Creation Of Aligned Partitioned Indexes
Jul 24, 2007
Hi All,
In the manual I find the following comment for creating indexes.
"If partition_scheme_name or filegroup is not specified and the table is partitioned, the index is placed in the same partition scheme, using the same partitioning column, as the underlying table."
We are creating some dimensional models in SQL Server with about 100M rows in the largest fact tables.
What I have created are base tables which were on 'primary' and then created a clustered index over a partitioning scheme. I did this as I figured the data will go into the clustered index in any case.
However, when I then create indexes on these tables they do not look like they are petitioned....at least not as far as I can tell.
Q1. Is there some way to tell if the index was partitioned properly?
Q2. If the index is not partitioned is there any simply way to alter the table to the partitioning scheme? My reading of the manual tells me I have to unload, truncate, alter and then reload the table. Is there a better way?
Thanks in advance for your assistance.
Best Regards
Peter
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Jun 26, 2002
Hi,
Can anybody help me how to Stop this 'System Creation Indexes' (Index Name like 'WA%')?.
Is there any method is available to delete the Existing 'System Indexes'?.
thanks,
Srini
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Jun 24, 2015
Script they use to generate indexes in SQL 2005.
I have 2 databases on a separate instance. I want to script out all indexes from database1 then execute it on database2.
How to accomplish this task efficiently.
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Apr 15, 2015
We are running SQL Server 2014 Enterprise Edition (64-Bit) on Windows 2012 R2 Standard (64-Bit).
1. When to create indexes, before or after data is added? Please address Clustered and Non-Clustered Indexes.
2. To move indexes to it's own filegroup, is it best to create the NON-Clustered Indexes on the separate filegroup with code similar to the example below?
CREATE NONCLUSTERED INDEX IX_Employee_OrganizationLevel_OrganizationNode
ON HumanResources.Employee (OrganizationLevel, OrganizationNode)
WITH (DROP_EXISTING = ON)
ON TransactionsFG1;
GO
I have read the following links that states that if you create the Clustered Index on a separate filegroup, it would also move the base table to that particular filegroup. (So I take it that you ONLY can move NON-CLustered Indexes to a separate filegroup.)
Placing Indexes on Filegroups:
[URL]
By default, indexes are stored in the same filegroup as the base table on which the index is created. A nonpartitioned clustered index and the base table always reside in the same filegroup. However, you can do the following:
• Create nonclustered indexes on a filegroup other than the filegroup of the base table.
Move an Existing Index to a Different Filegroup:
[URL]
Limitations and Restrictions
• If a table has a clustered index, moving the clustered index to a new filegroup moves the table to that filegroup.
• You cannot move indexes created using a UNIQUE or PRIMARY KEY constraint using Management Studio. To move these indexes use the CREATE INDEX statement with the (DROP_EXISTING=ON) option in Transact-SQL.
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Dec 17, 2007
I want to find a way to get partition info for all the tables in all the databases for a server. Showing database name, table name, schema name, partition by (maybe; year, month, day, number, alpha), column used in partition, current active partition, last partition (for date partitions I want to know if the partition goes untill 2007, so I can add 2008)
all I've come up with so far is:
Code Block
SELECT distinct o.name From sys.partitions p
inner join sys.objects o on (o.object_id = p.object_id)
where o.type_desc = 'USER_TABLE'
and p.partition_number > 1
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Jul 23, 2005
there are one table with a column with 16 varchar, eg. ________1245678( _stands for space.).the database size is 15 MB.when using bcp,right-aligned data will be display.Can i change it to left-aligned, eg. 12345678________?i have use the store procedure with "ltrim" to cut off the spacing, Can i useanother methods to change it??Thx
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Jan 10, 2008
Hello All,
I recently learned of the DiskPart.exe tool that is used to improved the performance of Exchange 2003 cluster implementations. The articles I read alluded to the fact that improperly align disks could ruin the phisical devices themselves due to stress.
So my question is:
How come the MS documentation does not suggest using "Disk Partitions Track-Aligned" methods to improve SQL?
