Date Difference Measurement And Weekends / Holidays
Jun 4, 2008
The below code works fine to measure the difference in days between two dates.
However, there is an additional business requirement to subtract week-ends, and holidays, from the equation.
Any ideas on how to accomplish this task, and leverage the below, existing code? Thanks in advance!
(SELECT ABS((TO_DATE(TO_CHAR(" & ToFieldDate & "),'yyyymmdd') - TO_DATE(TO_CHAR(" & FromFieldDate & "),'yyyymmdd'))) FROM DUAL) AS Measurement "
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Feb 2, 2014
I have already created a table name 'tblHolidays' and populated with 2014 Holidays. What I would like is be able to calculate (subtract or add) number of days from a date. For example subtract 2 days from 07/08/2014 and function should return 07/03/2014.
CREATE FUNCTION [dbo].[ElapsedBDays] (@Start smalldatetime, @End smalldatetime)
RETURNS int
AS
BEGIN
/*
Description:
Function designed to calculate the number of business days (In hours) between two dates.
[Code] ......
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Aug 28, 2013
I have a Bank holiday table (ID column, and Date column), how to exclude bank holidays in the datediff returned.
Create FUNCTION [dbo].days_diff ( @date1 datetime,@date2 datetime )
RETURNS int
AS
BEGIN
declare @i int
Declare @count int
[Code] .....
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Oct 14, 2015
Here I have 2 Dates. CreatedDttm & ModifiedDttm.
I want - DATEDIFF(Day,CreatedDttm,ModifiedDttm) and I have to exclude the Weekend days from that query result.
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May 19, 2014
I have a table with a list of jobs along with their start and end datetime values.
I am looking for a function which will return the time taken to process a job using a start date and an end date. If the date range covers a Saturday or Sunday I want the time to ignore the weekends.
Example
Start Date=2014-05-15 12:00:00.000
End Date=2014-05-19 13:00:00.000
Total Time should be: 2 Days, 1 Hour and 0 Minutes
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Jan 7, 2014
I have an SQL code below which removes weekends and non working days when calculating days difference between two dates:
ce.enquiry_time represents when the enquiry was logged
(DATEDIFF(dd, ce.enquiry_time, getdate()) + 1)
-(DATEDIFF(wk, ce.enquiry_time, getdate()) * 2)
-(CASE WHEN DATENAME(dw, ce.enquiry_time) = 'Sunday' THEN 1 ELSE 0 END)
-(CASE WHEN DATENAME(dw, getdate()) = 'Saturday' THEN 1 ELSE 0 END)
-(SELECT COUNT(*) FROM nonworking_day WHERE nonworking_day.nonworking_date >= ce.enquiry_time AND nonworking_day.nonworking_date < dateadd(dd,datediff(dd,0,getdate()),1))
It works but I don't understand how it works it out. I am having issues understanding each coloured piece of code and how it works together.
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Sep 1, 2015
I want go get all weekends of the year (year dynamic) with out CTE concept, because I need to implement in 2005 version.I have googled but getting only CTE examples.
Query to get the weekends in a year.
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May 12, 2005
Also includes ISOWeek & Weekends
Dont know whether this is of any use to anyone or it has been done before but there are a lot of posts on here regarding date calculation issues & usually the most straight forward answer is to compare against a table of dates.
