Current Week
Apr 30, 2008How can I filter Current Weeek Date? For example today week dates starts on April 27 and ends on May 3. Thanks
View 20 RepliesHow can I filter Current Weeek Date? For example today week dates starts on April 27 and ends on May 3. Thanks
View 20 RepliesWe are trying to compare our current calendar week (based on Monday being the first day of the week) with the previous calendar week.
I'm trying to produce a line chart with 2 axis:
- x axis; the day of the week (Mon, Tues, Wed etc - it is fine for this to be a # rather than text e.g. 1 = Mon, 2 = Tues etc)
- y axis; the cumulative number of orders
The chart needs two series:
Previous Week. The running count of orders placed that week.
Current Week. The running count of orders placed this week.
Obviously in such a chart the 'Current Week' series is going not going to have values along the whole axis until the end of the week. This is expected and the aim of the chart is to see the current week compares against the previous week for the same day.
I have two tables:
Orders TableCalendar Table
The calendar table's main date column is [calDate] and there are columns for the usual [calWeekNum], [calMonth] etc.
My measure for counting orders is simply; # Orders: = countrows[orders].
How do I take this measure and then work out my two series. I have tried numerous things such as adapting TOTALMTD(), following articles such as these:
- [URL] ...
- [URL] ...
But I have had no luck. The standard cumulative formulas do work e.g. if I wanted a MTD or YTD table I would be ok, it's just adjusting to a WTD that is causing me big issues.
seriously now
View 1 Replies View RelatedIn my reports I have data of all the weeks from 1 to 52. Now i want a report where there is data of only the current week in which we are there. So, I am trying out all the possibilities but nothing is working. Can any one help me with the logic of current week????/
View 4 Replies View RelatedCan anyone explain the result of the sql statement
Select DATEADD(wk, DATEDIFF(wk, 6,getdate()), 6)
Can we use this to get the start date of the current week always???
I am trying to always get the start of the week of the current quarter in my criteria
This is the statement for the current quarter
Dateadd(qq, Datediff(qq,0,GetDate()), 0)
This is the statement for the current week
DATEADD(wk, DATEDIFF(wk,0,GETDATE()), 0)
How to calculate from the start of the week of the current quarter...
One week have 168 hours.
How do you create SQl statement that return hour value for specific timestamp??
eg.
If week starts on system from Monday.
Monday 01:00 is hour 1
Tuesday 01:00 is hour 25
Sunday 23:00 is hour 167
etc.
Ideas??
Hi,
I have a Serial No which has a length as 14.For eg IL010730123456. IL01 is The Default Code. 07 is the current year and 30 is the week of the year. 123456 is Serial. How shoud I find The Year and week with the help of this serial no ie The First day of the 30th week of 2007.Is it Possible?
Plz Help me with an appropriate solution.
Thanks.....
I require some scripting to return data which sits in a rolling weeks date range of the current week.
For example, on a Monday I want to return data from the previous day (Sunday to the previous Monday).
On a Tuesday I want to return data from the previous day (Monday to the up coming Sunday).
On a Wednesday I want to return data from the Monday (previous 2 days ago to the upcoming Sunday)
On a Thursday I want to return data from the Monday (previous 3 days ago to the upcoming Sunday)
And so forth.
So I have my SQL script which works with static, fixed date ranges. But I need this additional dynamic date range logic built in.
hi friends,
I m new to asp.net... actually i have an application where the data for current week needs to be displayed from all the data present in different weeks.actually i want to retrieve the syllabus of current week from all weeks
i used the below query but itz not working
sqlString = "SELECT DATEPART(ww,sylWeeKID)AS Week FROM SylWeeks WHERE SyllabusIDFK= " & SylId & " GROUP BY DATEPART(ww,sylWeeKID) "
..can anyone suggest me how to retrieve data for current week , for a related item
thanks in advance
i need urgent help.
I have a table with score info for each group, and the table also contains historical data, I need to get the ranking for the current week and previous week, here is what I did and the result is apparently wrong:
select CurRank = row_number() OVER (ORDER BY cr.CurScore desc) , cr.group_name,cr.CurScore
, lastWeek.PreRank, lastWeek.group_name,lastWeek.PreScore
from
(select group_name,
Avg(case when datediff(day, asAtDate, getdate()) <= 7 then sumscore else 0 end) as CurScore
[Code] ....
The query consists two parts: from current week and previous week respectively. Each part returns correct result, the final merged result is wrong.
I can't seem to upload images so here's the link: [URL] ....