Is there some big difference in the way these two server suites managed I/O reads/writes?
- Rashad Rivera
www.omegusprime.com
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Sep 14, 2015
I want to add spaces (like space - len(col)) to first column so that second column will be aligned when exported to email (text).
DECLARE @ColumnSpaces TABLE (
 Col_1 VARCHAR(50),
 Col_2 VARCHAR(50)
 )
INSERT INTO @ColumnSpaces VALUES ('AAA', '123')
INSERT INTO @ColumnSpaces VALUES ('AAAAAAAAAAAAAAA', '123')
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Jul 1, 2014
I'm working to improve performance on a database I've inherited, and there are several thousand indexes. I've got a list of ones which should definitely exist within the database, and I'm looking to strip out all the others and start fresh, though this list is still quite large (1000 or so).
Is there a way I can remove all the indexes that are not in my list without too much trouble? I.e. without having to manually go through them all individually. The list is currently in a csv file.
I'm looking to either automate the removal of indexes not in the list, or possibly to generate the Create statements for the indexes on the list and simply remove all indexes and then run these statements.
As an aside, when trying to list all indexes in the database, I've found various scripts to do this, but found they all seem to produce differing results. What is the best script to list all indexes?
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Oct 8, 2014
We have an SSAS instance where when we run the query "select * from $system.discover_traces" the creation time in the resultset shows a different time from when we actually started the trace.
for example if we have create the trace at 3.30pm it shows 7.35 pm in the Sql server management studio resultset when we run the query "select * from $system.discover_traces".
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Aug 23, 2006
Hi,
I've starting to explore the Distributed Partitoned Views, in order to use it in the next project, and I've found the article:
"MS SQL Server Distributed Partitioned Views"
By Don Schlichting
I came across the following problem:
While running sample:
USE test
GO
CREATE VIEW AllAuthors
AS
SELECT *
FROM AuthorsAM,
TEST1.test.dbo.AuthorsNZ
GO
I got the error message:
Server: Msg 4506, Level 16, State 1, Procedure AllAuthors, Line 5
Column names in each view or function must be unique. Column name 'au_lname' in view or function 'AllAuthors' is specified more than once.
Could anyone please explain? Can't i use the same column names in both tables?
Regards,
Yifat
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Aug 17, 2001
I would like to break up a very large table into about ten smaller ones. With partitioning to be efficient the columns in the check constraint need to be used when accessing the view. The problem is the table has a composite primary key made up of LocationID/ProductID. With another composite index on ProductID/LocationID. This is accessed both ways from our applications.
I would like to partition the table by LocationID. But then when called by ProductID a scan of all tables in the view would have to be done.
In Oracle there is something called a global index that would solve this. Is there anything similar in SQL Server or does anybody have a work around?
Thanks,
Rob
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Mar 6, 2006
Hi! This is my first post and I really need help with Partitioned View. I'm using Sql Server 2000 and I created a partitioned view using 6 tables and now a need to create the table '7' and alter the view. But when i'm trying to insert new data i'm receiving the message: :eek:
"Server: Msg 4416, Level 16, State 5, Line 1
UNION ALL view 'tb_sld_cob_pap' is not updatable because the definition
contains a disallowed construct."