So while looking at Bretts blog and another post on here, i thought i'd post this on here
http://weblogs.sqlteam.com/brettk/archive/2005/05/12/5139.aspx
http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=49698
Special thanks to rockmoose & BOL (as always)
Edit: It also moves bank holidays to the following Monday (and Tuesday - xmas) if the bank holiday(s) falls on the weekend
SET DATEFIRST 1
SET NOCOUNT ON
GO
--Create ISO week Function (thanks BOL)
CREATE FUNCTION ISOweek (@DATE datetime)
RETURNS int
AS
BEGIN
DECLARE @ISOweek int
SET @ISOweek= DATEPART(wk,@DATE)+1
-DATEPART(wk,CAST(DATEPART(yy,@DATE) as CHAR(4))+'0104')
--Special cases: Jan 1-3 may belong to the previous year
IF (@ISOweek=0)
SET @ISOweek=dbo.ISOweek(CAST(DATEPART(yy,@DATE)-1
AS CHAR(4))+'12'+ CAST(24+DATEPART(DAY,@DATE) AS CHAR(2)))+1
--Special case: Dec 29-31 may belong to the next year
IF ((DATEPART(mm,@DATE)=12) AND
((DATEPART(dd,@DATE)-DATEPART(dw,@DATE))>= 28))
SET @ISOweek=1
RETURN(@ISOweek)
END
GO
--END ISOweek
--CREATE Easter algorithm function
--Thanks to Rockmoose (http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=45689)
CREATE FUNCTION fnDLA_GetEasterdate(@year INT)
RETURNS CHAR (8)
AS
BEGIN
-- Easter date algorithm of Delambre
DECLARE @A INT,@B INT,@C INT,@D INT,@E INT,@F INT,@G INT,
@H INT,@I INT,@K INT,@L INT,@M INT,@O INT,@R INT
SET @A = @YEAR%19
SET @B = @YEAR / 100
SET @C = @YEAR%100
SET @D = @B / 4
SET @E = @B%4
SET @F = (@B + 8) / 25
SET @G = (@B - @F + 1) / 3
SET @H = ( 19 * @A + @B - @D - @G + 15)%30
SET @I = @C / 4
SET @K = @C%4
SET @L = (32 + 2 * @E + 2 * @I - @H - @K)%7
SET @M = (@A + 11 * @H + 22 * @L) / 451
SET @O = 22 + @H + @L - 7 * @M
IF @O > 31
BEGIN
SET @R = @O - 31 + 400 + @YEAR * 10000
END
ELSE
BEGIN
SET @R = @O + 300 + @YEAR * 10000
END
RETURN @R
END
GO
--END fnDLA_GetEasterdate
--Create the table
CREATE TABLE MyDateTable
(
FullDate datetime NOT NULL CONSTRAINT PK_FullDate PRIMARY KEY CLUSTERED,
Period int,
ISOWeek int,
WorkingDay varchar(1) CONSTRAINT DF_MyDateTable_WorkDay DEFAULT 'Y'
)
GO
--End table create
--Populate table with required dates
DECLARE @DateFrom datetime, @DateTo datetime, @Period int
SET @DateFrom = CONVERT(datetime,'20000101') --yyyymmdd (1st Jan 2000) amend as required
SET @DateTo = CONVERT(datetime,'20991231') --yyyymmdd (31st Dec 2099) amend as required
WHILE @DateFrom <= @DateTo
BEGIN
SET @Period = CONVERT(int,LEFT(CONVERT(varchar(10),@DateFrom,112),6))
INSERT MyDateTable(FullDate, Period, ISOWeek)
SELECT @DateFrom, @Period, dbo.ISOweek(@DateFrom)
SET @DateFrom = DATEADD(dd,+1,@DateFrom)
END
GO
--End population
/* Start of WorkingDays UPDATE */
UPDATE MyDateTable
SET WorkingDay = 'B' --B = Bank Holiday
--------------------------------EASTER---------------------------------------------
WHERE FullDate = DATEADD(dd,-2,CONVERT(datetime,dbo.fnDLA_GetEasterdate(DATEPART(yy,FullDate)))) --Good Friday
OR FullDate = DATEADD(dd,+1,CONVERT(datetime,dbo.fnDLA_GetEasterdate(DATEPART(yy,FullDate)))) --Easter Monday
GO
UPDATE MyDateTable
SET WorkingDay = 'B'
--------------------------------NEW YEAR-------------------------------------------
WHERE FullDate IN (SELECT MIN(FullDate) FROM MyDateTable
WHERE DATEPART(mm,FullDate) = 1 AND DATEPART(dw,FullDate) NOT IN (6,7)
GROUP BY DATEPART(yy,FullDate))
---------------------MAY BANK HOLIDAYS(Always Monday)------------------------------
OR FullDate IN (SELECT MIN(FullDate) FROM MyDateTable
WHERE DATEPART(mm,FullDate) = 5 AND DATEPART(dw,FullDate) = 1
