and 8 to 14) on seperate subforms. In total I have 16 subforms, which actually source from a single table, just split depending on the day in the period.
As I see it now, creating views iis the best way for me to go, but I also have to be able to change the period id on the fly, so I'm think I have to use VBA to generate these views.
Does any of this make sense, and am I on the right track??
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Mar 18, 2006
hi,if the below query
select DISTINCT group_module_menu_info.menulink FROM
user_group_role_info,group_role_module_info,group_ module_menu_info
where user_group_role_info.userid=user_table.userid and
((group_module_menu_info.moduleid = user_group_role_info.moduleid)OR
(user_group_role_info.roleid=group_role_module_inf o.roleid and
group_module_menu_info.moduleid = group_role_module_info.moduleid))
if i want to create a view
how ?
thank you!
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Jan 26, 2006
Create a view showing every order that was shipped to Spain. Name the destination column "DestinationSpain". Include code that checks if the view already exists. If it does, it should be dropped and re-created.
Use Northwind
Go
DROP VIEW Spain_Orders
Go
CREATE VIEW Spain_Orders
AS
SELECT *
FROM Orders
WHERE ShipCountry = 'Spain'
this is what I get.
server: Msg 3701, Level 11, State 5, Line 1
Cannot drop the view 'Spain_Orders', because it does not exist in the system catalog.
albanie
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Nov 29, 2007
I know IIf doesn't exist in SQL. However, I am creating a view and want to check the value of a field and if it is 1 the field returns 'This value' if it is 2 then 'That value' , if 3 then 'Another value'.
How can I do this ?
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Jul 23, 2005
Hi Gurus,I'm a beginner. Would you please tell me if it's possible to create a viewhaving a calcuated column based on the condition of the column on the sqltable.create view vwImaging ASselectEmpID, LastName, FirstName, EmpTag = 'Act' ifFROM tblPerPayI have a table EMP:SSN (char 9)A view giving a formatted SSN (XXX-XX-XXXX,) a--Message posted via http://www.sqlmonster.com
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Jul 20, 2005
Hi.I created a simple view with the following statements:CREATE VIEW dbo.VIEW1ASSELECT dbo.VIEW_ALL.ID,dbo.VIEW_ALL.Code,Another.dbo.OTHER_VIEW.Label as SpecialCodeFROM dbo.VIEW_ALL LEFT OUTER JOINAnother.dbo.OTHER_VIEW ON(dbo.VIEW_ALL.Code + '_0') = Another.dbo.OTHER_VIEW.LabelWhen I run :select * from VIEW1 where code = 'abcde',I would get all 10 rows that are of the same data where the code is'abcde'. But what I thought it should return is really just one rowsince the rest of the 9 rows are exactly the same! I know that I canget my result if I useselect DISTINCT * from VIEW1 where code = 'abcde'But, is there any way I could change my SQL statements(CREATE VIEW)above so that I automatically get 1 row instead of 10 rows of exactlythe same value without using DISTINCT?Thank you for any help.
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Jan 8, 2008
I have a table in my program which going all the invoices,and I want to create a view where I can see the quantity of the products as many times by 1 as the quantity in the invoice:
Invoice:
Product name quantity
woods 3
at the view
woods 1
woods 1
woods 1
Thank you.
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Aug 2, 2006
how to create view in sql server 2005 that recognize Identity And Primary key of base table
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Aug 14, 2007
Good afternoon,
I have a user that needs read only access to all tables in a particular database - Which is working fine.
He also needs to create views, as well as the above, but nothing else.
Is this possible?
Many thanks.
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Mar 29, 2006
CREATE VIEW getUsedColumns AS SELECT * FROM (SELECT DISTINCT attr FROM iba UNION SELECT DISTINCT attr FROM new_iba) WHERE attr != 0;
its working with oracle
how to chenge in t-sql
thanx
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Jul 8, 2006
Hey guys, im really new ASP.net. I just upsized my access database to SQL Server Express and I'm trying to mimic some view functionalitty I had in access. I think they call it the expression builder.So bassically Im trying to make a column that does some calculations on other columns. Like:if columnA-columnB > 100 then columnC='YES' else columnC='NO'Does anyone know how to do this? I want to add this column in a view. Can i perhaps just do it in the datagrid? I'm so frusterated at the moment, ive been trying for about 3 hours!Thanks in advance for your help.
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Sep 17, 2007
I need to create view from the results of executing dynamic SQL.Query like this have incorrect syntax: CREATE VIEW vModuleCatalogObjectValues AS EXECUTE sp_executesql @sql, @paramDefinition, @moduleId; ENDWhat i need to do to get it work?!
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Jul 16, 2001
Hi,
Is there a way you can give a user a permission to "Create View" only but not to create other objects like tables or SP's in a database.