My code is:
drop VIEW tb_sld_cob_pap
GO
CREATE TABLE dbo.tb_sld_cob_pap_7 (
cod_operacao int NOT NULL ,
cod_contrato int NOT NULL ,
sequencial_duplicata int NOT NULL ,
data_sld_pap smalldatetime NOT NULL CHECK ([data_sld_pap] >= '20060201'),
liqex_dia_nom_outros float NULL ,
liqex_dia_moe_outros float NULL,
constraint pk_pap7 primary key (cod_operacao,cod_contrato,sequencial_duplicata,da ta_sld_pap)
)
GO
CREATE INDEX IdxSldCobPap7_1 ON dbo.tb_sld_cob_pap_7(cod_titulo, seq_titulo, data_sld_pap)
GO
CREATE INDEX IdxSldCobPap7_2 ON dbo.tb_sld_cob_pap_7(cod_operacao, seq_ctr_sacado, sequencial_duplicata, data_sld_pap)
GO
ALTER TABLE dbo.tb_sld_cob_pap_6
DROP CONSTRAINT CK__tb_sld_co__data___6C190EBB
GO
ALTER TABLE dbo.tb_sld_cob_pap_6 ADD CONSTRAINT
CK__tb_sld_co__data___6C190EBB CHECK (((([data_sld_pap] >= '20051201') and ([data_sld_pap] < '20060201'))))
GO
create VIEW tb_sld_cob_pap
as
select * from tb_sld_cob_pap_1
union all
select * from tb_sld_cob_pap_2
union all
select * from tb_sld_cob_pap_3
union all
select * from tb_sld_cob_pap_4
union all
select * from tb_sld_cob_pap_5
union all
select * from tb_sld_cob_pap_6
union all
select * from tb_sld_cob_pap_7
My table tb_sld_cob_pap_6 does NOT have data with ([data_sld_pap] >= '20060201').
I'm using this script in other database and I don't have this problem.
Thank you...
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Jun 18, 2007
USE Northwind
GO
CREATE TABLE myTable99_1 (
Accountchar(3)
, Ledgerchar(4)
, PostDatedatetime
, PRIMARY KEY (Account, Ledger)
, CHECK(PostDate> '1/1/1999' and PostDate < '12/31/1999 23:59:59'))
CREATE TABLE myTable99_2 (
Accountchar(3)
, Ledgerchar(4)
, PostDatedatetime
, PRIMARY KEY (Account, Ledger)
, CHECK(PostDate> '1/1/2000' and PostDate < '12/31/2000 23:59:59'))
CREATE TABLE myTable99_3 (
Accountchar(3)
, Ledgerchar(4)
, PostDatedatetime
, PRIMARY KEY (Account, Ledger)
, CHECK(PostDate> '1/1/2001' and PostDate < '12/31/2001 23:59:59'))
CREATE INDEX myTable99_1_IX ON MyTable99_1
(Account, Ledger)
CREATE INDEX myTable99_2_IX ON MyTable99_2
(Account, Ledger)
CREATE INDEX myTable99_3_IX ON MyTable99_3
(Account, Ledger)
GO
CREATE VIEW myView99
AS
SELECT Account
, Ledger
, PostDate
FROM myTable99_1
UNION ALL
SELECT Account
, Ledger
, PostDate
FROM myTable99_2
UNION ALL
SELECT Account
, Ledger
, PostDate
FROM myTable99_3
GO
SELECT * FROM myView99 WHERE Account = 1 AND Ledger = 1
GO
DROP VIEW myView99
DROP TABLE myTable99_1, myTable99_2, myTable99_3
GO
OK, so I thought I knew this, but I'm looking for parallelism...not only am I no getting it, I'm getting an Index scan....is it becuse I didn't put any data in the table? I thought it would stil show my index seek with parallelism
What up, homey?
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Mar 19, 2008
Hello,
I am implementing a table partitioning on our database with TSQL.
At the moment (it is under developing) the data are correctly located in the relavant file group.
Our target is to meke that the oldest partions/File groups can be backup and removed from the database. This to reduce the size of DB (time period is used for partitioning).
Then, if the need arises, restoring the filegroup to make reporting or analysis.
Take care that data are conitnuosly added and thus new File groups are added to represent the new time period (eg: new file group is the new month).
Based on your experience is it possible a solution like that?
Thank
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Sep 28, 2007
When do partitioned tables/indexes become beneficial? When a table has several million rows? Hundreds of millions of rows?
My tables all have clustered indexes based on the bigint identity PK. I am considering partitioning some of the larger tables by year. If the field I use is not part of the current clustered index then I can't use create index to create my partitions? I need to create an empty table for each year and then use the Alter Table switch? I have header/detail/sub-detail tables. As long as I create the partition function using a similar date field the partitions will be able to be joined? How do I insure my indexes will be aligned? Once I set up the partitions I assume new rows will be stored in the proper partitions based on the value of the date field.