GROUP BY DATEPART(yy,FullDate))
OR FullDate IN (SELECT MAX(FullDate) FROM MyDateTable
WHERE DATEPART(mm,FullDate) = 5 AND DATEPART(dw,FullDate) = 1
GROUP BY DATEPART(yy,FullDate))
--------------------AUGUST BANK HOLIDAY(Always Monday)------------------------------
OR FullDate IN (SELECT MAX(FullDate) FROM MyDateTable
WHERE DATEPART(mm,FullDate) = 8 AND DATEPART(dw,FullDate) = 1
GROUP BY DATEPART(yy,FullDate))
--------------------XMAS(Move to next working day if on Sat/Sun)--------------------
OR FullDate IN (SELECT CASE WHEN DATEPART(dw,FullDate) IN (6,7) THEN
DATEADD(dd,+2,FullDate) ELSE FullDate END
FROM MyDateTable
WHERE DATEPART(mm,FullDate) = 12 AND DATEPART(dd,FullDate) IN (25,26))
GO
---------------------------------------WEEKENDS--------------------------------------
UPDATE MyDateTable
SET WorkingDay = 'N'
WHERE DATEPART(dw,FullDate) IN (6,7)
GO
/* End of WorkingDays UPDATE */
--SELECT * FROM MyDateTable ORDER BY 1
DROP FUNCTION fnDLA_GetEasterdate
DROP FUNCTION ISOweek
--DROP TABLE MyDateTable
SET NOCOUNT OFF
Andy
Beauty is in the eyes of the beerholder
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Sep 11, 2015
I require outputting the date difference between two date's if it is greater than 7(DateDiff(day, DateAdd(day, t.[Started], Nxt.started), (t.[started])) > 7).I get incorrect syntax on my operator.What is the correct code?
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Apr 18, 2006
Hello,
I am trying some replication sample.I create a table with thousands of records in the publisher side. as I create a subscription(the subscription database is on a remote machine),
the whole table is created on the remote database.
I wanted to measure the performence as:
1. how much time was taken in filling the whole table in the subscriber side?
2. If i insert some 10000 records on publisher side, I want to measure, how much time was taken in inserting the same records on the subscriber?
How do I measure this ? Can I use some Log reader stuff.
thanks in advance
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Mar 24, 2014
I need accumulate the months by Quarter measurement. For example we're in March now and I need put these code in Where clause like:
Where MyDate > DATEADD(mm, -11, DATEADD(mm, DATEDIFF(mm, 0, GETDATE()), 0)) ...
here DATEADD(mm, -11, DATEADD(mm, DATEDIFF(mm, 0, GETDATE()), 0)) makes Apr of last year included because that is the first month in 2nd Quarter of last year. But in next month we're in Apr and I need make -11 as -12 in above code to include Apr of last year. And same reason if we're in Feb. 2014 then I need change -11 to -10.
So how can I calculate this to make the number fit into the code or some other way to get the same effect? I need get all last 4 quarters based on current month (include current Quarter).
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Jun 2, 2015
What is the measurement for Latency on the replication monitor? Is it hr:mm:ss, or is it mm:ss.ms?
I see
Performance = CriticalLatency = 2:41:52Last Synchronization = 6/2/2015 9:02:21 AM (current time)
Is the Latency 2 minutes 41 seconds behind or 2 hours 41 minutes behind?
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Aug 22, 2003
Hi I wanted to get difference between this two dates '12-31-2001','01-01-2002').
1 day 0 month 0 year.
Do we have any date function to get like this or we need write our own function stored proc?>
Any advice please?.