Thanks
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Feb 6, 1999
Hi,
I tried to create a view on following 4 tables with two different syntaxes. One with ANSI syntax and other with conventional(using WHERE clause). Both SELECT work fine and return same result sets. Views are created in both cases. SELECT from Conventional_View works fine But SELECT from the ANSI_View returns error message without Error Number as :
'DB-Library Process Dead - Connection Broken'
CREATE TABLE dbo.SILT01 (
SILF01A varchar (8) NOT NULL ,
SILF01B varchar (25) NULL ,
SILF01C smallint NULL ,
CONSTRAINT SILT01_PK PRIMARY KEY CLUSTERED
(SILF01A)
)
GO
CREATE TABLE dbo.SILT19 (
SILF23A varchar (8) NOT NULL ,
SILF01A varchar (8) NOT NULL ,
CONSTRAINT aaaaaSILT19_PK PRIMARY KEY CLUSTERED
(
SILF23A,
SILF01A
)
)
GO
CREATE TABLE dbo.SILT20 (
SILF23A varchar (8) NOT NULL ,
SILF15A varchar (8) NOT NULL ,
SILF01A varchar (8) NOT NULL ,
CONSTRAINT aaaaaSILT20_PK PRIMARY KEY CLUSTERED
(
SILF23A,
SILF15A,
SILF01A
)
)
GO
CREATE TABLE dbo.SILT23 (
SILF23A varchar (8) NOT NULL ,
SILF23B varchar (30) NULL ,
SILF23C varchar (40) NULL ,
SILF23D varchar (8) NULL ,
SILF23E varchar (1) NULL ,
SILF23F text NULL ,
SILF23G varchar (25) NULL ,
SILF23H varchar (8) NULL ,
SILF23I varchar (25) NULL ,
SILF23J varchar (25) NULL ,
SILF23K text NULL ,
SILF23L varchar (25) NULL ,
SILF23M varchar (8) NULL ,
SILF23N varchar (25) NULL ,
SILF23O varchar (25) NULL ,
SILF23P text NULL ,
SILF23Q varchar (25) NULL ,
SILF23R varchar (8) NULL ,
SILF23S varchar (25) NULL ,
SILF23T varchar (25) NULL ,
SILF23U varchar (15) NULL ,
SILF23V varchar (15) NULL ,
SILF23W varchar (15) NULL ,
SILF23X varchar (15) NULL ,
SILF23Y varchar (15) NULL ,
SILF23Z varchar (15) NULL ,
SILF23A1 varchar (15) NULL ,
SILF23A2 varchar (15) NULL ,
SILF23A3 varchar (15) NULL ,
SILF23A4 varchar (15) NULL ,
SILF23A5 varchar (15) NULL ,
SILF23A6 varchar (3) NULL ,
CONSTRAINT aaaaaSILT23_PK PRIMARY KEY CLUSTERED
(
SILF23A
)
)
GO
create view ANSI_View as
SELECT DISTINCT SILT01.SILF01A, SILT23.SILF23A,
SILT23.SILF23B, SILT20.SILF15A
FROM ((SILT01 INNER JOIN SILT19 ON SILT01.SILF01A = SILT19.SILF01A)
INNER JOIN SILT23 ON SILT19.SILF23A = SILT23.SILF23A)
LEFT JOIN SILT20 ON (SILT19.SILF01A = SILT20.SILF01A) AND
(SILT19.SILF23A = SILT20.SILF23A)
create view Conventional_View as
SELECT DISTINCT SILT01.SILF01A, SILT23.SILF23A,
SILT23.SILF23B, SILT20.SILF15A
FROM SILT01, SILT19,SILT23, SILT20
WHERE ( SILT01.SILF01A = SILT19.SILF01A AND
SILT19.SILF23A = SILT23.SILF23A ) AND
( ( SILT19.SILF01A *= SILT20.SILF01A) AND
(SILT19.SILF23A *= SILT20.SILF23A) )
SELECT * FROM ANSI_VIEW
'DB-Library Process Dead - Connection Broken'
SELECT * FROM Conventional_View (Works fine)
Expecting Help or Suggestions from experts.
Thanx,
Gunvant Patil( gunvantp@mail.usa.com )
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Dec 1, 2004
G'day all.
I am trying to create an index on a view that joins two tables.
I get the classic error of course:
'Cannot index the view 'dbname.dbo.HJC_net'. It contains one or more disallowed constructs.'
Thing that gets me is that it all seems pretty normal stuff and I can't see what is stopping it.
Code is below and any help greatly appreciated.
CREATE VIEW dbo.HJC_net WITH SCHEMABINDING AS
SELECTt_number
FROM dbo.ticket_cancellations RIGHT OUTER JOIN
dbo.tickets ON dbo.ticket_cancellations.tc_system_ref = dbo.tickets.t_number
WHERE dbo.tickets.t_cancelled <> - 1 OR
-- Add all cancellation codes that are to be excluded from the NET view below
(dbo.ticket_cancellations.tc_cancellation_code <> 83943
AND dbo.ticket_cancellations.tc_cancellation_code <> 83946)
GO
-- Create a clustered index, it MUST be unique
CREATE UNIQUE CLUSTERED INDEX t_number_unique ON HJC_net(t_number)
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