I've read BOL, etc & they are good sources for theory but I need a "Building Partitions for Dummies" type paper with step by step explanations. Anything out there like that?
Thanks.
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Jul 16, 2001
I'm running sqlserver 2000 enterprise edition on windows 2000 and I need
to know, how to create partition table. Please give me a small partition table example.
Thanks,
Ranjan
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Mar 7, 2012
This post concerns updating across a partitioned view, and not unlike others about this subject I am getting this error:
Msg 4436, Level 16, State 12, Line 1
UNION ALL view 'dbII.dbo.MyTable' is not updatable because a partitioning column was not found.
I am aware of the rules for defining a partitioning column, but interpreting them may have beaten me. So perhaps I haven't abided by all the rules. How to spot which one(s) from the view and table definitions? I suspect the CHECK constraint does not allow the ASCII function, but I can't see how to avoid using it given SYSCODE entries in one table are like "[A-Z]%" and in the other are like "[0-9]%".
Otherwise, I suspect it is because one of the tables has, by legacy, a text column and the view is casting it to varchar(MAX). I also suspect it is because there's a second column with a unique index. These aren't mentioned in the rules (are they?).
Here's the view definition:
SELECT SYSCODE, COL2, CAST(COMMENTS AS varchar(MAX)) AS COMMENTS
FROM dbo.MYTABLE
UNION ALL
SELECT SYSCODE, COL2, COMMENTS
FROM OTHERDATABASE.dbo.MYTABLE AS MYTABLE_1
And here are the table definitions:
-- Table in the database where view is defined
CREATE TABLE [dbo].[MYTABLE](
[SYSCODE] [char](12) NOT NULL,
[Code]....
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Apr 8, 2008
hello
i want to ask if the insertion of a record into a partion is slower than insertion it into a non partitioned table or not?
cuz sql has to decide to wich partion the record has to insert according to the partitioning key and is this decesion process is making insertion slower ?
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Jul 20, 2005
Hello,I have a large set of data that I have set up as a partitioned view.The view is partitioned by a datetime column and the individual tableseach represent one month's worth of data. I need to keep at least twoyear's worth of data at all times, but after two years I can archivethe data. A sample of the code used is below. It is simplified forspace reasons.My question is, how do other people maintain the database in this typeof scenario? I could create all of the tables necessary for the nextyear and then go through that at the end of each year (archive tablesover two years, add new tables, and change the view), but I was alsothinking that I might be able to write a stored procedure that runsonce a month and does all three of those tasks automatically. It seemslike a lot of dynamic SQL code though for something like that.Alternatively, I could write VB code to handle it in a DTS package.So, my question again is, how are others doing it? Any suggestions?Thanks!-Tom.CREATE TABLE [dbo].[Station_Events_200401] ([event_time] [datetime] NOT NULL ,[another_column] [char] (8) NOT NULL )GOCREATE TABLE [dbo].[Station_Events_200402] ([event_time] [datetime] NOT NULL ,[another_column] [char] (8) NOT NULL )GOCREATE VIEW Station_EventsASSELECT event_time,another_columnFROM Station_Events_200401UNION ALLSELECT event_time,another_columnFROM Station_Events_200402GO
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Sep 14, 2007
Hello;
I have inserted 200m rows into a partitioned table using SSIS, the table has a [RecID] column which is an identity(1,1) primary key.
When I open the table, I see that RecId doesn't start from 1(its not ordered), it starts from 889823. But, when I query the table for RecID = 1, I can see that row.
Is it a typical behavior of a partitioned table? Or am I doing something wrong?
This is the query I used to create the partitioned table.
create partition function pf_LoadDate(Datetime)
as range right for
values ('01/01/1997','01/01/1999','01/01/2001','01/01/2002','01/01/2003',
'01/01/2004','01/01/2005','01/01/2006','01/01/2007')
--------------
create partition Scheme ps_RecBuyLoadDateScheme
as partition pf_LoadDate
to (FG1,FG1,FG1,FG1,FG2,FG2,FG2,FG3,FG3,FG3)
I'll appreciate any help.