I need to get the last value of # Orders week avg in the current context (the highlighted value). The calendar dimension here is a week level one so I don't think I can use LASTNONBLANK. The measure is from the facts_sales table which is linked to a calendar dimension via a date key.
How can I get Saturday's date given the week number?
This is my week number, SELECT DATEPART(WEEK, DATEADD(MONTH, +3, ApptDt2)). I need to get Saturday's date from this week.
i have the following table I need to select dates grouping them by weeks, my week start is Saturday to Friday
CREATE TABLE weekdays
(
datevalue datetime NOT NULL
, numericvalue INT NOT NULL
);
INSERT INTO weekdays (datevalue, numericvalue) VALUES
[code]....
The output should look like this
weeknototalvalue
362015-09-01 00:00:00.000
362015-09-02 00:00:00.000
372015-09-07 00:00:00.000
372015-09-08 00:00:00.000
382015-09-12 00:00:00.000
382015-09-13 00:00:00.000
382015-09-14 00:00:00.000
392015-09-19 00:00:00.000
Hi all,
I'd like to add a yesterday dimension member to a new dimension, like a "Time Utility" dimension, that references the second last day of non empty data in a cube.
At the moment, I'm doing this:
Code Snippet
create member [MIA DW].[DATE TIME].[Date].[Yesterday]
as [DATE TIME].[Date].&[2007-01-01T00:00:00]
select [Measures].members on 0,
non empty [DATE TIME].[Date].members on 1
from [MIA DW]
But the [yesterday] member does not seem to belong to [DATE TIME].[Date].members?
So I guess there's two questions:
1) Can I have a new empty dimension which contains all these special members like "Yesterday" or "This Week" and "Last Week" (these last two obviously refer to a set of Dates)
2)How come the Yesterday member is not returned by the .members function?
Thanks
Greg
I am adding week hrs using while loop , but it can continue next week hrs also.
I can get every week start hrs while update @tem1 table
employeeidreportdatereportatleftattoaccountwrhrn
12902014-01-29 00:00:00.00009:3019:1556001
12902014-01-28 00:00:00.00009:0018:4555802
12902014-01-27 00:00:00.00009:0018:455585583
12902014-01-25 00:00:00.00008:0010:0012004 -- week end
12902014-01-24 00:00:00.00009:1718:4554105
12902014-01-23 00:00:00.00009:1918:4654606
12902014-01-22 00:00:00.00009:1718:4754507
12902014-01-21 00:00:00.00009:1618:3552608
12902014-01-20 00:00:00.00009:1818:555435439
My loop statement
while(select MAX(wrh) from @tem1 where wrh = 0) < 1
begin
update @tem1
set wrh = (select toaccount from @tem1
where reportdate = (select min(reportdate) from @tem1 where wrh = 0))+(select max(wrh) from @tem1)
where wrh = (select max(wrh) from @tem1 where wrh = 0 )
and reportdate = (select min(reportdate) from @tem1 where wrh = 0)
end
this is the result while executing loop statement .
employeeidreportdatereportatleftatdehdrhwehwrh
129029 Jan 201409:3019:15008:0009:20024:00065:54
129028 Jan 201409:0018:45008:0009:18016:00056:34
129027 Jan 201409:0018:45008:0009:18008:0009:18
129025 Jan 201408:0010:00005:0002:00045:00047:16 -- week end
129024 Jan 201409:1718:45008:0009:01040:00045:16
129023 Jan 201409:1918:46008:0009:06032:00036:15
129022 Jan 201409:1718:47008:0009:05024:00027:09
129021 Jan 201409:1618:35008:0008:46016:00018:04
129020 Jan 201409:1818:55008:0009:03008:0009:03
How to update only that week hrs , don't continue next week...
In my reports I am extracting the data of number of people joined in all the weeks of the year. And in one of reports I have to extract the data of the number of people joined until the last week from the first week. I am trying out all the logics but nothing is working for me as such. Can any one help me with this issue??????
View 4 Replies View RelatedI need a Select sentence that return me the first week of the month for a given week.
For example If I have week number 12 (Begins 2015/03/16 and Ends 2015/03/22) I need that returns 9, I mean Week number 9 wich is the first week of march (having in mind @@DATEFIRST).
I only need give a week number of the year and then returns the week number of the first week of that month.
I'm looking for a way to convert the [week number, year] back to the date for the 1st day of that week.
Example (assuming DATEFIRST has been set to 1) : Week 3, 2008 = January 14, 2008
Is there a SQL function that will do this?