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Jul 30, 2007
select datediff(ss,In_time,Out_time)
select datediff(ss,'23:22:11','00:40:50')
But out time is as 12/6/2007 00:40:50
and in time is as 11/6/2007 23:22:11
when iam trying to get the date diff it gives the negitive value as
Column
------------
-81681
how can i get the actual difference
Malathi Rao
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Oct 1, 2007
Hi,
I have a problem with the following:
I have 2 dates in the following format mm/dd/yyyy hh:mm:ss AM.
I would like to measure the difference between 2 dates (Date1 and Date2).
When I use the following expression "DATEDIFF(d, Date1, Date2)" I get a value
without decimals. How can I have a value in days with decimals like e.g. 5.38? If you calculate this using Excel you get decimals behind the comma.
Please help!!!
Thanks!
DHL
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Dec 18, 2007
Hi,
I and my friend are trying to solve problem :
I have a system where an employee makes a call. The call can be of type 1,2,3. I have to calculate:
a. the last time the employee called up for that particular call type.
b. Yesterday
c. Call Duration between the last call date and yesterday
Please see the expected output to get an idea.
I will be passing in EmpID and CallType to the procedure.
First a record gets inserted into CallDetail and then into the Call for each CallType.
SAMPLE SCRIPT:
DECLARE @Call TABLE(CallID INT, CallType INT, CallDetailID INT)
DECLARE @CallDetail TABLE(CallDetailID INT, EmpID INT, EntryDt DateTime)
INSERT @CallDetail
SELECT 12123, 1, '11/30/2007 10:41:34 AM' UNION ALL
SELECT 43555, 1, '12/1/2007 11:21:23 AM' UNION ALL
SELECT 65322, 1, '12/18/2007 04:12:34 AM'
-- 65322 is the current calldetail id
INSERT @Call
SELECT 111, 1, 12123 UNION ALL
SELECT 112, 2, 12123 UNION ALL
SELECT 113, 2, 12123 UNION ALL
SELECT 123, 1, 43555 UNION ALL
SELECT 134, 1, 43555 UNION ALL
SELECT 143, 1, 65322 UNION ALL
SELECT 145, 1, 65322 UNION ALL
SELECT 154, 2, 65322 UNION ALL
SELECT 185, 3, 65322
Select * from @Call
Select * from @CallDetail
EXPECTED OUTPUT-- For CallType 1 EmpID 1
LastCallDate Yesterday Duration
12/1/2007 12/17/2007 16 days
-- For CallType 2 EmpID 1
LastCallDate Yesterday Duration
11/30/2007 12/17/2007 17 days
-- For CallType 3 (There was no CallType 3 made earlier by Empid 1)
LastCallDate Yesterday Duration
- 12/17/2007 0 days
How to achieve it
thanks.
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Apr 15, 2015
Have a table that list item#, date the standard cost went into effect and the standard cost. How do I find the difference in StdCost on the last EffectiveDate and second to last EffectiveDate. 5.59 (01/05/2015) minus 5.81 (09/29/.014) = -.22.
Item# EffectiveDate StdCost
1152 01/01/2009 5.50
1152 09/29/2014 5.81
1152 04/04/2011 5.56
[code]....
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Apr 23, 2002
I have a table containing following Columns plus other columns:
Start Date 04-01-2002(mm-dd-yyyy) varchar(10)
Start Time column 09:30:30(hh:mm:ss) varchar(8)
End Date 04-05-2002(mm-dd-yyyy) varchar(10)
End Time column 09:45:30(hh:mm:ss) varchar(8)
1]We want to create a view for Report Users So that they could just select
the other columns and difference in start Date/time to End Date /Time.
2]The Difference in time should be based on Business Day. i.e.
Saturday & Sunday should be excluded. &
3]Each business day is defined as 8.00 am to 5 .00pm
( 1 Business day = 9 hrs)
4]The time is stored as 24 hour clock.
For e.g.