Prok
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Oct 18, 2007
Hi all,
I am designing 3 p:artitioned views for 3 tables. Those tables grow up in 1.5 millions of rows per month (each one), so I decided to partition those tables monthly. The issue is that if I want to create the views with more than 256 months (256 tables) SQL Server says: 'Server: Msg 106, Level 15, State 1, Procedure Jugadas, Line 258Too many table names in the query. The maximum allowable is 256.'
Is there any workaround for this?
Another solution maybe?
PD1: I've tested with less than 256 tables and it works fine, I can update and query the tables (except for a couple of querys where I've got to join 2 or more of the involucred views in which case I got a similar error saying about a 260 table limit).
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Nov 13, 2007
I have a table that I'm trying to scale out into a partitioned view. It's about 30 million rows. It's a workflow table and I have a taskID in the table. Originally the table was partitioned on this column but performance still wasn't what I wanted it to be, so we figured out how we could partition on a bit flag of IsOpen.
Question #1) Anyone know a best practice for creating apartitioned views on multi-columns?
What I'd like to try to do to lower the complexity of the original partitioned view is to create a view of partitioned views. Is this even possible (This is Q#2, BTW).
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Jul 14, 2006
Hi everyone,
I have some doubts about distributed partitioned views.
When we create a distributed partitioned view whcih include three server, do we have tocreate this same distributed partitioned view in that three server in order to make each server to see adn especially modify it ?
Thanks
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Apr 18, 2007
Hello all,
I was wondering if anyone else ran into this and if how you got around it.
In a nut shell the SQL optimizer it NOT pruning the additional partitions from the execution plan as would be expected when applying a constraint directly against the partitioned table€™s partition key, Instead its scanning every partition that you have set up in you partition function range.. Yet when you apply the actual value against the table the plan return as expected.
Hmm.... strange......ghost...ooooooo?
I have created a simple test to reproduce:
Code Snippet
CREATE PARTITION FUNCTION [PTFunction](int) AS RANGE LEFT FOR VALUES (1,2,3)
GO
CREATE PARTITION SCHEME [PTDataScheme] AS PARTITION [PTFunction] TO ([PRIMARY], [PRIMARY], [PRIMARY], [PRIMARY])
GO
CREATE TABLE tblPartitionTest(
ID int identity(1,1) ,
PartitionKey int,
Sales money)
ON PTDataScheme(PartitionKey)
GO
INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(1,10.00);
INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(1,20.00);
INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(1,30.00);
INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(1,40.00);
INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(1,50.00);
INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(2,10.00);
INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(2,20.00);
INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(2,30.00);
INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(2,40.00);
INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(2,50.00);
INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(3,10.00);
INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(3,20.00);
INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(3,30.00);
INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(3,40.00);
INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(3,50.00);
set showplan_text on;
-- query using the set value as a constraint
select * from tblpartitiontest
where partitionkey = 2
--show plan text on result:
|--Table Scan(OBJECT:([tblPartitionTest]), WHERE:([tblPartitionTest].[PartitionKey]=(2)) PARTITION ID:((2)))
-- query using the parameter as a constraint
declare @param_partitionkey int
set @param_partitionkey = 2
select * from tblpartitiontest
where partitionkey = @param_partitionkey
--show plan text on result:
|--Table Scan(OBJECT:([tblPartitionTest]), WHERE:([tblPartitionTest].[PartitionKey]=[@param_partitionkey]) PARTITION ID:(RangePartitionNew([@param_partitionkey],(0),(1),(2),(3))))
BTW I have reproduce this in SP 2 as well.
Any thoughts?