Thanks,
Mike
I have a query that run every day to update a summary table which has week number and day of week. what I currently do is delete all records from the summary table and then summarize all the data availabe from four tables adn then populate the table daily. I want to know if I can run the update query to run only for the week number and day of week depending on getdate. Can I do this?
Please help..
Function F_ISO_YEAR_WEEK_DAY_OF_WEEK returns the ISO 8601 Year Week Day of Week in format YYYY-W01-D for the date passed. W01 represents the week of the year from W01 through W53, and D represents the day of the week with 1 = Monday through 7 = Sunday.
The first week of each year starts on the first Monday on or before January 4 of that year, so that the year begins from December 28 of the prior year through January 4 of the current year.
This code creates the function and demos it for the first day, first date+60, and first date+364 for each ISO week/year from 1990 to 2030.
drop function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
GO
create function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
(
@Datedatetime
)
returnsvarchar(10)
as
/*
Function F_ISO_YEAR_WEEK_DAY_OF_WEEK
returns the ISO 8601 Year Week Day of Week
in format YYYY-W01-D for the date passed.
*/
begin
declare @YearWeekDayOfWeekvarchar(10)
Select
--Format to form YYYY-W01-D
@YearWeekDayOfWeek =
convert(varchar(4),year(dateadd(dd,7,a.YearStart)))+'-W'+
right('00'+convert(varchar(2),(datediff(dd,a.YearStart,@Date)/7)+1),2) +
'-'+convert(varchar(1),(datediff(dd,a.YearStart,@Date)%7)+1)
from
(
select
YearStart =
-- Case finds start of year
case
whenNextYrStart <= @date
thenNextYrStart
whenCurrYrStart <= @date
thenCurrYrStart
elsePriorYrStart
end
from
(
select
-- First day of first week of prior year
PriorYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,-1,aaa.Jan4))/7)*7,-53690),
-- First day of first week of current year
CurrYrStart =
dateadd(dd,(datediff(dd,-53690,aaa.Jan4)/7)*7,-53690),
-- First day of first week of next year
NextYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,1,aaa.Jan4))/7)*7,-53690)
from
(
select
--Find Jan 4 for the year of the input date
Jan4=
dateadd(dd,3,dateadd(yy,datediff(yy,0,@date),0))
) aaa
) aa
) a
return @YearWeekDayOfWeek
end
go
-- Execute function on first day, first day+60,
-- and first day+364 for years from 1990 to 2030.
select
DT= convert(varchar(10),DT,121),
YR_START_DT =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT),
YR_START_DT_60 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+60),
YR_START_DT_365 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+364)
from
(
select DT = getdate()union all
select DT = convert(datetime,'1990/01/01') union all
select DT = convert(datetime,'1990/12/31') union all
select DT = convert(datetime,'1991/12/30') union all
select DT = convert(datetime,'1993/01/04') union all
select DT = convert(datetime,'1994/01/03') union all
select DT = convert(datetime,'1995/01/02') union all
select DT = convert(datetime,'1996/01/01') union all
select DT = convert(datetime,'1996/12/30') union all
select DT = convert(datetime,'1997/12/29') union all
select DT = convert(datetime,'1999/01/04') union all
select DT = convert(datetime,'2000/01/03') union all
select DT = convert(datetime,'2001/01/01') union all
select DT = convert(datetime,'2001/12/31') union all
select DT = convert(datetime,'2002/12/30') union all
select DT = convert(datetime,'2003/12/29') union all
select DT = convert(datetime,'2005/01/03') union all
select DT = convert(datetime,'2006/01/02') union all
select DT = convert(datetime,'2007/01/01') union all
select DT = convert(datetime,'2007/12/31') union all
select DT = convert(datetime,'2008/12/29') union all