Start Date Start TimeEnd Date End Time Desired Output
04/01/2002 10:00:0004/01/2002 3:30:00 0 Days 5:30 Hrs
04/01/2002 16:00:0004/02/2002 10:45:00 0 Days 3:45 Hrs
04/01/2002 09:00:0004/03/2002 10:45:00 2 Days 1:45 Hrs
04/05/2002 16:30:0004/08/2002 9:45:00 0 Days 2:15 Hrs******
******In last case as 04/06/2002 & 04/07/2002 were Saturday & Sunday ,hence
excluded.So the difference of time is just 2:15 hrs
Can you please give me a suggestion/pseudo code/logic on how I might do this?
We cannot use cursors as we want to make a view.This is for SQL Server 2000
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Feb 24, 2006
Hi to all,
I want to make an sql query that will subtract two dates and the difference will be number in months.
i have this table TestTable with Fields ACost, Adate, AMonth
my formula is this X = (Now-Adate), should give me number in months
and Y = (ACost/AMonth)
i want to get the product of X and Y, (X*Y).
how can i make this in sql views?
can anyone help me with this?
thanks a lot!
best regards,
saldiboy
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Dec 12, 2007
Hi,
I have a BETWEEN query (at least I think that's what it will need), but with a difference.
Normally you would specific a field which was BETWEEN two set variables
ie. {fieldname} BETWEEN 1 AND 3
However I need mine the other way round.
I have a series of records which have a startdate and enddate held against them.
When a user submits a new record to the db, I need it to check that the starting and ending date range doesn't overlap any of the existing start-end date ranges that exist.
In order to do that I'm trying to build a query which takes in the incoming startdate variable and see if that is within any of the existing start-date-enddate dates ranges of the existing records, and then same for the incoming endate. I actually want the ones that are going to cause a problem to appear...
I;m sure there is a pretty easy way of coding this, but I'm struggling to get my head round it.
Anyone offer any advice?
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Mar 24, 2008
how do you determine the date difference between the current record and the next record. i want to use the enddate on record 1 and calulate the time it took the next occurance to happen (start time) on record 2? and so forth.
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Jun 18, 2014
I have a field called 'LOG_COMMENTS' in a table named T_PRODUCTION_WORK_LOG.
In the 'LOG_COMMENTS' whenever a request is placed on hold comments are added by the application, such as 'Status changed from Open to On Hold' and 'Status changed from On Hold to Open' along with a 'LOG_DATESTAMP' field. A request can go on and off Hold multiple times, how do I determine the days a request is On Hold?
I know I can use the sql function DATEDIFF ( datepart , startdate , enddate ), but how do I account for the possiblity that the request was On Hold more than once? And how would I get LOG_DATESTAMP' times for 'LOG_COMMENTS' that contain 'Status changed from Open to On Hold' and 'Status changed from On Hold to Open''?
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Feb 4, 2015
I have here a query which delivers me the user data from the last month. The problem what I have is, if employee have more then one rows in this month, they will be also deliverd. But exactly this is not needed. I need only the last record from last month.
SELECT a.FIRMA,
a.PSNR,
a.FELDNR,
a.PFLFDNR,
a.INHALT AS FTE,
a.PFGLTAB,
[Code] ....
Result from Query at the moment:
FIRMAPSNRFELDNRPFLFDNRFTEPFGLTABPFGLTBISKSTNRPSPERSNR
1351022112013082820320101000084000895
14702220,912014100120320101000079000057
1166022112011010120320101000077000543
1364022112013100120150114000072000920
136402220,942015011520321231000072000920
As you can see, PSNR=364 has two rows and i need only the row from last month and last date.Maybe we can use Field PFLFDNR as counter. get only one row for every employee?
like this
FIRMAPSNRFELDNRPFLFDNRFTEPFGLTABPFGLTBISKSTNRPSPERSNR
1351022112013082820320101000084000895
14702220,912014100120320101000079000057
1166022112011010120320101000077000543
136402220,942015011520321231000072000920
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Nov 7, 2007
How would you create a column which displays the difference of two other columns in SQL? For example, column C=column A – column B.