Thanks
Eric
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Sep 18, 2007
So I'm reading http://www.sql-server-performance.com/tips/clustered_indexes_p2.aspx and I come across this:
When selecting a column to base your clustered index on, try to avoid columns that are frequently updated. Every time that a column used for a clustered index is modified, all of the non-clustered indexes must also be updated, creating additional overhead. [6.5, 7.0, 2000, 2005] Updated 3-5-2004
Does this mean if I have say a table called Item with a clustered index on a column in it called itemaddeddate, and several non-clustered indexes associated with that table, that if a record gets modified and it's itemaddeddate value changes, that ALL my indexes on that table will get rebuilt? Or is it referring to the table structure changing?
If so does this "pseudocode" example also cause this to occur:
sqlstring="select * from item where itemid=12345"
rs.open sqlstring, etc, etc, etc
rs.Fields("ItemName")="My New Item Name"
rs.Fields("ItemPrice")=1.00
rs.Update
Note I didn't explicitly change the value of rs.fields("ItemAddedDate")...does rs.Fields("ItemAddedDate")=rs.Fields("ItemAddedDate") occur implicitly, which would force the rebuild of all the non-clustered indexes?
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Dec 10, 2002
Hi, I am using sql2000 ent edition. I have a partitioned view based on 8 tables. My selects and inserts are fine. But, when I run a delete on the view based on a query on the paritioned column, I get a "Transaction (Process ID 149) was deadlocked and has been chosen as a victim".
I looked at the query plan and it was showing a parallel query on all the underlying tables. So, I put the Option(maxdop 1), using only one processor and the delete worked fine.
Does anybody know why? is parallel query create deadlocks? is there any known problems with deletes on partitioned views?
same question for updates. I think I have the same problem for updates.
Any help will be useful.
thanks!!
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Jul 27, 1998
Hi,
Has anyone had any problems on one row updates on a table where you have defined horizontal and vertical partitioning of the data to be replicated?
When I execute an update clause that modifies just one row the log reader misses the modification and it does not get replicated to the other databases.
If I do the same update clause but on several rows then all the modifications are read by the log reader and the replication task goes ok.
What might be wrong?
-janne
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May 8, 2007
From BOL...
CHECK constraints are not needed for the partitioned view to return the correct results. However, if the CHECK constraints have not been defined, the query optimizer must search all the tables instead of only those that cover the search condition on the partitioning column. Without the CHECK constraints, the view operates like any other view with UNION ALL. The query optimizer cannot make any assumptions about the values stored in different tables and it cannot skip searching the tables that participate in the view definition.
Then why am I getting index scans on my partitioning column on tables that fail the search value based on their check constraint?
Not looking for an answer because I know the query optimizer is a fickle b*tch and I did not post any code, but I needed to rant.
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May 12, 2008
Thanks in advance in reading this post ! I'm facing a situation in sql server 2000 sp4 with partitioned views.
I have a partition views that joins about 10 tables, in each table there is a check constraint.
For example, if a exec a select count(*) from VIEW where col1 = '20080101' , it goes for the table that has data for '20080101' .
If I exec a select col1,col2,col3,col4 from VIEW where col1='20080101', it goes to all tables and make an index seek.
I want the beaviour of query 1, beause it is just looking on 1 table and not one the 10.
Thanks in advance !
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Jan 1, 2004
someone please tell me if i can bcp or dts data in to partition views
it is failing with the error the bulk operation does not support this
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Jan 13, 2004
I have a partitioned view defined by a UNTION ALL of member tables. I can update the member tables through the view without any problem. However, when I declare a cursor on this partitioned view and try to update the view using WHERE CURRENT OF, I get an error saying 'The target object type is not updatable through a cursor'. Does anyone know if it's the case that updating a partitioned view through cursor is not supported in SQL Server 2000?
Thanks
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May 13, 2014
SQL 2008R2, Standard on Windows 2008R2 Enterprise.I have implemented a set of local partitioned views to facilitate multi-threading in one of our applications.Testing with SQL and the insert, update, Delete all work fine. However the inserts from SSIS are Bulk and then fail.According to all I have read I should be able to add "instead of Trigger" for the insert and it should work fine. URL....
I have created instead of triggers for insert and delete and again they work fine when I test them with T-SQL but fail in the SSIS package. The error message is that the view is not updateable.
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