select DT = convert(datetime,'2010/01/04') union all
select DT = convert(datetime,'2011/01/03') union all
select DT = convert(datetime,'2012/01/02') union all
select DT = convert(datetime,'2012/12/31') union all
select DT = convert(datetime,'2013/12/30') union all
select DT = convert(datetime,'2014/12/29') union all
select DT = convert(datetime,'2016/01/04') union all
select DT = convert(datetime,'2017/01/02') union all
select DT = convert(datetime,'2018/01/01') union all
select DT = convert(datetime,'2018/12/31') union all
select DT = convert(datetime,'2019/12/30') union all
select DT = convert(datetime,'2021/01/04') union all
select DT = convert(datetime,'2022/01/03') union all
select DT = convert(datetime,'2023/01/02') union all
select DT = convert(datetime,'2024/01/01') union all
select DT = convert(datetime,'2024/12/30') union all
select DT = convert(datetime,'2025/12/29') union all
select DT = convert(datetime,'2027/01/04') union all
select DT = convert(datetime,'2028/01/03') union all
select DT = convert(datetime,'2029/01/01') union all
select DT = convert(datetime,'2029/12/31') union all
select DT = convert(datetime,'2030/12/30')
) a
Function Test Results:
DT YR_START_DT YR_START_DT_60 YR_START_DT_364
---------- ----------- -------------- ---------------
2006-01-18 2006-W03-3 2006-W11-7 2007-W03-3
1990-01-01 1990-W01-1 1990-W09-5 1991-W01-1
1990-12-31 1991-W01-1 1991-W09-5 1992-W01-1
1991-12-30 1992-W01-1 1992-W09-5 1992-W53-1
1993-01-04 1993-W01-1 1993-W09-5 1994-W01-1
1994-01-03 1994-W01-1 1994-W09-5 1995-W01-1
1995-01-02 1995-W01-1 1995-W09-5 1996-W01-1
1996-01-01 1996-W01-1 1996-W09-5 1997-W01-1
1996-12-30 1997-W01-1 1997-W09-5 1998-W01-1
1997-12-29 1998-W01-1 1998-W09-5 1998-W53-1
1999-01-04 1999-W01-1 1999-W09-5 2000-W01-1
2000-01-03 2000-W01-1 2000-W09-5 2001-W01-1
2001-01-01 2001-W01-1 2001-W09-5 2002-W01-1
2001-12-31 2002-W01-1 2002-W09-5 2003-W01-1
2002-12-30 2003-W01-1 2003-W09-5 2004-W01-1
2003-12-29 2004-W01-1 2004-W09-5 2004-W53-1
2005-01-03 2005-W01-1 2005-W09-5 2006-W01-1
2006-01-02 2006-W01-1 2006-W09-5 2007-W01-1
2007-01-01 2007-W01-1 2007-W09-5 2008-W01-1
2007-12-31 2008-W01-1 2008-W09-5 2009-W01-1
2008-12-29 2009-W01-1 2009-W09-5 2009-W53-1
2010-01-04 2010-W01-1 2010-W09-5 2011-W01-1
2011-01-03 2011-W01-1 2011-W09-5 2012-W01-1
2012-01-02 2012-W01-1 2012-W09-5 2013-W01-1
2012-12-31 2013-W01-1 2013-W09-5 2014-W01-1
2013-12-30 2014-W01-1 2014-W09-5 2015-W01-1
2014-12-29 2015-W01-1 2015-W09-5 2015-W53-1
2016-01-04 2016-W01-1 2016-W09-5 2017-W01-1
2017-01-02 2017-W01-1 2017-W09-5 2018-W01-1
2018-01-01 2018-W01-1 2018-W09-5 2019-W01-1
2018-12-31 2019-W01-1 2019-W09-5 2020-W01-1
2019-12-30 2020-W01-1 2020-W09-5 2020-W53-1
2021-01-04 2021-W01-1 2021-W09-5 2022-W01-1
2022-01-03 2022-W01-1 2022-W09-5 2023-W01-1
2023-01-02 2023-W01-1 2023-W09-5 2024-W01-1
2024-01-01 2024-W01-1 2024-W09-5 2025-W01-1
2024-12-30 2025-W01-1 2025-W09-5 2026-W01-1
2025-12-29 2026-W01-1 2026-W09-5 2026-W53-1
2027-01-04 2027-W01-1 2027-W09-5 2028-W01-1
2028-01-03 2028-W01-1 2028-W09-5 2029-W01-1
2029-01-01 2029-W01-1 2029-W09-5 2030-W01-1
2029-12-31 2030-W01-1 2030-W09-5 2031-W01-1
2030-12-30 2031-W01-1 2031-W09-5 2032-W01-1
(43 row(s) affected)
CODO ERGO SUM
hi friends,
how to get the date of the first/last day of the week in sql...
can any one help me
Cheers,
raj
I've this query
SELECT
t1.ID, t1.Date, t1.Time,
t1.VALUE
FROM RESULT WHERE t1.Date>=CONVERT(VARCHAR(10),DATEADD(d,-7,GETDATE()),101) AND
t1.Date<CONVERT(VARCHAR(10), GETDATE(), 101)
Let's say, current date is 8 AUG 2005 and current time is 2045
So, i will get
ID | Date (this is datetime) | Time (this is integer) | Value
--------------------------------------------------
204 | 8/1/2005| 2359 | 90
205 | 8/1/2005| 2250 | 99
206 | 8/1/2005| 1950 | 88
...