My idea is that when ever data enters column A and column B, column C should show the difference of the two automatically. A, B and C are datetime columns. I'm looking at setting up an 'after' trigger on the table. Is there a better approach? Thanks.
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Oct 9, 2007
Hi,
I have a table VisitLog
pkey customer_id
pkey user_id
visit_date
visit_note
Given both id's, I need a report that will list the visit interval. Assuming the rows are entered in ordered.
the result should just display a single column with rows filled with date difference.
Date Format in example below is dd/MM/yyyy
1, 1, '01/01/07', null
1, 1, '03/01/07', null
1, 1, '08/01/07', null
The result should list difference in days.
2
5
Is it possible to do this in a SELECT Statement?
Thanks,
Max
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Apr 2, 2007
Suppose I have these two days fields
ddold 1/1/2005 12:00:00 AM
ddnew 2/1/2007 12:00:00 AM
How can i get the DateDifference of these two dates in days.
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Mar 27, 2008
I am having a table where i have the following columns where the date format is dd/mm/yyyy
Purchase Description From_Date To_Date------------------------------- --------------- ----------------Desktop 2/2/2007 2/3/2007Mouse 2/1/2007 28/1/2007Laptop 5/1/2008 15/3/2008Speaker 4/1/2008 21/1/2008
My requirement is i need to create a stored procedure which will look for the from_date and to_date values. If the difference is more than 30 days that record should get deleted automatically. How to write the stored procedure?
Please provide me with full stored procedure
Thanx in advance
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Apr 14, 2008
I have two columns in my table. Both the columns contains datetime datatypes. I need to write a stored procedure which will calculate the date difference between the two columns and if it exceeds more than 5 days then that record should get deleted. How to do it?Thanx
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Dec 31, 2002
we are creating script file like below on everyday and I need to find difference between previous script and current script. I can use dos(FC ) command to diffentiate between two file. But How I can differentiate for date itenary file which are generating everyday.
e:scriptdes.proc.123000
e:scriptdes.function.123000
e:scriptdes.table.123000
e:scriptdes.proc.122900
e:scriptdes.function.122900
e:scriptdes.table.122900
Anybody has any suugestion for this issue?.
Thanks,
Ravi
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Aug 27, 2012
I have already seen stored procedures that can calculate a difference in dates, excluding the weekends. Any extension of such a SQL query to exclude not only weekends, but other dates as well. We have a table of "holidays" (not necessarily standard holidays), and I am wondering if there is a way to exclude them from the calculation.
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Jan 23, 2015
I would like to calculate difference between end_date and current date in Months.And also how we can calculate the sum of difference in months between start_date and end_date for each ID?
CREATE TABLE datedifference (
id INT
,start_date INT
,end_date INT
)
INSERT INTO datedifference VALUES (10,20091202,20100629)
INSERT INTO datedifference VALUES (20,20071202,20090330)
INSERT INTO datedifference VALUES (30,20051202,20101031)
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Mar 27, 2008
I am having a table where i have the following columns where the date format is dd/mm/yyyy
Purchase DescriptionFrom_DateTo_Date
------------------------- --------
Desktop2/2/20072/3/2007
Mouse2/1/200728/1/2007
Laptop5/1/200815/3/2008
Speaker4/1/200821/1/2008
My requirement is i need to create a stored procedure which will look for the from_date and to_date values. If the difference is more than 30 days that record should get deleted automatically. How to write the stored procedure?
Please provide me with full stored procedure
Thanx in advance
C.R.P RAJAN
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Dec 8, 2007
Hi All,
I want to get the date Difference with Day,hours,minutes,seconds of the given 2 dates.(Say the difference of
12/6/2007 7:00:00 AM, 12/8/2007 8:00:00 AM as 2 days 1:00:00)
Is there any inbuilt function in SSRS is available to implement this. Or any other way to do this.Please help me with this .Thanks in advance.
With Thanks
M.Mahendra
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