...
207 | 8/7/2005| 1845 | 77
208 | 8/7/2005| 2255 | 77
209 | 8/7/2005| 2140 | 77
Can someone can show me to filter data between
t1.Date>=CONVERT(VARCHAR(10),DATEADD(d,-7,GETDATE()),101) AND TIME>=CurrentTime
t1.Date<CONVERT(VARCHAR(10), GETDATE(), 101) AND TIME<=CurrentTime
If current date is 8 AUG 2005 and current time is 2045, so the result shown as follow
ID | Date (this is datetime) | Time (this is integer) | Value
--------------------------------------------------
204 | 8/1/2005| 2359 | 90
205 | 8/1/2005| 2250 | 99
...
...
207 | 8/7/2005| 1845 | 77
I only have this query,
SELECT
t1.ID, t1.Date, t1.Time,
t1.VALUE
FROM RESULT WHERE t1.Date>=CONVERT(VARCHAR(10),DATEADD(d,-7,GETDATE()),101) AND
t1.Date<CONVERT(VARCHAR(10), GETDATE(), 101)
lack of idea to put the TIME condition.
Plz help me..
Hi,
I'm making some sort of application where people can add their resume.
They also need something to add places where they have worked or currently are working.
I have a form where they can add this and i add this experience using the following stored procedure:
GO
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
create procedure [dbo].[sp_Insert_Experience]
@ExperienceId uniqueidentifier,
@ExperienceEmployee nvarchar(100),
@ExperienceFrom datetime,
@ExperienceUntil datetime,
@ExperienceQualifications nvarchar(250),
@ExperienceTechnologies nvarchar(250),
@ExperienceTasks nvarchar(250)
as
insert into Experiences
values(@ExperienceId,@ExperienceEmployee,@ExperienceFrom,@ExperienceUntil,@ExperienceQualifications,
@ExperienceTechnologies,@ExperienceTasks);
It must be possible to add the place where they currently are working. Then the ExperienceUntil has to be something like still going on. Then I decided that the user then had to set the current date.
But what I want is the following, I want that the ExperienceUntil keeps updating automatically, like everytime i get that record, it has to have current date.
Is this possible ?
But if the ExperienceUntil isn't the current date , it just had to take the supplied parameter date.
How to find the saturday in the current week using sql server 2000
View 5 Replies View RelatedI am trying to convert a field that has a Date and Time in smallDateTime format into something that will give me the day of the week that each Date corresponds to. For example, if my Date/Time field says "Jun 7 2001 09:30:00" I want my Day field to automatically say "Thursday". Is there a function that will do this? Or is there something close that will convert a variable of smalldatetime format into a number 0-6 which then can be converted to a day of the week?
View 3 Replies View RelatedIs it possible to write a sql querry to display day of the week?
If it is what is the syntax Pls.
Elsie Reed
Is there a way I can filter dates for last week (May 4 - 10)? This mean that every Mondays, I'll be getting last week's date range. Thanks
View 17 Replies View RelatedHow do I see which is the first day of the week setting in my server?
I was reading about @@DATEFIRST and SET FIRSTDATE, etc. But I don't want to set anything, I just want to know what is the first day of the week set on my server.
Any help will be appreciated.
Thanks
OPi
I need to write a user defined function that will return the date of the first day of a week when provided with the week number. I had an idea of using a while loop with that will keep adding 1 day from January 1st until the week number (found via the DATEPART function) is equal to the supplied week number. Not sure if this is the best way though - any ideas?
Donald.
Is there anyway to get SQL to convert a date to days of the week?
Example, I have a query where the date is "01/01/2006" but I would like it to display "Sunday". Thank you.
this might not be considered a sql problem but here goes anyways.
it was 53 weeks in 1998. however it seems like my computer considered week 53 last year as week 1 in 1999.
so when i perform an operation like this:
select datepart(wk, getdate())
next weeks number is returned. what to do?
Hi,
Is there an easy way to get the position (or number) of the week from a date? By position, I mean week number 1 if we are january 1st. For example:
Date | Week postion
=====================
2001-01-05 | 1
1996-12-28 | 52
1987-06-15 | 26
Thanks a lot,
Skip.